Rs. 720 was divided among A, B, C, D, E. The sum received by them was in ascending order and in arithmetic progression. E received Rs. 40 more than A. How much did B receive?
- AOption (a)
Rs. 134
- BOption (b)
Rs. 154
- COption (c)
Rs. 144
- DOption (d)
Rs. 124
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Correct answer
Rs. 134
Why this answer is correct
Shortcut Trick
In an Arithmetic Progression with 5 terms, the Average is always the middle term (C).
Average = 720 ÷ 5 = ₹144. So, C = ₹144.
Given E − A = 4d = 40, so common difference d = 10.
B = C − d = 144 − 10 = ₹134.
∴ The correct answer is ₹134.
Alternate Method
Given: Total sum = ₹720, Number of people = 5 (A, B, C, D, E), Difference E − A = ₹40.
Formula Used: Sum of AP = (n/2) × [2a + (n−1)d]
⇒ Let the amounts be a, a+d, a+2d, a+3d, a+4d.
⇒ E − A = 40 → (a + 4d) − a = 40 ⇒ 4d = 40 ⇒ d = 10.
⇒ Sum = 5a + 10d = 720.
⇒ 5a + 10(10) = 720 ⇒ 5a + 100 = 720.
⇒ 5a = 620 ⇒ a = 124.
⇒ B = a + d = 124 + 10 = 134.
∴ The correct answer is ₹134.
Additional Information
Arithmetic Progression Properties
For an odd number of terms in AP, the middle term is equal to the Average of the series (Sum ÷ n).
General Term of AP
The nth term is given by Tn = a + (n − 1)d, where 'a' is the first term and 'd' is the common difference.
Sum of n terms
Sn = (n/2) × [first term + last term]. In this case, 720 = (5/2) × [A + E].
























