One pipe can fill a tank in 6 minutes, while another pipe can empty the completely filled tank in 7 minutes. If both the pipes are opened together when the tank is empty, how many minutes will it take to fill one-half of the tank?
- AOption (a)
22
- BOption (b)
21
- COption (c)
42
- DOption (d)
43
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Correct answer
21
Why this answer is correct
Shortcut Trick
Net rate of filling = (1/6) − (1/7) = 1/42 part per minute.
Time to fill the full tank = 42 minutes.
Time to fill one-half (1/2) of the tank = 42 ÷ 2 = 21 minutes.
∴ The correct answer is 21 minutes.
Alternate Method
Given: Filling time = 6 min, Emptying time = 7 min.
Formula Used: Total Work = LCM of time; Efficiency = Work ÷ Time.
| Pipe | Time (min) | Total Capacity | Efficiency |
|---|---|---|---|
| Inlet Pipe | 6 | 42 units | +7 |
| Outlet Pipe | 7 | −6 |
⇒ Combined efficiency of both pipes = 7 − 6 = 1 unit/min.
⇒ Total capacity to be filled = 1/2 × 42 = 21 units.
⇒ Time taken = 21 units ÷ 1 unit/min = 21 minutes.
∴ The correct answer is 21 minutes.
Additional Information
Inlet and Outlet Logic
Efficiency of an inlet pipe is always positive (+), while the efficiency of an outlet (leakage) pipe is always negative (−).
Combined Rate Formula
If pipe A fills in 'x' hours and pipe B empties in 'y' hours, net work done in 1 hour = (1/x) − (1/y).
Work and Wages
Wages are always distributed in the ratio of work done or the ratio of efficiencies of the pipes/workers.