Shortcut Trick
The required greatest number is the HCF of the numbers obtained after subtracting the respective remainders.
Required Number = HCF of (2307 − 7) and (3105 − 5)
Required Number = HCF of 2300 and 3100
Both 2300 and 3100 are directly divisible by 100, and 23 and 31 are co-prime.
∴ The correct answer is 100.
Alternate Method
Given:
Dividend numbers = 2307 and 3105
Respective remainders = 7 and 5
Formula Used:
The greatest number that divides x and y leaving remainders a and b respectively is given by the Highest Common Factor (HCF) of (x − a) and (y − b).
Calculations:
⇒ First resulting number = 2307 − 7 = 2300
⇒ Second resulting number = 3105 − 5 = 3100
⇒ Now, find the prime factorization of 2300 and 3100:
⇒ 2300 = 23 × 100 = 23 × 22 × 52
⇒ 3100 = 31 × 100 = 31 × 22 × 52
⇒ The common factors between the two prime factorizations are 22 and 52.
⇒ HCF = 22 × 52
⇒ HCF = 4 × 25 = 100
∴ The correct answer is 100.
Additional Information
Greatest Number Dividing with Specific Remainders
The greatest number that will divide x, y, and z leaving individual remainders a, b, and c respectively is given by finding the HCF of (x − a), (y − b), and (z − c).
Greatest Number Dividing with Same Remainder
The greatest number that will divide x, y, and z leaving the exact same remainder 'r' in each case is given by finding the HCF of (x − r), (y − r), and (z − r).
Greatest Number Dividing with Unknown Same Remainder
When x, y, and z are divided by the greatest number leaving the same but unknown remainder, the required number is the HCF of the absolute differences: |x − y|, |y − z|, and |z − x|.
Product Rule of LCM and HCF
For any two numbers 'A' and 'B', the product of the given numbers is strictly equal to the product of their LCM and HCF. Rule: A × B = LCM(A, B) × HCF(A, B).