Central Teacher Eligibility Test (CTET) · Topic Collection

Mathematics and Science PYQs

Elementary mathematics and science content with the pedagogical issues of teaching both subjects, as asked in upper-primary teacher papers.

3840 Total Questions64 Official PapersYears: 2012–2026Search in Mathematics and Science
Showing questions 901–920 of 3840Page 46 of 100
CTET Paper 2 Maths & Science 6th Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 901

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

The largest and the smallest among the fractions \(\frac{1}{75},\frac{2}{149},\frac{3}{224},\frac{4}{299}\) and \(\frac{6}{449}\) are respectively:

  1. AOption (a)

    \(\frac{3}{224} \) and \(\frac{1}{75} \)

  2. BOption (b)

    \(\frac{2}{149} \) and \(\frac{1}{75} \)

  3. COption (c)

    \(\frac{4}{299}\) and \(\frac{3}{224} \)

  4. DOption (d)

    \(\frac{6}{449}\) and \(\frac{2}{149} \)

View answer & explanation

Correct answer

Answer: (b)B.

\(\frac{2}{149} \) and \(\frac{1}{75} \)

Why this answer is correct

Calculation:

1/75 = 0.01333

2/149 = 0.01342

3/224 = 0.01339

4/299 = 0.01337

6/449 = 0.01336

So, the largest and the smallest among the fractions \(\frac{2}{149} \) and \(\frac{1}{75} \)

∴ The correct answer is option 2

CTET Paper 2 Maths & Science 6th Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 902

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

The LCM of 767 and 2773 is k times their HCF. What is the value of k ? 

  1. AOption (a)

    607

  2. BOption (b)

    609

  3. COption (c)

    611

  4. DOption (d)

    613

View answer & explanation

Correct answer

Answer: (c)C.

611

Why this answer is correct

Calculations:

767 = 13 × 59 

2773 = 47 × 59 

LCM of 767 & 2773 = 13 × 47 × 59 = 36049 

HCF of 767 & 2773 = 59

According to Question Statement 

36049 = 59 × k 

k = 36049/59 = 611

Hence, The Correct Answer is 3.

CTET Paper 2 Maths & Science 6th Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 903

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

If (\(\frac{-3}{4}\))-3 ÷ (\(\frac{-4}{3}\))7 = \(\left[\left(-\frac{4}{3}\right)^2\right]^4 \)× \((\frac{3}{4})^{5x+2} \), then what is the value of x?

  1. AOption (a)

    0

  2. BOption (b)

    1

  3. COption (c)

    -1

  4. DOption (d)

    2

View answer & explanation

Correct answer

Answer: (d)D.

2

Why this answer is correct

Calculation:

\(\left(-\frac{3}{4}\right)^{-3}\div\left(-\frac{4}{3}\right)^7=\left[\left(-\frac{4}{3}\right)^2\right]^4×\left(\frac{3}{4}\right)^{5x+2} \)

⇒ \(-\frac{4^3}{3^3}\) × \(- \frac{3^7}{4^7}\) = \( \frac{4^8}{3^8}\) × \(\frac{3^{5x + 2}}{4^{5x + 2}}\) 

⇒ \(\frac{3^4}{4^4}\) = \(\frac{3^{5x + 2 - 8}}{4^{5x + 2 - 8}}\) 

Comparing we get,

(5x + 2 - 8) = 4

⇒ 5x - 6 = 4

⇒ x = 10/5 = 2

∴ The correct answer is 2

CTET Paper 2 Maths & Science 6th Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 904

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

Given that 2.142 + 1.102 + 0.21 - 4.124 = k - 3.26. What should be subtracted from k so that its value becomes 2.5 ?

  1. AOption (a)

    0.9

  2. BOption (b)

    0.6

  3. COption (c)

    0.06

  4. DOption (d)

    0.09

View answer & explanation

Correct answer

Answer: (d)D.

0.09

Why this answer is correct

Calculation:

2.142 + 1.102 + 0.21 - 4.124 = k - 3.26

⇒ 3.454 - 4.124 = k - 3.26

⇒ - 0.67 = k - 3.26

⇒ k = 3.26 - 0.67

⇒ k = 2.59

Let's assume that x is subtracted from k, to make its value become 2.5

2.59 − x = 2.5

⇒ x = 2.59 - 2.5

⇒ x = 0.09

∴ The correct answer is 0.09

CTET Paper 2 Maths & Science 6th Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 905

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

\(\sqrt[3]{16\times 1372}\div\sqrt{8\times288}\) is equal to:

  1. AOption (a)

    \(\frac{4}{9}\)

  2. BOption (b)

    \(\frac{14}{9}\)

  3. COption (c)

    \(\frac{7}{12}\)

  4. DOption (d)

    \(\frac{7}{16}\)

View answer & explanation

Correct answer

Answer: (c)C.

\(\frac{7}{12}\)

Why this answer is correct

Calculation:

\(√[3]{16\times 1372}÷√{8\times288} \)

⇒ \(√[3]{21952}\)  ÷ √2304

⇒ 28 ÷ 48

⇒ 7/12

∴ The correct answer is \(\frac{7}{12}\)

CTET Paper 2 Maths & Science 6th Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 906

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

If \(\rm \frac{2(3y-4)+6}{3y-(4+5y)}=0.6\), then what is the value of (9y + 2)?

  1. AOption (a)

    1.2

  2. BOption (b)

    1.5

  3. COption (c)

    1.8

  4. DOption (d)

    2.4

View answer & explanation

Correct answer

Answer: (b)B.

1.5

Why this answer is correct

Shortcut Trick

Numerator simplification: 2(3y − 4) + 6 = 6y − 2

Denominator simplification: 3y − (4 + 5y) = −2y − 4

Equation becomes: (6y − 2) / (−2y − 4) = 0.6 ⇒ 6y − 2 = −1.2y − 2.4

Solving for y: 7.2y = −0.4 → y = −1/18

Target value: 9 × (−1/18) + 2 = −0.5 + 2 = 1.5

∴ The correct answer is 1.5.

Alternate Method

Given: (2(3y − 4) + 6) / (3y − (4 + 5y)) = 0.6

Formula Used: Algebraic simplification and transposition.

⇒ (6y − 8 + 6) / (3y − 4 − 5y) = 0.6

⇒ (6y − 2) / (−2y − 4) = 0.6

⇒ 6y − 2 = 0.6 × (−2y − 4)

⇒ 6y − 2 = −1.2y − 2.4

⇒ 6y + 1.2y = −2.4 + 2

⇒ 7.2y = −0.4

⇒ y = −0.4 / 7.2 = −4 / 72 = −1/18

⇒ Required value = 9y + 2

⇒ 9 × (−1/18) + 2 = −1/2 + 2 = −0.5 + 2 = 1.5

∴ The correct answer is 1.5.

Additional Information

BODMAS Rule

Simplification follows the order: Brackets, Orders, Division, Multiplication, Addition, and Subtraction.

Transposition Method

While moving terms across the equal sign, addition becomes subtraction, and multiplication becomes division.

Linear Equations

An equation with a single variable and a maximum power of 1, typically solved by isolating the variable on one side.

CTET Paper 2 Maths & Science 6th Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 907

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

What is the product of the coefficients of x2 and x in the following ?

\(\rm \left(2x^2-3x-\frac{9}{x}\right)\left(-x+\frac{7}{x}\right) \)

  1. AOption (a)

    24

  2. BOption (b)

    28

  3. COption (c)

    36

  4. DOption (d)

    42

View answer & explanation

Correct answer

Answer: (d)D.

42

Why this answer is correct

Calculation:

\(\rm \left(2x^2-3x-\frac{9}{x}\right)\left(-x+\frac{7}{x}\right) \)

⇒ - 2x3 + 3x2 + 9 + 14x - 21 - 63/x2

⇒ - 2x3 +  3x2 + 9 + 14x - 21 - 63x-2

Here, coefficients of x2 and x  are 3 and 14 respectively,

Their product = 3 × 14 = 42

∴ The correct answer is 42

CTET Paper 2 Maths & Science 6th Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 908

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

A common factor of x2 - 13x + 40, x2 + 3x - 40 and x2 - 9x +20 is :

  1. AOption (a)

    x - 8

  2. BOption (b)

    x + 10

  3. COption (c)

    x + 4

  4. DOption (d)

    x - 5

View answer & explanation

Correct answer

Answer: (d)D.

x - 5

Why this answer is correct

Calculation:

Factors of x2 - 13x + 40 = (x - 8)(x - 5)

Factors of x2 + 3x - 40 = (x + 8)(x - 5)

Factors of x2 - 9x +20 = (x - 4)(x - 5)

So, the common factor among the factored expressions is (x - 5)

∴ The correct answer is (x - 5)

CTET Paper 2 Maths & Science 6th Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 909

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

If 5x -3y = 35 and xy = -20, then what is the value of \(\rm \frac{25x}{y}+\frac{9y}{x}\)?

  1. AOption (a)

    \(-\frac{125}{4}\)

  2. BOption (b)

    \(\frac{125}{4}\)

  3. COption (c)

    \(\frac{25}{4}\)

  4. DOption (d)

    \(-\frac{25}{8}\)

View answer & explanation

Correct answer

Answer: (a)A.

\(-\frac{125}{4}\)

Why this answer is correct

Concept used:

a2 + b2 = (a - b)2 + 2ab

Calculation:

\(\rm \frac{25x}{y}+\frac{9y}{x}\)

⇒ (25x2 + 9y2)/xy 

⇒ [(5x)2 + (3y)2]/xy

⇒ [(5x - 3y)2 + 30xy]/xy

⇒ [(35)2 + 30 × (- 20)]/-20

⇒ [1225 - 600]/-20

⇒ 625/-20

⇒ \(-\frac{125}{4}\) 

∴ The correct answer is \(-\frac{125}{4}\)

CTET Paper 2 Maths & Science 6th Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 910

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

A shopkeeper sells a toy by giving 20% discount on its marked price and gains 25%. What is the marked price of the toy, if its cost price is Rs. 160 ? 

  1. AOption (a)

    Rs. 300

  2. BOption (b)

    Rs. 280

  3. COption (c)

    Rs  250

  4. DOption (d)

    Rs. 240

View answer & explanation

Correct answer

Answer: (c)C.

Rs  250

Why this answer is correct

Calculation:

The shopkeeper sells a toy by giving 20% discount, so MP : SP = 5 : 4

If he gains 25% profit, then CP : SP = 4 : 5

So, CP : SP : MP = 16 : 20 : 25

Now, 16 unit → 160, then 25 unit → 160/16 × 25 = 250

∴ The correct answer is Rs. 250

CTET Paper 2 Maths & Science 6th Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 911

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

In Δ ABC, ∠A = x and the bisectors of ∠B and ∠C meet at D. If ∠BDC = 108°, then what is the value of x ? 

  1. AOption (a)

    36°

  2. BOption (b)

    54°

  3. COption (c)

    45°

  4. DOption (d)

    72°

View answer & explanation

Correct answer

Answer: (a)A.

36°

Why this answer is correct

Calculation:

According to the given picture, BD and CD are the angle bisectors, 

So, ∠BDC = 90 + 1/2∠A

⇒ 108 = 90 + 1/2x

⇒ 1/2x= 108 - 90

⇒ x = 18 × 2

⇒ x = 36° 

∴ The correct answer is 36°

CTET Paper 2 Maths & Science 6th Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 912

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

In which of the following cases, construction of quadrilateral ABCD is not possible ?

  1. AOption (a)

    AB = 3.5 cm, BC = 5.5 cm, CD = 5 cm, ∠B = 125° and ∠C = 80° 

  2. BOption (b)

    AB = 3.5 cm, BC = 6.5 cm, ∠A = 75°, ∠B = 105° and ∠C = 120°

  3. COption (c)

    AD = 5.5 cm, CD = 5 cm, BC = 4.5 cm, AC = 5.5 cm and BD = 7 cm

  4. DOption (d)

    AB = 3 cm, CD = 5.5 cm, DA = 6 cm, BC = 4 cm and BD = 9 cm

View answer & explanation

Correct answer

Answer: (d)D.

AB = 3 cm, CD = 5.5 cm, DA = 6 cm, BC = 4 cm and BD = 9 cm

Why this answer is correct

Calculation : 

In Option (4), we have AB + CD < AC.

This is not possible because the sum of the lengths of two sides of a triangle must be greater than the length of the third side.

Therefore, the construction of quadrilateral ABCD is not possible in this case.

In Option (1), we have AB + BC > CD, and ∠B + ∠C < 180°.

In Option (2), we have AB + BC > AC, and ∠A + ∠B + ∠C = 180°.

In Option (3), we have AD + CD > BC, and AB + AC > BD.

Therefore, the answer is (4).

CTET Paper 2 Maths & Science 6th Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 913

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

Points A and D are on the same side of line segment BC such that ∠DBC =  ∠ACB = 40° and ∠ABD = ∠DCA = 20°. Which of the following is correct ? 

  1. AOption (a)

    Δ ABC ≅ Δ DBC

  2. BOption (b)

    Δ ABC ≅ Δ BDC

  3. COption (c)

    Δ ACB ≅ Δ DBC

  4. DOption (d)

    Δ ACB ≅ Δ BDC

View answer & explanation

Correct answer

Answer: (c)C.

Δ ACB ≅ Δ DBC

Why this answer is correct

Calculations:

In Δ ACB  & Δ DBC

BC = BC (Common)

∠ACB = ∠DBC (40°)

∠ABC = ∠DCB (60°)

Hence, Δ ACB ≅ Δ DBC (By ASA Angle Side Angle Criteria)

CTET Paper 2 Maths & Science 6th Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 914

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

Which of the following cannot be the lengths of the sides of a right triangle ? 

  1. AOption (a)

    10 cm, 24 cm and 26 cm 

  2. BOption (b)

    48 cm, 55 cm and 73 cm 

  3. COption (c)

    12 cm, 35 cm and 47 cm 

  4. DOption (d)

    11 cm, 60 cm and 61 cm 

View answer & explanation

Correct answer

Answer: (c)C.

12 cm, 35 cm and 47 cm 

Why this answer is correct

Concept used:

According to Pythagoras' theorem,

Hypotenuse2 = Height2 + Base2

Calculation:

From the given options, according to option 3

472 = 2209, 352 = 1225 and 122 = 144

So, 472 ≠ (352 + 122)

∴ 12 cm, 35 cm and 47 cm cannot be the lengths of the sides of a right triangle

CTET Paper 2 Maths & Science 6th Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 915

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

Which of the following is not true for a polyhedron, where, F, E and V respectively denote the number of faces, edges and vertices of the polyhedron ?

  1. AOption (a)

    F = 6, E = 10 and V = 6 

  2. BOption (b)

    F = (n + 2), E = 3n and V = 2n 

  3. COption (c)

    F = 7, E = 14 and V = 10  

  4. DOption (d)

    F = 11, E = 17 and V = 8 

View answer & explanation

Correct answer

Answer: (c)C.

F = 7, E = 14 and V = 10  

Why this answer is correct

Concept use:

Euler's formula can be written as F + V = E + 2, where F is equal to the number of faces, V is equal to the number of vertices, and E is equal to the number of edges.

Calculations:

take option no 3 

F = 7, E = 14 and V = 10

Put the Values in the Equations 

F + V = E + 2

7 + 10 ≠ 14 + 2 satisfied

Hence, Option 3 is not true.

take option 1

F = 6, E = 10 and V = 6 

Put the Values in the Equations 

F + V = E + 2

6 + 6 = 10 + 2 satisfied

Hence, Option 1 is true

take option 2

F = (n + 2), E = 3n and V = 2n 

Put the Values in the Equations 

F + V = E + 2

n + 2 + 2n = 3n + 2 satisfied

Hence, option 2 is true.

take option 4

F = 11, E = 17 and V = 8 

Put the Values in the Equations 

F + V = E + 2

11 + 8 = 17 + 2 satisfied

Hence, option 4 is true

Hence, The Correct option is 3.

CTET Paper 2 Maths & Science 6th Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 916

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

The rectangle with both integer length (in cm) and width (in cm) has area 70 cm2 Which of the following cannot be the perimeter (in cm) of the rectangle ?

  1. AOption (a)

    38

  2. BOption (b)

    74

  3. COption (c)

    98

  4. DOption (d)

    142

View answer & explanation

Correct answer

Answer: (c)C.

98

Why this answer is correct

Concept used:

  • Area of rectangle = Length × Breadth
  • Perimeter of rectangle = 2(Length + Breadth)

Calculation:

The factor pairs of 70 are (Length × Breadth): 1 × 70, 2 × 35, 5 × 14, 7 × 10 

According to the factor pairs, all options are satisfies except option 3 which is 98

∴ The correct answer is 98

CTET Paper 2 Maths & Science 6th Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 917

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

The radius of the base of a solid right circular cylinder is 8 cm and its total surface area is 272π cm2 The volume (in cm3) of the cylinder is :

  1. AOption (a)

    192 π

  2. BOption (b)

    320 π

  3. COption (c)

    384 π

  4. DOption (d)

    576 π

View answer & explanation

Correct answer

Answer: (d)D.

576 π

Why this answer is correct

Concept used:

  • Volume of right circular cylinder = π × r2 × h
  • Total surface area of right circular cylinder = 2πrh + 2πr2

Calculation:

According to the question,

2π8h + 2π82 = 272π 

⇒ 16h + 128 = 272

⇒ 16h = 272 - 128

⇒ 16h = 144

⇒ h = 144/16 

⇒ h = 9

Now, the Volume of the right circular cylinder = π × 82 × 9 = 576π 

∴ The correct answer is 576π

CTET Paper 2 Maths & Science 6th Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 918

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

The areas of three adjacent faces of a cuboid are 192 cm2, 144 cm2 and 108 cm2. Two-third of the volume of this cuboid is equal to :

  1. AOption (a)

    576 cm3

  2. BOption (b)

    1152 cm3

  3. COption (c)

    1440 cm3

  4. DOption (d)

    1728 cm3

View answer & explanation

Correct answer

Answer: (b)B.

1152 cm3

Why this answer is correct

Given:

The areas of three adjacent faces are 108 cm2, 144 cm2 and 192 cm2

Formula Used:

Volume of cuboid = lbh

l = length, b = breadth and h = height 

Calculation:

According to the question 

lb = 108    -----(i)

bh = 144     -----(ii)

hl = 192    -----(iii)

On multiplying (i), (ii) and (iii), we get 

lb × bh × hl = 108 × 144 × 192 

⇒ (lbh)2 = 108 × 144 × 192 

⇒ (Volume of cuboid)2 = 36 × 3 × 144 × 3 × 64

⇒ (Volume of cuboid)2 = (6 × 3 × 12 × 8)2

⇒ Volume of cuboid = 1728 cm3

According to the question 

Volume of cuboid = 2/3 × 1728 = 1152 cm3

∴  The required answer will be 1152 cm3

CTET Paper 2 Maths & Science 6th Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 919

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

Let x be the median of the data : 5, 3, 2, 9, 13, 11, 17, 15, 21 and y be the median of the data obtained by replacing 3 and 21 by 16 and 14, respectively in the above data. What is the value of (2x - y) ? 

  1. AOption (a)

    7

  2. BOption (b)

    8

  3. COption (c)

    9

  4. DOption (d)

    11

View answer & explanation

Correct answer

Answer: (c)C.

9

Why this answer is correct

Calculation:

If we arrange it in ascending order, we get

2, 3, 5, 9, 11, 13, 15, 17, 21

So, the median of the data set is x = 11

If we replace 3 and 21 by 16 and 14 we get in ascending order,

2, 5, 9, 11, 13, 14, 15, 16, 17

So, median of the data set is y = 13

Then the value of (2x - y) = (2 × 11 - 13) = 9

∴ The correct answer is 9

CTET Paper 2 Maths & Science 6th Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 920

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

Numbers 26, 27, 28, 29, ..., 51 are written on separate cards (one number on one card), kept in a box and mixed well. One card is drawn at random from the box. What is the probability that the number on the card drawn is a multiple of 2 or 3 ? 

  1. AOption (a)

    \(\frac{15}{26}\)

  2. BOption (b)

    \(\frac{8}{13}\)

  3. COption (c)

    \(\frac{17}{26}\)

  4. DOption (d)

    \(\frac{9}{13}\)

View answer & explanation

Correct answer

Answer: (d)D.

\(\frac{9}{13}\)

Why this answer is correct

Calculatioin:

Counting multiples of 2:  26, 28, 30, 32,…,50 (all even numbers.)

Counting multiples of 3: 27, 30, 33, 36, …, 51 

There are some common multiples present in 2 and 3 both,

Total number of multiples of 2 is 13

Total number of multiples of 3 is 9

Total number of multiples of 6 (common multiples): 4

So, the total number of favorable outcomes is 13 + 9 − 4 = 18

The total number of possible outcomes is 51 − 26 + 1 = 26

Required probability = 18/26 = 9/13

∴ The correct answer is 9/13

How should I prepare for Mathematics and Science in Central Teacher Eligibility Test (CTET)?

Solving previous year questions by topic helps identify recurring concepts, question patterns, and frequently asked sub-topics. Attempt each question, review the step-by-step explanation, and note down key formulas or facts for quick revision before the exam.