Shortcut Trick
In ΔOBC, OB = OC (radii of the circle), so ∠OCB = ∠OBC = 40°.
Angle at the center: ∠BOC = 180° − (40° + 40°) = 100°.
Angle at the circumference: ∠BAC = ∠BOC ÷ 2 = 100° ÷ 2 = 50°.
∴ The correct answer is 50°.
Alternate Method
Given:
∠OBC = 40°
OB is the radius of the circle with center O.
Formula Used:
- In an isosceles triangle, angles opposite to equal sides are equal.
- The angle subtended by an arc at the center of a circle is twice the angle subtended by it at any point on the remaining part of the circle.
Calculations:
In ΔOBC:
⇒ OB = OC (since both are radii of the same circle)
⇒ ∠OCB = ∠OBC = 40° (angles opposite to equal sides are equal)
We know that the sum of angles in a triangle is 180°:
⇒ ∠BOC + ∠OBC + ∠OCB = 180°
⇒ ∠BOC + 40° + 40° = 180°
⇒ ∠BOC + 80° = 180°
⇒ ∠BOC = 180° − 80° = 100°
By the circle theorem, the angle subtended by arc BC at the center O is twice the angle subtended at the circumference at A:
⇒ ∠BOC = 2 × ∠BAC
⇒ 100° = 2 × ∠BAC
⇒ ∠BAC = 100° ÷ 2
⇒ ∠BAC = 50°
Option Verification:
⇒ Option (1) 35°: Incorrect, as this would imply ∠BOC = 70°, which means ∠OBC + ∠OCB = 110°, making each 55° instead of the given 40°.
⇒ Option (2) 45°: Incorrect, as this would imply ∠BOC = 90°, which means ∠OBC + ∠OCB = 90°, making each 45° instead of the given 40°.
⇒ Option (3) 50°: Correct, as it perfectly satisfies ∠BOC = 100° and ∠OBC = ∠OCB = 40°.
⇒ Option (4) 65°: Incorrect, as this would imply ∠BOC = 130°, which means ∠OBC + ∠OCB = 50°, making each 25° instead of the given 40°.
∴ The correct answer is 50°.
Additional Information
Angle in a Semicircle
The angle subtended by a diameter at any point on the circumference of the circle is always a right angle (90°).
Angles in the Same Segment
Angles subtended by the same arc or chord at any points on the remaining part of the circle are equal to each other.
Cyclic Quadrilateral Property
The sum of the opposite angles of a cyclic quadrilateral is always 180°.