Shortcut Trick
The cyclicity of both 7 and 3 is 4.
For 795, remainder of 95 ÷ 4 is 3 → 73 ends in 3.
For 358, remainder of 58 ÷ 4 is 2 → 32 ends in 9.
Unit digit ⇒ 3 − 9 → (borrow 10) → 13 − 9 = 4.
∴ The correct answer is 4.
Alternate Method
Given expression: 795 − 358
To find the unit digit, we use the power cycle of the base numbers.
⇒ Cyclicity of 7: 71=7, 72=9, 73=3, 74=1 (repeats every 4 powers).
⇒ Divide the power 95 by 4: 95 = (4 × 23) + 3. Remainder = 3.
⇒ Unit digit of 795 = Unit digit of 73 = 3.
⇒ Cyclicity of 3: 31=3, 32=9, 33=7, 34=1 (repeats every 4 powers).
⇒ Divide the power 58 by 4: 58 = (4 × 14) + 2. Remainder = 2.
⇒ Unit digit of 358 = Unit digit of 32 = 9.
⇒ Required unit digit = (Unit digit of 795) − (Unit digit of 358)
⇒ Unit digit = 3 − 9.
⇒ Since 3 is less than 9, we take a carry from the tens place: 13 − 9 = 4.
∴ The correct answer is 4.
Additional Information
Cyclicity of Digits
The unit digit of any number raised to a power repeats in a specific cycle. Digits 2, 3, 7, and 8 have a cyclicity of 4.
Special Cases (Cyclicity 1 and 2)
Digits 0, 1, 5, and 6 have a cyclicity of 1 (always end in themselves). Digits 4 and 9 have a cyclicity of 2.
Negative Unit Digit Rule
If the calculation of unit digits results in a negative value (e.g., a − b where a < b), simply add 10 to the result to find the correct unit digit.