Central Teacher Eligibility Test (CTET) · Topic Collection

Mathematics and Science PYQs

Elementary mathematics and science content with the pedagogical issues of teaching both subjects, as asked in upper-primary teacher papers.

3840 Total Questions64 Official PapersYears: 2012–2026Search in Mathematics and Science
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CTET Paper 2 Maths & Science 30th Jan 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 841

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

The value of 18 ÷ 3 + 5 × 6 - 1 is:

  1. AOption (a)

    31

  2. BOption (b)

    65

  3. COption (c)

    40

  4. DOption (d)

    35

View answer & explanation

Correct answer

Answer: (d)D.

35

Why this answer is correct

Concept used:

Calculation:

18 ÷ 3 + 5 × 6 - 1

⇒ 6 + 30 - 1

⇒ 35

∴ The correct answer is 35

CTET Paper 2 Maths & Science 30th Jan 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 842

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

If \(\rm \left(\frac{3}{5}\right)^5 \times\left(\frac{3}{5}\right)^{-3}=\left(\frac{3}{5}\right)^{5 x-3} \), then the value of x is :

  1. AOption (a)

    1

  2. BOption (b)

    0

  3. COption (c)

    2

  4. DOption (d)

    \(\frac{2}{5}\)

View answer & explanation

Correct answer

Answer: (a)A.

1

Why this answer is correct

Concept used:

Ab × Ac = A(b + c)

Calculation:

\(\rm \left(\frac{3}{5}\right)^5 \times\left(\frac{3}{5}\right)^{-3}=\left(\frac{3}{5}\right)^{5 x-3} \)

⇒ \((\frac{3}{5})^{(5 - 3)}\) = \((\frac{3}{5})^{5x - 3}\) 

⇒ \((\frac{3}{5})^2\) =  \((\frac{3}{5})^{5x - 3}\)

Comparing, we get,

(5x - 3) = 2

⇒ x = 1

∴ The correct answer is 1

CTET Paper 2 Maths & Science 30th Jan 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 843

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

If 21168 = p4q3r2, where p, q and r are prime numbers, then the value of (4p + 3q - 2r) is :

  1. AOption (a)

    6

  2. BOption (b)

    7

  3. COption (c)

    2

  4. DOption (d)

    3

View answer & explanation

Correct answer

Answer: (d)D.

3

Why this answer is correct

Given:

21168 = p4q3r2

Calculation:

To identify p, q, r, we have to factorize 21168

21168 = 24 × 33 × 72 comparing with p4q3r2 we get p = 2, q = 3, and r = 7

Then the value of (4p + 3q - 2r) = (4 × 2 + 3 × 3 - 2 × 7) = (8 + 9 - 14) = 3

∴ The correct answer is 3

CTET Paper 2 Maths & Science 30th Jan 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 844

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

The value of [(-20) ÷ 4] × (-2) + 6 × 3 - 1 is:

  1. AOption (a)

    27

  2. BOption (b)

    22

  3. COption (c)

    32

  4. DOption (d)

    30

View answer & explanation

Correct answer

Answer: (a)A.

27

Why this answer is correct

Concept used:

Calculation:

[(-20) ÷ 4] × (-2) + 6 × 3 - 1

⇒ [- 5] × (- 2) + 18 - 1

⇒ 10 + 18 - 1

⇒ 28 - 1

⇒ 27

∴ The correct answer is 27

CTET Paper 2 Maths & Science 30th Jan 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 845

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

The fractions \(\frac{30}{25}, \frac{27}{81}, \frac{22}{25} \) and \( \frac{45}{22}\) are written in ascending order as:

  1. AOption (a)

    \(\frac{27}{81}, \frac{30}{25}, \frac{45}{22}, \frac{22}{25} \)

  2. BOption (b)

    \(\frac{27}{81}, \frac{45}{22}, \frac{22}{25}, \frac{30}{25} \)

  3. COption (c)

    \(\frac{45}{22}, \frac{30}{25}, \frac{22}{25}, \frac{27}{81} \)

  4. DOption (d)

    \(\frac{27}{81}, \frac{22}{25}, \frac{30}{25}, \frac{45}{22}\)

View answer & explanation

Correct answer

Answer: (d)D.

\(\frac{27}{81}, \frac{22}{25}, \frac{30}{25}, \frac{45}{22}\)

Why this answer is correct

Calculation:

This question can be solved by simply converting the fractions in decimal forms and then comparing them.

30/25 = 1.2

27/81 = 0.333

22/25 = 0.88

45/22 = 2.045

∴ The correct ascending order is =  \(\frac{27}{81}, \frac{22}{25}, \frac{30}{25}, \frac{45}{22}\)

CTET Paper 2 Maths & Science 30th Jan 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 846

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

The marked price of an article is Rs. 420. A shopkeeper gives a discount of 15% on the marked price and still makes a profit of 19%. What is the cost price of the article?

  1. AOption (a)

    Rs. 270

  2. BOption (b)

    Rs. 290

  3. COption (c)

    Rs. 300

  4. DOption (d)

    Rs. 320

View answer & explanation

Correct answer

Answer: (c)C.

Rs. 300

Why this answer is correct

Calculation:

A 15% discount given on MP = 420, then SP = 420 × 17/20 = 357

Selling at the price of Rs. 357, the shopkeeper makes 19% profit, then CP = 357 × 100/119 = Rs. 300

∴ The correct answer is Rs. 300

CTET Paper 2 Maths & Science 30th Jan 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 847

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

If \(\rm x+\frac{1}{x}=4 \), then the value of \(\rm x^4+\frac{1}{x^4}\) is:

  1. AOption (a)

    128

  2. BOption (b)

    194

  3. COption (c)

    196

  4. DOption (d)

    256

View answer & explanation

Correct answer

Answer: (b)B.

194

Why this answer is correct

Concept used:

  • If x + 1/x = a, then x2 + 1/x2 = a2 - 2
  • If x2 + 1/x2 = a, then x4 + 1/x4 = a2 - 2

Calculation:

Here, x + 1/x = 4, then x2 + 1/x2 = 42 - 2 = 14,

Again if x2 + 1/x2 = 14, then x4 + 1/x4 = 142 - 2 = 194

∴ The correct answer is 194

CTET Paper 2 Maths & Science 30th Jan 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 848

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

One of the factors of the expression x2y - xy2 + x - y is:

  1. AOption (a)

    x2 - y2

  2. BOption (b)

    x + y

  3. COption (c)

    xy + 1

  4. DOption (d)

    xy

View answer & explanation

Correct answer

Answer: (c)C.

xy + 1

Why this answer is correct

Calculation:

(x2y - xy2)+ (x - y) 

⇒ xy(x - y) + (x - y)

⇒ (x - y)(xy + 1)

∴ From the given options, (xy + 1) is one of the factors of the given expression

CTET Paper 2 Maths & Science 30th Jan 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 849

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

In the product (x - 2)(x - 3)(x - 5), the co-efficient of x2 is:

  1. AOption (a)

    -30

  2. BOption (b)

    10

  3. COption (c)

    1

  4. DOption (d)

    -10

View answer & explanation

Correct answer

Answer: (d)D.

-10

Why this answer is correct

Calculation:

Multiply the first two factors, we get

(x - 2)(x - 3)

⇒ x2 - 3x - 2x + 6

⇒ x2 - 5x + 6

Now multiply the result above with the third factor (x - 5), we get

(x - 5)(x2 - 5x + 6)

⇒ x3 - 5x2 + 6x - 5x2 + 25x - 30

⇒ x3 - 10x2 + 31x - 30

Here, we see the co-efficient of x2 is - 10

∴ The correct answer is - 10

CTET Paper 2 Maths & Science 30th Jan 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 850

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

If x2 + y2 = 6 and x3y + xy3 + x2 + y2 = 36, then the value of xy is :

  1. AOption (a)

    4

  2. BOption (b)

    3

  3. COption (c)

    5

  4. DOption (d)

    6

View answer & explanation

Correct answer

Answer: (c)C.

5

Why this answer is correct

Shortcut Trick

Factor out the common factor (x2 + y2) from the given expression: xy(x2 + y2) + (x2 + y2) = 36

Substitute the value x2 + y2 = 6 into the equation: 6(xy) + 6 = 36

⇒ 6(xy + 1) = 36

⇒ xy + 1 = 6 ⇒ xy = 5

∴ The correct answer is 5.

Alternate Method

Given:

x2 + y2 = 6 --- (1)

x3y + xy3 + x2 + y2 = 36 --- (2)

Method: Factorization by grouping

⇒ xy(x2 + y2) + (x2 + y2) = 36

⇒ (x2 + y2)(xy + 1) = 36

Substitute the value of (x2 + y2) from equation (1):

⇒ 6 × (xy + 1) = 36

⇒ xy + 1 = 36 ÷ 6

⇒ xy + 1 = 6

⇒ xy = 6 − 1

⇒ xy = 5

∴ The correct answer is 5.

Additional Information

Factorization by Grouping

This method involves rearranging the terms of a polynomial into groups that share a common factor, such as a(x + y) + b(x + y) = (a + b)(x + y).

Algebraic Identity for Squares

The square of a binomial is given by (x + y)2 = x2 + y2 + 2xy. This is useful for finding the sum of squares when the product is known.

Substitution Method

In a system of equations, a known value or expression from one equation is substituted into another to reduce the number of variables and solve the problem.

CTET Paper 2 Maths & Science 30th Jan 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 851

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

Which of the following is a Pythagorean triplet ?

  1. AOption (a)

    12, 15, 19

  2. BOption (b)

    8, 13, 18

  3. COption (c)

    5, 12, 13

  4. DOption (d)

    14, 20, 24

View answer & explanation

Correct answer

Answer: (c)C.

5, 12, 13

Why this answer is correct

Calculation:

According to the given options, option 3

52 + 122 = 169 = 132 holds Pythagoras theorem

So, 5, 12, 13 are Pythagorean triplet

∴ The correct answer is option 3

CTET Paper 2 Maths & Science 30th Jan 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 852

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

If one of the angles of a triangle is 120°, then the angle between the bisectors of the other two angles is :

  1. AOption (a)

    60°

  2. BOption (b)

    120°

  3. COption (c)

    130°

  4. DOption (d)

    150°

View answer & explanation

Correct answer

Answer: (d)D.

150°

Why this answer is correct

Shortcut Trick

In any triangle, the angle formed by the internal bisectors of two angles (say ∠B and ∠C) at the incenter (I) is related to the third angle (∠A) by the formula:

Angle between bisectors = 90° + (∠A ÷ 2)

Given ∠A = 120°

⇒ Required Angle = 90° + (120° ÷ 2)

⇒ Required Angle = 90° + 60° = 150°

∴ The correct answer is 150°ree;.

Alternate Method

Given:

One angle of the triangle (∠A) = 120°

The other two angles are ∠B and ∠C.

Property Used: Sum of interior angles of a triangle is 180°.

⇒ In ΔABC, ∠A + ∠B + ∠C = 180°

⇒ 120° + ∠B + ∠C = 180°

⇒ ∠B + ∠C = 180° − 120° = 60°

Let I be the point of intersection of the bisectors of ∠B and ∠C.

⇒ In ΔBIC, the sum of angles is also 180°:

⇒ ∠BIC + ∠IBC + ∠ICB = 180°

⇒ Since BI and CI are bisectors, ∠IBC = ∠B ÷ 2 and ∠ICB = ∠C ÷ 2.

⇒ ∠BIC + (∠B ÷ 2) + (∠C ÷ 2) = 180°

⇒ ∠BIC + (∠B + ∠C) ÷ 2 = 180°

⇒ ∠BIC + (60° ÷ 2) = 180°

⇒ ∠BIC + 30° = 180°

⇒ ∠BIC = 180° − 30° = 150°

∴ The correct answer is 150°ree;.

Additional Information

Incenter

The point where all internal angle bisectors of a triangle meet. It is the center of the incircle.

Angle at Excenter

The angle formed by the external bisectors of two angles of a triangle is given by the formula 90° − (∠A ÷ 2).

Angle in a Straight Line

Internal bisector and external bisector of the same angle are always perpendicular (form a 90° angle) to each other.

CTET Paper 2 Maths & Science 30th Jan 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 853

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

A regular polygon of 6 sides has :

  1. AOption (a)

    3 lines of symmetry

  2. BOption (b)

    6 lines of symmetry

  3. COption (c)

    12 lines of symmetry

  4. DOption (d)

    9 lines of symmetry

View answer & explanation

Correct answer

Answer: (b)B.

6 lines of symmetry

Why this answer is correct

Concept used:

In a regular polygon, the lines of symmetry are equal to the number of sides

Calculation:

According to the given concept,

A regular polygon of 6 sides (Hexagon) has 6 lines of symmetry

∴ The correct answer is 6 lines of symmetry

CTET Paper 2 Maths & Science 30th Jan 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 854

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

In triangles ABC and DEF, ∠C = ∠F, AC = DF and BC = EF. If AB = 4x - 2 and DE = 3x - 1, then the value of x is:

  1. AOption (a)

    1

  2. BOption (b)

    2

  3. COption (c)

    3

  4. DOption (d)

    4

View answer & explanation

Correct answer

Answer: (a)A.

1

Why this answer is correct

Shortcut Trick

Given AC = DF, BC = EF, and the included angle ∠C = ∠F.

By the SAS (Side-Angle-Side) congruence rule, ΔABC ≅ ΔDEF.

In congruent triangles, corresponding parts are equal (CPCT), so AB = DE.

⇒ 4x − 2 = 3x − 1

⇒ 4x − 3x = 2 − 1

⇒ x = 1

∴ The correct answer is 1.

Alternate Method

Given: In ΔABC and ΔDEF, AC = DF, BC = EF, ∠C = ∠F. Also, AB = 4x − 2 and DE = 3x − 1.

Formula Used: SAS Congruence Criterion and CPCT (Corresponding Parts of Congruent Triangles).

Applying the SAS Congruence Rule:

⇒ Side AC = Side DF (Given)

⇒ Angle ∠C = Angle ∠F (Given)

⇒ Side BC = Side EF (Given)

⇒ ∴ ΔABC ≅ ΔDEF (By SAS criterion)

Since the triangles are congruent, their corresponding sides are equal:

⇒ AB = DE

⇒ 4x − 2 = 3x − 1

⇒ 4x − 3x = 2 − 1

⇒ x = 1

∴ The correct answer is 1.

Additional Information

SAS Congruence Rule

Two triangles are congruent if two sides and the included angle of one triangle are equal to the two sides and the included angle of the other triangle.

CPCT Property

Corresponding Parts of Congruent Triangles are always equal in measure (sides and angles).

Other Congruence Criteria

Triangles can also be proven congruent using SSS (Side-Side-Side), ASA (Angle-Side-Angle), AAS (Angle-Angle-Side), and RHS (Right angle-Hypotenuse-Side).

CTET Paper 2 Maths & Science 30th Jan 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 855

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

Which of the following triplets can form a polyhedron, if the numbers represent the number of faces, vertices and edges, respectively ?

  1. AOption (a)

    4, 4 and 5

  2. BOption (b)

    6, 8 and 12

  3. COption (c)

    6, 8 and 10

  4. DOption (d)

    5, 6 and 8

View answer & explanation

Correct answer

Answer: (b)B.

6, 8 and 12

Why this answer is correct

Concept used : 

Euler's formula for polyhedra states that F + V - E = 2. This formula holds true for all polyhedra, regardless of their shape or size.

Calculation :

The triplets (4, 4, 5) and (5, 6, 8) do not satisfy Euler's formula, so they cannot form polyhedra.

The triplet (6, 8, 10) satisfies Euler's formula, but it is not possible to form a polyhedron with 6 faces that are all triangles.

The minimum number of edges for a polyhedron with 6 faces that are all triangles is 9, but the triplet (6, 8, 10) only has 10 edges.

The triplet (6, 8, 12) satisfies Euler's formula and it is possible to form a polyhedron with 6 faces that are all triangles.

The minimum number of edges for a polyhedron with 6 faces that are all triangles is 9, and the triplet (6, 8, 12) has 12 edges, so it is possible to form a polyhedron with these properties.

Therefore, the only triplet that can form a polyhedron is (6, 8, 12).

CTET Paper 2 Maths & Science 30th Jan 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 856

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

The heights of two right circular cylinders are in the ratio of 8 ∶ 5 and their radii of bases are in the ratio of 1 ∶ 2. The ratio of their volumes is :

  1. AOption (a)

    2 ∶ 5 

  2. BOption (b)

    1 ∶ 4

  3. COption (c)

    16 ∶ 25  

  4. DOption (d)

    9 ∶ 7

View answer & explanation

Correct answer

Answer: (a)A.

2 ∶ 5 

Why this answer is correct

Concept used:

The volume of right circular cylinder = π × r2 × h

Calculation:

Let's assume that the height of the cylinder is 8x and 5x and the radius is k and 2k

So, the ratio of the volume of the two cylinders is

π × k2 ×  8x : π × (2k)2 × 5x

⇒ 8 : 4 × 5

⇒ 2 : 5

∴ The correct answer is 2 : 5

CTET Paper 2 Maths & Science 30th Jan 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 857

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

If each edge of a solid cube is increased by 100%, then the percentage increase in its surface area is :

  1. AOption (a)

    100

  2. BOption (b)

    200

  3. COption (c)

    300

  4. DOption (d)

    400

View answer & explanation

Correct answer

Answer: (c)C.

300

Why this answer is correct

Concept used:

The total Surface area of a Cube = 6 × side2

Calculation:

Let's assume that each side of the cube be 10 unit

So, TSA = 6 × 102 = 600

Now, if each side increased by 100%, then the sides becomes = 10 × 200/100 = 20

Now, TSA = 6 × 202 = 2400

TSA increased (2400 - 600) = 1800

Percentage increase in TSA = 1800/600 × 100 = 300%

∴ The correct answer is 300%

CTET Paper 2 Maths & Science 30th Jan 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 858

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

If the sum of the parallel sides of a trapezium is 40 cm and its height is 10 cm, then the area of the trapezium is:

  1. AOption (a)

    400 cm2

  2. BOption (b)

    200 cm2

  3. COption (c)

    40 cm2

  4. DOption (d)

    100 cm2

View answer & explanation

Correct answer

Answer: (b)B.

200 cm2

Why this answer is correct

Concept used:

Area of trapezium = 1/2 × (Sum of parallel sides) × (distance between them)

Calculation:

According to the given formula,

Area of trapezium = 1/2 × 40 × 10 = 200 cm2

∴ The correct answer is 200 cm2

CTET Paper 2 Maths & Science 30th Jan 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 859

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

Following table shows marks obtained by 40 students. What is the mode of this data ?

Marks obtained4236304550
No. of students7101382
  1. AOption (a)

    50

  2. BOption (b)

    30

  3. COption (c)

    10

  4. DOption (d)

    36

View answer & explanation

Correct answer

Answer: (b)B.

30

Why this answer is correct

Concept used:

The number which has. the highest frequency is called the mode.

Calculation:

According to the given data set,

Marks 30 is obtained by 13 numbers of students which is the highest,

So, the mode of this data = 30

∴ The correct answer is 30

CTET Paper 2 Maths & Science 30th Jan 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 860

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

Cards numbered as 12, 13, 14, . . ., 51, (one number on one card) are kept in a box and mixed thoroughly. One card is chosen at random from the box. What is the probability that the number on the chosen card is a composite number between 21 and 42 ?

  1. AOption (a)

    \(\frac{1}{2} \)

  2. BOption (b)

    \(\frac{7}{20} \)

  3. COption (c)

    \(\frac{3}{8} \)

  4. DOption (d)

    \(\frac{17}{40}\)

View answer & explanation

Correct answer

Answer: (c)C.

\(\frac{3}{8} \)

Why this answer is correct

Concept used:

Probability of any event = favorable number of cases / Total number of cases

Calculation:

Total number of cases from 12 to 51 is 40

Favorable number of cases = composite number between 21 and 42 = (22, 24, 25, 26, 27, 28, 30, 32, 33, 34, 35, 36, 38, 39, 40) total 15 numbers

So, required probability = 15/40 = 3/8

∴ The correct answer is 3/8

How should I prepare for Mathematics and Science in Central Teacher Eligibility Test (CTET)?

Solving previous year questions by topic helps identify recurring concepts, question patterns, and frequently asked sub-topics. Attempt each question, review the step-by-step explanation, and note down key formulas or facts for quick revision before the exam.