Mistake Points
Please note that
When A + B are working then they will remove 40 units of water from the tank in 4 minutes. After that, B and C are working together and we have to find the time required to fill the tank.
Please note that when we close pipe A and open pipe C at that time, 40 units of the tank are empty.
When B + C work together then they fill -4 + 5 = 1 unit water in 1 minute.
So, to fill 40 units of tank, B + C have to work for 40 minutes.
So 40 is the correct answer.
Given:
A pipe can empty in 10 minutes
B pipe can empty in 15 minutes
C pipe can fill in 12 minutes
A and B opened for 4 minutes
Then only pipe A closed and c opened
- sign = For tank emptying pipes
- sign = For tank filling pipes
A and B are opened for 4 minutes:
Therefore, 60 - 4 × (6 + 4) = 60 - 40 = 20 ---(40units removed)
Then only pipe A is closed, and C is opened instantly with B:
Efficiency of B + C = - 4 + 5 = 1
Time required = 40/1 = 40 min.
∴ Time required to fill the tank completely is 40 minutes.
Alternate Method
Concept Used:
Efficiency = Total work / Total time taken
A and B pipes emptied the tank so their efficiency should be calculated as negative
on the other hand, C pipe is filling the tank, so its efficiency should be calculated as positive.
Calculation:
Let , total work is = LCM of 10,12 & 15
⇒ 60 unit
Efficiency of Pipe A = 60/10
⇒ 6 unit
Efficiency of Pipe B = 60/15
⇒ 4 unit
Efficiency of Pipe C 60/12
⇒ 5 unit
So in 4 minutes pipe A and B eliminated together (6 + 4) × 4 = 40 unit of water.
The remaining water, 60 - 40 = 20 units.
Now, only pipe A is closed, and C is opened instantly (with B)
B eliminated 4 units of water in 1 minute and C filled 5 units in 1 minute.
They are working together,
Both B and C together filled (5 - 4) = 1 unit of water in 1 minute.
They filled the remaining 60 - 20 = 40 units of water in 40 minutes.
∴ Time required to fill the tank completely is 40 minutes.
Additional Information Efficiency is inversely proportionate to the number of time to complete the work.