IBPS Probationary Officer (PO) · Topic Collection

Quantitative Aptitude PYQs

Arithmetic, number systems, percentages, ratios, profit and loss, time and work, algebra, geometry, mensuration, and trigonometry.

1305 Total Questions38 Official PapersYears: 2021–2026Search in Quantitative Aptitude
Showing questions 381–400 of 1305Page 20 of 66
IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 381

IBPS Probationary Officer (PO) 2024• Quantitative Aptitude• Quantitative Aptitude

Find the wrong term in the following series.

205 , 236 , 279 , 304 , 341

  1. AOption (a)

    205

  2. BOption (b)

    236

  3. COption (c)

    279

  4. DOption (d)

    304

  5. EOption (e)

    341

View answer & explanation

Correct answer

Answer: (c)C.

279

Why this answer is correct

Given:

205 , 236 , 279 , 304 , 341

Calculation:

Here the logic follows as,

Hence, 279 is the wrong term

\(\therefore\) The correct answer is 279.

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 382

IBPS Probationary Officer (PO) 2024• Quantitative Aptitude• Quantitative Aptitude

In the following number series, a wrong number is given. Find out the wrong number.

74, 125, 76, 122, 79, 117

  1. AOption (a)

    79

  2. BOption (b)

    117

  3. COption (c)

    122

  4. DOption (d)

    74

  5. EOption (e)

    125

View answer & explanation

Correct answer

Answer: (a)A.

79

Why this answer is correct

Calculation:

⇒ 74 + 51 = 125

⇒ 125 – 49 = 76

⇒ 76 + 46 = 122

⇒ 122 – 42 = 80

⇒ 80 + 37 = 117

∴ The wrong number is 79

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 383

IBPS Probationary Officer (PO) 2024• Quantitative Aptitude• Quantitative Aptitude

In each of the following number series, the wrong number is given, find out that number.

87, 114, 103, 130, 119, 144, 135

  1. AOption (a)

    119

  2. BOption (b)

    114

  3. COption (c)

    87

  4. DOption (d)

    135

  5. EOption (e)

    144

View answer & explanation

Correct answer

Answer: (e)E.

144

Why this answer is correct

Calculation:

The series follows the following pattern:

⇒ 87 + 27 = 114

⇒ 114 – 11 = 103

⇒ 103 + 27 = 130

⇒ 130 – 11 = 119

⇒ 119 + 27 = 146

⇒ 146 – 11 = 135

∴ The wrong number is 144

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 384

IBPS Probationary Officer (PO) 2024• Quantitative Aptitude• Quantitative Aptitude

A principal of Rs. 12000 is 3/5 th itself at x% rate of interest for 5 years. If the same principal is invested for 2 years  at compound interest (x + 4)% annum. Find the interest amount.

  1. AOption (a)

    Rs.4292.3

  2. BOption (b)

    Rs.4890.4

  3. COption (c)

    Rs.4147.2

  4. DOption (d)

    Rs. 4219.8

  5. EOption (e)

    Rs.4231.9

View answer & explanation

Correct answer

Answer: (c)C.

Rs.4147.2

Why this answer is correct

Shortcut Trick

Simple Interest = 3/5 × Principal ⇒ Rate x = (3/5 × 100) ÷ 5 = 12%.

New CI Rate = 12% + 4% = 16%.

For 2 years at 16%, Effective Rate = 16 + 16 + (16 × 16)/100 = 34.56%.

CI = 12000 × 34.56% = 120 × 34.56 = ₹4147.2.

∴ The correct answer is ₹4147.2.

Alternate Method

Given: Principal (P) = ₹12000, Time (T1) = 5 years, SI = 3/5 × P, Time (T2) = 2 years, CI Rate = (x + 4)%.

Formula Used: SI = (P × R × T)/100 and CI = P[(1 + R/100)n − 1].

⇒ SI = 3/5 × 12000 = ₹7200.

⇒ 7200 = (12000 × x × 5) / 100.

⇒ 7200 = 600x ⇒ x = 12%.

⇒ New Rate = 12 + 4 = 16%.

⇒ CI = 12000 × [(1 + 16/100)2 − 1].

⇒ CI = 12000 × [(1.16)2 − 1] = 12000 × [1.3456 − 1].

⇒ CI = 12000 × 0.3456 = ₹4147.2.

∴ The correct answer is ₹4147.2.

Additional Information

Effective Rate of CI

For 2 years, the effective interest rate is R + R + (R × R)/100 percent of the Principal.

Relationship between SI and CI

Difference for 2 years = P × (R/100)2. For the 1st year, SI and CI are always equal if compounded annually.

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 385

IBPS Probationary Officer (PO) 2024• Quantitative Aptitude• Quantitative Aptitude

Shyam travels 360 km at 'x + 4' km/hr, completing the journey in 15 hours. If he boosted his speed by (x + 4)/4, it would decrease his trip time by 'y' hours. If Shyam were to travel at a pace of 'x - y' km/hr, how many hours would it take him to cover a distance of 187 km?

  1. AOption (a)

    12 hr

  2. BOption (b)

    13 hr

  3. COption (c)

    14 hr

  4. DOption (d)

    11 hr

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (d)D.

11 hr

Why this answer is correct

Shortcut Trick

Initial speed (x + 4) = 360 ÷ 15 = 24 kmph.

Speed boost = 24 ÷ 4 = 6 kmph → New speed = 30 kmph.

New time = 360 ÷ 30 = 12 hours → Time saved y = 15 − 12 = 3 hours.

Final speed = x − y = 20 − 3 = 17 kmph.

Required time = 187 ÷ 17 = 11 hours.

∴ The correct answer is 11 hr.

Alternate Method

Given: Total distance = 360 km, Time taken = 15 hours at speed (x + 4) km/hr.

Formula Used: Speed = Distance ÷ Time; Time = Distance ÷ Speed.

⇒ Speed (x + 4) = 360 ÷ 15

⇒ x + 4 = 24 km/hr

⇒ x = 20 km/hr

⇒ Boosted speed = (x + 4) + (x + 4)/4 = 24 + 24/4 = 30 km/hr

⇒ New trip time = 360 ÷ 30 = 12 hours

⇒ y (Time decrease) = 15 − 12 = 3 hours

⇒ Target speed = x − y = 20 − 3 = 17 km/hr

⇒ Required time = 187 ÷ 17 = 11 hours

∴ The correct answer is 11 hr.

Additional Information

Speed-Time Relation

For a constant distance, speed is inversely proportional to time (S1 × T1 = S2 × T2).

Average Speed

Average Speed = Total Distance ÷ Total Time. For two equal distances with speeds a and b, Average Speed = 2ab/(a + b).

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 386

IBPS Probationary Officer (PO) 2024• Quantitative Aptitude• Quantitative Aptitude

A , B and C started a business with capital in the ratio of 8 : 6 : 5. After 8 months A withdrew 25% of his capital while C increased 20% of his investment if at the end of the year total profit of the business is Rs14000 then what is the profit share of C?

  1. AOption (a)

     12000

  2. BOption (b)

     7000

  3. COption (c)

     4000

  4. DOption (d)

     8000

  5. EOption (e)

     6000

View answer & explanation

Correct answer

Answer: (c)C.

 4000

Why this answer is correct

Shortcut Trick

Ratio of Profit = Σ(Capital × Time)

A : B : C = (8 × 8 + 6 × 4) : (6 × 12) : (5 × 8 + 6 × 4)

A : B : C = (64 + 24) : 72 : (40 + 24) = 88 : 72 : 64

Simplified Ratio = 11 : 9 : 8. Total units = 11 + 9 + 8 = 28 units.

28 units = Rs. 14000 ⇒ 1 unit = Rs. 500. Profit of C = 8 × 500 = Rs. 4000. ∴ The correct answer is Rs. 4000.

Alternate Method

Given → Initial Capital Ratio A:B:C = 8:6:5. Time = 12 months.
Formulas → Profit Share = Capital × Time Period

⇒ A's investment: (8 × 8 months) + (8 × 75% × 4 months) = 64 + 24 = 88.
⇒ B's investment: (6 × 12 months) = 72.
⇒ C's investment: (5 × 8 months) + (5 × 120% × 4 months) = 40 + 24 = 64.
⇒ Total Investment Ratio A:B:C = 88 : 72 : 64 = 11 : 9 : 8.
⇒ Sum of ratios = 11 + 9 + 8 = 28.
⇒ C's share = (8 ÷ 28) × 14000 = 8 × 500 = 4000.

∴ The correct answer is Rs. 4000.

Additional Information

Partnership Basics

Profit is distributed based on the product of Capital and Time. If time is constant, profit ratio equals capital ratio.

Percentage Changes

To calculate a 25% decrease, multiply by 0.75. For a 20% increase, multiply by 1.20.

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 387

IBPS Probationary Officer (PO) 2024• Quantitative Aptitude• Quantitative Aptitude

In an election, 5% of the applicants were found ineligible and 85% of the eligible candidates belonged to the general category. If 4275 eligible candidates belonged to other categories, then how many voters appeared for the elections?

  1. AOption (a)

    30,000

  2. BOption (b)

    35,000

  3. COption (c)

    37,000

  4. DOption (d)

    35,500

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (a)A.

30,000

Why this answer is correct

Shortcut Trick

Let the total number of applicants be 100 units.

Eligible candidates = 95% of 100 = 95 units.

Other categories = (100% − 85%) of eligible = 15% of 95 = 14.25 units.

Given: 14.25 units = 4275 ⇒ 1 unit = 300.

Total applicants = 100 × 300 = 30,000.

∴ The correct answer is 30,000.

Alternate Method

Given:

Ineligible = 5% ⇒ Eligible = 95%

General Category = 85% of eligible ⇒ Other Categories = 15% of eligible

Other Categories candidates = 4275

Calculations:

Let the total number of voters be x.

⇒ Eligible candidates = x × (95/100)

⇒ Other categories = x × (95/100) × (15/100) = 4275

⇒ x × 0.95 × 0.15 = 4275

⇒ x × 0.1425 = 4275

⇒ x = 4275 ÷ 0.1425

⇒ x = 30,000

∴ The correct answer is 30,000.

Additional Information

Successive Percentage change

When a value is reduced by a% and then further by b%, the remaining value is P × (1 − a/100) × (1 − b/100).

Base change in Election problems

Always identify the base for each percentage. Here, 85% is of the eligible candidates, not the total applicants.

Ratio Method

Fractions can be used for faster calculation: 95% = 19/20 and 15% = 3/20. Total = 4275 × (20/19) × (20/3).

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 388

IBPS Probationary Officer (PO) 2024• Quantitative Aptitude• Quantitative Aptitude

A container contains 100 litres of milk. If 10 % of milk was replaced by water and this process was repeated two times more, then find the quantity of the milk in the final mixture.

  1. AOption (a)

    82.9 litres

  2. BOption (b)

    72.9 litres

  3. COption (c)

    62.9 litres

  4. DOption (d)

    72 litres

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (b)B.

72.9 litres

Why this answer is correct

Shortcut Trick

Initial quantity = 100 litres

Replacement fraction = 10% = 1/10

Remaining fraction after 1 process = 1 − 1/10 = 9/10

Since the process is repeated two times more (total 3 times):

Final Milk = 100 × (9/10)3 = 100 × 729/1000 = 72.9 litres

∴ The correct answer is 72.9 litres.

Alternate Method

Given:

Initial quantity of milk (x) = 100 litres

Quantity replaced (y) = 10% of 100 = 10 litres

Number of times the process is performed (n) = 3

Formula Used:

Final quantity = x × (1 − y/x)n

Calculations:

⇒ Final Quantity = 100 × (1 − 10/100)3

⇒ Final Quantity = 100 × (1 − 1/10)3

⇒ Final Quantity = 100 × (9/10) × (9/10) × (9/10)

⇒ Final Quantity = 100 × 0.9 × 0.9 × 0.9

⇒ Final Quantity = 100 × 0.729

⇒ Final Quantity = 72.9 litres

∴ The correct answer is 72.9 litres.

Additional Information

Successive Replacement Formula

The formula Final Quantity = Initial × (1 − r/100)n is used when a fixed percentage r is replaced n times.

Mixture Replacement with Different Quantities

If different amounts a, b, c are replaced each time, the final quantity is x × (1 − a/x) × (1 − b/x) × (1 − c/x).

Ratio of Milk to Water

After the process, the quantity of water = Total Capacity − Final Milk. In this case, 100 − 72.9 = 27.1 litres.

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 389

IBPS Probationary Officer (PO) 2024• Quantitative Aptitude• Quantitative Aptitude

What approximate value should come in the place of the question mark ‘?’ in the following question?

(5.96)3 ÷ 17.98 + 47.88 – ? × 1.95 = 19.93

  1. AOption (a)

    15

  2. BOption (b)

    12

  3. COption (c)

    25

  4. DOption (d)

    20

  5. EOption (e)

    18

View answer & explanation

Correct answer

Answer: (d)D.

20

Why this answer is correct

Concept Used:

Follow the BODMAS rule according to the table given below:

Calculation:

(5.96)3 ÷ 17.98 + 47.88 – ? × 1.95 = 19.93

⇒ 63 ÷ 18 + 48 – ? × 2 = 20

⇒ 216 ÷ 18 + 48 – ? × 2 = 20

⇒ 12 + 48 – ? × 2 = 20

⇒ – ?× 2 = 20 – 60

⇒ -2 × ? = -40

⇒ ? = 20

∴ The value of ? is 20

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 390

IBPS Probationary Officer (PO) 2024• Quantitative Aptitude• Quantitative Aptitude

What approximate value should come in place of ‘?’ in the following equation:

350.97 ÷ 27.02 + (13.99)2 ÷ 28.04 = ?

  1. AOption (a)

    13

  2. BOption (b)

    20

  3. COption (c)

    7

  4. DOption (d)

    15

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (b)B.

20

Why this answer is correct

Solution:

Rules of Approximation:

  1. If a number has digits to the right of the decimal less than 5, then just drop the digits to the right of the decimal. The number so obtained will be the approximated value.
  2. If a number has digits to the right of the decimal more than 5, then just drop the digits to the right of the decimal and raise the remaining number by '1'.The number so obtained will be the approximated value.

Concept Used:       

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

351 ÷ 27 + (14)2 ÷ 28 = ?

⇒ 351 ÷ 27 + 196 ÷ 28 = ?

⇒ 13 + 7 = ?

∴ ? = 20

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 391

IBPS Probationary Officer (PO) 2024• Quantitative Aptitude• Quantitative Aptitude

What approximate will come in the place of the question mark ‘?’ in the following question?

{(17.09 + 2.01) × 107.6 ÷ 75.6} + 71.40 × 11.90 = ?

  1. AOption (a)

    859

  2. BOption (b)

    889

  3. COption (c)

    879

  4. DOption (d)

    825

  5. EOption (e)

    881

View answer & explanation

Correct answer

Answer: (c)C.

879

Why this answer is correct

Concept used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculations:

{(17.09 + 2.01) × 107.6 ÷ 75.6} + 71.40 × 11.90 = ?

⇒ {(17 + 2) × 108 ÷ 76} + 71 × 12 = ?

⇒ 19 × 108 ÷ 76 + 852 = ?

⇒ 27 + 852 = ?

⇒ ? = 879

∴ The value of ? is 879

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 392

IBPS Probationary Officer (PO) 2024• Quantitative Aptitude• Quantitative Aptitude

What approximate value should come in place of “?” in the following equation:

{(784.03)1/2 × 3.97} + (29.07 × 12.96) = (?)2 – (7.92 × 5.01)

  1. AOption (a)

    529

  2. BOption (b)

    8

  3. COption (c)

    24

  4. DOption (d)

    23

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (d)D.

23

Why this answer is correct

Rules of Approximation:

  1. If a number has digits to the right of the decimal less than 5, then just drop the digits to the right of the decimal. The number so obtained will be the approximated value.
  2. If a number has digits to the right of the decimal more than 5, then just drop the digits to the right of the decimal and raise the remaining number by '1'.The number so obtained will be the approximated value.

Concept Used:       

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

{(784)1/2 × 4} + (29 × 13) = (?)2 – (8 × 5)

⇒ {28 × 4} + (29 × 13) = (?)2 – (8 × 5)

⇒ {28 × 4} + 377 = (?)2 – 40

⇒ 112 + 377 = (?)2 – 40

⇒ 489 = (?)2 – 40

⇒ (?)2 = 489 + 40

⇒ (?)2 = 529

∴ ? = 23

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 393

IBPS Probationary Officer (PO) 2024• Quantitative Aptitude• Quantitative Aptitude

What approximate value will come in the place of the question mark ‘?’ in the following question?

49.99% of 799.897 + 24.99% of 200.012 = 9 × ?

  1. AOption (a)

    80

  2. BOption (b)

    60

  3. COption (c)

    50

  4. DOption (d)

    70

  5. EOption (e)

    None

View answer & explanation

Correct answer

Answer: (c)C.

50

Why this answer is correct

Concept used:

Follow BODMAS rule to solve this question, as per the order given below:

Calculation:

49.99% of 799.897 + 24.99% of 200.012 = 9 × ?

On taking the approximate values, we get:

⇒ 50% of 800 + 25% of 200 = 9 × ?

⇒ (50/100) × 800 + (25/100) × 200 = 9 × ?

⇒ 400 + 50 = 9 × ?

⇒ ? = 450/9 = 50

∴ The value of ? is 50

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 394

IBPS Probationary Officer (PO) 2024• Quantitative Aptitude• Quantitative Aptitude

A shopkeeper allows two successive discounts of X% on a shirt which is marked at Rs 2500 and sells it at Rs 1764. Find the selling price of the shirt if the shopkeeper would have given X  + 2 % of two equal successive discounts?

  1. AOption (a)

     1681

  2. BOption (b)

     2025

  3. COption (c)

     1936

  4. DOption (d)

     1600

  5. EOption (e)

     1849

View answer & explanation

Correct answer

Answer: (a)A.

 1681

Why this answer is correct

Shortcut Trick

For two equal successive discounts of X%, the ratio of Marked Price (MP) to Selling Price (SP) is (100)2 : (100 − X)2.

Given MP = 2500 and SP = 1764 ⇒ √2500 : √1764 = 50 : 42.

Discount X% = (50 − 42) ÷ 50 × 100 = 16%.

New discount rate = 16% + 2% = 18%.

New SP = 2500 × (82 ÷ 100) × (82 ÷ 100) = 25 × 0.82 × 82 = 1681.

∴ The correct answer is Rs 1681.

Alternate Method

Formulas: SP = MP × (1 − d1/100) × (1 − d2/100) | Net Discount = a + b − ab/100

⇒ 1764 = 2500 × (1 − X/100)2

⇒ (1 − X/100)2 = 1764 ÷ 2500 = 0.7056

⇒ 1 − X/100 = √0.7056 = 0.84 ⇒ X/100 = 0.16 ⇒ X = 16%

⇒ New Discount rate = X + 2 = 18%

⇒ New SP = 2500 × (1 − 18/100)2 = 2500 × (0.82)2

⇒ New SP = 2500 × 0.6724 = 1681

∴ The correct answer is Rs 1681.

Additional Information

Successive Discounts

When two discounts 'a' and 'b' are given one after another, the single equivalent discount is (a + b − ab/100)%.

Relation between MP and SP

SP is always calculated on the Marked Price. SP = MP × (100 − D%)/100.

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 395

IBPS Probationary Officer (PO) 2024• Quantitative Aptitude• Quantitative Aptitude

If the price of an Iphone is reduced by 20% during the festival season, its sale is increased by 80%. If the percentage by which the net sale is increased be m, then what will be the square root of m+5 ? 

  1. AOption (a)

    7

  2. BOption (b)

    11

  3. COption (c)

    13

  4. DOption (d)

    17

  5. EOption (e)

    5

View answer & explanation

Correct answer

Answer: (a)A.

7

Why this answer is correct

Shortcut Trick

Net change % = x + y + (x × y)/100 where x = −20% (reduction) and y = +80% (increase).

m = −20 + 80 + (−20 × 80)/100 = 60 − 16 = 44%.

Required value = √(m + 5) = √(44 + 5) = √49 = 7.

∴ The correct answer is 7.

Alternate Method

Given:

Initial Price = 100, Initial Sale = 100 ⇒ Initial Revenue = 100 × 100 = 10000

Calculations:

⇒ New Price = 100 − 20% of 100 = 80

⇒ New Sale = 100 + 80% of 100 = 180

⇒ New Revenue = 80 × 180 = 14400

⇒ Increase in Revenue = 14400 − 10000 = 4400

⇒ Percentage increase (m) = (4400 ÷ 10000) × 100 = 44%

⇒ Value to find = √(m + 5) = √(44 + 5) = √49 = 7

∴ The correct answer is 7.

Additional Information

Successive Percentage Change

When a quantity is changed by x% and then by y%, the overall change is given by [x + y + (xy/100)]%.

Revenue Relationship

Revenue is the product of Price and Consumption (or Sale). If both change, the product change follows the successive percentage rule.

Percentage to Fraction

20% reduction = 4/5 multiplier; 80% increase = 9/5 multiplier. Net multiplier = (4/5) × (9/5) = 36/25. Increase = 11/25 = 44%.

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 396

IBPS Probationary Officer (PO) 2024• Quantitative Aptitude• Quantitative Aptitude

Directions: Study the following direction shows the total number of persons invested in Fixed deposits and mutual funds and number of persons invested in mutual funds in five different banks A, B, C, D and E.

 

20% of the persons who invested in Fixed deposit in Bank A are females and remaining are males and 30% of the persons invested in Mutual funds are in Bank A males , Find the number of males invested in both Fixed deposit and Mutual funds in bank A.

  1. AOption (a)

    460

  2. BOption (b)

    380

  3. COption (c)

    390

  4. DOption (d)

    420

  5. EOption (e)

    520

View answer & explanation

Correct answer

Answer: (b)B.

380

Why this answer is correct

General solution:

Bank A:

Number of persons invested in (Fixed deposit + Mutual Funds) = 600

Number of persons invested in Fixed deposit = 400

Number of persons invested in Mutual Funds = (600 - 400) =200

 

Bank B:

Number of persons invested in (Fixed deposit + Mutual Funds) = 450

Number of persons invested in Fixed deposit = 300

Number of persons invested in Mutual Funds = (450 - 300) =150

 

Bank C:

Number of persons invested in (Fixed deposit + Mutual Funds) = 750

Number of persons invested in Fixed deposit = 500

Number of persons invested in Mutual Funds = (750 - 500) =250

 

Bank D:

Number of persons invested in (Fixed deposit + Mutual Funds) = 700

Number of persons invested in Fixed deposit = 250

Number of persons invested in Mutual Funds = (700 - 250) = 450

 

Bank E:

Number of persons invested in (Fixed deposit + Mutual Funds) = 650

Number of persons invested in Fixed deposit = 350

Number of persons invested in Mutual Funds = (650 - 350) = 300 

 

Name of the bankNumber of persons invested in Fixed depositNumber of persons invested in Mutual Fund
Bank A400200
Bank B300150
Bank C500250
Bank D250450
Bank E350300

Solution:

Number of persons invested in Fixed deposition Bank A = 400

Number of females invested in Fixed deposit in Bank A= 400 ×  20/100 = 80

Number of males invested in Fixed deposit in Bank A = (400 - 80) = 320

Number of males invested in Mutual funds in Bank A = 200 ×  (30/100) = 60

Total males invested in both Mutual funds and Fixed deposit in Bank A = (320 + 60) = 380

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 397

IBPS Probationary Officer (PO) 2024• Quantitative Aptitude• Quantitative Aptitude

Directions: Study the following direction shows the total number of persons invested in Fixed deposits and mutual funds and number of persons invested in mutual funds in five different banks A, B, C, D and E.

 

If 1/3 and 1/5 of the number of persons invested in Fixed deposit in Bank B and C respectively for 2 years and remaining are invested for 5 years. Find the difference between the total number of persons invested in Mutual funds in Bank  B and Bank C together and the number of persons invested in fixed deposits for the time period of 5 years from the Bank B and C.

  1. AOption (a)

    220

  2. BOption (b)

    180

  3. COption (c)

    150

  4. DOption (d)

    250

  5. EOption (e)

    200

View answer & explanation

Correct answer

Answer: (e)E.

200

Why this answer is correct

General solution:

Bank A:

Number of persons invested in (Fixed deposit + Mutual Funds) = 600

Number of persons invested in Fixed deposit = 400

Number of persons invested in Mutual Funds = (600 - 400) =200

 

Bank B:

Number of persons invested in (Fixed deposit + Mutual Funds) = 450

Number of persons invested in Fixed deposit = 300

Number of persons invested in Mutual Funds = (450 - 300) =150

 

Bank C:

Number of persons invested in (Fixed deposit + Mutual Funds) = 750

Number of persons invested in Fixed deposit = 500

Number of persons invested in Mutual Funds = (750 - 500) =250

 

Bank D:

Number of persons invested in (Fixed deposit + Mutual Funds) = 700

Number of persons invested in Fixed deposit = 250

Number of persons invested in Mutual Funds = (700 - 250) = 450

 

Bank E:

Number of persons invested in (Fixed deposit + Mutual Funds) = 650

Number of persons invested in Fixed deposit = 350

Number of persons invested in Mutual Funds = (650 - 350) = 300 

 

Name of the bankNumber of persons invested in Fixed depositNumber of persons invested in Mutual Fund
Bank A400200
Bank B300150
Bank C500250
Bank D250450
Bank E350300

Solution:

Number of persons invested in Fixed deposit in Bank B = 300

Number of persons invested in Fixed deposit in Bank C = 500

Number of persons invested in Fixed deposit in Bank B for 2 years = 300 ×  1/3 = 100

Number of persons invested in Fixed deposit in Bank B for 5 years = (300 - 100) = 200

Number of persons invested in Fixed deposit in Bank C for 2 years = 500 ×  1/5 = 100

Number of persons invested in Fixed deposit in Bank C for 5 years = (500 - 100) = 400

Total number of persons invested in Mutual funds in Bank B and C = (150 + 250) = 400

Required difference = (600 - 400) = 200

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 398

IBPS Probationary Officer (PO) 2024• Quantitative Aptitude• Quantitative Aptitude

Directions: Study the following direction shows the total number of persons invested in Fixed deposits and mutual funds and number of persons invested in mutual funds in five different banks A, B, C, D and E.

 

If the number of persons invested in Fixed deposit from Bank D is increased by x the ratio between the number of persons invested in Fixed deposits to Mutual funds in Bank D is 13: 18. Find the value of x.

  1. AOption (a)

    95

  2. BOption (b)

    60

  3. COption (c)

    75

  4. DOption (d)

    125

  5. EOption (e)

    80

View answer & explanation

Correct answer

Answer: (c)C.

75

Why this answer is correct

General solution:

Bank A:

Number of persons invested in (Fixed deposit + Mutual Funds) = 600

Number of persons invested in Fixed deposit = 400

Number of persons invested in Mutual Funds = (600 - 400) =200

 

Bank B:

Number of persons invested in (Fixed deposit + Mutual Funds) = 450

Number of persons invested in Fixed deposit = 300

Number of persons invested in Mutual Funds = (450 - 300) =150

 

Bank C:

Number of persons invested in (Fixed deposit + Mutual Funds) = 750

Number of persons invested in Fixed deposit = 500

Number of persons invested in Mutual Funds = (750 - 500) =250

 

Bank D:

Number of persons invested in (Fixed deposit + Mutual Funds) = 700

Number of persons invested in Fixed deposit = 250

Number of persons invested in Mutual Funds = (700 - 250) = 450

 

Bank E:

Number of persons invested in (Fixed deposit + Mutual Funds) = 650

Number of persons invested in Fixed deposit = 350

Number of persons invested in Mutual Funds = (650 - 350) = 300 

 

Name of the bankNumber of persons invested in Fixed depositNumber of persons invested in Mutual Fund
Bank A400200
Bank B300150
Bank C500250
Bank D250450
Bank E350300

Solution:

Number of persons invested in Fixed deposit from Bank D = 250

Number of persons invested  in Mutual deposits from Bank D = 450

Number of persons invested in Bank D is increased by x in Fixed deposit then the ratio becomes 13: 18

(250 + x)/(450) = 13/18

(4500 +18x) = 5850

1350/18 = x

x = 75

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 399

IBPS Probationary Officer (PO) 2024• Quantitative Aptitude• Quantitative Aptitude

Directions: Study the following direction shows the total number of persons invested in Fixed deposits and mutual funds and number of persons invested in mutual funds in five different banks A, B, C, D and E.

 

Find the difference between the average number of persons invested in Fixed deposit in Bank B, Bank D and Bank E and the average number of persons invested in Mutual funds in Bank A, Bank C and Bank E.

  1. AOption (a)

    45

  2. BOption (b)

    65

  3. COption (c)

    30

  4. DOption (d)

    50

  5. EOption (e)

    40

View answer & explanation

Correct answer

Answer: (d)D.

50

Why this answer is correct

General solution:

Bank A:

Number of persons invested in (Fixed deposit + Mutual Funds) = 600

Number of persons invested in Fixed deposit = 400

Number of persons invested in Mutual Funds = (600 - 400) =200

 

Bank B:

Number of persons invested in (Fixed deposit + Mutual Funds) = 450

Number of persons invested in Fixed deposit = 300

Number of persons invested in Mutual Funds = (450 - 300) =150

 

Bank C:

Number of persons invested in (Fixed deposit + Mutual Funds) = 750

Number of persons invested in Fixed deposit = 500

Number of persons invested in Mutual Funds = (750 - 500) =250

 

Bank D:

Number of persons invested in (Fixed deposit + Mutual Funds) = 700

Number of persons invested in Fixed deposit = 250

Number of persons invested in Mutual Funds = (700 - 250) = 450

 

Bank E:

Number of persons invested in (Fixed deposit + Mutual Funds) = 650

Number of persons invested in Fixed deposit = 350

Number of persons invested in Mutual Funds = (650 - 350) = 300 

 

Name of the bankNumber of persons invested in Fixed depositNumber of persons invested in Mutual Fund
Bank A400200
Bank B300150
Bank C500250
Bank D250450
Bank E350300

Solution:

 Number of persons invested in Fixed deposits in Bank B = 300

Number of persons invested in Fixed deposits in Bank D = 250

Number of persons invested in Fixed deposits in Bank E = 350

Average number of persons  invested in Fixed deposits in Bank B, D and E = (300 + 250 + 350)/3 = 900/3 = 300

Number of persons invested in Mutual deposits in Bank  A = 200

Number of persons invested in Mutual deposits in Bank C = 250

Number of persons invested in Mutual deposits in Bank E = 300

Average  number of persons invested in Mutual funds in Bank A, C and E = (200 + 250 + 300) = 750/3 = 250

Required difference = (300 - 250) = 50

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Quantitative Aptitude
View full paper

Question 400

IBPS Probationary Officer (PO) 2024• Quantitative Aptitude• Quantitative Aptitude

Directions: Study the following direction shows the total number of persons invested in Fixed deposits and mutual funds and number of persons invested in mutual funds in five different banks A, B, C, D and E.

 

Find the ratio between the number of persons invested in Mutual funds in Bank E to the number of persons invested in Fixed deposits in same Bank. 

  1. AOption (a)

    7: 9

  2. BOption (b)

    6: 7

  3. COption (c)

    3: 5

  4. DOption (d)

    4: 5

  5. EOption (e)

    5: 6

View answer & explanation

Correct answer

Answer: (b)B.

6: 7

Why this answer is correct

General solution:

Bank A:

Number of persons invested in (Fixed deposit + Mutual Funds) = 600

Number of persons invested in Fixed deposit = 400

Number of persons invested in Mutual Funds = (600 - 400) =200

 

Bank B:

Number of persons invested in (Fixed deposit + Mutual Funds) = 450

Number of persons invested in Fixed deposit = 300

Number of persons invested in Mutual Funds = (450 - 300) =150

 

Bank C:

Number of persons invested in (Fixed deposit + Mutual Funds) = 750

Number of persons invested in Fixed deposit = 500

Number of persons invested in Mutual Funds = (750 - 500) =250

 

Bank D:

Number of persons invested in (Fixed deposit + Mutual Funds) = 700

Number of persons invested in Fixed deposit = 250

Number of persons invested in Mutual Funds = (700 - 250) = 450

 

Bank E:

Number of persons invested in (Fixed deposit + Mutual Funds) = 650

Number of persons invested in Fixed deposit = 350

Number of persons invested in Mutual Funds = (650 - 350) = 300 

 

Name of the bankNumber of persons invested in Fixed depositNumber of persons invested in Mutual Fund
Bank A400200
Bank B300150
Bank C500250
Bank D250450
Bank E350300

Solution:

Number of persons invested in Mutual funds in Bank E = 300

Number of persons invested in Fixed deposits in Bank E = 350

Required ratio = 300: 350 = 6: 7

How should I prepare for Quantitative Aptitude in IBPS Probationary Officer (PO)?

Solving previous year questions by topic helps identify recurring concepts, question patterns, and frequently asked sub-topics. Attempt each question, review the step-by-step explanation, and note down key formulas or facts for quick revision before the exam.