
Shortcut Trick
Arrange data in ascending order: 0.1, 0.9, 1, 1.1, 2.3, 2.5, 3.9, 4.2, 4.6, 5.
Total number of terms (n) = 10 (even).
Median = Average of the middle two terms (5th and 6th terms).
Median = (2.3 + 2.5) ÷ 2 = 4.8 ÷ 2 = 2.4.
∴ The correct answer is 2.4.

Alternate Method
Given: Data set = {1, 1.1, 2.3, 0.1, 0.9, 5, 3.9, 2.5, 4.2, 4.6}
Formula Used:
For an even number of observations (n), Median = [(n/2)th observation + (n/2 + 1)th observation] ÷ 2

Calculations:
⇒ Arranging data in ascending order: 0.1, 0.9, 1, 1.1, 2.3, 2.5, 3.9, 4.2, 4.6, 5
⇒ Total observations n = 10
⇒ Position of the middle terms = 10 ÷ 2 = 5th and (10 ÷ 2 + 1) = 6th
⇒ 5th observation = 2.3
⇒ 6th observation = 2.5
⇒ Median = (2.3 + 2.5) ÷ 2
⇒ Median = 4.8 ÷ 2 = 2.4
Comparing the result with the given options, the value matches Option (2).
∴ The correct answer is 2.4.

Additional Information
Median for Odd Observations
If n is odd, the median is the value of the ((n + 1) ÷ 2)th observation after arranging the data in order.
Mean
The arithmetic average calculated by dividing the sum of all observations by the total count (n).
Mode
The observation that occurs most frequently in the data set.
Empirical Relationship
The relationship between Mean, Median, and Mode is given by: Mode = 3 × Median − 2 × Mean.