Reasoning PYQs

BODMAS Rule:

According to the question, the signs are interchanged as follows:

Now, given the equation: 12 + 105 × 3 ÷ 14 − 3 = ?

After interchanging the specified signs, the new equation is:

12 − 105 ÷ 3 + 14 × 3 = ?

Perform operations according to BODMAS:

⇒ 12 − 105 ÷ 3 + 14 × 3

⇒ 12 − 35 + 42

⇒ −23 + 42

⇒ 19

Hence, the correct answer is "Option 2".

Calculation:

"PEST’ is coded as ‘6324’

‘PENS’ is coded as ‘8634’

PEST ⇒ 6324

PENS ⇒ 8634

Since P, E, and S are common to these two words. Similarly, common numbers are 6, 3 and 4

So,

code of T → 2

code of N → 8

So, 8  is the code for ‘N’ in the given code language.

Hence, the correct answer is "Option 2".

The logic followed here is:

For, LGEI is related to RMKO

For, JECG is related to PKIM

Similarly, for HCAE

So, 'HCAE will be related to 'NIGK

Hence, the correct answer is "Option 4".

The logic followed here is:

Option 1) NJL

Option 2)  LHJ

Option 3) TPS

Option 4) QMO

Here, 'TPS' is odd among the given options.

Hence, the correct answer is "Option 3".

The logic followed here is: 

Thus, 445 will come in place of question mark.

Hence, the correct answer is 'Option 2'.

Given

Statements:

Some woods are chisels.

Some chisels are graphs.

The least possible Venn diagram for the given statement is:

Conclusions:

(I) Some woods are graphs:

It is possible that some Woods are Graphs, but it is not necessary (i.e., not a definite conclusion). There are possible Venn diagram arrangements where Woods and Graphs do not overlap.

Therefore, conclusion (I) does not logically follow.

(II) All graphs are chisels:

 The relationship is only a 'Some' relationship (a partial overlap).

A 'Some' relationship does not imply an 'All' relationship (where the entire set of Graphs is contained within Chisels).

Therefore, conclusion (II) does not logically follow.

So, Neither conclusion (I) nor (II) follows. 

Hence, the correct answer is "Option 4".

Given

Statements:

Some nuts are berries.

All fruits are berries.

The least possible Venn diagram for the given statement is:

Conclusions:

(I) Some nuts are fruits:

From the statements, we know Nuts overlap Berries, and Fruits are inside Berries. The statements do not provide any definite link between Nuts and Fruits. The overlap is a possibility, but not a certainty.

Conclusion (I) does not follow definitively.

(II) All berries are fruits:

The statement says "All fruits are berries" (Fruits $\subset$ Berries), which means Berries is the larger set, containing Fruits. The conclusion attempts to reverse this relationship.

Conclusion (II) does not follow.

So, Neither conclusion (I) nor (II) follows.

Hence, the correct answer is "Option 3".

Given: 

Binoy starts from Point Y and drives 16 km towards the north.

He then takes a right turn and drives 43 km,

then turns right and drives 38 km.

He then takes a right turn and drives 19 km.

He takes a final right turn, drives 22 km and stops at Point Z.

So, He should drive 24 km towards the west i in order to reach Point Y again.

Hence, the correct answer is 'Option 2'.

The given coded language is:

 

Therefore, the code for ‘T’ is 3.

Hence, the correct answer is "Option 2".

The logic followed here is:

For, DUMB is related to TMCT

For,  POYV is related to FGON

Similarly, for LQUX

So, 'LQUX' will be related to 'BIKP'

Hence, the correct answer is "Option 4".

Given: Seven boxes F, G, H, M, N, O and P are kept one over the other but not necessarily in the same order.

1. Only two boxes are kept below O.

2) Only one box is kept above N.

3. Only one box is kept between N and H.

4) G is kept immediately above M.

5)  F is kept at some place below P.

 

So, there are 'Four' boxes are kept between P and G.

Hence, the correct answer is "Option 4".

The letter-cluster that DOES NOT belong to the group is POT.

The logic followed here is:

Option 1) BX – HK

Option 2) GC – MP 

 

Option 3) TP – ZD

 

Option 4) XT – DG

 

Thus, the letter-cluster that DOES NOT belong to that group is  TP – ZD.

Hence, the correct answer is "Option 3".

The logic followed here is:

Thus, the missing term in the series is KPI69.

Hence, the correct answer is "Option 4".

Given: L, M, N, O, Q, R and S are sitting around a circular table facing the centre of the table.

1. Only one person sits between N and Q when counted from the left of Q.

2. S sits third to the right of R.

3. L sits third to the left of M.

4. S sits to the immediate right of L.

5) O is not an immediate neighbour of L.

Thus, Three people sit between O and Q when counted from the right of O.

Hence, the correct answer is "Option 1".

The logic followed here is:

Logic: Divide the first number by 5 to get the second number.

130, 26

130 ÷ 5 = 26

225, 45 

225 ÷ 5 = 45

Now, checking the options:

Option 1) 155, 30

155 ÷ 5 = 31. (31 ≠ 30) - Incorrect

Option 2) 160, 32

160 ÷ 5 = 32. (32 = 32) - Correct

Option 3)  200, 42 

200 ÷ 5 = 40. (40 ≠ 42) - Incorrect

Option 4)  185, 36

185 ÷ 5 = 37. (37 ≠ 36) - Incorrect

Hence, the correct option is "Option 2"

The logic followed here is:

So, 'PJK 112' will replace the question mark in the given series.

Hence, the correct answer is "Option 2".

Given: Five people (A, B, C, D and E) are sitting in a straight line. They all are facing towards the north.

1. B is sitting immediately between C and E.

2. A is sitting third to the left of E..

3) C is sitting second to the right of D.

So, D is sitting at the extreme left end of line.

Hence, the correct answer is "Option 1".

Given series:

(Left) £ $ 7 1 1 @ @ 2 © 5 $ & @ £ % # 7 € © @ 8 $ (Right)

Condition to be checked:

Number → Number → Symbol

£ $ 7 1 1 @ @ 2 © 5 $ & @ £ % # 7 € © @ 8 $

There is only one such number that meets the criteria: 1 (in the sequence 1 1 @).

Hence, the correct answer is "Option 3".

Given: Seven boxes A, B, C, D, E, F, and G are kept one over the other but not necessarily in the same order.

1) Only four boxes are kept between A and E.

2)  Only G is kept above A.

3. Only two boxes are kept between B and C.

4) D is kept immediately above F.

5) C is not kept immediately above D.

 

So, there are Three boxes are kept above D.

Hence, the correct answer is "Option 4".

Given:

Total students in the row = 47.

Shivangi's position = 21^st from the Left end

Ankit's position is 22^nd to the Right of Shivangi.

Since Ankit is to the right of Shivangi,

A = Shivangi + 22

 = 21 + 22

= 43^rd from the Left end.

Ankit position from right

⇒ Total students -  Ankit from left end + 1

= 47 - 43 + 1

= 4 + 1

= 5^th from the Right end.

Hence, the correct answer is "Option 2".