GIVEN:
P completes a work in 30 days and works on first day
Q completes a work in 15 days and works on Second day
R completes a work in 20 days and works on third day
After that again P works for one day then Q works for next day and R works for next to next day and so on.
CONCEPT:
First we calculate work completed by individual per day then we calculate work completed by single men in successive days
Calculation:
LCM of 30, 15, 20 = 60
Let the total work be 60 units
Efficiency of P = 60 / 30 = 2 units
Efficiency of Q = 60 / 15 = 4 units
Efficiency of R = 60 / 20 = 3 units
According to question
1st day P come on work 2nd day Q come on work and 3rd day R come on work
Work complete on 1st day = 2 units
Work complete on 2nd day = 4 units
Work complete on 3rd day = 3 units
So, total work completed in 3 days = (2 + 4 + 3) = 9 units
We can take this 3 days work as 1 cycle
∴ in 6 cycles work completed = 9 × 6 = 54 units
Remaining work = 60 units – 54 units = 6 units
(1 cycle = 3 days)
∴ 6 cycles = 6 × 3 = 18 days
19th day P come on work
Work done by P on 19th day = 2 units
Work left after 19 days = 60 – 56 = 4 units
Q work on 20th day
Efficiency of Q = 4 units
Q complete the remaining work on 20th day
Total time taken to complete the work = 20days