Given:
The speed of a train was increasing by 3 km/h after every one hour for up to 10 hours.
After 10 hrs it was increasing by 5 km/h.
The distance traveled in the first one hour was 40 km.
Concept used:
Distance = speed × time
Calculation:
For first 1 hour speed is 40 km/h.
The speed of a train was increasing by 3 km/h after every one hour .
So for the next nine hours speed will be 43,46,49,52,55,58,61,64,and 67
Total distance covered in 1st 10 hours = 43 + 46 + 49 + 52 + 55 + 58 + 61 + 64 + 67 = 535 km
So for the next 10 hours speed will be 72 ,77,82,87, 92,97,102,107,112,117
The total distance covered in next 10 hrs will be 72 + 77 + 82 + 87 + 92 + 97 + 102 + 107 + 112 + 117 = 945 km
So total distance covered in 20 hrs will be 945 + 535 = 1480 km
The total distance covered by the train in 20 hours is 1480 km
Alternate Method Given:
The speed of a train was increasing by 3 km/h after every hour for up to 10 hours.
After 10 hrs it was increasing by 5 km/h.
The distance traveled in the first hour was 40 km.
Concept used:
In an A.P series if the first term = a and the last term = l
The total number of terms = n,
Then, the sum of the series will be n / 2 (a + l)
Calculation:
The distance traveled in the first one hour was 40 km.
We can find that the series is in A.P
First term (a) = 40 and 10th term = 67
Number of terms = 10
So, sum of the series = 10 / 2 (40 + 67)
⇒ 5 × 107
⇒ 535
Again for 2nd case, it is also an A.P series
First term (a) = 72 and 10th term = 117
Number of terms = 10
So, sum of the series = 10 / 2 (72 + 117)
⇒ 5 × 189
⇒ 945
So total distance covered in 20 hrs will be 945 + 535 = 1480 km
The total distance covered by the train in 20 hours is 1480 km