IBPS Probationary Officer (PO) · Topic Collection

Reasoning PYQs

Verbal and non-verbal reasoning, analogies, syllogisms, number series, coding-decoding, blood relations, and analytical puzzles.

1315 Total Questions38 Official PapersYears: 2021–2026Search in Reasoning
Showing questions 401–420 of 1315Page 21 of 66
IBPS Probationary Officer (PO) 2024 Previous Year Paper·Reasoning Ability
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Question 401

IBPS Probationary Officer (PO) 2024• Reasoning Ability• Reasoning Ability

In the word ‘ORGANIZE’, how many pairs of the letters have the same number of letters between them (both forward and backward direction) in the word as in the alphabet?

  1. AOption (a)

    Four

  2. BOption (b)

    Two

  3. COption (c)

    One

  4. DOption (d)

    Three

  5. EOption (e)

    More than four

View answer & explanation

Correct answer

Answer: (c)C.

One

Explanation not yet available.
IBPS Probationary Officer (PO) 2024 Previous Year Paper·Reasoning Ability
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Question 402

IBPS Probationary Officer (PO) 2024• Reasoning Ability• Reasoning Ability

Directions (32-34): Study the information carefully answer the questions given below.

Six persons P, Q, R, S, T and U in a family have different weights. The third heaviest person weight is 40kg. Q's weight is in odd number and is lighter than S but heavier than R. The number of persons lighter than S is one more than P. T is heavier than R and U. T is 20kg more than P who is heavier than Q. The second lightest person is not Q.

What is the possible weight of S?

  1. AOption (a)

    39kg

  2. BOption (b)

    34kg

  3. COption (c)

    53kg

  4. DOption (d)

    67kg

  5. EOption (e)

    62kg

View answer & explanation

Correct answer

Answer: (c)C.

53kg

Explanation not yet available.
IBPS Probationary Officer (PO) 2024 Previous Year Paper·Reasoning Ability
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Question 403

IBPS Probationary Officer (PO) 2024• Reasoning Ability• Reasoning Ability

Directions (32-34): Study the information carefully answer the questions given below.

Six persons P, Q, R, S, T and U in a family have different weights. The third heaviest person weight is 40kg. Q's weight is in odd number and is lighter than S but heavier than R. The number of persons lighter than S is one more than P. T is heavier than R and U. T is 20kg more than P who is heavier than Q. The second lightest person is not Q.

If R’s weight is 15kg less than P and 5 kg more than U then what is the sum weight of R and U?

  1. AOption (a)

    38kg

  2. BOption (b)

    45kg

  3. COption (c)

    50kg

  4. DOption (d)

    40kg

  5. EOption (e)

    35kg

View answer & explanation

Correct answer

Answer: (b)B.

45kg

Explanation not yet available.
IBPS Probationary Officer (PO) 2024 Previous Year Paper·Reasoning Ability
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Question 404

IBPS Probationary Officer (PO) 2024• Reasoning Ability• Reasoning Ability

Directions (32-34): Study the information carefully answer the questions given below.

Six persons P, Q, R, S, T and U in a family have different weights. The third heaviest person weight is 40kg. Q's weight is in odd number and is lighter than S but heavier than R. The number of persons lighter than S is one more than P. T is heavier than R and U. T is 20kg more than P who is heavier than Q. The second lightest person is not Q.

The numbers of persons heavier than P is same as the numbers of persons lighter than ______.

  1. AOption (a)

    S

  2. BOption (b)

    T

  3. COption (c)

    Q

  4. DOption (d)

    P

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (c)C.

Q

Explanation not yet available.
IBPS Probationary Officer (PO) 2024 Previous Year Paper·Reasoning Ability
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Question 405

IBPS Probationary Officer (PO) 2024• Reasoning Ability• Reasoning Ability

If in the given word “CONVERSION”, if we replaced all odd position letter (from left) with its just next letter and replace all the even position letter (from left) with its just previous letter then find how many letters are repeated there in the new arrangement?

  1. AOption (a)

    One

  2. BOption (b)

    Two

  3. COption (c)

    Four

  4. DOption (d)

    Three

  5. EOption (e)

    None

View answer & explanation

Correct answer

Answer: (e)E.

None

Explanation not yet available.
IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Reasoning Ability
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Question 406

IBPS Probationary Officer (PO) 2024• Reasoning Ability• Reasoning Ability

Directions: Read the given information carefully and answer the following questions.

Seven persons Kriti, Lavanya, Mahesh, Narender, Pooja, Rajat, and Suman are sitting around a circular table.

Some of them are facing outside and some of them are facing inside the centre. 

Rajat is sitting second to the left of Lavanya. One person is sitting between Pooja and Rajat. Three persons are sitting between Pooja and Kriti. Mahesh and Suman are immediately left of each other. Suman is not the immediate neighbour of Pooja. Narender sits second to the right of Kriti. The Immediate neighbours of Narender faces the same direction. Rajat and Kriti face opposite directions. Narender faces inside.

No three persons facing the same direction sit together.

Who is sitting second to the left of the one who is sitting third to the left of Pooja?

  1. AOption (a)

    Mahesh

  2. BOption (b)

    Narender

  3. COption (c)

    Rajat

  4. DOption (d)

    Kriti

  5. EOption (e)

    Suman

View answer & explanation

Correct answer

Answer: (c)C.

Rajat

Why this answer is correct

Seven persons Kriti, Lavanya, Mahesh, Narender, Pooja, Rajat, and Suman are sitting around a circular table.

Some of them are facing outside and some of them are facing inside the centre.

  1. Rajat is sitting second to the left of Layanya. One person is sitting between Pooja and Rajat.

  2. Three persons are sitting between Pooja and Kriti. Mahesh and Suman are immediately left of each other. Suman is not the immediate neighbor of Pooja.

  3. Narender sits second to the right of Kriti. Rajat and Kriti face opposite directions. The immediate neighbor of Narender faces the same direction. Narender faces inside

  4. No three persons facing the same direction sit together.

In Case 1, Narender, Rajat, Pooja, and Mahesh are facing the same direction. This contradicts the given condition. So, case 1 is eliminated.

The final arrangement is:

Hence, Rajat is sitting second to the left of the one sitting third to the left of Pooja.

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Reasoning Ability
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Question 407

IBPS Probationary Officer (PO) 2024• Reasoning Ability• Reasoning Ability

Directions: Read the given information carefully and answer the following questions.

Seven persons Kriti, Lavanya, Mahesh, Narender, Pooja, Rajat, and Suman are sitting around a circular table.

Some of them are facing outside and some of them are facing inside the centre. 

Rajat is sitting second to the left of Lavanya. One person is sitting between Pooja and Rajat. Three persons are sitting between Pooja and Kriti. Mahesh and Suman are immediately left of each other. Suman is not the immediate neighbour of Pooja. Narender sits second to the right of Kriti. The Immediate neighbours of Narender faces the same direction. Rajat and Kriti face opposite directions. Narender faces inside.

No three persons facing the same direction sit together.

Who are the immediate neighbours of Suman?

  1. AOption (a)

    Pooja, Rajat

  2. BOption (b)

    Narender, Kriti

  3. COption (c)

    Rajat, Lavanya

  4. DOption (d)

    Mahesh, Lavanya

  5. EOption (e)

    Narender, Pooja

View answer & explanation

Correct answer

Answer: (d)D.

Mahesh, Lavanya

Why this answer is correct

Seven persons Kriti, Lavanya, Mahesh, Narender, Pooja, Rajat, and Suman are sitting around a circular table.

Some of them are facing outside and some of them are facing inside the centre.

  1. Rajat is sitting second to the left of Layanya. One person is sitting between Pooja and Rajat.

  2. Three persons are sitting between Pooja and Kriti. Mahesh and Suman are immediately left of each other. Suman is not the immediate neighbor of Pooja.

  3. Narender sits second to the right of Kriti. Rajat and Kriti face opposite directions. The immediate neighbor of Narender faces the same direction. Narender faces inside

​

  1. No three persons facing the same direction sit together.

In Case 1, Narender, Rajat, Pooja, and Mahesh are facing the same direction. This contradicts the given condition. So, case 1 is eliminated.

The final arrangement is:

Mahesh and Lavanya are the immediate neighbours of Suman.

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Reasoning Ability
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Question 408

IBPS Probationary Officer (PO) 2024• Reasoning Ability• Reasoning Ability

Directions: Read the given information carefully and answer the following questions.

Seven persons Kriti, Lavanya, Mahesh, Narender, Pooja, Rajat, and Suman are sitting around a circular table.

Some of them are facing outside and some of them are facing inside the centre. 

Rajat is sitting second to the left of Lavanya. One person is sitting between Pooja and Rajat. Three persons are sitting between Pooja and Kriti. Mahesh and Suman are immediately left of each other. Suman is not the immediate neighbour of Pooja. Narender sits second to the right of Kriti. The Immediate neighbours of Narender faces the same direction. Rajat and Kriti face opposite directions. Narender faces inside.

No three persons facing the same direction sit together.

Who is sitting just between Kriti and Narender ?

  1. AOption (a)

    Rajat

  2. BOption (b)

    Mahesh

  3. COption (c)

    Suman

  4. DOption (d)

    Lavanya

  5. EOption (e)

    Pooja

View answer & explanation

Correct answer

Answer: (a)A.

Rajat

Why this answer is correct

Seven persons Kriti, Lavanya, Mahesh, Narender, Pooja, Rajat, and Suman are sitting around a circular table.

Some of them are facing outside and some of them are facing inside the centre.

  1. Rajat is sitting second to the left of Layanya. One person is sitting between Pooja and Rajat.

  2. Three persons are sitting between Pooja and Kriti. Mahesh and Suman are immediately left of each other. Suman is not the immediate neighbor of Pooja.

  3. Narender sits second to the right of Kriti. Rajat and Kriti face opposite directions. The immediate neighbor of Narender faces the same direction. Narender faces inside

​

  1. No three persons facing the same direction sit together.

In Case 1, Narender, Rajat, Pooja, and Mahesh are facing the same direction. This contradicts the given condition. So, case 1 is eliminated.

The final arrangement is:

Rajat is sitting between Kriti and Narender.

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Reasoning Ability
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Question 409

IBPS Probationary Officer (PO) 2024• Reasoning Ability• Reasoning Ability

Directions: Read the given information carefully and answer the following questions.

Seven persons Kriti, Lavanya, Mahesh, Narender, Pooja, Rajat, and Suman are sitting around a circular table.

Some of them are facing outside and some of them are facing inside the centre. 

Rajat is sitting second to the left of Lavanya. One person is sitting between Pooja and Rajat. Three persons are sitting between Pooja and Kriti. Mahesh and Suman are immediately left of each other. Suman is not the immediate neighbour of Pooja. Narender sits second to the right of Kriti. The Immediate neighbours of Narender faces the same direction. Rajat and Kriti face opposite directions. Narender faces inside.

No three persons facing the same direction sit together.

How many persons are facing inside?

  1. AOption (a)

    One 

  2. BOption (b)

    Two

  3. COption (c)

    Three

  4. DOption (d)

    Four

  5. EOption (e)

    Five

View answer & explanation

Correct answer

Answer: (c)C.

Three

Why this answer is correct

Seven persons Kriti, Lavanya, Mahesh, Narender, Pooja, Rajat, and Suman are sitting around a circular table.

Some of them are facing outside and some of them are facing inside the centre.

  1. Rajat is sitting second to the left of Layanya. One person is sitting between Pooja and Rajat.

  2. Three persons are sitting between Pooja and Kriti. Mahesh and Suman are immediately left of each other. Suman is not the immediate neighbor of Pooja.

  3. Narender sits second to the right of Kriti. Rajat and Kriti face opposite directions. The immediate neighbor of Narender faces the same direction. Narender faces inside

​

  1. No three persons facing the same direction sit together.

In Case 1, Narender, Rajat, Pooja, and Mahesh are facing the same direction. This contradicts the given condition. So, case 1 is eliminated.

The final arrangement is:

Three persons are facing inside.

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Reasoning Ability
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Question 410

IBPS Probationary Officer (PO) 2024• Reasoning Ability• Reasoning Ability

Directions: Read the given information carefully and answer the following questions.

Seven persons Kriti, Lavanya, Mahesh, Narender, Pooja, Rajat, and Suman are sitting around a circular table.

Some of them are facing outside and some of them are facing inside the centre. 

Rajat is sitting second to the left of Lavanya. One person is sitting between Pooja and Rajat. Three persons are sitting between Pooja and Kriti. Mahesh and Suman are immediately left of each other. Suman is not the immediate neighbour of Pooja. Narender sits second to the right of Kriti. The Immediate neighbours of Narender faces the same direction. Rajat and Kriti face opposite directions. Narender faces inside.

No three persons facing the same direction sit together.

How many persons are sitting between Pooja and Lavanya when counted to the right of Pooja?

  1. AOption (a)

    One

  2. BOption (b)

    Two

  3. COption (c)

    Three

  4. DOption (d)

    Four

  5. EOption (e)

    Five

View answer & explanation

Correct answer

Answer: (c)C.

Three

Why this answer is correct

Seven persons Kriti, Lavanya, Mahesh, Narender, Pooja, Rajat, and Suman are sitting around a circular table.

Some of them are facing outside and some of them are facing inside the centre.

  1. Rajat is sitting second to the left of Layanya. One person is sitting between Pooja and Rajat.

  2. Three persons are sitting between Pooja and Kriti. Mahesh and Suman are immediately left of each other. Suman is not the immediate neighbor of Pooja.

  3. Narender sits second to the right of Kriti. Rajat and Kriti face opposite directions. The immediate neighbor of Narender faces the same direction. Narender faces inside

​

  1. No three persons facing the same direction sit together.

In Case 1, Narender, Rajat, Pooja, and Mahesh are facing the same direction. This contradicts the given condition. So, case 1 is eliminated.

The final arrangement is:

Three persons are sitting between Pooja and Lavanya when counted to the right of Pooja

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Reasoning Ability
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Question 411

IBPS Probationary Officer (PO) 2024• Reasoning Ability• Reasoning Ability

Find the odd one out from the given options:

  1. AOption (a)

    BEIN

  2. BOption (b)

    LOSX

  3. COption (c)

    DGJN

  4. DOption (d)

    HKOT

  5. EOption (e)

    FIMR

View answer & explanation

Correct answer

Answer: (c)C.

DGJN

Why this answer is correct

The pattern followed here is:

  1. BEIN → B + 3 = E; E + 4 = I; I + 5 = N

  2. LOSX → L + 3 = O; O + 4 = S; S + 5 = X

  3. DGJN → D + 3 = G; G + 3 = J; J + 4 = N

  4. HKOT → H + 3 = K; K + 4 = O; O + 5 = T

  5. FIMR → F + 3 = I; I + 4 = M; M + 5 = R

Thus, DGJN does not fulfil the above condition. So, it is the odd one out from the given options.

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Reasoning Ability
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Question 412

IBPS Probationary Officer (PO) 2024• Reasoning Ability• Reasoning Ability

If all the vowels of the word ‘UMBRELLA’ are changed to the letter which sits two positions behind in the English alphabetical series and all the consonants are changed to the letter which sits two positions ahead in the English alphabetical series, then the alphabets thus obtained are arranged in reverse order, starting from the left to the right, according to the English alphabetical series. Which of the following is the combination of letters that are second from the left end and second from the right end respectively of the newly formed rearranged sequence?

  1. AOption (a)

    CS

  2. BOption (b)

    NO

  3. COption (c)

    YC

  4. DOption (d)

    NN

  5. EOption (e)

    TD

View answer & explanation

Correct answer

Answer: (e)E.

TD

Why this answer is correct

The word is ‘UMBRELLA’.

The vowels are shifted to two places behind and the consonants are shifted two places ahead in the English alphabetical series. The alphabets thus formed are then arranged in a reverse order according to the English alphabetical series. Hence, we get-

LETTERSUMBRELLA
CONSONANTS (C)/ VOWELS (V)VCCCVCCV
-2 IF V/+2 IF C-2+2+2+2-2+2+2-2
RESULTANT LETTERSODTCNNY
REARRANGEMENTYTSONNDC

 

The second letter from the left is T and the second letter from the right is D.

Hence, the correct combination of letters is TD.

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Reasoning Ability
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Question 413

IBPS Probationary Officer (PO) 2024• Reasoning Ability• Reasoning Ability

Direction: Study the following information carefully and answer the questions given below:

Eight persons - F, G, H, I, J, K, L, and M were born in the years - 1951, 1960, 1965, 1971, 1975, 1982, 1987, and 1994 not necessarily in the same order. They were born on the same date i.e. on 1st February of these years. Make all the age calculations as of 1st February 2023.

F was aged twice as old as H. Two persons were younger than G but older than H. The number of persons older than I was twice as much as the number of persons older than L. K was born after 1980. Nobody was born between I and M.

In which of the following year was J born?

  1. AOption (a)

    1951

  2. BOption (b)

    1960

  3. COption (c)

    1975

  4. DOption (d)

    ​1994

  5. EOption (e)

    Cannot be determined

View answer & explanation

Correct answer

Answer: (b)B.

1960

Why this answer is correct

Given:

Eight persons - F, G, H, I, J, K, L, and M

Eight years - 1951, 1960, 1965, 1971, 1975, 1982, 1987 and 1994

They were born on the same date i.e. on 1st February of these years.

Make all the age calculations as of 1st February 2023.

So, the ages of all the persons will be as follows -

YearAgePersons
195172
196063
196558
197152
197548
198241
198736
199429

 

Now,

1) F was aged twice as old as H. H's age can be 29 or 36 while F's age can be 58 or 72.

  1. Two persons were younger than G but older than H. 
YearAgeCase ICase II
195172F
196063
196558F
197152G
197548G
198241
198736H
199429H

 

3) The number of persons older than I was twice as much as the number of persons older than L.

4) Nobody was born between I and M.

YearAgeCase ICase II
195172F
196063
196558FL
197152LG
197548GI
198241MM
198736IH
199429H

 

5) K was born after 1980. This is not possible in Case I so it gets eliminated.

The final arrangement is -

YearAgeCase II
195172F
196063J
196558L
197152G
197548I
198241M
198736H
199429K

 

J was born in the year 1960.

Hence, the correct answer is 1960.

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Reasoning Ability
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Question 414

IBPS Probationary Officer (PO) 2024• Reasoning Ability• Reasoning Ability

Direction: Study the following information carefully and answer the questions given below:

Eight persons - F, G, H, I, J, K, L, and M were born in the years - 1951, 1960, 1965, 1971, 1975, 1982, 1987, and 1994 not necessarily in the same order. They were born on the same date i.e. on 1st February of these years. Make all the age calculations as of 1st February 2023.

F was aged twice as old as H. Two persons were younger than G but older than H. The number of persons older than I was twice as much as the number of persons older than L. K was born after 1980. Nobody was born between I and M.

Who among the following was the youngest?

  1. AOption (a)

    J

  2. BOption (b)

    F

  3. COption (c)

    H

  4. DOption (d)

    K

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (d)D.

K

Why this answer is correct

Given:

Eight persons - F, G, H, I, J, K, L, and M

Eight years - 1951, 1960, 1965, 1971, 1975, 1982, 1987 and 1994

They were born on the same date i.e. on 1st February of these years.

Make all the age calculations as of 1st February 2023.

So, the ages of all the persons will be as follows -

YearAgePersons
195172
196063
196558
197152
197548
198241
198736
199429

 

Now,

1) F was aged twice as old as H. H's age can be 29 or 36 while F's age can be 58 or 72.

  1. Two persons were younger than G but older than H. 
YearAgeCase ICase II
195172F
196063
196558F
197152G
197548G
198241
198736H
199429H

 

3) The number of persons older than I was twice as much as the number of persons older than L.

4) Nobody was born between I and M.

YearAgeCase ICase II
195172F
196063
196558FL
197152LG
197548GI
198241MM
198736IH
199429H

 

5) K was born after 1980. This is not possible in Case I so it gets eliminated.

The final arrangement is -

YearAgeCase II
195172F
196063J
196558L
197152G
197548I
198241M
198736H
199429K

 

K is the youngest among all.

Hence, the correct answer is K.

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Reasoning Ability
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Question 415

IBPS Probationary Officer (PO) 2024• Reasoning Ability• Reasoning Ability

Direction: Study the following information carefully and answer the questions given below:

Eight persons - F, G, H, I, J, K, L, and M were born in the years - 1951, 1960, 1965, 1971, 1975, 1982, 1987, and 1994 not necessarily in the same order. They were born on the same date i.e. on 1st February of these years. Make all the age calculations as of 1st February 2023.

F was aged twice as old as H. Two persons were younger than G but older than H. The number of persons older than I was twice as much as the number of persons older than L. K was born after 1980. Nobody was born between I and M.

How many persons were born between F and L?

  1. AOption (a)

    None

  2. BOption (b)

    One

  3. COption (c)

    Two

  4. DOption (d)

    Three

  5. EOption (e)

    More than three

View answer & explanation

Correct answer

Answer: (b)B.

One

Why this answer is correct

Given:

Eight persons - F, G, H, I, J, K, L, and M

Eight years - 1951, 1960, 1965, 1971, 1975, 1982, 1987 and 1994

They were born on the same date i.e. on 1st February of these years.

Make all the age calculations as of 1st February 2023.

So, the ages of all the persons will be as follows -

YearAgePersons
195172
196063
196558
197152
197548
198241
198736
199429

 

Now,

1) F was aged twice as old as H. H's age can be 29 or 36 while F's age can be 58 or 72.

  1. Two persons were younger than G but older than H. 
YearAgeCase ICase II
195172F
196063
196558F
197152G
197548G
198241
198736H
199429H

 

3) The number of persons older than I was twice as much as the number of persons older than L.

4) Nobody was born between I and M.

YearAgeCase ICase II
195172F
196063
196558FL
197152LG
197548GI
198241MM
198736IH
199429H

 

5) K was born after 1980. This is not possible in Case I so it gets eliminated.

The final arrangement is -

YearAgeCase II
195172F
196063J
196558L
197152G
197548I
198241M
198736H
199429K

 

One person was born between F and L.

Hence, the correct answer is One.

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Reasoning Ability
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Question 416

IBPS Probationary Officer (PO) 2024• Reasoning Ability• Reasoning Ability

Direction: Study the following information carefully and answer the questions given below:

Eight persons - F, G, H, I, J, K, L, and M were born in the years - 1951, 1960, 1965, 1971, 1975, 1982, 1987, and 1994 not necessarily in the same order. They were born on the same date i.e. on 1st February of these years. Make all the age calculations as of 1st February 2023.

F was aged twice as old as H. Two persons were younger than G but older than H. The number of persons older than I was twice as much as the number of persons older than L. K was born after 1980. Nobody was born between I and M.

How many persons were younger than I?

  1. AOption (a)

    One

  2. BOption (b)

    Three

  3. COption (c)

    Five

  4. DOption (d)

    Seven

  5. EOption (e)

    None of the above

View answer & explanation

Correct answer

Answer: (b)B.

Three

Why this answer is correct

Given:

Eight persons - F, G, H, I, J, K, L, and M

Eight years - 1951, 1960, 1965, 1971, 1975, 1982, 1987 and 1994

They were born on the same date i.e. on 1st February of these years.

Make all the age calculations as of 1st February 2023.

So, the ages of all the persons will be as follows -

YearAgePersons
195172
196063
196558
197152
197548
198241
198736
199429

 

Now,

1) F was aged twice as old as H. H's age can be 29 or 36 while F's age can be 58 or 72.

  1. Two persons were younger than G but older than H. 
YearAgeCase ICase II
195172F
196063
196558F
197152G
197548G
198241
198736H
199429H

 

3) The number of persons older than I was twice as much as the number of persons older than L.

4) Nobody was born between I and M.

YearAgeCase ICase II
195172F
196063
196558FL
197152LG
197548GI
198241MM
198736IH
199429H

 

5) K was born after 1980. This is not possible in Case I so it gets eliminated.

The final arrangement is -

YearAgeCase II
195172F
196063J
196558L
197152G
197548I
198241M
198736H
199429K

 

Three persons were younger than I.

Hence, the correct answer is Three.

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Reasoning Ability
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Question 417

IBPS Probationary Officer (PO) 2024• Reasoning Ability• Reasoning Ability

Direction: Study the following information carefully and answer the questions given below:

Eight persons - F, G, H, I, J, K, L, and M were born in the years - 1951, 1960, 1965, 1971, 1975, 1982, 1987, and 1994 not necessarily in the same order. They were born on the same date i.e. on 1st February of these years. Make all the age calculations as of 1st February 2023.

F was aged twice as old as H. Two persons were younger than G but older than H. The number of persons older than I was twice as much as the number of persons older than L. K was born after 1980. Nobody was born between I and M.

Which of the following combination is correct?

  1. AOption (a)

    K - 1987

  2. BOption (b)

    L - 52 years

  3. COption (c)

    M - 1982

  4. DOption (d)

    H - 29 years

  5. EOption (e)

    All are correct

View answer & explanation

Correct answer

Answer: (c)C.

M - 1982

Why this answer is correct

Given:

Eight persons - F, G, H, I, J, K, L, and M

Eight years - 1951, 1960, 1965, 1971, 1975, 1982, 1987 and 1994

They were born on the same date i.e. on 1st February of these years.

Make all the age calculations as of 1st February 2023.

So, the ages of all the persons will be as follows -

YearAgePersons
195172
196063
196558
197152
197548
198241
198736
199429

 

Now,

1) F was aged twice as old as H. H's age can be 29 or 36 while F's age can be 58 or 72.

  1. Two persons were younger than G but older than H. 
YearAgeCase ICase II
195172F
196063
196558F
197152G
197548G
198241
198736H
199429H

 

3) The number of persons older than I was twice as much as the number of persons older than L.

4) Nobody was born between I and M.

YearAgeCase ICase II
195172F
196063
196558FL
197152LG
197548GI
198241MM
198736IH
199429H

 

5) K was born after 1980. This is not possible in Case I so it gets eliminated.

The final arrangement is -

YearAgeCase II
195172F
196063J
196558L
197152G
197548I
198241M
198736H
199429K

 

Among the given options, only 'M - 1982' is correct.

Hence, the correct answer is M - 1982.

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Reasoning Ability
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Question 418

IBPS Probationary Officer (PO) 2024• Reasoning Ability• Reasoning Ability

Direction: Study the following information carefully to answer the given questions.

In a certain code language,

"black is cool color" is coded as "ku lo si ri"

"beige furniture is boring" is coded as "xo fi lo bo"

"some movie is black" is coded as "ko vi lo ku"

"some black is cool" is coded as "ko ku lo si"

What is the code for 'cool'

  1. AOption (a)

    si

  2. BOption (b)

    ku

  3. COption (c)

    ko

  4. DOption (d)

    lo

  5. EOption (e)

    xo

View answer & explanation

Correct answer

Answer: (a)A.

si

Why this answer is correct

Given

Statement:

"black is cool color" is coded as "ku lo si ri"

"beige furniture is boring" is coded as "xo fi lo bo"

"some movie is black" is coded as "ko vi lo ku"

"some black is cool" is coded as "ko ku lo si"

We get:

is – lo

some - ko

black - ku

cool - si

The codes for ‘movie’, ' boring', and ‘color’ is determined by elimination, i.e. all the other codes in the sentence are determined:

movie - vi

color – ri

We can not clearly determine the codes for ‘beige’ and ‘furniture’:

beige – xo/fi/bo

furniture – xo/fi/bo

boring - xo/fi/bo

Hence, the code for 'cool' is si.

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Reasoning Ability
View full paper

Question 419

IBPS Probationary Officer (PO) 2024• Reasoning Ability• Reasoning Ability

Direction: Study the following information carefully to answer the given questions.

In a certain code language,

"black is cool color" is coded as "ku lo si ri"

"beige furniture is boring" is coded as "xo fi lo bo"

"some movie is black" is coded as "ko vi lo ku"

"some black is cool" is coded as "ko ku lo si"

What does the code 'bo' mean?

  1. AOption (a)

    color

  2. BOption (b)

    boring

  3. COption (c)

    movie

  4. DOption (d)

    beige

  5. EOption (e)

    Can not be determined

View answer & explanation

Correct answer

Answer: (e)E.

Can not be determined

Why this answer is correct

Given

Statement:

"black is cool color" is coded as "ku lo si ri"

"beige furniture is boring" is coded as "xo fi lo bo"

"some movie is black" is coded as "ko vi lo ku"

"some black is cool" is coded as "ko ku lo si"

We get:

is – lo

some - ko

black - ku

cool - si

The codes for ‘movie’, ' boring', and ‘color’ is determined by elimination, i.e. all the other codes in the sentence are determined:

movie - vi

color – ri

We can not clearly determine the codes for ‘beige’ and ‘furniture’:

beige – xo/fi/bo

furniture – xo/fi/bo

boring - xo/fi/bo

Hence, the code 'bo' can not be determined.

IBPS PO Prelims Memory Based Paper (Held On: 19 October 2024 Shift 1) (Previous Year Paper)·Reasoning Ability
View full paper

Question 420

IBPS Probationary Officer (PO) 2024• Reasoning Ability• Reasoning Ability

Direction: Study the following information carefully to answer the given questions.

In a certain code language,

"black is cool color" is coded as "ku lo si ri"

"beige furniture is boring" is coded as "xo fi lo bo"

"some movie is black" is coded as "ko vi lo ku"

"some black is cool" is coded as "ko ku lo si"

How will the sentence 'black is not cool' be coded as?

  1. AOption (a)

    ku lo xo bo

  2. BOption (b)

    ku ko ni bo

  3. COption (c)

    ku lo ni si

  4. DOption (d)

    xo fi lo bo

  5. EOption (e)

    ku lo ko ni

View answer & explanation

Correct answer

Answer: (c)C.

ku lo ni si

Why this answer is correct

Given

Statement:

"black is cool color" is coded as "ku lo si ri"

"beige furniture is boring" is coded as "xo fi lo bo"

"some movie is black" is coded as "ko vi lo ku"

"some black is cool" is coded as "ko ku lo si"

We get:

is – lo

some - ko

black - ku

cool - si

The codes for ‘movie’, ' boring', and ‘color’ is determined by elimination, i.e. all the other codes in the sentence are determined:

movie - vi

color – ri

We can not clearly determine the codes for ‘beige’ and ‘furniture’:

beige – xo/fi/bo

furniture – xo/fi/bo

boring - xo/fi/bo

 

Since 'Not' is not given, we will go for a code that is not given in the information.

And we know, the codes for:

black - ku

is - lo

cool - si

Hence, the code for 'black is not cool' is ku lo ni si.

How should I prepare for Reasoning in IBPS Probationary Officer (PO)?

Solving previous year questions by topic helps identify recurring concepts, question patterns, and frequently asked sub-topics. Attempt each question, review the step-by-step explanation, and note down key formulas or facts for quick revision before the exam.