A certain quantity of a 35% sugar solution is mixed with 8 litres of a 48% sugar solution to obtain a 40% sugar solution. How many litres of the 35% sugar solution was there in the mixture?
- AOption (a)
13.6
- BOption (b)
13.2
- COption (c)
12.5
- DOption (d)
12.8
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Correct answer
12.8
Why this answer is correct
Shortcut Trick
Using the alligation cross method, the ratio of quantities = (48 − 40) : (40 − 35) = 8 : 5
Here, 5 parts correspond to 8 litres of the 48% solution.
So, 1 part = 8 ÷ 5 = 1.6 litres.
Quantity of 35% solution = 8 parts = 8 × 1.6 = 12.8 litres.
∴ The correct answer is 12.8 litres.
Alternate Method
Given:
Concentration of first sugar solution = 35%
Concentration of second sugar solution = 48%
Quantity of second solution = 8 litres
Desired mixture concentration = 40%
35% Solution 48% Solution 35% 48%
40%
8 5 Ratio = 8 : 5
Calculations:
Let the quantity of the 35% sugar solution be x litres.
⇒ Total sugar in 35% solution + Total sugar in 48% solution = Total sugar in final mixture
⇒ (35 ÷ 100) × x + (48 ÷ 100) × 8 = (40 ÷ 100) × (x + 8)
⇒ 35x + 384 = 40(x + 8)
⇒ 35x + 384 = 40x + 320
⇒ 40x − 35x = 384 − 320
⇒ 5x = 64
⇒ x = 64 ÷ 5 = 12.8
∴ The correct answer is 12.8 litres.
Additional Information
Rule of Alligation
When two mixtures of different concentrations are mixed, the ratio of their quantities is inversely proportional to the absolute difference of their concentrations from the average mixture concentration.
Repeated Replacement Formula
If from a vessel containing volume V of pure liquid, a quantity R is drawn out and replaced by water n times, the final quantity of pure liquid left = V × (1 − R ÷ V)n.