Shortcut Trick
In any triangle, the angle formed by the internal bisectors of two angles (say ∠B and ∠C) at the incenter (I) is related to the third angle (∠A) by the formula:
Angle between bisectors = 90° + (∠A ÷ 2)
Given ∠A = 120°
⇒ Required Angle = 90° + (120° ÷ 2)
⇒ Required Angle = 90° + 60° = 150°
∴ The correct answer is 150°ree;.
Alternate Method
Given:
One angle of the triangle (∠A) = 120°
The other two angles are ∠B and ∠C.
Property Used: Sum of interior angles of a triangle is 180°.
⇒ In ΔABC, ∠A + ∠B + ∠C = 180°
⇒ 120° + ∠B + ∠C = 180°
⇒ ∠B + ∠C = 180° − 120° = 60°
Let I be the point of intersection of the bisectors of ∠B and ∠C.
⇒ In ΔBIC, the sum of angles is also 180°:
⇒ ∠BIC + ∠IBC + ∠ICB = 180°
⇒ Since BI and CI are bisectors, ∠IBC = ∠B ÷ 2 and ∠ICB = ∠C ÷ 2.
⇒ ∠BIC + (∠B ÷ 2) + (∠C ÷ 2) = 180°
⇒ ∠BIC + (∠B + ∠C) ÷ 2 = 180°
⇒ ∠BIC + (60° ÷ 2) = 180°
⇒ ∠BIC + 30° = 180°
⇒ ∠BIC = 180° − 30° = 150°
∴ The correct answer is 150°ree;.
Additional Information
Incenter
The point where all internal angle bisectors of a triangle meet. It is the center of the incircle.
Angle at Excenter
The angle formed by the external bisectors of two angles of a triangle is given by the formula 90° − (∠A ÷ 2).
Angle in a Straight Line
Internal bisector and external bisector of the same angle are always perpendicular (form a 90° angle) to each other.