Central Teacher Eligibility Test (CTET) · Topic Collection

Mathematics and Science PYQs

Elementary mathematics and science content with the pedagogical issues of teaching both subjects, as asked in upper-primary teacher papers.

3840 Total Questions64 Official PapersYears: 2012–2026Search in Mathematics and Science
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CTET Paper 2 Maths & Science 3rd Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 781

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

If \(\rm x = \sqrt{(2019)^2+2019+2020}\), then the value of (2x - 1) is:

  1. AOption (a)

    4040

  2. BOption (b)

    4038

  3. COption (c)

    4039

  4. DOption (d)

    4041

View answer & explanation

Correct answer

Answer: (c)C.

4039

Why this answer is correct

Formula used:

(a + b)2 = a2 + b2 + 2ab

Calculation : 

\(\rm x = \sqrt{(2019)^2+2019+2020}\)

x = \(\sqrt{(2019)^2+2019+1 +2019}\)

⇒ x = \(\sqrt{(2019)^2+(1)^2 +2\times 2019\times1}\)

⇒ x = \(\sqrt{(2019+1)^2}\)

⇒ x = \(\sqrt{(2020)^2}\) = 2020

Now,

(2x - 1)

⇒ 2 × 2020 - 1

⇒ 4040 - 1= 4039

∴ The correct answer is 4039.

CTET Paper 2 Maths & Science 3rd Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 782

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

What is the sum of the greatest and the smallest of the following fractions \(\frac{4}{9},\frac{5}{6}, \frac{7}{12}, \frac{11}{24}\) and \(\frac{8}{11}\) ?

  1. AOption (a)

    \(\frac{17}{12}\)

  2. BOption (b)

    \(\frac{37}{36}\)

  3. COption (c)

    \(\frac{23}{18}\)

  4. DOption (d)

    \(\frac{31}{24}\)

View answer & explanation

Correct answer

Answer: (c)C.

\(\frac{23}{18}\)

Why this answer is correct

Calculation : 

4/9 = 0.444

5/6 = 0.833

7/12 = 0.583

11/24 = 0.458

8/11 = 0.727

Smallest fractions = 4/9

Largest fractions = 5/6

Sum = 4/9 + 5/6 = [(8 + 15)/18] = 23/18

∴ The correct answer is 23/18.

CTET Paper 2 Maths & Science 3rd Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 783

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

What is the reciprocal of x, where \(\rm x=\left(\frac{2}{3}\right)^{-3}\div\left(\frac{1}{2}\right)^2\times\left(\frac{2}{3}\right)^2 \)?

  1. AOption (a)

    \(\frac{1}{6}\)

  2. BOption (b)

    \(\frac{1}{9}\)

  3. COption (c)

    \(\frac{1}{3}\)

  4. DOption (d)

    \(\frac{2}{9}\)

View answer & explanation

Correct answer

Answer: (a)A.

\(\frac{1}{6}\)

Why this answer is correct

Calculation : 

\(\rm x=\left(\frac{2}{3}\right)^{-3}\div\left(\frac{1}{2}\right)^2×\left(\frac{2}{3}\right)^2 \)

⇒ (3/2)3/ (1/2)2 × (2/3)2

⇒ 27/8 × 4 × 4/9

⇒ 3 × 2 = 6

Reciprocal of x = 1/6

∴ The correct answer is 1/6.

CTET Paper 2 Maths & Science 3rd Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 784

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

If 3.101 - 2.11 - k = 2.65 - 0.256, then what is the value of (1 - k)? 

  1. AOption (a)

    2.304

  2. BOption (b)

    2.403

  3. COption (c)

    0.597

  4. DOption (d)

    0.403

View answer & explanation

Correct answer

Answer: (b)B.

2.403

Why this answer is correct

Calculation :

⇒ 3.101 - 2.11 - k = 2.65 - 0.256 

⇒ 0.991 - k = 2.394

⇒ k = -1.403

Now, (1 - k) = 1 - (- 1.403) = 2.403

∴ The correct answer is 2.403.

CTET Paper 2 Maths & Science 3rd Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 785

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

\(\frac{1.2\times 10^3}{2.4\times 10^{-4}}\) is written in the standard form as :

  1. AOption (a)

    5 × 106

  2. BOption (b)

    0.5 × 106

  3. COption (c)

    5 × 107

  4. DOption (d)

    2 × 107

View answer & explanation

Correct answer

Answer: (a)A.

5 × 106

Why this answer is correct

Calculation :

\(\frac{1.2× 10^3}{2.4× 10^{-4}}\)

⇒ 1/2 × 103/10-4

⇒ 0.5 × 107

⇒ 5 × 106

∴ The correct answer is 5 ×106.

CTET Paper 2 Maths & Science 3rd Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 786

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

\(\rm \frac{(x^2+y^2-z^2)^2-(x^2-y^2-z^2)^2}{(x+z)(x-z)y^2}\) is equal to:

  1. AOption (a)

    2

  2. BOption (b)

    4

  3. COption (c)

    1

  4. DOption (d)

    0

View answer & explanation

Correct answer

Answer: (b)B.

4

Why this answer is correct

Calculation :

\(\rm \frac{(x^2+y^2-z^2)^2-(x^2-y^2-z^2)^2}{(x+z)(x-z)y^2}\)

⇒ x4 + y4 + z4 + 2x2y2 - 2y2z2 - 2x2z2 - [x4 + y4 + z4 - 2x2y2 + 2y2z2 - 2x2z2]

On canceling out the similar terms with opposite signs we get,

⇒ {4x2y2 - 4y2z2}/(x2 - z2)y2

⇒  {4x2y2 - 4y2z2}/(x2y2 - z2y2)

⇒ 4

∴ The correct answer is 4.

CTET Paper 2 Maths & Science 3rd Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 787

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

What is the sum of coefficients of x2 and x in the following expression ? 

(x - 2)(2x2 + x - 15) - (x + 2)(x2 + 11x + 10)

  1. AOption (a)

    35

  2. BOption (b)

    -49

  3. COption (c)

    65

  4. DOption (d)

    -65

View answer & explanation

Correct answer

Answer: (d)D.

-65

Why this answer is correct

Calculation : 

⇒ (x - 2)(2x2 + x - 15) - (x + 2)(x2 + 11x + 10)

⇒ [2x3 + x2 - 15x - 4x2 - 2x + 30] - [x3 + 11x2 + 10x + 2x2 + 22x + 20]

⇒ [2x3 - 3x2 -17x + 30] - [x3 + 13x2 + 32x + 20]

⇒ x3 - 16x2 - 49x + 10

sum of coefficients of x2 and x = -16 - 49 = - 65

∴ The correct answer is - 65.

CTET Paper 2 Maths & Science 3rd Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 788

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

The solution of the equation 

\(\rm \frac{y+6}{4}+\rm \frac{y-3}{5}=\rm \frac{5y-4}{8}\)

is also the solution of the equation :

  1. AOption (a)

    \(\rm \frac{y+5}{2}=\frac{1}{4}+\frac{y+3}{5}\)

  2. BOption (b)

    \(\rm \frac{y+5}{2}=\frac{1}{2}+\frac{y+3}{5}\)

  3. COption (c)

    \(\rm \frac{y-5}{2}=\frac{1}{2}+\frac{y-3}{5}\)

  4. DOption (d)

    \(\rm \frac{y+3}{2}=\frac{1}{2}-\frac{y-5}{2}\)

View answer & explanation

Correct answer

Answer: (c)C.

\(\rm \frac{y-5}{2}=\frac{1}{2}+\frac{y-3}{5}\)

Why this answer is correct

Calculation : 

\(\rm \frac{y+6}{4}+\rm \frac{y-3}{5}=\rm \frac{5y-4}{8}\)

⇒ 5(y + 6) + 4(y - 3)/20 = 5y - 4/8

⇒ 5y + 30 + 4y -12/20 = 5y - 4/8

⇒ 9y + 18/20 =5y - 4/8

⇒ 72y + 144 = 100y - 80

⇒ 28y = 224

⇒ y = 8

Now by putting value of y in \(\rm \frac{y-5}{2}=\frac{1}{2}+\frac{y-3}{5}\)

⇒ 8 - 5/2 = 1/2 + 8 - 3/5

⇒ 3/2 = 1/2 + 5/5

⇒ 1 = 1

∴ The correct answer is option 3.

CTET Paper 2 Maths & Science 3rd Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 789

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

On selling a calculator for Rs. 980, a person loses \(6\frac{2}{3}%\) For how much (in Rs.) should he sell it to gain 8% ?

  1. AOption (a)

    1132

  2. BOption (b)

    1134

  3. COption (c)

    1240

  4. DOption (d)

    1244

View answer & explanation

Correct answer

Answer: (b)B.

1134

Why this answer is correct

Given : 

SP = Rs.980

Loss =  \(6\frac{2}{3}%\)

Gain= 8%

Calculation : 

By applying ratio method,

Loss =   \(6\frac{2}{3}%\) = 20/3% = 2/30

Gain = 8% = 8/100 = 2/25 

Now, 

SP = 28 = 980

⇒ 1 = 35

CP = 30 × 35 = 1050

Now,

CP = 25 = 1050 

⇒ 1 = 42

SP = 27 × 42 = 1134

∴ The correct answer is 1134.

CTET Paper 2 Maths & Science 3rd Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 790

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

If \(\rm 3x+\frac{1}{2x}=5\), then what will be the value of 3x2 + (12x2)-1 ?

  1. AOption (a)

    \(7\frac{1}{3}\)

  2. BOption (b)

    \(6\frac{2}{3}\)

  3. COption (c)

    \(8\frac{1}{3}\)

  4. DOption (d)

    \(9\frac{2}{3}\)

View answer & explanation

Correct answer

Answer: (a)A.

\(7\frac{1}{3}\)

Why this answer is correct

Concept use:

(a + b)2 = a2 + b2 + 2ab

Calculations:

3x + 1/2x = 5 

squaring both sides 

(3x + 1/2x)2 = 52

9x2 + 1/4x2 + 3 = 25

9x2 + 1/4x2 = 22

Divide by 3 both sides 

3x2 + 1/12x2 = 22/3 = \(7\frac{1}{3}\)

Hence, The Correct Option is 1.

CTET Paper 2 Maths & Science 3rd Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 791

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

In Δ PQR, side QR is produced to a point T and side PQ is produced to a point X. If ∠PRT = 136° and ∠RQX = 104°, then the complement of ∠P is: 

  1. AOption (a)

    30°

  2. BOption (b)

    50°

  3. COption (c)

    60°

  4. DOption (d)

    66°

View answer & explanation

Correct answer

Answer: (a)A.

30°

Why this answer is correct

Shortcut Trick

In any triangle, the sum of two exterior angles is equal to the interior angle at the third vertex plus 180°.

∠P + 180° = Ext ∠Q + Ext ∠R

∠P + 180° = 104° + 136° = 240°

∠P = 240° − 180° = 60°

Complement of ∠P = 90° − 60° = 30°

∴ The correct answer is 30°.

Alternate Method

Given:

Exterior angle at R, ∠PRT = 136°

Exterior angle at Q, ∠RQX = 104°

Formula Used:

  1. Linear Pair: Sum of angles on a straight line is 180°.
  2. Angle Sum Property: Sum of interior angles of a triangle is 180°.
  3. Complementary Angles: Two angles are complementary if their sum is 90°.

P
Q
R
X
T
136°
104°
P=?

CTET Paper 2 Maths & Science 3rd Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 792

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

If the complement of an angle x is equal to the supplement of angle 4x and the supplement of an angle y is 4 times its complement, then what is the value of (x + y) ?  

  1. AOption (a)

    80°

  2. BOption (b)

    90°

  3. COption (c)

    100°

  4. DOption (d)

    120°

View answer & explanation

Correct answer

Answer: (b)B.

90°

Why this answer is correct

Shortcut Trick

From the first condition: 90° − x = 180° − 4x → 3x = 90° → x = 30°

From the second condition: 180° − y = 4 × (90° − y) → 3y = 180° → y = 60°

Required sum = x + y = 30° + 60° = 90°

∴ The correct answer is 90°.

Alternate Method

Given:

Complement of an angle x = Supplement of angle 4x

Supplement of an angle y = 4 × Complement of y

Formula Used:

Complement of angle θ = 90° − θ

Supplement of angle θ = 180° − θ

y = 60°
x = 30°
Result: x + y = 90°

Calculations:

For finding the angle x:

⇒ 90° − x = 180° − 4x

⇒ 4x − x = 180° − 90°

⇒ 3x = 90°

⇒ x = 30°

For finding the angle y:

⇒ 180° − y = 4 × (90° − y)

⇒ 180° − y = 360° − 4y

⇒ 4y − y = 360° − 180°

⇒ 3y = 180°

⇒ y = 60°

Now, calculate the value of (x + y):

⇒ x + y = 30° + 60° = 90°

∴ The correct answer is 90°.

Additional Information

Complementary Angles

Two angles are complementary if their sum is exactly 90°. If one angle is θ, its complement is (90° − θ).

Supplementary Angles

Two angles are supplementary if their sum is exactly 180°. If one angle is θ, its supplement is (180° − θ).

Straight Angle & Complete Angle

A straight angle measures exactly 180° and forms a straight line, while a complete angle measures exactly 360° around a single central point.

CTET Paper 2 Maths & Science 3rd Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 793

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

In a quadrilateral ABCD, ∠C = 72° and ∠D = 80°. The bisectors of ∠A and ∠B meet at a point P inside the quadrilateral. What is the measure of ∠APB ? 

  1. AOption (a)

    70°

  2. BOption (b)

    76°

  3. COption (c)

    78°

  4. DOption (d)

    86°

View answer & explanation

Correct answer

Answer: (b)B.

76°

Why this answer is correct

Given : 

∠C = 72° and ∠D = 80°

Bisectors of ∠A and ∠B meet at a point P inside the quadrilateral.

Calculation : 

We know,

∠A  + ∠B + ∠C  + ∠D = 360°

⇒ ∠A  + ∠B + 72 + 80 = 360

⇒ ∠A  + ∠B + 152 = 360

⇒ ∠A  + ∠B = 360 - 152

⇒ ∠A  + ∠B = 208°

Now,

∠APB = 180 - ∠A/2 - ∠B/2

⇒ ∠APB = 180 - 1/2(∠A  + ∠B)

⇒ ∠APB = 180 - 1/2 × 208

⇒ ∠APB = 180 - 104

⇒ ∠APB = 76°

∴ The correct answer is 76°.

CTET Paper 2 Maths & Science 3rd Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 794

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

If x, y and z are the number of faces, edges and vertices respectively of a pentagonal pyramid, then what is the value of \(\left(\frac{x+y-z}{2}\right)^2+1\) ?

  1. AOption (a)

    22

  2. BOption (b)

    24

  3. COption (c)

    26

  4. DOption (d)

    28

View answer & explanation

Correct answer

Answer: (c)C.

26

Why this answer is correct

Calculation : 

Number of faces = x = 6

Number of edges = y = 10

Number of vertices = z = 6

Now, \(\left(\frac{x+y-z}{2}\right)^2+1\) = (16 - 6/2) + 1 

⇒ (5)2 + 1 = 26

∴ The correct answer is 26.

CTET Paper 2 Maths & Science 3rd Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 795

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

In which of the following cases, the construction of a quadrilateral ABCD is not possible ? 

  1. AOption (a)

    AB = 4.8 cm, BC =4.3 cm, CD = 3.6 cm, AD = 4.2 cm and AC = 6 cm 

  2. BOption (b)

    AB = 7 cm, BC = 8 cm, AD = 10 cm, ∠A = 120° and ∠B = 80° 

  3. COption (c)

    AB = 9 cm, BC = 7.6 cm, ∠A = 60°, ∠B = 120° and ∠D = 80°

  4. DOption (d)

    AB = 8 cm, BC = 10 cm, ∠A = 75°, ∠B = 150° and ∠C = 135°

View answer & explanation

Correct answer

Answer: (d)D.

AB = 8 cm, BC = 10 cm, ∠A = 75°, ∠B = 150° and ∠C = 135°

Why this answer is correct

Concept use:

A quadrilateral can be constructed given specific lengths and angles, but the set of conditions must meet certain rules to make it feasible.

If given the lengths of all four sides and one diagonal, a quadrilateral can be constructed if and only if the length of the diagonal is less than the sum of the lengths of the pair of non-adjacent sides.

If given the lengths of two sides and all three angles that are around them, a quadrilateral can be constructed if the sum of angles is less than 360°.

Calculations:

option 1.

The sums of each pair of non-adjacent sides are

AB + CD = 8.4 cm; BC + AD = 8.5 cm; and the given AC = 6 cm.

The given side lengths satisfy the triangle inequality (the sum of any two sides must be greater than the third side),

So we can construct a quadrilateral with these measurements.

Option 2.

The given side lengths also satisfy the triangle inequality. However, the given angles (∠A = 120° and ∠B = 80°) do not add up to 360°, which is necessary for a quadrilateral.

So we can construct a quadrilateral with these measurements.

Option 3.

Again, the side lengths satisfy the triangle inequality. However, the given angles (∠A = 60°, ∠B = 120°, and ∠C = 80°) do not add up to 360°.

So we can construct a quadrilateral with these measurements.

Option 4.

the sum of the three given angles A, B, and C is 360°, which is equal to 360°, not less.

Therefore, a quadrilateral cannot be constructed in this case as it violates the rule about the sum of the three angles being less than 360°.

So, the construction of a quadrilateral is not possible here.

Hence, Option 4 is Correct.

CTET Paper 2 Maths & Science 3rd Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 796

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

The area of a trapezium is 1.6 m2 and the distance between its parallel sides is 10 dm. If one of its parallel sides is longer than the other by 8 dm, then the longer parallel side is :

  1. AOption (a)

    140 cm

  2. BOption (b)

    180 cm

  3. COption (c)

    200 cm

  4. DOption (d)

    280 cm

View answer & explanation

Correct answer

Answer: (c)C.

200 cm

Why this answer is correct

Shortcut Trick

Convert units to cm: Area = 16000 cm2, Height = 100 cm, Difference = 80 cm.

Sum of parallel sides = (2 × Area) ÷ Height = (2 × 16000) ÷ 100 = 320 cm.

Longer side = (Sum + Difference) ÷ 2 = (320 + 80) ÷ 2 = 200 cm.

∴ The correct answer is 200 cm.

Alternate Method

Given:

Area of trapezium = 1.6 m2 = 1.6 × 10000 = 16000 cm2

Height (distance between sides) = 10 dm = 10 × 10 = 100 cm

Difference between parallel sides = 8 dm = 80 cm

Formula Used:

Area of Trapezium = 1/2 × (Sum of parallel sides) × Height

Calculations:

Let the shorter side be x cm. Then the longer side is (x + 80) cm.

⇒ 16000 = 1/2 × (x + x + 80) × 100

⇒ 16000 = 50 × (2x + 80)

⇒ 320 = 2x + 80

⇒ 2x = 240

⇒ x = 120 cm

⇒ Longer side = x + 80 = 120 + 80 = 200 cm

∴ The correct answer is 200 cm.

Additional Information

Area of a Trapezium

The area is calculated as the product of the average of the parallel sides and the vertical distance between them: Area = (a + b)/2 × h.

Unit Conversions

Always ensure uniform units: 1 m = 10 dm = 100 cm. For area, 1 m2 = 100 dm2 = 10,000 cm2.

Median of a Trapezium

The median (or midsegment) connects the midpoints of non-parallel sides and its length is equal to the average of the parallel sides: M = (a + b)/2.

CTET Paper 2 Maths & Science 3rd Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 797

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

The height of a solid right circular cylinder is 15 cm. If 4 times its curved surface area is equal to 6 times the sum of areas of its bases, then its volume (in cm3) is equal to :

  1. AOption (a)

    900 π

  2. BOption (b)

    1200 π

  3. COption (c)

    1350 π

  4. DOption (d)

    1500 π

View answer & explanation

Correct answer

Answer: (d)D.

1500 π

Why this answer is correct

Shortcut Trick

Given height (h) = 15 cm.

Condition: 4 × (2πrh) = 6 × (2πr2)

8πrh = 12πr2 ⇒ 2h = 3r ⇒ r = 2h/3

r = (2 × 15) / 3 = 10 cm.

Volume = πr2h = π × 102 × 15 = 1500π cm3.

∴ The correct answer is 1500π cm3.

Alternate Method

Given: Height (h) = 15 cm. Let radius be 'r'.

Formula Used: Curved Surface Area (CSA) = 2πrh; Area of Bases = 2 × πr2; Volume = πr2h.

⇒ 4 × (2πrh) = 6 × (2πr2)

⇒ 8πrh = 12πr2

⇒ 8 × 15 = 12 × r

⇒ 120 = 12r

⇒ r = 10 cm

⇒ Volume = π × (10)2 × 15

⇒ Volume = π × 100 × 15 = 1500π cm3

∴ The correct answer is 1500π cm3.

Additional Information

Total Surface Area of Cylinder

The total surface area includes the curved surface and the two circular bases: TSA = 2πrh + 2πr2 = 2πr(h + r).

Volume of a Hollow Cylinder

If R is the outer radius and r is the inner radius, Volume = π(R2 − r2)h.

Relationship between Dimensions

When the volume is constant, the height is inversely proportional to the square of the radius: h ∝ 1/r2.

CTET Paper 2 Maths & Science 3rd Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 798

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

The internal length of a rectangular water tank is 5 m and depth is 1.5 m. If it can hold 30000 litres of water, what is the internal width of the tank ? 

  1. AOption (a)

    3.5 m

  2. BOption (b)

    4 m

  3. COption (c)

    4.2 m

  4. DOption (d)

    4.5 m

View answer & explanation

Correct answer

Answer: (b)B.

4 m

Why this answer is correct

Given :

Length of rectangular park = 5 m

Depth of rectangular park = 1.5 m

Capacity of tank  = 30000 liters.

Formula used :

Voulme of cuboid = length × breadth × height

Calculation :

According to question,

Capacity = 30000 Liters = 30 m3

⇒ 30 = 5 × 1.5 × b

⇒ b = 60/15 = 4

∴ The correct answer is 4 m.

CTET Paper 2 Maths & Science 3rd Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 799

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

What is the mean of mode, median and range of the data given below ?

9, 11, 4, 7, 10, 23, 21, 29, 23, 33, 18

  1. AOption (a)

    20

  2. BOption (b)

    21

  3. COption (c)

    \(\frac{68}{3}\)

  4. DOption (d)

    \(\frac{70}{3}\)

View answer & explanation

Correct answer

Answer: (d)D.

\(\frac{70}{3}\)

Why this answer is correct

Shortcut Trick

Arrange the data in ascending order: 4, 7, 9, 10, 11, 18, 21, 23, 23, 29, 33.

Mode = Most frequent term = 23.

Median = Middle (6th) term = 18.

Range = Maximum − Minimum = 33 − 4 = 29.

Required Mean = (23 + 18 + 29) ÷ 3 = 70/3.

∴ The correct answer is 70/3.

Alternate Method

Given:

Data set: 9, 11, 4, 7, 10, 23, 21, 29, 23, 33, 18

Formula Used:

Mean = Sum of observations ÷ Total number of observations

Median (for odd n) = ((n + 1) ÷ 2)th observation

Range = Maximum value − Minimum value

Mode = Observation with the highest frequency

4

7

9

10

11

18

21

23

23

29

33

Mode

Median

Range = 33 − 4 = 29
Required Mean = (23 + 18 + 29) ÷ 3 = 70/3

Calculations:

⇒ Sorted data: 4, 7, 9, 10, 11, 18, 21, 23, 23, 29, 33

⇒ Number of terms (n) = 11

⇒ Median = ((11 + 1) ÷ 2)th term = 6th term = 18

⇒ The number 23 appears maximum times (2 times), so Mode = 23

⇒ Minimum value = 4 and Maximum value = 33

⇒ Range = 33 − 4 = 29

⇒ Required Mean = (Mode + Median + Range) ÷ 3

⇒ Required Mean = (23 + 18 + 29) ÷ 3 = 70 ÷ 3 = 70/3

∴ The correct answer is 70/3.

Additional Information

Mean

Mean (Average) is the sum of all observations divided by the total number of observations. Formula: Mean = Sum ÷ n.

Median

For a sorted data set, if the number of terms (n) is odd, Median = ((n+1) ÷ 2)th term. If n is even, Median is the average of (n ÷ 2)th and (n ÷ 2 + 1)th terms.

Mode

Mode is the value that appears most frequently in a data set. A set may have one mode, more than one mode, or no mode at all.

Range

Range is the difference between the highest and lowest values in the data set. It provides a quick measure of data spread.

CTET Paper 2 Maths & Science 3rd Feb 2023 (English-Hindi) (Previous Year Paper)·Mathematics and Science
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Question 800

Central Teacher Eligibility Test (CTET) 2023• Mathematics and Science• Mathematics and Science

Numbers 35, 36, 37, . . ., 64 are written on cards (one number on one card) and put in a box. A card is drawn at random from the box. What is the probability that the number on the card drawn is divisible by 3 or 5 ? 

  1. AOption (a)

    \(\frac{1}{2}\)

  2. BOption (b)

    \(\frac{7}{15}\)

  3. COption (c)

    \(\frac{1}{3}\)

  4. DOption (d)

    \(\frac{13}{30}\)

View answer & explanation

Correct answer

Answer: (b)B.

\(\frac{7}{15}\)

Why this answer is correct

Concept use:

Probability of an Event = Outcomes in Favour/ Total No of Outcomes

P(A ∪ B) = P(A) + P(B) - P(A∩B)

Calculations:

Number Divisible by 3 = 36, 39, 42, 45, 48, 51, 54, 57, 60, 63 

then P(A) = 10/30 where P(A) is the Probability of divisible by 3 

Number Divisible by 5 = 35, 40, 45, 50, 55, 60

then P(B) = 6/30 where P(B) is the Probability of divisible by 5

Number Divisible by both = 45, 60 

then P(A∩B) = 2/30 where P(A∩B) is the Probability of divisible by 5 and 3 both

P(A ∪ B) = P(A) + P(B) - P(A∩B) = 10/30 + 6/30  - 2/30 = 14/30 = 7/15

How should I prepare for Mathematics and Science in Central Teacher Eligibility Test (CTET)?

Solving previous year questions by topic helps identify recurring concepts, question patterns, and frequently asked sub-topics. Attempt each question, review the step-by-step explanation, and note down key formulas or facts for quick revision before the exam.