Reasoning PYQs

Given : 335 × 5 ÷ 7 + 65 − 213 = 321 

According to the question, after interchanging the signs:

Option 1) + and =

335 × 5 ÷ 7 + 65 − 213 = 321 ⇒ 335 × 5 ÷ 7 = 65 − 213 + 321

⇒ 335 × 5 ÷ 7 = 65 + 321 − 213

⇒ 335 × 0.71 = 386 − 213

⇒ 238 ≠ 173 (LHS ≠ RHS)

Option 2) ÷ and ×

335 × 5 ÷ 7 + 65 − 213 = 321 ⇒ 335 ÷ 5 × 7 + 65 − 213 = 321

⇒ 335 ÷ 5 × 7 + 65 − 213 = 321

⇒ 67 × 7 + 65 − 213 = 321

⇒ 469 + 65 − 213 = 321

⇒ 534 − 213 = 321

⇒ 321 = 321 (LHS = RHS)

Option 3) ÷ and −

335 × 5 ÷ 7 + 65 − 213 = 321 ⇒ 335 × 5 - 7 + 65 ÷ 213 = 321

⇒ 335 × 5 - 7 + 65 ÷ 213 = 321

⇒ 335 × 5 - 7 + 0.30 = 321

⇒ 1657 + 0.30 - 7 = 321

⇒ 1657.30 - 7 = 321

⇒ 1650.30 ≠ 321 (LHS ≠ RHS)

Option 4) + and −

335 × 5 ÷ 7 + 65 − 213 = 321 ⇒ 335 × 5 ÷ 7 - 65 + 213 = 321

⇒ 335 × 5 ÷ 7 - 65 + 213 = 321

⇒ 335 × 0.71 - 65 + 213 = 321

⇒ 238 + 213 - 65 = 321

⇒ 451 - 65 = 321

⇒ 386 ≠ 321 (LHS ≠ RHS)

Hence, "Option 2" is the correct answer.

The figure which when put in place of '?' will logically complete the pattern is shown below:

Thus, option Figure 2 will logically complete the pattern given.

Hence, "Option 2" is the correct answer.

The logic followed here is:

KFUB : BKLG

And,

PNTD : GSKI

Similarly,

IVFQ : ?

Hence, "Option 1" is the correct answer.

The logic followed here is :-

From the given three different cubes the adjacent sides are as shown below :

As 5 is common on both the dices figure 2 and figure 3, it is clear that 1, 6, 3, and 4 are adjacent to it, and the remaining i.e. 2 will be opposite to it.

Opposite pairs:

1 → 3

6 → 4

5 → 2

So, the opposite side of "2" will be side "5".

Hence, the correct answer is "Option 3".

The correct mirror image of the given figure is:

Hence, the correct answer is "Option 1".

The logic followed here is:

1. First box series →

The first two elements from the left interchange positions.

The last two elements from the left interchange positions.

The center element is replaced by new element.

2. Second box series → 

All the elements shift anticlockwise.

The fourth element from the left is replaced by new element.

Thus, the final series is:

Hence, "Option 2" is the correct answer.

The logic followed here is:

Logic: (2^nd number × 5) + 6 = 1^st number.

Now,

For, 121 : 23

⇒ (23 × 5) + 6 = 115 + 6 = 121.

For, 166 : 32

⇒ (32 × 5) + 6 = 160 + 6 = 166.

Similarly, for ? : 14

⇒ (14 × 5) + 6 = 70 + 6 = 76.

Hence, the correct answer is "Option 3".

The least possible Venn diagram for the given statements is as shown below :

Conclusions:

I. Some bags are balloons → Follow (As some balloons are bags. As some part of balloons is common with bags, therefore it is true.)

II. Some belts are balloons → Does not follow (As some balloons are bags and all belts are bags. So it is possible but not definite.)

∴ Here, Only conclusion I follows.​

Hence, the correct answer is "Option 3".

Given: Six students are seated around a circular table, facing the center.

1) Tanay is seated second to the left of Palak.

2) Palak and Ruchi both have Sahil as their immediate neighbor. 

3) Urmi is seated third to the right of Ruchi. 

4) Both Ruchi and Tanay have Qasim as their immediate neighbor. 

Thus, according to the final arrangement Tanay is the immediate neighbor of both Urmi and Qasim.

Hence, "Option 2" is the correct answer.

The logic followed here is :-

From the given three different cubes the adjacent sides are as shown below :

As 4 is common on both the dices figure 1 and figure 2, it is clear that 2, 5, 3, and 6 are adjacent to it, and the remaining i.e. 1 will be opposite to it.

Opposite pairs:

2 → 6

5 → 3

4 → 1

So, the opposite side of "5" will be side "3".

Hence, the correct answer is "Option 3".

The logic followed here is:

1. First box series →

The top and 1^st element of 2^nd row elements interchange positions.

The rest of the element shift clockwise.

2. Second box series → 

The 1^st column and 3^rd column elements shift anticlockwise.

The center element is replaced by new element.

Thus, the final series is:

Hence, "Option 1" is the correct answer.

The logic followed here is :-

From the given two different dices the adjacent sides are as shown below :

As C is common on both the dices, it is clear that B, D, F, and E are adjacent to it, and the remaining i.e. A will be opposite to it.

Opposite pairs:

B → F

D → E

C → A

So, the opposite side of "D" will be side "E".

Hence, the correct answer is "Option 2".

Given series: b _ d _ p b c _ p _ _ c _ p p b _ _ p p 

Option 1) cpdpdbdc → b c d p p b c d p p d c b p p b d c p p → (It doesn't follow any pattern)

Option 2) cpdpbdcd → b c d p p b c d p p b c d p p b c d p p  → (It follows the pattern of: bcdpp - bcdpp - bcdpp - bcdpp)

Option 3) cdppbddc → b c d d p b c p p p b c d p p b d c p p → (It doesn't follow any pattern)

Option 4) pcdpbdcd → b p d c p b c d p p b c d p p b c d p p → (It doesn't follow any pattern)

Hence, "Option 2" is the correct answer.

The logic followed here is:

Hence, "Option 2" is the correct answer.

The logic followed here is:

1) Alternately shaded arrow pointing upwards and nonshaded arrow pointing downwards are added in each box subsequently.

Thus, the final series is:

Hence, "Option 2" is the correct answer.

The image embedded in the given figure is as shown below :

∴ Here, the given figure is embedded in the option figure 1.

Hence, the correct answer is "Option 1".

Given : 18 * 14 * 6 * 16 * 4 * 254

According to the question, after replacing the signs:

Option 1) +, ×, –, =, ÷

18 * 14 * 6 * 16 * 4 * 254 ⇒ 18 + 14 × 6 - 16 = 4 ÷ 254

⇒ 18 + 14 × 6 - 16 = 4 ÷ 254

⇒ 18 + 84 - 16 = 0.015

⇒ 102 - 16 = 0.015

⇒ 86 ≠ 0.015 (LHS ≠ RHS)

Option 2) ÷, –, ×, +, =

18 * 14 * 6 * 16 * 4 * 254 ⇒ 18 ÷ 14 - 6 × 16 + 4 = 254

⇒ 18 ÷ 14 - 6 × 16 + 4 = 254

⇒ 1.28 - 6 × 16 + 4 = 254

⇒ 1.28 + 4 - 96 = 254

⇒ 5.28 - 96 = 254

⇒ 90.72 ≠ 254 (LHS ≠ RHS)

Option 3) ×, +, –, ÷, = 

18 * 14 * 6 * 16 * 4 * 254 ⇒ 18 × 14 + 6 - 16 ÷ 4 = 254

⇒ 18 × 14 + 6 - 16 ÷ 4 = 254

⇒ 18 × 14 + 6 - 4 = 254

⇒ 252 + 6 - 4 = 254

⇒ 258 - 4 = 254

⇒ 254 = 254 (LHS = RHS)

Option 4) +, ×, –, ÷, =

18 * 14 * 6 * 16 * 4 * 254 ⇒ 18 + 14 × 6 - 16 ÷ 4 = 254

⇒ 18 + 14 × 6 - 16 ÷ 4 = 254

⇒ 18 + 14 × 6 - 4 = 254

⇒ 18 + 84 - 4 = 254

⇒ 102 - 4 = 254

⇒ 98 ≠ 254 (LHS ≠ RHS)

Hence, "Option 3" is the correct answer.

The logic followed here is :-

From the given two different dices the adjacent sides are as shown below :

As one dot is common on both the dices, it is clear that two dots, three dots, four dots, and five dots are adjacent to it, and the remaining i.e. six dots will be opposite to it.

Opposite pairs:

Three dots → Five dots

Two dots → Four dots

One dot → Six dots

So, the opposite side of "Four dots" will be side "Two dots".

Hence, the correct answer is "Option 2".

The image embedded in the given figure is as shown below :

∴ Here, the given figure is embedded in the option figure 2.

Hence, the correct answer is "Option 2".

The figure which when put in place of '?' will logically complete the pattern is shown below:

Thus, option Figure 3 will logically complete the pattern given.

Hence, "Option 3" is the correct answer.