Previous Year Paper

UGC NET Paper 2: Environmental Science 29th Sep 2020 Shift 2 (Previous Year Paper)

Held in 2020

100 questions120 minutes
With answers
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Question 1

In an objective type examination, hundred questions are given. One mark is given for each correct answer while 0.2 marks are deducted for each incorrect answer. The number of marks scored by students appearing in the examination is an example of :

  1. AOption (a)

    Nominal variable

  2. BOption (b)

    Ordinal variable

  3. COption (c)

    Discrete variable

  4. DOption (d)

    Continuous variable

View answer & explanation

Correct answer

Answer: (c)C.

Discrete variable

Why this answer is correct

The correct answer is the Discrete variable.

Key Points

Variables: Variables are measurable characteristics that can be numerically expressed in some terms of some units. These are quantities that are capable of being measured by quantitative methods directly. For example, the height in inches, weight in kg, marks in examination, etc.

  1. ​​Discrete Variables (Discontinuous/meristic): These are the quantities that can be measured in whole integral values. It does not take a fractional value. For example, the number of marks in an examination.
  2. Continuous Variables: These are the quantities that can take any value in a specified range. Thus it can take integral and fractional values both. For example. Heights, weights, etc.
  3. Nominal: Data that can't be ordered or have two or more categories. For example, the colour of hair, marital status (married, separated, divorced), nature of the disaster (fire, accident, theft), etc.
  4. Ordinal: Data that can be ordered in terms of their characteristics. For example, tidiness (messy, fairly, very neat, etc).

Therefore, the number of marks scored by students appearing in the examination is an example of discrete variables.

Question 2

According to Solid Waste Management Rules 2016, a landfill site should be at a distance of how many meters away from a pond?

  1. AOption (a)

    200 meters

  2. BOption (b)

    150 meters

  3. COption (c)

    100 meters

  4. DOption (d)

    50 meters

View answer & explanation

Correct answer

Answer: (a)A.

200 meters

Why this answer is correct

The correct answer is 200 meters.

Key Points

  • Solid Waste Management Rules 2016 specifies the criteria for site selection of landfills as follows:
Sites/LocationsDistance of landfill
River100 meters
Pond200 meters
Highways, Habitations, Public Parks and water supply wells200 meters
Airports or Airbase10-20 km

 

 

 

 

 

Therefore, according to Solid Waste Management Rules 2016, a landfill site should be 200 meters away from a pond.

Question 3

The Brundtland Commission Report was entitled

  1. AOption (a)

    Limits to Growth

  2. BOption (b)

    Our Common Future

  3. COption (c)

    Sustainable Development

  4. DOption (d)

    Tragedy of Commons

View answer & explanation

Correct answer

Answer: (b)B.

Our Common Future

Why this answer is correct

The correct answer is Our Common Future.

Key Points

  • The Brundtland Commission was created by the United Nations to suggest measures to protect the human environment and natural resources and prevent the deterioration of economic and social development.
  • It is formally called World Commission on Environment and Development.
  • Its report was titled as "Our Common Future".
  • It was released in 1987.
  • The Brundtland Commission’s characterization of ‘sustainable development’ is the development that meets the needs of the present without compromising the ability of future generations to meet their own needs.
  • The prominence given to ‘needs’ reflects a concern to eradicate poverty and meet basic human needs, broadly understood.

Therefore, the Brundtland Commission Report was entitled as Our Common Future.

Question 4

Given below are two statements :

Statement I :

In clear water, the reflectance is very high in the visible region of the electromagnetic spectrum

Statement II :

Pure water strongly absorbs radiation from the mid-infrared spectral region

In light of the above statements, choose the correct answer from the options given below

  1. AOption (a)

    Both Statement I and Statement II are true

  2. BOption (b)

    Both Statement I and Statement II are false

  3. COption (c)

    Statement I is correct but Statement II is false

  4. DOption (d)

    Statement I is incorrect but Statement II is true

View answer & explanation

Correct answer

Answer: (d)D.

Statement I is incorrect but Statement II is true

Why this answer is correct

The correct answer is 'Statement I is incorrect but Statement II is true'.

Key Points

Statement I: In clear water, the reflectance is very high in the visible region of the electromagnetic spectrum is incorrect because,-

  • Reflectance refers to the fraction of incident electromagnetic power that is reflected at an interface.
  • In clear water, the majority of light in the visible region is transmitted rather than reflected.
  • Visible light (wavelengths roughly between 400-700 nm) penetrates and is absorbed or scattered within water, leading to low reflectance.
  • Reflectance is typically higher in the ultraviolet (UV) or near-infrared (NIR) regions rather than the visible region in aquatic environments.
  • Thus, the statement that reflectance is very high in the visible region for clear water is not accurate.

Statement II: Pure water strongly absorbs radiation from the mid-infrared spectral region is true because,-

  • The mid-infrared (mid-IR) region spans wavelengths roughly between 2.5 to 25 micrometers (μm).
  • Pure water has strong absorption bands in the mid-IR region, particularly around 3 micrometers (O-H stretch) and 6 micrometers (H-O-H bending).
  • This strong absorption is due to the vibrational modes of water molecules which are active in the mid-IR range.
  • As a result, pure water is an effective absorber of mid-IR radiation, which is why this statement is true.

Additional Information

  • Water's absorption characteristics change across the electromagnetic spectrum, making it transparent to certain wavelengths (like visible light) and absorptive to others (like mid-IR).
  • Reflectance and absorption properties of water are critical in various fields such as remote sensing, environmental monitoring, and optical instrument design.
  • The study of spectral properties (how substances absorb, reflect, and emit light) helps in understanding the composition and physical properties of water bodies.

Question 5

Consider the following statements regarding the solubility of gases in water

A. The concentration of a dissolved gas in water is proportional to its partial pressure in the air

B. The solubility of a gas in water remains unaffected as other dissolved material in it increases

C. The solubility of a gas increases as temperature increases

D. The solubility of gases in water is governed by Henry's law

Choose the correct answer from the options given below :

  1. AOption (a)

    A and B only

  2. BOption (b)

    B and C only

  3. COption (c)

    C and D only

  4. DOption (d)

    A and D only

View answer & explanation

Correct answer

Answer: (d)D.

A and D only

Why this answer is correct

The correct answer is A and D only.

Key Points

Henry's law is a gas law that states that the amount of gas that is dissolved in a liquid is directly proportional to the partial pressure of that gas above the liquid when the temperature is kept constant. 

P = kH.C

  • 'P' denotes the partial pressure of the gas in the atmosphere above the liquid.
  • 'C' denotes the concentration of the dissolved gas.
  • 'kH' is Henry's law constant of the gas.

The value of Henry's law constant of a gas is dependent on the following factors:

  1. The nature of the gas.
  2. The nature of the solvent.
  3. Temperature and pressure.

The solubility of gases varies inversely with respect to temperature. As the temperature increases, the solubility of the gases in liquids decreases.

The solubility of any substance in any medium is dependent on the amount of solute and solvent involved.

Therefore, regarding the solubility of gases in water only statements A and D are correct.

Question 6

If the mean of two groups of 'm' and 'n' observations are 40 and 60 respectively, and the combined mean of two groups is 48, the ratio m ∶ n is

  1. AOption (a)

    2 ∶ 3

  2. BOption (b)

    3 ∶ 2

  3. COption (c)

    1 ∶ 2

  4. DOption (d)

    2 ∶ 1

View answer & explanation

Correct answer

Answer: (b)B.

3 ∶ 2

Why this answer is correct

The correct answer is 3 ∶ 2.

Key Points

Given:

  • ​Combined mean = 48
  • Mean of the first group = 40
  • Number of items in the first set = m
  • Mean of the second group = 60
  • Number of items in the second set = n

Since we know that, 

x12ˉ=n1x1ˉ + n2x2ˉn1 + n2\bar{x_{12}} = \frac{n_1\bar{x_1}\ +\ n_2\bar{x_2}}{n_1\ +\ n_2}

Where, 

x12‾\overline{x_{12}}  = Combined mean of two groups

n1 = Number of items in first group

x1‾\overline {x{_1}}  = Arthmetic mean of first group

n2 = Number of items in second group

x2‾\overline {x{_2}} =  Arthmetic mean of second group

Therefore, 

x12‾=m × 40 + n × 60m+n\overline {x_{12}} = {m\ \times \ 40 \ + \ n\ \times \ 60 \over m+n}

 48=m × 40 + n × 60m+n48 = {m\ \times \ 40 \ + \ n\ \times \ 60 \over m+n}

48(m+n)=m40+n6048(m+n) = m40 + n60

48m−40m=60n−48n48m - 40m = {60n - 48n }

8m=12n8m = {12n}             

mn=32{m\over n} = {3\over 2}  

Therefore, the ratio m ∶ n is 3 : 2

Question 7

Which of the following does NOT fall under the major goals of the National Mission for Green India?

  1. AOption (a)

    To increase forest/tree cover to the extent of five million hectares.

  2. BOption (b)

    To improve/enhance eco-system services like carbon sequestration and storage, hydrological services and biodiversity.

  3. COption (c)

    To increase forest-based livelihood income of about three million households.

  4. DOption (d)

    To study the traditional knowledge systems for community participation in adaptation and mitigation strategies.

View answer & explanation

Correct answer

Answer: (d)D.

To study the traditional knowledge systems for community participation in adaptation and mitigation strategies.

Why this answer is correct

The correct answer is To study the traditional knowledge systems for community participation in adaptation and mitigation strategies.

Key Points

  • National Mission for Green India is one of the 8 missions of the National Action Plan for Climate Change launched in 2008.
  • The objectives/goals of the Green India Mission are:
  • Increased forest/tree cover on 5 million hectares of forest/non-forest lands and improved quality of forest cover on another 5 million hectares (a total of 10 million hectares).
  • Improved ecosystem services including biodiversity, hydrological services and carbon sequestration as a result of the treatment of 10 million hectares.
  • Increased forest-based livelihood income of about 3 million households living in and around the forests.
  • Enhanced annual CO2 sequestration by 50 to 60 million tonnes in the year 2020.

Therefore, to study the traditional knowledge systems for community participation in adaptation and mitigation strategies is not the part of objectives/goals of the National Mission for Green India.

Additional Information

  • To study the traditional knowledge systems for community participation in adaptation and mitigation strategies is one of the objectives of the National Mission for Sustainable Himalayan Ecosystem.
  • The 8 missions under the National Action Plan for Climate Change are:​
  1. National Solar Mission
  2. National Mission for Enhanced Energy Efficiency
  3. National Mission on Sustainable Habitat
  4. National Water Mission
  5. National Mission for Sustaining Himalayan Ecosystem
  6. Green India Mission
  7. National Mission for Sustainable Agriculture
  8. National Mission on Strategic Knowledge for Climate Change

Question 8

If ∑x = 230, ∑x2 = 6500 and the numbers of observations N = 10, the value of standard deviation is

  1. AOption (a)

    9

  2. BOption (b)

    10

  3. COption (c)

    1 1

  4. DOption (d)

    12

View answer & explanation

Correct answer

Answer: (c)C.

1 1

Why this answer is correct

Concept-

Standard deviation-

  • Standard Deviation is a measure that shows how much variation (such as spread, dispersion, spread,) from the mean exists.
  • The standard deviation indicates a “typical” deviation from the mean. It is a popular measure of variability because it returns to the original units of measure of the data set.
  • Like the variance, if the data points are close to the mean, there is a small variation whereas the data points are highly spread out from the mean, then it has a high variance.
  • Standard deviation calculates the extent to which the values differ from the average. Standard Deviation, the most widely used measure of dispersion, is based on all values.
  • Therefore a change in even one value affects the value of the standard deviation. It is independent of origin but not of scale. It is also useful in certain advanced statistical problems.
  • The formula for standard deviation = σ = ∑xi2N−(∑xiN)2\sqrt {\frac{{\sum {x_i^2} }}{N} - {{\left( {\frac{{\sum {{x_i}} }}{N}} \right)}^2}}

Given data and Calculation-

If ∑x = 230, ∑x2 = 6500

Numbers of observations, N = 10

σ = ∑xi2N−(∑xiN)2\sqrt {\frac{{\sum {x_i^2} }}{N} - {{\left( {\frac{{\sum {{x_i}} }}{N}} \right)}^2}}

 

σ = 650010−(23010)2\sqrt {\frac{{6500}}{{10}} - {{\left( {\frac{{230}}{{10}}} \right)}^2}}  = 11

Question 9

Following are the examples of Persistent Organic Pollutants (POPs)

A. Dioxin

B. Volatile Organic Compounds (VOCs)

C. Poly Chlorinated Biphenyl (PCBs)

D. Furans

E. Organochlorine pesticides

Choose the correct answer from the options given below :

  1. AOption (a)

    A, B and C only

  2. BOption (b)

    A, B, C and D only

  3. COption (c)

    A, D, and E only

  4. DOption (d)

    A, C, D and E only

View answer & explanation

Correct answer

Answer: (d)D.

A, C, D and E only

Why this answer is correct

Concept:

Persistent organic pollutants (POPs):

  • Persistent Organic Pollutants (POPs) are organic chemical substances, that is, they are carbon-based.
  • They possess a particular combination of physical and chemical properties such that, once released into the environment, they:
  • Remain intact for exceptionally long periods of time (many years);
  • Become widely distributed throughout the environment as a result of natural processes involving soil, water, and, most notably, air;
  • Accumulate in living organisms including humans, and are found at higher concentrations at higher levels in the food chain; and
  • Are toxic to both humans and wildlife.
  • Persistent organic pollutants (POPs) are chemicals of global concern due to their potential for long-range transport, persistence in the environment, ability to bio-magnify and bio-accumulate in ecosystems, as well as their significant negative effects on human health and the environment.
  • The most commonly encountered POPs are Furans, organochlorine pesticides, such as DDT, industrial chemicals, polychlorinated biphenyls (PCB) as well as unintentional by-products of many industrial processes, especially polychlorinated dibenzo-p-dioxins (PCDD) and dibenzofurans (PCDF), commonly known as dioxins.

Question 10

Which of the following is a correct statement regarding range as a measure of dispersion?

  1. AOption (a)

    The range is independent of the change of origin and scale

  2. BOption (b)

    The range is independent of the change of origin but not of the scale

  3. COption (c)

    The range is independent of the change of scale but not of the origin

  4. DOption (d)

    The range is not affected by fluctuations of sampling

View answer & explanation

Correct answer

Answer: (b)B.

The range is independent of the change of origin but not of the scale

Why this answer is correct

The correct answer is The range is independent of the change of origin but not of the scale.

Key Points

Dispersion is the measure of the variation of the items. In other words, the measurement of the scatteredness of the mass of figures in a series about an average is called a measure of variation or dispersion. The following are the methods of studying variation:

  1. The range
  2. The quartile deviation
  3. The Mean deviation
  4. The standard deviation
  5. Variance.

Range is defined as the difference between the value of the smallest item and the value of the largest item in the distribution.

Range = L - S 

Where,  L = largest item

             S = smallest item.

  • The range is independent of the change in origin. This implies that the value of the range remains constant if, in a series, a constant is added (or subtracted) to all observations.
  • However, the range is affected by the change of scale. This implies that if all observations are multiplied or divided by a constant, then the value of the range will be affected.

Therefore, the correct statement is that the range is independent of the change of origin but not of the scale.

Question 11

Under the GRIHA Rating Norms, a building securing 57 points on a 100 point scale, will be assigned which of the following star ratings?

  1. AOption (a)

    Two star

  2. BOption (b)

    Three star

  3. COption (c)

    Four star

  4. DOption (d)

    Five star

View answer & explanation

Correct answer

Answer: (b)B.

Three star

Why this answer is correct

The correct answer is Three star.

Key Points

  • GRIHA means Green Rating for Integrated Habitat Assessment.
  • GRIHA is a rating tool that helps people assess the performance of their building against certain nationally acceptable benchmarks.
  • It evaluates the environmental performance of a building holistically over its entire life cycle, thereby providing a definitive standard for what constitutes a 'green building'.
  • It consists of 34 criteria categorized under 4 categories.
  • Different levels of certifications (1 to 5 stars) are given based on the points earned.
Points earnedRating (Stars)
25 - 401
41 - 552
56 - 703
71 - 854
86 - 1005

 

 

 

 

 

Therefore, if a building has scored 57 points on a 100-point scale, it will be assigned 3 stars.

Additional Information

  • It was amended in 2019.
  • Now it consists of 30 criteria categorized under 11 sections.
  • The new rating is done in the following manner:
Points earnedRating (Stars)
50 -601
61 - 702
71 - 803
81 - 904
91 - 1005

Question 12

Consider the following statement regarding ex-situ bioremediation of contaminated soil :

A. Bioremediation techniques can be applied at or very near the site of contamination.

B. Biopiles and windrow composting are the most dominant ex-situ bioremediation techniques for treating contaminated soils.

C. Biopiles can be formed with larger volumes of soil than windrows.

D. Both biopiles and windrow composting are anaerobic processes.

Choose the correct answer from the options given below :

  1. AOption (a)

    A and B only

  2. BOption (b)

    B and D only

  3. COption (c)

    A, B and C only

  4. DOption (d)

    A, B, and D only

View answer & explanation

Correct answer

Answer: (b)B.

B and D only

Why this answer is correct

Correct Answer: None of the given options is fully correct; only statements B and C are correct.

Ex-situ bioremediation is a soil treatment method where contaminated materials are removed from the site and treated elsewhere under controlled conditions. Common techniques include biopiles and windrow composting, which are widely used for hydrocarbon and organic contaminant degradation using aerobic microbes.

Key Points:

  • Statement A – Incorrect:
  • This statement refers to in-situ bioremediation, which occurs at or near the site of contamination without excavation.
  • Ex-situ bioremediation involves removing contaminated material for off-site treatment or treatment in engineered systems nearby.
  • Statement B – Correct:
  • Biopiles and windrow composting are dominant ex-situ bioremediation techniques for treating hydrocarbon-contaminated soils.
  • These systems optimize conditions for microbial degradation of contaminants.
  • Statement C – Correct:
  • Biopiles can be constructed to treat larger volumes of soil compared to windrow composting, which is less scalable.
  • They use controlled aeration and moisture to enhance microbial activity.
  • Statement D – Incorrect:
  • Both biopiles and windrow composting are primarily aerobic processes, relying on oxygen to support microbial degradation.
  • Anaerobic conditions can inhibit their efficiency unless specially designed for such conditions.

Additional Information:

  • In-situ methods: bioventing, biosparging, phytoremediation.
  • Ex-situ methods: landfarming, biopiles, windrow composting, slurry-phase treatment.
  • Aerobic bacteria are more efficient at degrading petroleum hydrocarbons than anaerobic bacteria.

Question 13

Diesel Exhaust Particles (DEP), known to manifest asthma-like features, are responsible for

A. Chronic airway inflammation

B. Mucus hypersecretion

C. Airway expansion

D. Marked infiltration of eosinophils

E. Airway hyperresponsiveness

Choose the correct answer from the options given below

  1. AOption (a)

    A, C, D and E only

  2. BOption (b)

    A, B, C and D only

  3. COption (c)

    A, B, D, and E only

  4. DOption (d)

    B, C, D and E only

View answer & explanation

Correct answer

Answer: (c)C.

A, B, D, and E only

Why this answer is correct

The correct answer is A, B, D, and E only.

Key Points

  • Diesel exhaust particles are produced when an engine burns diesel fuel.
  • Because high compression ratios create high temperatures, NOx emissions can be relatively high.
  • In addition, diesel engine exhaust has been labelled a probable human carcinogenic containing over 40 cancer-related substances including benzene, arsenic and formaldehyde.
  • Exposure to diesel exhaust can have immediate health effects.
  • It causes inflammation in the lungs which may aggravate chronic respiratory symptoms and increase the frequency or intensity of asthma attacks.
  • NOx emitted can damage lung tissue causing chronic airway inflammation, hyper-secretion of mucus and airway constriction.
  • Studies reveal that diesel exhaust particles enhance eosinophil adhesion to nasal epithelial cells and cause degranulation and airway hyper-responsiveness.

 Therefore, only A, B, D, and E are correct.

Question 14

Consider the following statements regarding the phytoremediation of metal contaminated sites :

A. Natural abilities of certain plant species are utilized to remove or stabilize toxic metals.

B. Certain species termed hyperaccumulators can adsorb 50-100 times larger amounts of metals compared to most ordinary plants.

C. The best candidates for removal by phytoremediation are arsenic and cadmium

D. The harvested hyperaccumulating plants can be recycled in agriculture

Choose the correct answer from the options given below

  1. AOption (a)

    A only

  2. BOption (b)

    A and B only

  3. COption (c)

    A, B, and C only

  4. DOption (d)

    A, C, and D only

View answer & explanation

Correct answer

Answer: (b)B.

A and B only

Why this answer is correct

The correct answer is A and B only.

Key Points

  • Phytoremediation involves the use of plants to remove and stabilize toxic substances from the environment.
  • It takes advantage of the unique, selective and naturally occurring uptake capabilities of plant root systems, together with the translocation, bioaccumulation and pollutant storage/degradation abilities of the entire plant body.
  • Compared to typical plants, hyperaccumulators accumulate 50 - 1000 fold higher heavy metals in their shoots than non-accumulators. Furthermore, they have remarkable effectiveness in binding or generating toxic metals into various chemical compositions, resulting in a decreased concentration of those toxic metals in the free ionic form.
  • The phytoextraction technique can remove trace metals such as chromium, cadmium, copper, cobalt, silver, zinc, nickel, molybdenum, lead and mercury.
  • Phytovolatilization has been proven effective to remove toxic metals like selenium and mercury.
  • Toxic metals such as cadmium, nickel, and chromium can be easily removed using rhizofiltration processes.
  • Phytoremediation of arsenic-contaminated areas requires the development of new plant varieties with enhanced uptake and accumulation of this metalloid in order to remove as much arsenic as possible from the environment.
  • Although, a fern - Pteris vittata also known as the Chinese brake fern, holds promise for reducing both the time and cost associated with arsenic cleanup but arsenic can be best removed through traditional conventional methods.
  • The harvested hyperaccumulating plants cannot be recycled in agriculture. It is required to safely dispose-off hyperaccumulators. The disposal technologies include incineration, composting, burial methods etc.

Question 15

Given below are two statements :

Statement I :

Many bacteria carry plasmids, which are much smaller pieces of DNA, also circular, and self- replicating.

Statement II :

Plasmids are vitally important in the context of the environmental biotechnology in that they frequently carry the genes for degradative pathways.

In light of the above statements, choose the most appropriate answer from the options given below

  1. AOption (a)

    Both Statement I and Statement II are correct

  2. BOption (b)

    Both Statement I and Statement II are incorrect

  3. COption (c)

    Statement I is correct but Statement II is incorrect

  4. DOption (d)

    Statement I is incorrect but Statement II is correct

View answer & explanation

Correct answer

Answer: (a)A.

Both Statement I and Statement II are correct

Why this answer is correct

The correct answer is Both Statement I and Statement II are correct.

Key Points

  • A plasmid is a small, circular, double-stranded DNA molecule that is distinct from a cell's chromosomal DNA.
  • Plasmids naturally exist in bacterial cells, and they also occur in some eukaryotes.
  • Plasmid genes frequently confer genetic advantages to bacteria, such as antibiotic resistance.
  • Plasmids are used as tools for gene cloning, transfer, and manipulation.
  • They are used experimentally for these purposes and are called vectors.
  • These are critical in the context of environmental biotechnology because they frequently contain genes for degradative pathways.
  • Many of these plasmids can move between bacteria where they replicate, allowing the metabolic capability they carry to be transferred.
  • Bacteria are extremely promiscuous when it comes to sharing their DNA.
  • Bacteria that live in a contaminated environment frequently develop additional degradative abilities.
  • The source of that genetic information new to the organism, whether it is from internal DNA modification, transfer from other microbes, or free DNA in the environment, is a source of heated debate among microbiologists.

 Therefore, both Statement I and Statement II are correct.

Question 16

Consider the following statements regarding reactions in moderately acidic soils :

A. Base saturation is higher than that in the strongly acidic soils.

B. Free aluminium ions are abundant in soil solutions.

C. Aluminium hydroxy ions act as exchangeable cations.

D. 'Small amounts of readily exchangeable hydrogen contributes to soil acidity

Choose the correct answer from the options given below

  1. AOption (a)

    A and B only

  2. BOption (b)

    A, B and C only

  3. COption (c)

    A, C, and D only

  4. DOption (d)

    B, C, and D only

View answer & explanation

Correct answer

Answer: (c)C.

A, C, and D only

Why this answer is correct

The correct answer is A, C, and D only.

Key Points

  • Base saturation refers to the percentage of cation exchange capacity occupied by a base cation. Base saturation is closely related to pH. To be more precise, base saturation is directly proportional to pH. It increases with an increase in pH. Moderately acidic soil has higher pH in comparison to strongly acidic soil. Therefore, the base saturation of moderately acidic soil is greater than strongly acidic soil.
  • Free aluminium ions are the acidic cations present in the soil that lower the pH of the soil. Moderately acidic soil has a lower concentration of Al+3 in comparison to strongly acidic soils. Therefore, the abundance of Al+3 is less in moderately acidic soil.
  • Under moderately acidic soil, the percentage of base saturation and pH values are somewhat higher. At such higher pH values, aluminium exists as aluminium hydroxy ions which act as exchangeable ions. On hydrolysis, aluminium hydroxy ios liberate H+ in soil solution.
  • Exchangeable acidity refers to hydrogen and aluminium ions retained on the exchanged complex of the soil, that is on the surface of the soil colloids.

 Therefore, only A, C, and D are correct.

Question 17

Given below are two statements.

Statement I :

Cyclonic wind flow in the northern hemisphere is counter-clockwise.

Statement II :

If you stand with your back to the wind in the northern hemisphere, low pressure will be to your left and high pressure will be to your right.

In light of the above statements, choose the most appropriate answer from the options given below

  1. AOption (a)

    Both Statement I and Statement II are correct

  2. BOption (b)

    Both Statement I and Statement II are incorrect

  3. COption (c)

    Statement I is correct but Statement II is incorrect

  4. DOption (d)

    Statement I is incorrect but Statement II is correct

View answer & explanation

Correct answer

Answer: (a)A.

Both Statement I and Statement II are correct

Why this answer is correct

The correct answer is Both Statement I and Statement II are correct.

Key Points

  • In some atmospheric conditions, the radius of the rotation becomes so small that the centrifugal force becomes quite strong in comparison with the Coriolis force.
  • This is particularly where the Coriolis force is quite small, to begin with.
  • In this case, the pressure gradient force is nearly balanced by the centrifugal force alone.
  • When this occurs, the wind is said to be cyclonic.
  • In other words, cyclonic wind exists when the pressure gradient force is balanced by the centrifugal force.
  • Air spirals in towards the centre in a counter-clockwise pattern in the northern hemisphere and out of the top in opposite direction.
  • They blow clockwise in the southern hemisphere.
  • This can be explained because of the Coriolis effect.
  • Due to the rotation of the earth, winds do not move perpendicular to the pressure belt. They are rather deflected from their original path.
  • In the northern hemisphere, they get deflected to the right of their path (counter-clockwise) and in the southern hemisphere to the left of their path. It is called Ferrel's law.
  • Buys Ballot's law states that in the northern hemisphere if you stand with your back to the wind, low pressure will be found to your left and high pressure to your right. In the southern hemisphere, the situation is reversed.

Therefore, both Statement I and Statement II are correct.

Question 18

What is the correct increasing order of following rocks by percent volume in the earth's crust?

A. Igneous rocks

B. Sedimentary rocks.

C. Metamorphic rocks

Choose the correct answer from the options given below :

  1. AOption (a)

    A, B, C

  2. BOption (b)

    C, B, A

  3. COption (c)

    A, C, B

  4. DOption (d)

    B, C, A

View answer & explanation

Correct answer

Answer: (d)D.

B, C, A

Why this answer is correct

The correct answer is B, C, A.

Key Points

  • According to Clarke and Washington, igneous and metamorphic rocks comprise 95% volume of the earth's crust.
  • Sedimentary rocks comprise just 5% volume.
  • About 65% of the earth's crust by volume consists of igneous rocks.
  • Of these, 66% are basalt and gabbro, 16% are granite and 17% grandiorite and diorite. Only 0.6% are syenite and 0.3% are ultramafic.

Therefore, the correct increasing order of rocks by percent volume in the earth's crust is Sedimentary rocks < Metamorphic rocks <  Igneous rocks.

Question 19

Consider the following statements regarding reactions of pesticides in soils :

A. They may vaporize into the atmosphere without any chemical change.

B. They do not move downward through the soil in solution form.

C. They are resistant to microbial decay.

D. They may be absorbed by plants.

Choose the most appropriate answer from the options given below.

  1. AOption (a)

    A and D only

  2. BOption (b)

    A, B, and D only

  3. COption (c)

    A, C, and D only

  4. DOption (d)

    A and C only

View answer & explanation

Correct answer

Answer: (a)A.

A and D only

Why this answer is correct

The correct answer is A and D only.

Key Points

Characteristics of prsticides:

  • Pesticides are the chemical compounds that are used to control various pests and disease-spreading vectors like mosquitoes, ticks and household pests such as rats and cockroaches.
  • Soil is one of the final destinations of pesticides after application.
  • While utilizing the pesticides, the residues can remain in the environment for a long period and can be dispersed over a long distance.
  • While spraying these chemical pesticides, a series of reactions can undergo; plants can take up pesticides through leaves and roots, the atmosphere can take up pesticides as vapors carried off as drift, pesticides can get ingested by insects, worms and microorganisms.
  • The pesticides may be sorbed the particles or be leached and/or carried on the surface by the rains reaching subterranean waters and rivers.
  • Environmental degradation of pesticides involves biotic transformation processes facilitated by microorganisms or plants and by abiotic processes such as chemical and photochemical reactions.
  • Microorganisms present in the soil, chemical reactions and sunlight play a key role in the degradation of pesticides.
  • When exposed to air or evaporate, pesticides may change into a vapor by a process called volatility.
  • Once a pesticide evaporates, it is carried for miles simultaneously with the dust particles in the air.

 Therefore, only statements A and D are correct.

Question 20

Consider the following regarding the incineration process of solid waste.

A. It is an oxidation process.

B. The two major combustible chemical elements are carbon and hydrogen.

C. Cellulose in the biowaste is transformed into organic acids.

D. Excess source of air is not necessary.

Choose the correct answer from the options given below

  1. AOption (a)

    A and C only

  2. BOption (b)

    B and C only

  3. COption (c)

    A and B only

  4. DOption (d)

    B and D only

View answer & explanation

Correct answer

Answer: (c)C.

A and B only

Why this answer is correct

Concept:

Incineration:

  • Incineration can be defined as the oxidation of waste materials using high temperatures.
  • Incineration is also known as calcination or controlled flame combustion.
  • The energy produced owing to waste treatment is used to produce electric power, making it an essential process.
  • It reduces the cost of landfills.
  • The two major combustible chemical elements are carbon and hydrogen.
  • It is a process where the destruction of organic compounds takes place in waste treatment.
  • This process is capable of destroying contaminants using high temperatures which cannot be fulfilled by any other treatments.

Question 21

Given below are two statements :

Statement I : Increasing the productivity of forests to meet essential needs is one of the major objectives of the National Forest Policy, 1988.

Statement II : According to the National Forest Policy,1988, no forest-based enterprise should provide employment to local people on a priority basis.

In light of the above statements, choose the correct answer from the options given below :

  1. AOption (a)

    Both Statement I and Statement II are true

  2. BOption (b)

    Both Statement I and Statement II are false

  3. COption (c)

    Statement I is correct but Statement II is false

  4. DOption (d)

    Statement I is incorrect but Statement II is true

View answer & explanation

Correct answer

Answer: (c)C.

Statement I is correct but Statement II is false

Why this answer is correct

The correct answer is Statement I is correct but Statement II is false.

Key Points

  • The principal aim of the National Forest Policy, of 1988 is to ensure environmental stability and maintenance of ecological balance including atmospheric equilibrium which is vital for the sustenance of all life forms, human, animal and plant.
  • Objectives:
  • Maintenance of environmental stability through preservation and, where necessary, restoration of the ecological balance that has been adversely disturbed by the serious depletion of the forests of the country.
  • Conserving the natural heritage of the country by preserving the remaining natural forests with a vast variety of flora and fauna, which represent the remarkable biological diversity and genetic resources of the country.
  • Checking soil erosion and denudation in the catchment areas of rivers, lakes, and reservoirs in the "interest of soil and water conservation, for mitigating floods and droughts and for the retardation of siltation of reservoirs.
  • Checking the extension of sand dunes in the desert areas of Rajasthan and along the coastal tracts.
  • Increasing substantially the forest/tree cover in the country through massive afforestation and social forestry programmes, especially on all denuded, degraded and unproductive lands.
  • Meeting the requirements of fuel-wood, fodder, minor forest produce and small timber of the rural and tribal populations.
  • Increasing the productivity of forests to meet essential national needs.
  • Encouraging efficient utilisation of forest produce and maximising substitution of wood.
  • Creating a massive people's movement with the involvement of women, for achieving these objectives and to minimise pressure on existing forests.
  • According to the National Forest Policy, 1988, forest-based industries must not only provide employment to local people on priority but also involve them fully in raising trees and raw-material.

Therefore, statement I is correct but Statement II is false.

Question 22

Given below are two statements :

Statement I : Hazardous materials such as lead, mercury, and hexavalent chromium in one form or other are present in electronic wastes.

Statement II : Landfilling of electronic waste is the best operation from the environmental viewpoint.

In light of the above statements, choose the correct answer from the options given below

  1. AOption (a)

    Both Statement I and Statement II are true

  2. BOption (b)

    Both Statement I and Statement II are false

  3. COption (c)

    Statement I is correct but Statement II is false

  4. DOption (d)

    Statement I is incorrect but Statement II is true

View answer & explanation

Correct answer

Answer: (c)C.

Statement I is correct but Statement II is false

Why this answer is correct

Concept-

  • Electronic waste or e-waste is one of the emerging problems in developed and developing countries worldwide.
  • It comprises a multitude of components with valuable materials, some containing toxic substances, that can have an adverse impact on human health and the environment.
  • Previous studies show that India generated 0.4 million tons of e-waste in 2010 which may increase to 0.5 to 0.6 million tons by 2013–2014.
  • Electronic waste or e-waste is the term used to describe old, end-of-life electronic appliances such as computers, laptops, TVs, DVD players, mobile phones, mp3 players, etc., which have been disposed of by their original users.
  • Television and computer monitors normally contain hazardous materials such as lead, mercury, and cadmium, while nickel, beryllium, and zinc can often be found on circuit boards. Due to the presence of these substances, recycling and disposal of e-waste become an important issue.
  • Landfilling of electronic waste is not the best operation from an environmental viewpoint.

Question 23

Relative contribution (%) of the Green House Gases to global warming in decreasing order

A. Carbon dioxide

B. Methane

C. CFC-12

D. Nitrous oxide

Choose the correct answer from the options given below :

  1. AOption (a)

    A > B > C > D

  2. BOption (b)

    A > B > D > C

  3. COption (c)

    C > A > D > B

  4. DOption (d)

    C > A > B > D

View answer & explanation

Correct answer

Answer: (b)B.

A > B > D > C

Why this answer is correct

The correct answer is: 2) A > B > D > C

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Key Points

  • Greenhouse Gases (GHGs):
  • These are gases that trap heat in the atmosphere, contributing to the greenhouse effect, which leads to global warming.
  • The major greenhouse gases include Carbon dioxide (CO2), Methane (CH4), Nitrous oxide (N2O), and Chlorofluorocarbons (CFCs).
  • Each of these gases has a different impact on global warming, quantified as relative contribution (%) to global warming.
  • Relative Contributions of GHGs:
  • Carbon Dioxide (CO2):
  • CO2 is the most significant greenhouse gas, contributing approximately 76% to global warming from anthropogenic sources.
  • Sourced mainly from burning fossil fuels, deforestation, and various industrial processes.
  • Methane (CH4):
  • CH4 is the second most significant greenhouse gas, contributing about 16% to global warming.
  • Main sources include agriculture (particularly ruminant digestion), landfills, and natural gas extraction.
  • Nitrous Oxide (N2O):
  • N2O contributes around 6% to global warming.
  • Major sources include agricultural activities, industrial activities, and the burning of fossil fuels and biomass.
  • Chlorofluorocarbons (CFCs):
  • CFC-12 is particularly potent but contributes a smaller fraction to global warming compared to CO2, CH4, and N2O.
  • Despite their high global warming potential (GWP), their lower concentration leads to a relative contribution less than that of CO2, CH4, and N2O.
  • Used historically in refrigeration, air conditioning, and as propellants, but their use has been significantly reduced due to their role in ozone depletion.

Additional Information

  • Global Warming Potential (GWP):
  • GWP measures the impact of a greenhouse gas in warming the atmosphere relative to CO2 over a specified time period (usually 100 years).
  • For example, Methane has a GWP of about 25-28, meaning it is 25-28 times more potent than CO2 over a 100-year period.
  • CFC-12 has a GWP of over 10,000, making it extremely potent despite its lower concentration.
  • Total Radiative Forcing:
  • It is the combined effect of all the greenhouse gases in the atmosphere, influencing the Earth's energy balance.
  • Radiative forcing is a measure used to compare the strength of different factors (including GHGs) in causing warming or cooling of the climate system.
  • Mitigation Measures:
  • Reducing fossil fuel use, increasing renewable energy sources, enhancing energy efficiency, and adopting sustainable agricultural practices.
  • International agreements like the Paris Agreement aim to limit global warming by reducing GHG emissions.
  • Phasing out substances like CFCs under protocols such as the Montreal Protocol to protect the ozone layer and mitigate global warming.

Question 24

Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R

Assertion A : The risks from radioactive liquid wastes are caused under decontamination, solidification and disposal procedures.

Reason R : The chemicals in radioactive liquid wastes are hazardous in nature.

In light of the above statements, choose the most appropriate answer from the options given below

  1. AOption (a)

    Both A and R are correct and R is the correct explanation of A

  2. BOption (b)

    Both A and R are correct but R is NOT the correct explanation of A

  3. COption (c)

    A is correct but R is not correct

  4. DOption (d)

    A is not correct but R is correct

View answer & explanation

Correct answer

Answer: (a)A.

Both A and R are correct and R is the correct explanation of A

Why this answer is correct

The correct answer is Both A and R are correct and R is the correct explanation of A.

Key Points

  • Radioactive liquid wastes are generated in nuclear facilities such as nuclear power plants, reprocessing facilities, research reactors and laboratories.
  • They often contain not only radiotoxic isotopes but also hazardous chemicals with high reactivity, low flash or ignition points, potential risks to produce explosive materials combined with other reagents, etc.
  • The chemical compositions and radioactivity levels of the generated wastes depend on the conducted operation.
  • Liquid radioactive wastes possess a potential risk of human exposure during the decontamination process of radioactive waste which includes stabilization/solidification and its ultimate disposal.
  • Aqueous wastes may contain short lived beta/gamma activity. They are kept in storage before disposal.
  • Characteristics of reagents in the wastes and risks caused by the reagents under decontamination, solidification or disposal procedures have to be carefully investigated in advance and then an appropriate treatment process for each item preventing hazardous events has to be designed and adopted.

Therefore, both assertion and reason are correct and reason is the correct explanation of assertion.

Question 25

Identify the correct sequence of the following countries/group of countries credited with the highest to the lowest shares of cumulative CO2 emissions to date.

A. USA

B. China

C. EU

D. India

E. Japan

Choose the correct answer from the options given below

  1. AOption (a)

    A, B, C, E, D

  2. BOption (b)

    A, C, E, D, B

  3. COption (c)

    A, C, B, D, E

  4. DOption (d)

    A, C, B, E, D

View answer & explanation

Correct answer

Answer: (a)A.

A, B, C, E, D

Why this answer is correct

Concept-

  • Carbon dioxide ( CO2) makes up the vast majority of greenhouse gas emissions from the sector, but smaller amounts of methane (CH4) and Nitrous Oxide (NO2) are also emitted.
  • These gases are released during the combustion of fossil fuels, such as coal, oil, and natural gas to produce electricity.

Question 26

Provision of Extended Producer's Responsibility (EPR) of producer, importer and brand owner for collecting back the waste generated by their product has been in the

A. Solid Waste Management Rules, 2016

B. Construction & Demolition Waste Management Rules, 2016

C. Plastic Waste Management Rules, 2016

D. E-waste (Management) Rules, 2016

E. Biomedical Waste Management Rules, 2016

Choose the correct answer from the options given below

  1. AOption (a)

    A, B, D only

  2. BOption (b)

    B, C, D only

  3. COption (c)

    C, D, E only

  4. DOption (d)

    A, B, C, D only

View answer & explanation

Correct answer

Answer: (d)D.

A, B, C, D only

Why this answer is correct

Concept-

Solid Waste Management Rules, 2016-

  • As per SWM 2016, “extended producer responsibility” (EPR) means the responsibility of any producer of packaging products such as plastic, tin, glass and corrugated boxes, etc., for environmentally sound management, till the end-of-life of the packaging products;

Plastic Waste Management Rules, 2016

  • The Ministry of Environment, Forest and Climate Change has notified the Guidelines on Extended Producer's Responsibility on plastic packaging under Plastic Waste Management Rules, 2016.
  • The Guidelines provide a framework to strengthen the circular economy of plastic packaging waste, promote the development of new alternatives to plastics and provide further next steps for moving towards sustainable plastic packaging by businesses.

Construction & Demolition Waste Management Rules, 2016

  • Every waste generator shall segregate construction and demolition waste and deposit it at a collection center or hand it over to the authorized processing facilities
  • Shall ensure that there is no littering or deposition so as to prevent obstruction to the traffic or the public or drains.

E-waste (Management) Rules, 2016

  • Manufacturers, dealers, refurbished, and Producer Responsibility Organizations (PRO) have been introduced as additional stakeholders in the rules.
  • A collection mechanism-based approach has been adopted to include a collection center, collection point, take-back system, etc for the collection of e-waste by Producers under Extended Producer Responsibility (EPR).

 

So the correct answer is option D.

Question 27

Given below are two statements :

Statement I : Covariance between two variables X and Y determines whether the correlation between them is negative or positive.

Statement II : The product of the standard deviation of two variables X and Y can be both positive or negative.

In light of the above statements, choose the most appropriate answer from the options given below

  1. AOption (a)

    Both Statement I and Statement II are correct

  2. BOption (b)

    Both Statement I and Statement II are incorrect

  3. COption (c)

    Statement I is correct but Statement II is incorrect

  4. DOption (d)

    Statement I is incorrect but Statement II is correct

View answer & explanation

Correct answer

Answer: (c)C.

Statement I is correct but Statement II is incorrect

Why this answer is correct

The correct answer is Statement I is correct but Statement II is incorrect.

Key Points

Covariance:

  • It measures the direction of a relationship between two variables, positive or negative correlation.
  • The sign of covariance, therefore, shows the tendency for a linear relationship between the variables.
  • The standard deviation is the root of variance and variance is always positive. So, the standard deviation will always be positive.
  • This makes it very obvious that the product of standard deviations of two variables X and Y will always be positive.

σ = ΣX2N\sqrt{\frac{\Sigma X^{2}}{N}}

where, 

 X = x - μ (μ = mean)

 N = Total number of observations

Therefore, the statement I is correct but Statement II is incorrect.

Question 28

Consider the following statements regarding skewness :

A. For a positively skewed distribution, the value of the mean is the greatest among the mean, median and mode.

B. For a negatively skewed distribution, the median is greater than the mean.

C. Karl Pearson's coefficient of skewness always lies between the limits ±1

D. Bowley's coefficient of skewness always lies between the limits ±1

Choose the correct answer from the options given below

  1. AOption (a)

    A, B and C only

  2. BOption (b)

    B, C and D only

  3. COption (c)

    A, C, and D only

  4. DOption (d)

    A, B and D only

View answer & explanation

Correct answer

Answer: (d)D.

A, B and D only

Why this answer is correct

The correct answer is A, B, and D only.

Key Points

A distribution that is not symmetrical is called a skewed distribution. Such skewed distribution could be either positively skewed or negatively skewed.

1) Positively skewed distribution: It is the frequency curve of the distribution which has a longer tail towards the right side of the curve.

  • In a positively skewed distribution, the values of the mean are maximum.
  • The value of mode is minimum and the median lies between the two values, i.e., mean and mode.
  • Mean > Median > Mode

2) Negatively skewed distribution: It is the frequency curve of the distribution which has a longer tail towards the left side of the curve.

  • Here, the value of the mean is minimum and the value of the mode is maximum and the median lies in between the two.
  • Mean < Median < Mode

3) Mathematical measures of skewness can be calculated by:

  1. Bowley's Method: It is based on the values of median, lower and upper quartiles. The coefficient of skewness lies within the limit of ±1.
  2. Karl-Pearson's Method: Where the relationship of mean and mode is established, the coefficient of skewness generally lies within +1. Where the relationship between mean and median is not established, the coefficient of skewness generally lies within +3.

 Therefore, only statements A, B, and D are correct.

Question 29

Consider the following statements about normal distribution :

A. This distribution is applicable to continuous random variables.

B. It is a symmetrical distribution.

C. The mean of a standard normal distribution is 1.

D. The standard deviation of the standard normal distribution is 1.

Choose the correct answer from the options given below :

  1. AOption (a)

    A, B, and C only

  2. BOption (b)

    B, C, and D only

  3. COption (c)

    A, B, and D only

  4. DOption (d)

    A, C, and D only

View answer & explanation

Correct answer

Answer: (c)C.

A, B, and D only

Why this answer is correct

The correct answer is A, B, and D only.

Key Points

  • Normal distribution is a probability distribution of random variables.
  • Also called "Gaussian curve", it presents a bell shaped symmetrical curve which is continuous for continuous variables.
  • In the normal curve, all distribution is symmetrical about the mean i.e., there is 'no skewness' in it.
  • The mean, median and mode have the same value i.e., they coincide.
  • The standard normal distribution, also called the z-distribution, is a special normal distribution where the mean is 0 and the standard deviation is 1.

Additional Information

  • Any normal distribution can be standardized by converting its values into z-scores.
  • Z-scores tell you how many standard deviations from the mean each value lies.
  • Converting a normal distribution into a z-distribution allows you to calculate the probability of certain values occurring and to compare different data sets.

Therefore, the correct statements are A, B, and D only.

Question 30

Consider the following statements pertaining to sampling theory :

A. The standard deviation of the sampling distribution of a statistic is known as its standard error.

B. The precision of the sample estimate of some population parameter is the reciprocal of the standard error of the sampling distribution of the estimate.

C. A Type - I error in hypothesis testing occurs when we accept a wrong null hypothesis.

D. A Type - II error in hypothesis testing occurs when we reject a true null hypothesis.

Choose the correct answer from the options given below

  1. AOption (a)

    A and B only

  2. BOption (b)

    B and C only

  3. COption (c)

    A and C only

  4. DOption (d)

    C and D only

View answer & explanation

Correct answer

Answer: (a)A.

A and B only

Why this answer is correct

The correct answer is A and B only.

Key Points

Standard Error (SE):

  • It is the standard deviation of the sampling distribution of a statistic.
  • It's an indication of how spread out the numbers are.
  • The term may also be used to refer to an estimate of that standard deviation, derived from a particular sample used to compute the estimate.

Precision:

  • The property of the set of measurements of being very reproducible or of an estimate having a small random error of estimation.
  • Precision is determined by standard deviation which is how much and how much and how often measurements differ from one another.
  • If a standard deviation is high, then it suggests low precision.
  • In other words, the precision of the sample estimate of some population parameter is the reciprocal of the standard error of the sampling distribution of the estimate.

​Types of error:

  • The decision of acceptance or rejection of a null hypothesis is made on the basis of a sample from a population and hence; an element of uncertainty is always involved in making such decisions.
  • Two types of errors are likely to be committed in the procedure of testing of hypothesis. These are Type-I and Type-II errors.
  • Type - I error is committed when a true null hypothesis is rejected. The probability of this error is termed the level of significance of the test.
  • Contrary to this, a Type-II error is committed when a false null hypothesis is accepted.

Therefore, only statements A and B are correct.

Question 31

Match List I (Instrument) with List  II (Function)

List IList II
InstrumentFunction
A.Campbell-Stokes RecorderI.To measure the visible light flux
B.PyraheliometerII.To measure total solar irradiance on a plain surface
C.PyranometerIII.To measure direct beam solar irradiance
D.Lux meterIV.To measure the sunshine duration

Choose the correct answer from the options given below

  1. AOption (a)

    (A) - (I), (B) - (III), (C) - (II), (D) - (IV)

  2. BOption (b)

    (A) - (I), (B) - (II), (C) - (III), (D) - (IV)

  3. COption (c)

    (A) - (IV), (B) - (III), (C) - (II), (D) - (I)

  4. DOption (d)

    (A) - (IV), (B) - (I), (C) - (II), (D) - (III)

View answer & explanation

Correct answer

Answer: (c)C.

(A) - (IV), (B) - (III), (C) - (II), (D) - (I)

Why this answer is correct

The correct answer is (A) - (IV), (B) - (III), (C) - (II), (D) - (I).

Key Points

InstrumentsFunctions
Campbell-Stokes RecorderA device for recording hours of sunshine per day.
PyraheliometerAn instrument for the measurement of direct beam solar irradiance.
PyranometerAn instrument used to measure the amount of solar radiation (power) the sun produces in a specific location
Lux meterLux meters are used for measuring brightness specifically, the intensity with which the brightness appears to the human eye.

 

 

 

 

 

 

 

 

 

 

 

Therefore, the correct answer is (A) - (IV), (B) - (III), (C) - (II), (D) - (I).

Question 32

Match List I (Analysis) with List II (Analytical techniques)

List IList II
AnalysisAnalytical techniques
A.To analyze organic compounds of pollutantsI.SEM
B.To analyze the elemental composition of pollutantsII.XRD
C.Morphological analysis of pollutantsIII.FTIR
D.To analyze crystalline materials of pollutantsIV.XRF

Choose the correct answer from the options given below

  1. AOption (a)

    (A) - (III), (B) - (II), (C) - (IV), (D) - (I)

  2. BOption (b)

    (A) - (IV), (B) - (III), (C) - (I), (D) - (II)

  3. COption (c)

    (A) - (III), (B) - (IV), (C) - (I), (D) - (II)

  4. DOption (d)

    (A) - (IV), (B) - (III), (C) - (II), (D) - (I)

View answer & explanation

Correct answer

Answer: (c)C.

(A) - (III), (B) - (IV), (C) - (I), (D) - (II)

Why this answer is correct

The correct answer is (A) - (III), (B) - (IV), (C) - (I), (D) - (II).

Analytical techniquesFull FormsApplications
SEMScanning Electron Microscope- Scanning Electron Microscope (SEM) has found application in the field of particulate air pollution. - Its use has helped the study of particle morphology and single-particle chemical composition.
XRDX-Ray Diffraction- X-ray diffraction (XRD) is a powerful nondestructive technique for characterizing crystalline materials. - It provides information on structures, phases, preferred crystal orientations (texture), and other structural parameters, such as average grain size, crystallinity, strain, and crystal defects.
FTIRFourier Transform Infrared- FTIR analysis is used for the identification of organic, inorganic, and polymeric materials utilizing infrared light for scanning the samples.
XRFX-Ray Fluorescence- It is a non-destructive analytical technique used to determine the elemental composition of materials.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Therefore the correct answer is  (A) - (III), (B) - (IV), (C) - (I), (D) - (II).

Question 33

Match List I (Organism) with List II (Ecosystem structure components)

List IList II
OrganismEcosystem structure components
A.EarthwormsI.Producer
B.GrassII.Secondary carnivore
C.FrogsIII.Primary carnivore
D.HawksIV.Detrivore

Choose the correct answer from the options given below

  1. AOption (a)

    (A) - (IV), (B) - (I), (C) - (II), (D) - (III)

  2. BOption (b)

    (A) - (II), (B) - (III), (C) - (IV), (D) - (I)

  3. COption (c)

    (A) - (III), (B) - (IV), (C) - (I), (D) - (II)

  4. DOption (d)

    (A) - (IV), (B) - (I), (C) - (III), (D) - (II)

View answer & explanation

Correct answer

Answer: (d)D.

(A) - (IV), (B) - (I), (C) - (III), (D) - (II)

Why this answer is correct

correct option is (A) - (IV), (B) - (I), (C) - (III), (D) - (II). 

Key Points 

 

 

 

 

 

 

 

 

 

 

Hence, correct option is (A) - (IV), (B) - (I), (C) - (III), (D) - (II).

Question 34

Match List I (Elements) with List II (Characteristics)

List IList II
ElementsCharacteristics
A.LithophileI.Occur mainly as sulfides
B.ChalcophileII.Gaseous elements do not generally form compounds
C.SiderophileIII.Occur mainly in oxygen compounds
D.AtmophileIV.Occur mainly as native elements

Choose the correct answer from the options given below :

  1. AOption (a)

    (A) - (I), (B) - (II), (C) - (III), (D) - (IV)

  2. BOption (b)

    (A) - (I), (B) - (IV), (C) - (III), (D) - (II)

  3. COption (c)

    (A) - (III), (B) - (IV), (C) - (I), (D) - (II)

  4. DOption (d)

    (A) - (III), (B) - (I), (C) - (IV), (D) - (II)

View answer & explanation

Correct answer

Answer: (d)D.

(A) - (III), (B) - (I), (C) - (IV), (D) - (II)

Why this answer is correct

The correct answer is (A) - (III), (B) - (I), (C) - (IV), (D) - (II).

 

Key Points

ElementsCharacteristics
Lithophile| The lithophile elements bond readily with oxygen and are concentrated in the Earth's silicate shell (crust and mantle). They occur naturally as stable ions in silicates, oxides, halides, phosphates, sulfates, and carbonates. They include aluminium, astatine, boron, barium, beryllium, bromine, calcium, chlorine, chromium, caesium, fluorine, iodine, hafnium, potassium, lithium, magnesium, sodium, niobium, oxygen, phosphorus, rubidium, scandium, silicon, strontium, tantalum, technetium, thorium, titanium, uranium, vanadium, yttrium, zirconium, tungsten, and the lanthanides. | | --- |The lithophile elements bond readily with oxygen and are concentrated in the Earth's silicate shell (crust and mantle). They occur naturally as stable ions in silicates, oxides, halides, phosphates, sulfates, and carbonates. They include aluminium, astatine, boron, barium, beryllium, bromine, calcium, chlorine, chromium, caesium, fluorine, iodine, hafnium, potassium, lithium, magnesium, sodium, niobium, oxygen, phosphorus, rubidium, scandium, silicon, strontium, tantalum, technetium, thorium, titanium, uranium, vanadium, yttrium, zirconium, tungsten, and the lanthanides.
The lithophile elements bond readily with oxygen and are concentrated in the Earth's silicate shell (crust and mantle). They occur naturally as stable ions in silicates, oxides, halides, phosphates, sulfates, and carbonates. They include aluminium, astatine, boron, barium, beryllium, bromine, calcium, chlorine, chromium, caesium, fluorine, iodine, hafnium, potassium, lithium, magnesium, sodium, niobium, oxygen, phosphorus, rubidium, scandium, silicon, strontium, tantalum, technetium, thorium, titanium, uranium, vanadium, yttrium, zirconium, tungsten, and the lanthanides.
ChalcophileThe chalcophile elements predominantly represent sulfide ores. They include antimony, arsenic, bismuth, cadmium, copper, gallium, germanium, indium, lead, mercury, polonium, selenium, silver, sulfur, tellurium, thallium, tin, and zinc.
SiderophileSiderophile elements have an affinity for a metallic liquid phase. They are depleted in the silicate portion of the earth and presumably concentrated in the core. They include ruthenium, rhodium, palladium, rhenium, osmium, iridium, platinum and gold.
AtmophileAtmophile elements are volatile (i.e., they form gases or liquids at the surface of the Earth) and are concentrated in the atmosphere and hydrosphere. The atmophile elements are hydrogen, carbon, nitrogen, and noble gases, namely helium, neon, argon, krypton, xenon, and radon.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Therefore, the correct answer is (A) - (III), (B) - (I), (C) - (IV), (D) - (II).

Question 35

Match List I (Rock types) with List II (Characteristics)

List - IList - II
Rock typesCharacteristics
A.RudaceousI.Rocks consisting mainly of silt and siltstones
B.ArenaceousII.Rocks consisting mainly of gravels, pebbles, cobbles, and boulders
C.Silt rocksIII.Rocks consisting mainly of dust, mud, and clay
D.ArgillaceousIV.Rocks consisting mainly of sands

Choose the correct answer from the options given below

  1. AOption (a)

    (A) - (II), (B) - (I), (C) - (IV), (D) - (III)

  2. BOption (b)

    (A) - (IV), (B) - (II), (C) - (I), (D) - (III)

  3. COption (c)

    (A) - (IV), (B) - (I), (C) - (III), (D) - (II)

  4. DOption (d)

    (A) - (II), (B) - (IV), (C) - (I), (D) - (III)

View answer & explanation

Correct answer

Answer: (d)D.

(A) - (II), (B) - (IV), (C) - (I), (D) - (III)

Why this answer is correct

Concept-

Sedimentary rocks may be classified on the basis of grain size into three types:

Rudaceous, Arenaceous, and silt rocks.

Rudaceous (in Latin Rudous—pebbles):

  • Rudaceous rocks are those rocks, which are made up of particles having a grain size of more than 2 mm in diameter.
  • Rocks consist mainly of gravel, pebbles, cobbles, and boulders.
  • Example- Breccia, Conglomerate.

Arenaceous (in Latin Arena—sand):

  • Arenaceous rocks are those rocks, which are made up of particles having a grain size between 0.1 -2 mm diameter.
  • Rocks consist mainly of sand.
  • Example- sandstone

Silt rocks-

  • Siltstone is a sedimentary rock composed mainly of silt-sized particles. Rocks consist mainly of silt and siltstones.
  • It forms where water, wind, or ice deposit silt, and the silt is then compacted and cemented into a rock.
  • Silt accumulates in sedimentary basins throughout the world.

Argillaceous-

  • Argillaceous rocks are those rocks, which are made up of the finest clay particles i.e., the size of particles is less than 0.1 mm in diameter.
  • Rocks consist mainly of dust, mud, and clay.
  • Example- Shale

Question 36

Match List I (Air pollutants) with List II (Control Technique/Equipment)

List - IList - II
Air pollutantsControl Technique/Equipment
A.PM 2.5   I.Selective catalytic reduction
B.SO2II.Electrostatic precipitator
C.NOXIII.Cyclone collectors
D.Coarse particulate matterIV.Scrubber

Choose the correct answer from the options given below

  1. AOption (a)

    (A) - (I), (B) - (II), (C) - (III), (D) - (IV)

  2. BOption (b)

    (A) - (II), (B) - (IV), (C) - (I), (D) - (III)

  3. COption (c)

    (A) - (I), (B) - (IV), (C) - (II), (D) - (III)

  4. DOption (d)

    (A) - (IV), (B) - (I), (C) - (III), (D) - (II)

View answer & explanation

Correct answer

Answer: (b)B.

(A) - (II), (B) - (IV), (C) - (I), (D) - (III)

Why this answer is correct

Concept:

Selective catalytic reduction:

  • Selective catalytic reduction (SCR ) is a means of converting nitrogen oxides, also referred to as NOx with the aid of a catalyst into diatomic nitrogen (N2), and water (H2O).
  • A reductant, typically anhydrous ammonia (NH3), aqueous ammonia (NH4OH), or a urea (CO(NH2)2) solution, is added to a stream of flue or exhaust gas and is reacted onto a catalyst.
  • As the reaction drives toward completion, nitrogen (N2), and carbon dioxide (CO2), in the case of urea use, are produced.

Electrostatic precipitator:

The gas is made to pass through a highly ionized zone where the particles get electrically charged & are separated out from the gas with the help of electrostatic forces in a powerful electric field.

  • Widely used in thermal power plants, mining, iron and steel plants, etc.
  • Sensitive to variable dust loadings & flow rates
  • Particles collected may be wet or dry
  • 99% or more efficiency can be obtained
  • PM2.5 is removed here.

Cyclone Collectors:

  • Cyclone collectors are the devices through which air pollutants can be removed from the air stream with the help of vortex separation.
  • It does not use filters to remove the particulates from the air stream.
  • Coarse particulate matter is removed in cyclone collectors.
  • The vortex separation is the method where the various gases that include the mixture of hydrogen and uranium hydro fluoride gas are injected inside the tubes and from the other tube the clean gas is separated out.
  • While the electrostatic precipitator is a device that is issued to remove those particulate matters that are suspended in the air and are removed with the help of the application of the high voltage electrostatic charge that helps in collecting the dust particles on the charged plate.
  • They both are devices that are used to control air pollution in the case of industries.

Scrubbers:

  • Also called Venturi scrubbers and spray towers.
  • Smokestacks with scrubbers
  • Can remove gaseous pollutants also. Ex. SO2,NO2
  • The particulate material can also be controlled
  • Hot gases can be cooled down
  • Maintenance cost is high
  • A lot of waste water is produced which requires further disposal

Question 37

Match List I (Atmospheric stability) with List II (Lapse Rate)

List - IList - II
Atmospheric stabilityLapse Rate
A.Absolutely StableI.ELR = DALR
B.Absolutely UnstableII.ELR < DALR
C.Conditionally UnstableIII.ELR > DALR
D.Dry NeutralIV.SALR < ELR < DALR

Choose the correct answer from the options given below

  1. AOption (a)

    (A) - (II), (B) - (III), (C) - (I), (D) - (IV)

  2. BOption (b)

    (A) - (II), (B) - (III), (C) - (IV), (D) - (I)

  3. COption (c)

    (A) - (III), (B) - (II), (C) - (IV), (D) - (I)

  4. DOption (d)

    (A) - (III), (B) - (II), (C) - (I), (D) - (IV)

View answer & explanation

Correct answer

Answer: (b)B.

(A) - (II), (B) - (III), (C) - (IV), (D) - (I)

Why this answer is correct

The correct answer is (A) - (II), (B) - (III), (C) - (IV), (D) - (I).

Key Points

Absolutely stable atmosphere:

  • When the ambient temperatures cool less rapidly than the saturated adiabatic lapse rate, the atmosphere is absolutely stable.
  • The air wants to stay where it is.
  • Environment Lapse Rate (ELR) < Dry Adiabatic Lapse Rate (DALR).

Absolutely unstable atmosphere:   

  • ​If the ambient lapse rate shows cooling at a faster rate than the dry adiabatic lapse rate, the atmosphere is absolutely unstable.
  • The air will always want to move to some new altitude so the vertical dispersion of pollution is enhanced.
  • Environment Lapse Rate (ELR) > Dry Adiabatic Lapse Rate (DALR).

Conditional stability/instability:

  • For ambient lapse rates between the dry and wet adiabatic lapse rates, the atmosphere may be stable or it may be unstable.
  • We can’t tell without knowing the actual ambient temperature profile and the actual adiabatic profile.
  • That region is labelled as having conditional stability.
  • Saturated Adiabatic Lapse Rate < Environmental Lapse Rate < Dry Adiabatic Lapse Rate.

Dry neutral:

  • ​If the ambient lapse rate is equal to the adiabatic lapse rate, moving the parcel upward or downward results in its temperature changing by the same amount as its surroundings.
  • In any new position, it experiences no forces that either make it continue its motion or make it want to return to its original elevation.
  • The parcel likes where it was, and it likes its new position too.
  • Such an atmosphere is said to be neutrally stable.
  • Environment Lapse Rate (ELR) = Dry Adiabatic Lapse Rate (DALR).

​​Therefore, the correct answer is (A) - (II), (B) - (III), (C) - (IV), (D) - (I).

Question 38

Match List I (Statistical Test) with List II (Applications)

List - IList - II
Statistical testApplications
A.χ2-testI.Testing the significance of difference of means
B.One-Way ANOVAII.Testing the significance of a single mean
C.Paired t-testIII.Testing the goodness of fit between theory and experiment
D.Z-testIV.Comparing more than two sample means

Choose the correct answer from the options given below

  1. AOption (a)

    (A) - (I), (B) - (II), (C) - (III), (D) - (IV)

  2. BOption (b)

    (A) - (II), (B) - (III), (C) - (IV), (D) - (I)

  3. COption (c)

    (A) - (III), (B) - (IV), (C) - (I), (D) - (II)

  4. DOption (d)

    (A) - (IV), (B) - (I), (C) - (II), (D) - (III)

View answer & explanation

Correct answer

Answer: (c)C.

(A) - (III), (B) - (IV), (C) - (I), (D) - (II)

Why this answer is correct

The correct answer is (A) - (III), (B) - (IV), (C) - (I), (D) - (II).

Key Points

  • χ2-test:
  • ​The χ2-test is one of the simplest and most widely used non-parametric tests in statistical work.
  • The quantity χ2-test describes the magnitude of the discrepancy between theory and observation.
  • Uses of χ2-test:
  1. χ2-test is used as a test of independence that is to check whether two or more attributes are associated or not.
  2. χ2-test is used as a test of goodness of fit because it enables us to ascertain how appropriately the theoretical distributions such as binomial, Poisson, normal etc fit the empirical distribution.
  • ​**One-Way ANOVA:**​
  • ​One-Way ANOVA compares the means of two or more independent groups in order to determine whether there is statistical evidence that the associated population means are significantly different.
  • One-Way ANOVA is a parametric test.
  • ​​Paired t-test:
  • ​A paired t-test is a statistical test that compares the averages/means and standard deviations of two related groups to determine if there is a significant difference between the two groups.
  • In paired t-test, we compare the means of two groups of observations which are randomly assigned.
  • ​Z-test:
  • ​A z-test is used for testing the mean of a population versus a standard or testing the significance of a single mean.
  • It indicates how much observation is bigger or smaller than the mean in units of standard deviation.

 Therefore, the correct answer is (A) - (III), (B) - (IV), (C) - (I), (D) - (II).

Question 39

Match List I (Environmentally significant Days) with List II (Dates)

List - IList - II
Environmentally significant DaysDates
A.World Ozone DayI.16 September
B.World Habitat DayII.21 March
C.World Forest DayIII.5 October
D.World Water DayIV.22 March

Choose the correct answer from the options given below

  1. AOption (a)

    (A) - (IV), (B) - (III), (C) - (I), (D) - (II)

  2. BOption (b)

    (A) - (II), (B) - (I), (C) - (IV), (D) - (III)

  3. COption (c)

    (A) - (I), (B) - (III), (C) - (II), (D) - (IV)

  4. DOption (d)

    (A) - (III), (B) - (I), (C) - (IV), (D) - (II)

View answer & explanation

Correct answer

Answer: (c)C.

(A) - (I), (B) - (III), (C) - (II), (D) - (IV)

Why this answer is correct

Concept-

World Ozone Day-

  • World Ozone Day or International Day for Preservation of Ozone Layers is observed on September 16 every year.
  • The motto behind its observation is spreading awareness among people about Ozone Layer depletion and searching for possible solutions to preserve it.

World Habitat Day-

  • The United Nations has designated the first Monday of October of every year as World Habitat Day to reflect on the state of our habitats, and on the basic right of all to adequate shelter.
  • The Day is intended to remind the world that we all have the power and the responsibility to shape the future of our cities and towns.

World Forest Day-

  • Every year 21st of March is celebrated as the International Day of Forests (IDF) by the United Nations (UN).
  • The UN proclaimed 21st March as the IDF in 2012 to celebrate and raise awareness of the importance of all types of forests.

World water day-

  • World Water Day is celebrated on 22nd March Every Year to highlight the importance of water.
  • On the Occasion of the World Water Day UN (United Nations) University’s Canadian-based Institute for Water Environment and Health (UNU-INWEH) has published an assessment report, showing the levels of water security in Africa overall are unacceptably low.

Question 40

Match List - I (Processes) with List - II (Energy Transfer)

List - IList - II
ProcessesEnergy Transfer
A.ConductionI.Energy is transferred by motion of a fluid
B.ConvectionII.Energy is transferred in the form of electromagnetic waves through a vacuum.
C.RadiationIII.Energy is transferred between two points in a material at different temperatures
D.EvaporationIV.Energy is lost through a phase change

Choose the correct answer from the options given below

  1. AOption (a)

    (A) - (II), (B) - (I), (C) - (III), (D) - (IV)

  2. BOption (b)

    (A) - (II), (B) - (IV), (C) - (III), (D) - (I)

  3. COption (c)

    (A) - (III), (B) - (IV), (C) - (II), (D) - (I)

  4. DOption (d)

    (A) - (III), (B) - (I), (C) - (II), (D) - (IV)

View answer & explanation

Correct answer

Answer: (d)D.

(A) - (III), (B) - (I), (C) - (II), (D) - (IV)

Why this answer is correct

Concept-

ConductionConvectionRadiation
In conduction, heat transfer occurs between objects by direct contact.In convection, heat transfer takes within the fluid.In radiation, heat transfer occurs through electromagnetic waves without involving particles.
Heat transfer takes place due to the difference in temperature.Heat transfer occurs due to the difference in density.Heat transfer occurs in all objects with a temperature greater than 0 K.
Heat transfer in conduction is slow.Heat transfer in convection is faster.Heat transfer in radiation is the fastest.
It does not follow the law of reflection and refraction.It does not follow the law of reflection and refraction.It follows the law of reflection and refraction.
Heat transfer occurs through a heated solid object.Heat transfer occurs through intermediate objects. For example, heat transfer between air and water.Heat transfer occurs through electromagnetic waves.

 

Evaporation-

  • Evaporation can generally be defined as a process by which a liquid is transformed into vapor.
  • Evaporation is a form of vaporization that usually happens on the surface of liquids and it involves the transition of the liquid particles into the gaseous phase. Therefore, this process is said to involve a change in the phases.
  • The surrounding gas must not be saturated with the substance which is evaporating.
  • They transfer energy to each other as the molecules of the liquid collide, depending on how they collide with each other.
  • The liquid particles will generally escape and enter the surrounding air as a gas when a molecule near the surface consumes enough energy to overcome the vapor pressure.
  • The energy extracted from the vaporized liquid as evaporation occurs will decrease the temperature of the liquid, resulting in a process known as evaporative cooling.

 

So the correct option is option D.

Question 41

A strategy favoured by r-selection is :

  1. AOption (a)

    Higher proportional allocation to non-reproductive activities.

  2. BOption (b)

    Living in environments imposing high-density independent mortality.

  3. COption (c)

    Living in environments imposing high-density dependent regulation.

  4. DOption (d)

    Higher proportional allocation to reproductive activities.

View answer & explanation

Correct answer

Answer: (d)D.

Higher proportional allocation to reproductive activities.

Why this answer is correct

Explanation:

  • r species are characterized by smaller body sizes, rapid developmental rates, and smaller offspring.
  • r-selected species thrive in disturbed habitats.
  • These species have a shorter life span.
  • These species adopt the r-Reproductive strategy.
  • These populations are governed by their biotic potential and have the maximum reproductive capacity, .
  • The production of numerous small offspring followed by exponential population growth is the defining characteristic of r-selected species.
  • They require short gestation periods, mature quickly, and require little or no parental care.

Examples of r-selected species include pest organisms, such as rodents, insects, and weeds.

Population growth in r-selected species behaves according to the exponential growth equation:

ΔNΔt=rN\frac{\Delta N}{\Delta t} = rN

In this equation, N is the number of individuals in the population and t is time.

The factor (1–[N/K]) is often added to the equation to place an upper limit on population growth by accounting for environmental resistance.

Hence, option 4 is the correct answer.

Question 42

Traditionally membranes have been classified based on the minimum size of the contaminant that is excluded from passing through the particular membrane. Arrange the following in the correct sequence of decreasing pore size

A. Reverse Osmosis

B. Nanofiltration

C. Microfiltration

D. Ultrafiltration

Choose the correct answer from the options given below

  1. AOption (a)

    A, B, C, D

  2. BOption (b)

    D, C, B, A

  3. COption (c)

    C, D, B, A

  4. DOption (d)

    D, C, A, B

View answer & explanation

Correct answer

Answer: (c)C.

C, D, B, A

Why this answer is correct

Concept-

Reverse Osmosis-

  • Reverse osmosis (RO) is a water purification process that uses a partially permeable membrane to separate ions, unwanted molecules, and larger particles from drinking water.
  • Reverse osmosis filters have a pore size of around 0.0001 microns.
  • In reverse osmosis, an applied pressure is used to overcome osmotic pressure, a colligative property that is driven by potential chemical differences of the solvent, a thermodynamic parameter.
  • Reverse osmosis can remove many types of dissolved and suspended chemical species as well as biological ones (principally bacteria) from water, and is used in both industrial processes and potable water production.

Nanofiltration-

  • A nanofiltration filter has a pore size of around 0.001 microns.
  • Nanofiltration removes most organic molecules, nearly all viruses, most of the natural organic matter, and a range of salts. Nanofiltration removes divalent ions, which make water hard, so nanofiltration is often used to soften hard water.

Ultrafiltration-

  • An ultrafiltration filter has a pore size of around 0.01 microns.
  • A microfiltration filter has a pore size of around 0.1 microns, so when water undergoes microfiltration, many microorganisms are removed, but viruses remain in the water.
  • Ultrafiltration would remove these larger particles, and may remove some viruses. Neither microfiltration nor ultrafiltration can remove dissolved substances unless they are first adsorbed (with activated carbon) or coagulated (with alum or iron salts).

Microfiltration-

  • Microfiltration (MF) is a pressure-driven separation process, which is widely used in concentrating, purifying or separating macromolecules, colloids, and suspended particles from solution.
  • MF membranes typically have nominal pore sizes on the order of 0.1–1.0 μm.
  • MF processing is widely used in the food industry for applications such as wine, juice, and beer clarification, for wastewater treatment, and plasma separation from the blood for therapeutic and commercial uses.
  • In biotechnology industries, MF concerns applications such as cell recycling and harvesting, separation of recombinant proteins from cell debris, and purification of process streams.

 

So the sequence of decreasing pore size is Microfiltration > Ultrafiltration > Nanofiltration > Reverse Osmosis.

Question 43

For a given noise signal, what would be the correct order of noise indices in terms of increasing values?

A. L10

B. L50

C. L1

D. L90

Choose the correct answer from the options given below

  1. AOption (a)

    C < A < B < D

  2. BOption (b)

    A < B < C < D

  3. COption (c)

    D < C < B < A

  4. DOption (d)

    D < B < A < C

View answer & explanation

Correct answer

Answer: (d)D.

D < B < A < C

Why this answer is correct

Concept-

  • Noise pollution is a significant problem for the quality of life in urban areas.
  • Traffic noise is considered one of the important sources of noise pollution that adversely affects human health in residential urban areas.
  • In most cases, the sounds and noises we hear are not steady. Apart from variations in tones, the magnitude of the sound pressure level of a sound or noise changes with time.
  • The n-percent exceeded level, Ln, is the sound pressure level exceeded for n percent of the time. In other words, for n percent of the time, the fluctuating sound pressure levels are higher than the Ln level.
  • Ln can be obtained by analyzing a given noise by statistical means.
  • Ln, where n may be anything from 1 to 99, is that noise level exceeded for n% of the measurement time.
  • By definition of percentiles, L1 must be greater than or equal to L2, which must be greater than or equal to L3, etc.
  • The commonly used value of n for the n-percent exceeded level, Ln, are 10, 50 and 90.
  • L10 is the level exceeded 10% of the time. For 10% of the time, the sound or noise has a sound pressure level above L10.
  • For the rest of the time, the sound or noise has a sound pressure level at or below L10.

Hence, increasing order in terms of noise level starting from minimum to maximum is L90 < L50 < L10 < L1.

Question 44

Identify the correct sequence of steps involved in the development of a model.

A. Validation

B. Formulation

C. Identification

D. Solution

Choose the correct answer from the options given below

  1. AOption (a)

    A, B, C, D

  2. BOption (b)

    B, C, D, A

  3. COption (c)

    C, B, D, A

  4. DOption (d)

    C, D, B, A

View answer & explanation

Correct answer

Answer: (c)C.

C, B, D, A

Why this answer is correct

Concept-

The correct sequence of steps involved in the development of a model is Identification > Formulation > Solution > validation.

  • Identification- A good problem identification is always the starting point for good modeling.
  • Formulation- 
  • The model formulation is the step where our knowledge of a natural system is translated into mathematical form.
  • It involves two steps: the construction of a conceptual model and the formulation of this conceptual model into mathematical equations.
  • Solution- Finding the solution to the mathematical equations is carried out in this step.
  • Validation- The verification of the solution is carried out in this step which is known as the validation of the model.

Hence, option 3 is the correct answer.

Question 45

Given below are two statements : one is labelled as Assertion A and other is labelled as Reason R

Assertion A : Plants generally reflect radiation highly in the near-infrared region of the electromagnetic spectrum.

Reason R : Plant leaves generally contain high chlorophyll content.

In light of the above statements, choose the correct answer from the options given below

  1. AOption (a)

    Both A and R are true and R is the correct explanation of A

  2. BOption (b)

    Both A and R are true but R is NOT the correct explanation of A

  3. COption (c)

    A is true but R is false

  4. DOption (d)

    A is false but R is true

View answer & explanation

Correct answer

Answer: (b)B.

Both A and R are true but R is NOT the correct explanation of A

Why this answer is correct

Explanation:

  • Chlorophyll is a green color pigment present in the leaves of plants. It helps in the process of photosynthesis. Generally leaves contain it in a higher proportion. Therefore, R is correct.
  • Chlorophyll is located in a plant’s chloroplasts, which are tiny structures in a plant’s cells. This is where photosynthesis takes place. Plants absorb most of the red and blue light that they receive as part of the process of photosynthesis.
  • Some of the green light is absorbed and some are reflected off the leaves. This is the reason that plants look green.
  • Chlorophyll, which cannot be detected by visible light, is sensitive to near-infrared light.
  • A high percentage of near-infrared light is reflected off the leaves in healthy plants. When a plant is unhealthy, it has less chlorophyll and therefore reflects less near-infrared light. Therefore, A is correct.
  • Unhealthy plants also reflect more red light. The difference between red and near-infrared light reflected off a plant is a good indicator of plant healthiness.
  • Healthy vegetation absorbs blue- and red-light energy to fuel photosynthesis and create chlorophyll.
  • A plant with more chlorophyll will reflect more near-infrared energy than an unhealthy plant.

​Hence, option B is the correct answer.

Question 46

Given below are two statements : One is labelled as Assertion A and other is labelled as Reason R

Assertion A : Tropopause acts as a 'lid limiting both convection and transport from the troposphere into the higher layers of the atmosphere.

Reason R : At tropopause height and at higher levels, the atmosphere is stable.

In light of the above statements, choose the correct answer from the options given below

  1. AOption (a)

    Both A and R are true and R is the correct explanation of A

  2. BOption (b)

    Both A and R are true but R is NOT the correct explanation of A

  3. COption (c)

    A is true but R is false

  4. DOption (d)

    A is false but R is true

View answer & explanation

Correct answer

Answer: (a)A.

Both A and R are true and R is the correct explanation of A

Why this answer is correct

The correct answer is Both A and R are true and R is the correct explanation of A.

Key Points

  • At tropopause, the dependence of air temperature on height is reversed.
  • In other words, the temperature begins to increase with altitude.
  • This type of temperature profile is called a stable profile, because rising air parcels lose buoyancy i.e., the air surrounding them is warmer than they are.
  • Therefore, they tend to sink instead of rising.
  • The tropopause thus acts like a "lid" for the troposphere and prevents the mixing of air across it into the next layer, the stratosphere.
  • The stratosphere is also very dry because the moisture that is evaporated from the Earth's surface from oceans and land cannot rise past the lid presented by the tropopause.

Therefore, both the assertion and reason are correct and the reason is the correct explanation of the assertion.

Question 47

A sample of air has a relative humidity of 60%. Given that the Saturated Vapour Pressure of water is 2260 Pa, calculate the vapour pressure of the air at 20°C.

  1. AOption (a)

    ∼ 1460 Pa

  2. BOption (b)

    ∼ 452 Pa

  3. COption (c)

    ∼ 3767 Pa

  4. DOption (d)

    ∼ 1356 Pa

View answer & explanation

Correct answer

Answer: (d)D.

∼ 1356 Pa

Why this answer is correct

Concept:

  • Vapour pressure is defined as the pressure exerted by a vapor when it is in equilibrium with the condensed form i.e. liquid or solid form or both.
  • The substance under consideration may exist in three phases under the equilibrium condition.
  • The relative humidity is defined as the ratio of the partial pressure of water vapour and the equilibrium vapour pressure of water vapour multiplied by 100.

It is expressed as 

Φ=PH2OPH2O∗\Phi = \frac{{{P_{{H_2}O}}}}{{P_{{H_2}O}^*}}

Calculation:

Relative humidity = 60 %

Saturated Vapour Pressure of water = 2260 Pa

So vapour pressure of air = 0.6 × 2260 = 1356 Pa

Question 48

Which among the following is short-lived species in the atmosphere?

  1. AOption (a)

    CH4

  2. BOption (b)

    CO

  3. COption (c)

    N2O

  4. DOption (d)

    OH radical

View answer & explanation

Correct answer

Answer: (d)D.

OH radical

Why this answer is correct

The correct answer is OH radical.

Key points Lifetime of different chemical species in the atmosphere is:

Chemical speciesLifetime
CH412 years
CO2 to 4 months
N20114 years
OH radical<1 second

 

 

 

 

Therefore, the chemical species with the shortest lifetime is OH radical.

Additional Information

  • Hydroxyl radicals (OH) are often called the “detergent/scavenger” of the atmosphere because they control the atmosphere's capacity to cleanse itself of pollutants.
  • It controls the concentrations of toxic gases like carbon monoxide and climate-relevant gases like methane.
  • Its concentration in the atmosphere is very small (about 1×106 molecules cm−3).
  • OH is formed in the atmosphere when ultraviolet light (UV) from the sun strikes ozone in the presence of water vapour (H2O). The initial reaction involves the photolysis of O3 by solar radiation. Then the oxygen atom (O) reacts with water vapour to produce two OH radicals.

Question 49

The chemical composition CFC-113 is

  1. AOption (a)

    CF2ClCFCl2

  2. BOption (b)

    CFHClCFCl2

  3. COption (c)

    CF3CF2Cl2

  4. DOption (d)

    CF2HCF2Cl2

View answer & explanation

Correct answer

Answer: (a)A.

CF2ClCFCl2

Why this answer is correct

The correct answer is: CF2ClCFCl2

CFC-113 (Trichlorotrifluoroethane) is a chlorofluorocarbon compound widely used in refrigeration, cleaning solvents, and as a propellant before its regulation due to ozone depletion concerns. The name CFC-113 is derived from the numbering system used to identify the number of carbon, fluorine, and chlorine atoms in the molecule.

Key Points

  • Composition:
  • CFC-113 has the molecular formula CF2Cl–CFCl2.
  • This means it contains 2 carbon atoms, 3 chlorine atoms, and 3 fluorine atoms.
  • Numbering System for CFCs:
  • The CFC number (e.g., 113) is derived from:
  • First digit: Number of carbon atoms minus 1 → (2–1 = 1)
  • Second digit: Number of hydrogen atoms plus 1 → (0+1 = 1)
  • Third digit: Number of fluorine atoms → 3
  • Structure:
  • It is a halogenated hydrocarbon where chlorine and fluorine atoms are bonded to carbon atoms.
  • Its structure contributes to chemical stability and long atmospheric lifetime.

Additional Information

  • Uses of CFC-113:
  • Formerly used as an industrial solvent for cleaning electronic components.
  • Used as a refrigerant in some cooling systems.
  • Environmental Impact:
  • High Ozone Depletion Potential (ODP).
  • Its production and use are now phased out under the Montreal Protocol.
  • Alternatives:
  • Hydrofluorocarbons (HFCs) and other environmentally safer refrigerants have replaced CFC-113 in most applications.

Question 50

Basel convention (1989) was designed to :

  1. AOption (a)

    Reduce global waste generation

  2. BOption (b)

    Control hazardous waste generation

  3. COption (c)

    Determine safe handling measures for hazardous waste

  4. DOption (d)

    Prevent trans-boundary movement of hazardous waste between nations

View answer & explanation

Correct answer

Answer: (d)D.

Prevent trans-boundary movement of hazardous waste between nations

Why this answer is correct

The correct answer is Prevent trans-boundary movement of hazardous waste between nations.

Key Points

  • The Basel Convention on the Control of Transboundary Movements of Hazardous Wastes and their Disposal.
  • It came into force in 1992 adopted in 1989
  • The Convention aims to protect human health and the environment against the adverse effects of generation, transboundary movements, and management of hazardous wastes and other wastes.
  • The Basel Convention regulates the transboundary movements of hazardous wastes and other wastes and obliges its Parties to ensure that such wastes are managed and disposed of in an environmentally sound manner.
  • It is the most comprehensive global environmental agreement on hazardous wastes and other wastes.
  • With 175 Parties, it has nearly universal membership.
  • The Convention covers toxic, poisonous, explosive, corrosive, flammable, ecotoxic, and infectious wastes.
  • Parties are also obligated to minimize the quantities transported, to treat and dispose of wastes as close as possible to their place of generation and to prevent or reduce the generation of wastes at source.

Therefore, the Basel convention (1989) was designed to prevent the transboundary movement of hazardous waste between nations.

Question 51

Which of the following is NOT an epigeic earthworm species?

  1. AOption (a)

    Eisenia fetida

  2. BOption (b)

    Eisenia andrei

  3. COption (c)

    Metaphire posthuma

  4. DOption (d)

    Eudrilus eugeniae

View answer & explanation

Correct answer

Answer: (c)C.

Metaphire posthuma

Why this answer is correct

The correct answer is Metaphire posthuma.

Key Points

  • Epigeic earthworms live in areas containing high amounts of organic matter.
  • They live at or near the soil surface and feed on leaf litter, decaying plant roots or dung.
  • These earthworms do not form permanent burrows.
  • Epigeic species tend to have dark skin colour (pigmentation).
  • Epigeic species tend to be small (1 – 18 cm) in length.

Examples of Epigeic earthworms:

  • Dendrobaena veneta
  • Dendrobaena hortensis
  • Dendrobaena octaedra
  • Eisenia fetida
  • Eisenia andrei
  • Dendrodrilus rubidus
  • Eiseniella tetraedra
  • Eudrilus eugeniae
  • Allolobophoridella eiseni

​Metaphire posthuma is an endogeic geophagous earthworm.

Therefore, the correct answer is Metaphire posthuma.

Question 52

Which among the following is the major product of slow pyrolysis of biomass?

  1. AOption (a)

    Biochar

  2. BOption (b)

    Biogas

  3. COption (c)

    Carbon monoxide

  4. DOption (d)

    Carbon dioxide

View answer & explanation

Correct answer

Answer: (a)A.

Biochar

Why this answer is correct

Concept-

Pyrolysis-

  • Pyrolysis is one of the technologies available to convert biomass to an intermediate liquid product that can be refined to drop-in hydrocarbon biofuels, oxygenated fuel additives, and petrochemical replacements.
  • Pyrolysis is the heating of organic material, such as biomass, in the absence of oxygen.
  • Biomass pyrolysis is usually conducted at or above 500 °C, providing enough heat to deconstruct the strong bio-polymers mentioned above.
  • Because no oxygen is present combustion does not occur, rather the biomass thermally decomposes into combustible gases and bio-char.
  • Most of these combustible gases can be condensed into a combustible liquid, called pyrolysis oil (bio-oil), though there are some permanent gases (CO­2, CO, H2, light hydrocarbons).

Slow pyrolysis-

  • Slow pyrolysis is the slow heating of organic material in absence of oxygen. Instead of combusting, the volatiles from the organic material evaporates partly, and a product (charcoal) remains, consisting of a large part (normally 80%) of carbon.
  • Slow pyrolysis is also called carbonization, and emphasizes the solid charcoal as the main product, instead of fast pyrolysis which emphasizes the liquid product.
  • Biochar is the main product of the slow pyrolysis of biomass.

Question 53

Which of the following are the dominant products of anaerobic digestion of municipal solid waste?

  1. AOption (a)

    CO2 and H2

  2. BOption (b)

    CH4 and CO2

  3. COption (c)

    CH4, CO2, and H2

  4. DOption (d)

    O2 and H2S

View answer & explanation

Correct answer

Answer: (b)B.

CH4 and CO2

Why this answer is correct

The correct answer is: "CH4 and CO2"

Key Points

  • Process of Anaerobic Digestion:
  • Anaerobic digestion is a biological process by which microorganisms break down organic matter in the absence of oxygen.
  • It is widely used in managing municipal solid waste (MSW), sewage sludge, and agricultural residues.
  • Stages of Anaerobic Digestion:
  • Hydrolysis: Complex organic polymers like carbohydrates, fats, and proteins are broken into simple sugars, fatty acids, and amino acids.
  • Acidogenesis: These simple compounds are converted to volatile fatty acids (VFAs), CO2, and hydrogen (H2).
  • Acetogenesis: VFAs are further converted into acetic acid, CO2, and H2.
  • Methanogenesis: Finally, methanogenic archaea convert acetic acid and CO2/H2 into methane (CH4) and carbon dioxide (CO2).
  • Dominant Gaseous Products:
  • The final gas mixture, commonly known as biogas, mainly contains:
  • Methane (CH4): ~50–70%
  • Carbon dioxide (CO2): ~30–50%
  • These two are the dominant products, especially from municipal waste rich in organic matter.

Additional Information

  • CO2 and H2:
  • These gases are intermediate products formed during acidogenesis and acetogenesis.
  • Hydrogen is not a major end-product, as it is consumed during methanogenesis to reduce CO2 into CH4.
  • CH4, CO2, and H2:
  • Although all three can be present, H2 occurs in small, transient amounts, not as a dominant component.
  • Only CH4 and CO2 are dominant and stable in the biogas output.
  • O2 and H2S:
  • Oxygen is absent in anaerobic processes by definition.
  • Hydrogen sulfide (H2S) may be present in trace amounts due to degradation of sulfur-containing compounds, but it is not a dominant product.

Question 54

Ecological engineering is based on which one of the four classes of ecotechnology?

  1. AOption (a)

    Use of ecosystems to reduce a pollution problem

  2. BOption (b)

    Imitation of ecosystems to reduce pollution leading to constructed ecosystems

  3. COption (c)

    Recovery of ecosystems after significant disturbances

  4. DOption (d)

    All of th above

View answer & explanation

Correct answer

Answer: (d)D.

All of th above

Why this answer is correct

The correct answer is All of the above.

Key Points

The following four categories of ecotechnology may serve as the foundation for ecological engineering:

  1. Ecosystems are used to reduce or solve a pollution problem that otherwise would be (more) harmful to other ecosystems. A typical example is the use of wetlands for wastewater treatment.
  2. Ecosystems are imitated or copied to reduce or solve a pollution problem, leading to constructed ecosystems. Examples are fishponds and constructed wetlands for treating wastewater or diffuse pollution sources.
  3. The recovery of ecosystems after significant disturbances. Examples are coal mine reclamation and restoration of lakes and rivers.
  4. The use of ecosystems for the benefit of humanity without destroying the ecological balance (i.e., the utilization of ecosystems on an ecologically sound basis). Typical examples are the use of integrated agriculture and the development of organic agriculture; this type of ecotechnology finds wide application in the ecological management of renewable resources.

Since all statements regarding ecotechnology are correct. Therefore, the correct option should have been all of the above only.

Question 55

What is the maximum period valid for granting Environmental Clearance (EC) for mining projects?

  1. AOption (a)

    30 Years

  2. BOption (b)

    10 Years

  3. COption (c)

    5 Years

  4. DOption (d)

    20 Years

View answer & explanation

Correct answer

Answer: (a)A.

30 Years

Why this answer is correct

The correct answer is 30 Years.

Key Points

Validity of environmental clearance (EC):

  • River valley projects - 10 years
  • Mining - 30 years
  • Other projects/activities - 5 years

The period of validity may be extended by the regulatory authority concerned by a maximum period of five years.

Therefore the correct answer is 30 years.

Additional Information

  • The EIA Notification of 1994 made environmental clearance (EC) mandatory for all new projects and expansion/modernisation of existing projects covering 29 disciplines (later increased to 32 ) which included hydro-power, major irrigation and flood control projects.
  • The following projects or activities require prior environmental clearance from the concerned regulatory authority:
  • ​All new projects or activities, and
  • Expansion and modernization of existing projects or activities with the addition of capacity beyond the limits specified for the concerned sector, that is, projects or activities which cross the threshold limits, after expansion or modernization.
  • All projects or activities included as Category ‘A’ require prior environmental clearance from the Ministry of Environment and Forests (MoEF) on the recommendations of an Expert Appraisal Committee (EAC) to be constituted by the Central Government.
  • All projects or activities included as Category ‘B’ require prior environmental clearance from the State Environment Impact Assessment Authority (SEIAA). The SEIAA shall base its decision on the recommendations of a State Expert Appraisal Committee (SEAC).
  • The environmental clearance process for new projects comprises a maximum of four stages:
  • Stage (1) Screening
  • Stage (2) Scoping
  • Stage (3) Public Consultation
  • Stage (4) Appraisal

Question 56

The Environmental Relief fund was created under :

  1. AOption (a)

    Environmental Protection Act

  2. BOption (b)

    Forest Conservation Act

  3. COption (c)

    Public Liability Insurance Act

  4. DOption (d)

    Wildlife Protection Act

View answer & explanation

Correct answer

Answer: (c)C.

Public Liability Insurance Act

Why this answer is correct

The correct answer is Public Liability Insurance Act.

Key Points

  • The Environment Relief Fund (ERF) was established under the Public Liability Act, 1991 (PLIA), to provide immediate relief to victims of accidents involving hazardous substances.
  • It falls under Section 7A of the Public Liability Act, of 1991.
  • ERF consists of compensation awarded by the National Green Tribunal (NGT) for damage to the environment under Section 24 of the NGT Act, 2010.

​Therefore, the correct answer is Public Liability Act.

Additional Information

  • The Environment (Protection) Act was enacted in 1986 with the objective of providing for the protection and improvement of the environment. 
  • It empowers the Central Government to establish authorities charged with the mandate of preventing environmental pollution in all its forms and tackling specific environmental problems that are peculiar to different parts of the country.
  • The Act was last amended in 1991.
  • The Forest (Conservation) Act of 1980 is an act by the Parliament of India which ensures the conservation of forests and their resources.​
  • The Act restricts the state government and other authorities from taking decisions first without permission from the central government.
  • This Act also provides penalties for the infringement of the provisions of this Act.
  • The Wild Life (Protection) Act, 1972 is an Act of the Parliament of India enacted for the protection of plants and animal species.
  • The Act provides for the formation of wildlife advisory boards, and wildlife wardens specify their powers and duties, etc.
  • It helped India become a party to the Convention on International Trade in Endangered Species of Wild Fauna and Flora (CITES).
  • Its provisions paved the way for the formation of the Central Zoo Authority.
  • The Act created six schedules which gave varying degrees of protection to classes of flora and fauna.

Question 57

Which one of the categories of development projects does NOT require an Environmental Impact Assessment (EIA) report?

  1. AOption (a)

    Category 'A' projects

  2. BOption (b)

    Category 'B2' projects

  3. COption (c)

    Category 'B1' projects

  4. DOption (d)

    Category 'B1' and 'B2' projects

View answer & explanation

Correct answer

Answer: (b)B.

Category 'B2' projects

Why this answer is correct

The correct answer is Category 'B2' projects.

Key Points

  • According to the EIA notification 2006, all projects and activities are broadly categorized into two categories - Category A and Category B.
  • All projects or activities included as Category ‘A’ require prior environmental clearance from the Central Government in the Ministry of Environment and Forests (MoEF) on the recommendations of an Expert Appraisal Committee (EAC) to be constituted by the Central Government.
  • All projects or activities included as Category ‘B’ require prior environmental clearance from the State/Union Territory Environment Impact Assessment Authority (SEIAA).
  • The projects requiring an Environmental Impact Assessment report shall be termed Category ‘B1’.
  • The projects which do not require an Environmental Impact Assessment report shall be termed Category ‘B2’.

Therefore, the correct answer is Category ‘B2’.

Question 58

A random variable X follows Poisson distribution such that probabilities P(X = 1) = P(X = 2). Now consider the following statements :

A. The mean of this Poisson distribution is 2.

B. The variance of this Poisson distribution is 2.

C. Probability P(X = 0) is equal to e-2

D. Probability P(X = 0) = P(X = 1)

Choose the correct answer from the options given below

  1. AOption (a)

    A, B, and C only

  2. BOption (b)

    B, C and D only

  3. COption (c)

    A, B and D only

  4. DOption (d)

    A, C and D only

View answer & explanation

Correct answer

Answer: (a)A.

A, B, and C only

Why this answer is correct

The correct answer is A, B, and C only.

Key Points

  • Probability of Poisson distribution:

​

Hence, Mean = 2

  • In the case of Poison distribution of this type,

          μ = variance

Therefore, variance = 2

  • By solving P(x=1) = P(x=2), we concluded μ = 2.
  • Applying this value in the below equation.

​

 

The answer is e-2.

Therefore, only A, B, and C are correct.

Question 59

Given below are two statements : one is labelled as Assertion A and other is labelled as Reason R

Assertion A : Some countries are immune to the impacts of climate change

Reason R : The net contribution of some countries is less than 1% towards the global CO2 emissions as a whole.

In light of the above statements, choose the correct answer from the options given below

  1. AOption (a)

    Both A and R are true and R is the correct explanation of A

  2. BOption (b)

    Both A and R are true but R is NOT the correct explanation of A

  3. COption (c)

    A is true but R is false

  4. DOption (d)

    A is false but R is true

View answer & explanation

Correct answer

Answer: (d)D.

A is false but R is true

Why this answer is correct

Explanation

  • Climate change refers to the variability in the average weather conditions that are measured for a long period or decades.
  • Many consequences are there due to this climate change.
  • According to Inter-governmental Panel on Climate Change (IPCC), there are some countries that are resilient but not immune to climate change.
  • The top countries ranked by resilience to climate change include Norway, New Zealand, Finland, Denmark, and Sweden. Therefore, A is false.
  • These countries are resilient to climate change because of the measures taken to tackle the effects including green buildings, reduced use of fossil fuels, use of renewable energy, etc.
  • Nearly, 46 least-developed countries (LDCs) which have just 14% of the world population have higher contributions to CO2 emissions.
  • But, there are some countries, which contribute less than 1% of carbon-dioxide emissions
  • Recently held Conference of Parties, COP-26 referred that three of the world’s smallest nations – Bhutan, Suriname, and Panama – stood out from the rest by showing that they absorb more greenhouse gas than they emit.
  • This is mainly by the carbon-negative actions taken throughout the nations. Therefore, R is true.

​Hence, option 4 is the correct answer.

Question 60

Given below are two statements : One is labelled as Assertion A and other is labelled as Reason R

Assertion A : Solar and wind energy systems require quite large structures relative to power produced.

Reason R : Energy flux densities associated with solar energy and wind energy are on average small.

In light of the above statements, choose the most appropriate answer from the options given below

  1. AOption (a)

    Both A and R are correct and R is the correct explanation of A

  2. BOption (b)

    Both A and R are correct but R is NOT the correct explanation of A

  3. COption (c)

    A is correct but R is not correct

  4. DOption (d)

    A is not correct but R is correct

View answer & explanation

Correct answer

Answer: (a)A.

Both A and R are correct and R is the correct explanation of A

Why this answer is correct

Explanation:

  • The standard solar panel size, the 60-cell is structured as a 6×10 grid and measures 3.25 feet by 5.5 feet.
  • The average 72-cell solar panel size measures 3.25 feet by 6.42 feet and is laid out as a 6 x 12 grid, making them almost a foot taller than the 60-cell standard-size panels.
  • The average rotor diameter in 2021 was 127.5 meters (418 feet)—longer than a football field.
  • Larger rotor diameters allow wind turbines to sweep more area, capture more wind, and produce more electricity.

Therefore, A is true.

  • The energy per unit area per unit time passing through a plane perpendicular to the wave, called the energy flux and denoted by S, can be calculated by dividing the energy by the area A and the time interval Δ t.
  • Low energy flux density is the shared characteristic of almost all renewable energy sources. Therefore, B is true.
  • The mean and 90-percentile power densities for wind are 0.50 and 0.80 We m−2, while the corresponding values for solar are 5.4 and 7.1 We m−2.

​Hence, option 1 is the correct answer.

Question 61

Given below are two statements : one is labelled as Assertion A and other is labelled as Reason R

Assertion A : Hydrofluorocarbons (HFCs) and hydrochlorofluorocarbon (HCFCs) are used as substitute compounds for chlorofluorocarbons (CFCs)

Reason R : HCFCs and HFCs are quite susceptible to reaction with OH radicals in the troposphere

In light of the above statements, choose the correct answer from the options given below

  1. AOption (a)

    Both A and R are true and R is the correct explanation of A

  2. BOption (b)

    Both A and R are true but R is NOT the correct explanation of A

  3. COption (c)

    A is true but R is false

  4. DOption (d)

    A is false but R is true

View answer & explanation

Correct answer

Answer: (a)A.

Both A and R are true and R is the correct explanation of A

Why this answer is correct

The correct option is 'Both (A) and (R) are true and (R) is the correct explanation of (A)'.

Key Points

  • Assertion A: Hydrofluorocarbons (HFCs) and hydrochlorofluorocarbons (HCFCs) are used as substitute compounds for chlorofluorocarbons (CFCs).
  • This statement is true.
  • Environmental Concerns: CFCs were widely used in refrigeration, air conditioning, foam production, and as propellants in aerosol sprays. However, they were found to be major contributors to ozone layer depletion, prompting the search for safer alternatives.
  • International Agreements: The Montreal Protocol, an international treaty adopted in 1987, aimed to phase out the production and consumption of ozone-depleting substances, including CFCs. HFCs and HCFCs were introduced as less harmful alternatives.
  • Reason R: HCFCs and HFCs are quite susceptible to reaction with OH radicals in the troposphere.
  • This statement is true.
  • Atmospheric Chemistry: Hydroxyl (OH) radicals are highly reactive molecules that play a crucial role in the chemical transformation of pollutants in the atmosphere. They help to break down various compounds, including HCFCs and HFCs.
  • Decomposition Process: When HCFCs and HFCs are emitted into the atmosphere, they undergo reactions with OH radicals in the troposphere. This significantly reduces their atmospheric lifetime compared to CFCs, which are less susceptible to such reactions and can persist longer, reaching the stratosphere and causing more harm to the ozone layer.
  • Evaluation of the Relationship Between A and R:
  • Both the assertion and the reason are accurate and interlinked.
  • The reason explains why HFCs and HCFCs are preferred over CFCs. Their susceptibility to reacting with OH radicals means they degrade faster in the troposphere. This reduces the likelihood of them reaching the stratosphere and causing significant ozone depletion, thus making them better alternatives.
  • Therefore, the reason (R) directly supports and provides a correct explanation for the assertion (A).

Additional Information

  • Environmental Impact: The introduction of HFCs and HCFCs was largely driven by environmental needs. CFCs were recognized as primary culprits in creating the ozone hole over Antarctica, which led to stringent regulations and the search for safer alternatives.
  • Montreal Protocol: This treaty has been one of the most successful international environmental agreements. It has led to the significant reduction in the use of ozone-depleting substances, contributing to the gradual recovery of the ozone layer.
  • OH Radicals: Hydroxyl radicals are often referred to as the "detergent" of the atmosphere due to their role in decomposing a wide range of atmospheric pollutants. Their reaction with HCFCs and HFCs makes these substitutes shorter-lived in the lower atmosphere.

Question 62

Given below are two statements : one is labelled as Assertion A and other is labelled as Reason R

Assertion A : Regression analysis is suitable for two variables having a linear causal relationship between them.

Reason R : The causal relationship between two variables is never curvilinear.

In light of the above statements, choose the most appropriate answer from the options given below

  1. AOption (a)

    Both A and R are correct and R is the correct explanation of A

  2. BOption (b)

    Both A and R are correct but R is NOT the correct explanation of A

  3. COption (c)

    A is correct but R is not correct

  4. DOption (d)

    A is not correct but R is correct

View answer & explanation

Correct answer

Answer: (c)C.

A is correct but R is not correct

Why this answer is correct

Explanation:

  • Regression analysis is a set of statistical methods used for the estimation of relationships between a dependent variable and one or more independent variables. Therefore, A is true.
  • It can be utilized to assess the strength of the relationship between variables and for modeling the future relationship between them.
  • Regression analysis includes several variations, such as linear, multiple linear, and nonlinear. The most common models are simple linear and multiple linear.
  • Nonlinear regression analysis is commonly used for more complicated data sets in which the dependent and independent variables show a nonlinear relationship. This includes a curvilinear relationship between the variables. Therefore, R is false.

Hence, option 3 is the correct answer.

Additional Information:

Simple Linear Regression

Simple linear regression is a model that assesses the relationship between a dependent variable and an independent variable. The simple linear model is expressed using the following equation:

Y = a + bX + ϵ

Where:

  • Y – Dependent variable
  • X – Independent (explanatory) variable
  • a – Intercept
  • b – Slope
  • ϵ – Residual (error)

Read the given passage and answer the questions that follow

The fermentation products prior to 1900 AD were confined to potable alcohol and vinegar. However, the first true large-scale breweries date from the 1700s AD when wooden vats of 1500 barrels capacity were introduced. By the mid-1800s AD, the role of yeasts in alcohol fermentation had been demonstrated independently by Cagniard-Latour, Schwann and Kutzing but it was Louis Pasteur who convinced the scientific world of the obligatory role of micro-organisms in the process. During the 1800s AD, Hansen started his pioneering work for isolating and propagating single yeast cells to produce pure culture. However, many traditional ale-producing breweries still use mixed yeast cultures. Vinegar was originally produced by leaving wine in shallow bowls or partially filled barrels where it was slowly oxidized to vinegar by the development of natural flora. The appreciation of the importance of air in the process led to the development of the 'generator. Between the years, 1900 AD and 1940 AD, the most important advances were the development in the baker's yeast, solvent fermentation, citric acid production and lactic acid production.

Question 63

Vinegar is a product of

  1. AOption (a)

    Solvent fermentation

  2. BOption (b)

    Alcoholic fermentation

  3. COption (c)

    Aerobic fermentation

  4. DOption (d)

    Anaerobic fermentation

View answer & explanation

Correct answer

Answer: (c)C.

Aerobic fermentation

Why this answer is correct

The correct answer is Aerobic fermentation.

Key Points

  • Take a look at the sixth sentence of the passage:
  • ​Vinegar was originally produced by leaving wine in shallow bowls or partially filled barrels where it was slowly oxidized to vinegar by the development of natural flora.
  • ​Thus, it can be concluded that vinegar is produced by the oxidation of wine which is carried out in the presence of oxygen. The whole process is called aerobic fermentation.

​​Therefore, the correct answer is aerobic fermentation.

Question 64

Many traditional ale-producing breweries use

  1. AOption (a)

    Yeast pure culture

  2. BOption (b)

    Mixed culture of bacteria

  3. COption (c)

    Mixed culture of yeasts

  4. DOption (d)

    Bakers' yeast

View answer & explanation

Correct answer

Answer: (c)C.

Mixed culture of yeasts

Why this answer is correct

The correct answer is Mixed culture of yeasts.

Key Points

  • Examine the fifth sentence of the passage:
  • ​However, many traditional ale-producing breweries still use mixed yeast cultures.

​Therefore, the correct answer is mixed yeast cultures.

Question 65

Who among the following first developed the method of producing a pure culture of yeasts?

  1. AOption (a)

    Cagniard-Latour

  2. BOption (b)

    Hansen

  3. COption (c)

    Louis Pasteur

  4. DOption (d)

    Schwann and Kutzing

View answer & explanation

Correct answer

Answer: (b)B.

Hansen

Why this answer is correct

The correct answer is Hansen.

Key Points

  • Consider the fourth sentence of the passage:
  • ​Hansen started his pioneering work by isolating and propagating single yeast cells to produce pure culture.

​​Therefore, the correct answer is Hansen.

Question 66

In pre-1900s AD, which types of vessels were used in large-scale breweries?

  1. AOption (a)

    Wooden

  2. BOption (b)

    Copper

  3. COption (c)

    Steel

  4. DOption (d)

    Mechanical fermenters

View answer & explanation

Correct answer

Answer: (a)A.

Wooden

Why this answer is correct

The correct answer is Wooden.

Key Points

  • Take a look at the second sentence of the passage:
  • However, the first true large-scale breweries date from the 1700s AD when wooden vats of 1500 barrels capacity were introduced.

​​​Therefore, the correct answer is wooden.​

Question 67

Which among the following is one of the oldest products of fermentation technology?

  1. AOption (a)

    Bakers' yeast

  2. BOption (b)

    Yeast biomass

  3. COption (c)

    Lactic acid

  4. DOption (d)

    Alcohol

View answer & explanation

Correct answer

Answer: (d)D.

Alcohol

Why this answer is correct

The correct answer is Alcohol.

Key Points

  • Analyze the first sentence of the passage:
  • ​The fermentation products prior to 1900 AD were confined to potable alcohol and vinegar.
  • ​Analyze the last sentence of the passage:
  • ​Between the years, 1900 AD and 1940 AD, the most important advances were the development of the baker's yeast, solvent fermentation, citric acid production and lactic acid production.
  • ​When we analyse these two sentences and the passage as a whole, it can be concluded that the oldest product of fermentation technology has been the production of alcohol. It was after 1900 AD that the development of other products of fermentation like baker's yeast, citric acid and lactic acid started taking place.

​Therefore, the correct answer is alcohol.

Question 68

Soil humic acids are

  1. AOption (a)

    Insoluble in alkali

  2. BOption (b)

    Insoluble in acid

  3. COption (c)

    Soluble in acid

  4. DOption (d)

    Insoluble in both acid and alkali

View answer & explanation

Correct answer

Answer: (b)B.

Insoluble in acid

Why this answer is correct

Concepts:

  • Humic acids (HA) are organic molecules that play essential roles in improving soil properties, plant growth, and agronomic parameters.
  • The sources of HA include coal, lignite, soils, and organic materials.
  • Humic acid-based products have been used in crop production in recent years to ensure the sustainability of agriculture production.
  • HA can positively affect soil physical, chemical, and biological characteristics, including texture, structure, water holding capacity, cation exchange capacity, pH, soil carbon, enzymes, nitrogen cycling, and nutrient availability.
  • Humic substances are complex, heterogeneous molecules that are operationally defined on the basis of solubility fulvic acid is completely soluble in aqueous solution whereas humic acid is “soluble” in alkali but precipitates in acid solutions.

Question 69

The most toxic form of mercury in water is 

  1. AOption (a)

    Hg2+

  2. BOption (b)

    H3C - Hg+

  3. COption (c)

    Hg0

  4. DOption (d)

    Hg+

View answer & explanation

Correct answer

Answer: (b)B.

H3C - Hg+

Why this answer is correct

Concept:

Toxicity of Mercury:

  • The toxic effects of mercury depend on its chemical form and the route of exposure.
  • Methylmercury [CH3Hg] is the most toxic form.
  • The most toxic form of mercury in water is H3C - Hg+
  • It affects the immune system, alters genetic and enzyme systems, and damages the nervous system, including coordination and the senses of touch, taste, and sight.
  • Methylmercury is particularly damaging to developing embryos, which are five to ten times more sensitive than adults.
  • Exposure to methylmercury is usually by ingestion, and it is absorbed more readily and excreted more slowly than other forms of mercury.
  • Elemental mercury, (Hg), the form released from broken thermometers, causes tremors, gingivitis, and excitability when vapors are inhaled over a long period of time.
  • Although it is less toxic than methylmercury, elemental mercury may be found in higher concentrations in environments such as gold mine sites, where it has been used to extract gold.
  • If elemental mercury is ingested, it is absorbed relatively slowly and may pass through the digestive system without causing damage.
  • Ingestion of other common forms of mercury, such as the salt HgCl2, which damages the gastrointestinal tract and causes kidney failure, is unlikely from environmental sources.

Question 70

One Dobson unit, represents the ozone layer of thickness

  1. AOption (a)

    One-hundredth of a centimeter

  2. BOption (b)

    One-tenth of a centimetre

  3. COption (c)

    One-hundredth of a millimeter

  4. DOption (d)

    One-thousandth of a millimeter

View answer & explanation

Correct answer

Answer: (c)C.

One-hundredth of a millimeter

Why this answer is correct

Concept-

Dobson unit-

  • The Dobson Unit is the most common unit for measuring ozone concentration.
  • One Dobson Unit is the number of molecules of ozone that would be required to create a layer of pure ozone 0.01 millimeters (One-hundredth of a millimeter) thick at a temperature of 0 degrees Celsius and a pressure of 1 atmosphere (the air pressure at the surface of the Earth).
  • Expressed another way, a column of air with an ozone concentration of 1 Dobson Unit would contain about 2.69x1016 ozone molecules for every square centimeter of an area at the base of the column.
  • Over the Earth’s surface, the ozone layer’s average thickness is about 300 Dobson Units or a layer that is 3 millimeters thick.

Important Points

  • The Richter magnitude scale was developed in 1935 by Charles F. Richter of the California Institute of Technology as a mathematical device to compare the magnitudes of earthquakes.
  • The decibel (abbreviated dB) is the unit used to represent the intensity of sound.

Question 71

Beside steam, next gas in order of abundance emitted from a volcanic eruption is

  1. AOption (a)

    Sulphur dioxide

  2. BOption (b)

    Nitrogen dioxide

  3. COption (c)

    Carbon dioxide

  4. DOption (d)

    Carbon monoxide

View answer & explanation

Correct answer

Answer: (c)C.

Carbon dioxide

Why this answer is correct

The correct answer is Carbon dioxide.

Key Points

The components of volcanic gases are water vapour (H2O), carbon dioxide (CO2), sulfur either as sulfur dioxide (SO2) hydrogen sulfide (H2S), nitrogen, argon, helium, neon, methane, carbon monoxide, and hydrogen.

The proportion of different gases in volcanic eruption are:

  • Water vapour — 50 - 90%
  • Carbon dioxide — 1 - 40%
  • Sulphur dioxide — 1 - 25%
  • Hydrogen sulfide — 1 - 10%
  • Hydrogen chloride — 1 - 10%
  • Other gases found in lower amounts include carbon disulfide, carbonyl sulfide, and hydrogen fluoride.

Therefore, after water vapour (steam), carbon dioxide is the next abundant gas in a volcanic eruption.

Question 72

A Si-solar cell has the minority carrier saturation current = 60 nAm-2 and solar radiation-induced current = 600 Am-2. If the ambient temperature is 27°C, what is the open-circuit voltage of the solar cell?

  1. AOption (a)

    ∼ 0.6 V

  2. BOption (b)

    ∼ 0.45 V

  3. COption (c)

    ∼ 0.5 V

  4. DOption (d)

    ∼ 1.5 V

View answer & explanation

Correct answer

Answer: (a)A.

∼ 0.6 V

Why this answer is correct

Calculation:

Given:

Saturation current = 60 nAm-2

Solar radiation-induced current = 600 Am

Temperature = 27°C

As we know that Open-circuit current, 

Voc  =  kBTqln(Jph) (Jo)\frac{k_BT}{q}ln {(J_{ph}) \ {} \over (J_o)}

Voc = open-circuit voltage of the solar cell

kBTq\frac{k_BT}{q}= thermal voltage (25.85 mV at 300 K)

Jph = solar radiation-induced current

Jo = minority saturation current or dark current

Voc  = kBTqln(Jph) (Jo)\frac{k_BT}{q}ln {(J_{ph}) \ {} \over (J_o)}

Voc = 0.2585 ln(600) (60)ln {(600) \ {} \over (60)}

Voc = 0.2585 ln=(10)ln = (10)

Voc = 0.2585 × 2.3025 = 0.5951 = ~0.6 V

Therefore, Voc = ~0.6 V

Question 73

Which one among the following Solar Collectors has the highest Concentration Ratio or CR value (a measure of the efficiency of the Solar Collectors)?

  1. AOption (a)

    Compound Parabolic Collector with a plane receiver

  2. BOption (b)

    Cylindrical Parabolic Collector

  3. COption (c)

    Fresnel Lens Collector

  4. DOption (d)

    Paraboloid dish collector

View answer & explanation

Correct answer

Answer: (d)D.

Paraboloid dish collector

Why this answer is correct

The correct answer is Paraboloid dish collector.

Key Points

  • A solar parabolic dish is a type of solar collector that uses a parabolic reflector to focus sunlight onto a central receiver, where the solar energy is absorbed and converted into heat.
  • It accomplishes this through the use of a computer and dual-axis tracking.
  • Within CSP technologies, parabolic dish concentrators are the most efficient of all solar collector types due to a combination of dual-axis tracking and a high concentration ratio.
  • The dishes are laid out on a solar field with spacing to minimize collisions and shading of the collector while allowing sufficient access for maintenance and minimizing the pipework and parasitic pumping energy for the heat transfer fluid.
  • The operating temperature of the system is over 1800 K while the concentration ratio is in the range between 1000 and 5000 K.

Therefore, the solar collector that has the highest concentration ratio is a paraboloid dish collector.

Additional Information

  • A compound parabolic collector with a plane receiver has a concentration ratio of 1.7.
  • Fresnel lens collector has a concentration ratio of 1500.
  • The cylindrical parabolic collector has a concentration ratio of 20.

Question 74

In the 'A' weighting network used in noise measurements, sounds of which of the following frequencies would require the least correction?

  1. AOption (a)

    31.5 Hz

  2. BOption (b)

    125 Hz

  3. COption (c)

    1000 Hz

  4. DOption (d)

    12500 Hz

View answer & explanation

Correct answer

Answer: (c)C.

1000 Hz

Why this answer is correct

Explanation:

  • Frequency weightings are used to measure and report noise levels in a sound level meter or noise dosimeter.
  • The most used frequency weightings are A, C, and Z.
  • ‘A’ Frequency Weighting - This is the standard weighting of the audible frequencies and reflects the response of the human ear to noise. The frequency of 1000 Hz has the least correction.
  • ‘C’ Frequency weighting - Used for the measurement of Peak Sound Pressure level.
  • ‘Z’ Frequency weighting - It is a flat frequency response between 10 Hz and 20 kHz ±1.5 dB excluding microphone response.

Question 75

Given below are two statements : one is labelled as Assertion A and other is labelled as Reason R

Assertion A : Isomorphous substitution is the source of constant charges on soil silicate clays.

Reason R : Cations of comparable size substitute each other in respective tetrahedral and octahedral sheets in silicate clays.

In light of the above statements, choose the correct answer from the options given below

  1. AOption (a)

    Both A and R are true and R is the correct explanation of A

  2. BOption (b)

    Both A and R are true but R is NOT the correct explanation of A

  3. COption (c)

    A is true but R is false

  4. DOption (d)

    A is false but R is true

View answer & explanation

Correct answer

Answer: (a)A.

Both A and R are true and R is the correct explanation of A

Why this answer is correct

The correct answer is Both A and R are true and R is the correct explanation of A.

Key Points

  • The process of replacing one structural cation for another of similar size is referred to as isomorphous substitution.
  • This replacement represents the primary source of both negative and positive charges in clay minerals.
  • The importance of isomorphous substitution is that it produces a net negative charge in clays.
  • This charge must be balanced by positively charged ions from the solution.
  • It is the source of constant charge on soil silicate particles.
  • The important thing to remember is that isomorphic substitution only occurs between cations of similar ionic radii.

Example:

  • Isomorphic substitution of Mg2+ for Al3+ in the octahedral layer of a 2:1 clay mineral.
  • Therefore, cations of comparable size substitute each other in respective tetrahedral and octahedral sheets in silicate clays.

Therefore, both the assertion and reason are correct and reason correctly explains the assertion.

Question 76

Yaw control used in wind turbine generator is a :

  1. AOption (a)

    Microprocessor-based control unit

  2. BOption (b)

    The mechanism to keep the rotor axis along wind direction.

  3. COption (c)

    The mechanism to keep the rotor axis perpendicular to wind direction.

  4. DOption (d)

    Gear mechanism to control the speed of the rotor when wind speed is extremely high

View answer & explanation

Correct answer

Answer: (b)B.

The mechanism to keep the rotor axis along wind direction.

Why this answer is correct

Explanation

  • Yaw is one of the components of a wind turbine.
  • It is used to turn the turbine rotor against the wind.
  • Almost all horizontal-axis wind turbines use forced yawing, i.e. they use a mechanism that uses electric motors and gearboxes to keep the turbine yawed against the wind.
  • The yaw mechanism is activated by the electronic controller which several times per second checks the position of the wind vane on the turbine, whenever the turbine is running.
  • The Yaw error would occur in the wind turbine when the rotor is not perpendicular to the wind.​

Hence, option 2 is the correct answer.

Question 77

Regarding Bharat Stage (BS-VI) vehicular emissions norms, choose the correct statements :

A. BS (VI) emission norms are equivalent to Euro (VI) norms.

B. BS (VI) norms require the up-gradation of engine and emission control technology

C. BS(VI) norms are applicable to all categories of the vehicles including two, three and four- wheelers.

D. BS (VI) norms do not require any change in fuel quality

Choose the correct answer from the options given below

  1. AOption (a)

    A, B, C, only

  2. BOption (b)

    B, C, D only

  3. COption (c)

    A, C, D only

  4. DOption (d)

    A, B, C, D - All

View answer & explanation

Correct answer

Answer: (a)A.

A, B, C, only

Why this answer is correct

Explanation:

  • Bharat stage emission standards (BSES) are emission standards instituted by the Government of India to regulate the output of air pollutants from compression ignition engines and Spark-ignition engine equipment, including motor vehicles.
  • The standards and the timeline for implementation are set by the Central Pollution Control Board under the Ministry of Environment, Forest and Climate Change.
  • The standards, based on European regulations were first introduced in 2000. Therefore, A is correct.
  • To regulate the pollution emitted by cars and two-wheelers, the Government of India has placed set forth regulations known as Bharat Stage Emission Standards (BSES).
  • BS VI norms the upgradation of engine and emission control technology. Therefore, B is correct.
  • The Central Government has mandated that every vehicle manufacturer, each two-wheeler, three-wheeler, and four-wheeler, ought to manufacture, sell and register solely BS6 (BSVI) vehicles from 1 April 2020. Therefore, C is correct.
  • The fuel types include petroleum distillate vehicles and diesel fuel vehicles with nitrogen oxide (60 mg)  and particulate matter limit(4.5 mg/km)  was assigned. Therefore, D is not correct.

​Hence, option 1 is the correct answer.

Question 78

Which among the following atmospheric constituents have a negative radiative forcing?

A. Tropospheric ozone

B. Stratospheric ozone

C. Sulphate Aerosol

D. Nitrous oxide

Choose the correct answer from the options given below

  1. AOption (a)

    A and B only

  2. BOption (b)

    B and C only

  3. COption (c)

    C and D only

  4. DOption (d)

    A and D only

View answer & explanation

Correct answer

Answer: (b)B.

B and C only

Why this answer is correct

Concept-

  • Radiative forcing (or climate forcing) is the change in energy flux in the atmosphere caused by natural or anthropogenic factors of climate change as measured by watts / metre2.
  • It is a scientific concept used to quantify and compare the external drivers of change to Earth's energy balance.
  • Positive radiative forcing means Earth receives more incoming energy from sunlight than it radiates to space. This net gain of energy will cause warming.
  • Conversely, negative radiative forcing means that Earth loses more energy to space than it receives from the sun, which produces cooling.
  • A planet in radiative equilibrium with its parent star and the rest of space can be characterized by net zero radiative forcings and by a planetary equilibrium temperature.
  • Positive forcing” is exerted by climatic factors that contribute to the warming of the Earth’s surface, whereas “negative forcing” is exerted by factors that cool the Earth’s surface.
  • Anthropogenic increases in carbon dioxide, methane, nitrous oxide, halogenated gases, and other factors are estimated to account for 2.72 watts per square meter of positive radiative forcing.
  • Tropospheric ozone has a positive radiative forcing.
  • Stratospheric ozone and Sulphate Aerosol have a negative radiative forcing.

Read the given passage carefully and answer the questions that follow

The colour photograph of Earthrise, taken by Apollo 8 astronaut William A. Anders on December 24, 1968, is a powerful and eloquent image. One leading environmentalist has rightfully described it as "the most influential environmental photograph ever taken". Inspired by the photograph, economist Kenneth E. Boulding summed up the finite nature of our planet as viewed in the context of the vast expanse of space in his metaphor "Spaceship Earth". What had been perceived throughout human history as a limitless frontier had suddenly become a tiny sphere: limited in its resources, crowded by an ever-expanding human population, and threatened by our use of the atmosphere and the oceans as repositories for our consumptive wastes.

Question 79

Perception of the planet Earth before 1968 was that it had

  1. AOption (a)

    Infinite resources

  2. BOption (b)

    Limited resources

  3. COption (c)

    Finite carrying capacity

  4. DOption (d)

    Scarce resources

View answer & explanation

Correct answer

Answer: (a)A.

Infinite resources

Why this answer is correct

The correct answer is Infinite resources.

Key Points

Analyze the first sentence of the passage:

  • ​The colour photograph of Earthrise, taken by Apollo 8 astronaut William A. Anders on December 24, 1968, is a powerful and eloquent image.​

Analyze the last sentence of the passage:

  • What had been perceived throughout human history as a limitless frontier had suddenly become a tiny sphere: limited in its resources, crowded by an ever-expanding human population, and threatened by our use of the atmosphere and the oceans as repositories for our consumptive wastes.
  • ​Thus it can be concluded that before 1968 when the colour photograph of Earthrise was taken by Apollo 8 astronaut William A. Anders, there was a perception that planet Earth had infinite resources.

Therefore, the correct answer is infinite resources.

Question 80

Carrying capacity of the Earth is threatened by

A. Human population explosion

B. Irrational use of atmosphere

C. Dumping of consumptive wastes in the ocean

D. Development of space technology

  1. AOption (a)

    A, C and D only

  2. BOption (b)

    B, C and D only

  3. COption (c)

    A, B and C only

  4. DOption (d)

    A, B and D only

View answer & explanation

Correct answer

Answer: (c)C.

A, B and C only

Why this answer is correct

The correct answer is A, B and C only.

Key Points

Consider the last sentence of the passage:

  • ​What had been perceived throughout human history as a limitless frontier had suddenly become a tiny sphere: limited in its resources, crowded by an ever-expanding human population, and threatened by our use of the atmosphere and the oceans as repositories for our consumptive wastes.
  • ​When we analyse this sentence, it can be concluded that with the passage of time, the resources of the Earth have decreased which has threatened the overall carrying capacity of the Earth.
  • The reasons for this are the ever-expanding human population, irrational use of our atmosphere and dumping wastes into the oceans.

​​​Therefore, the correct answer is A, B and C only.

Question 81

Perception about the planet Earth is that, it is a

  1. AOption (a)

    Tiny life support system

  2. BOption (b)

    Vast life support system

  3. COption (c)

    Vast expanse of space

  4. DOption (d)

    Limitless frontier in its extent

View answer & explanation

Correct answer

Answer: (a)A.

Tiny life support system

Why this answer is correct

The correct answer is the Tiny life support system.

Key Points

  • Examine the last sentence of the passage:
  • ​What had been perceived throughout human history as a limitless frontier had suddenly become a tiny sphere: limited in its resources, crowded by an ever-expanding human population, and threatened by our use of the atmosphere and the oceans as repositories for our consumptive wastes.
  • ​Thus, it can be concluded that the earth is a tiny sphere which has resources to support the life on it in the whole vast universe.

​Therefore, the correct answer is the tiny life support system.

Question 82

The metaphor "Spaceship Earth" was used to described the Earth as

  1. AOption (a)

    Tiny sphere in the vast universe

  2. BOption (b)

    Repository of natural resources

  3. COption (c)

    Consisting of modern space infrastructure

  4. DOption (d)

    Unmanned spacecraft

View answer & explanation

Correct answer

Answer: (a)A.

Tiny sphere in the vast universe

Why this answer is correct

The correct answer is a Tiny sphere in the vast universe.

Key Points

  • Take a look at the third sentence of the passage:
  • ​Inspired by the photograph, economist Kenneth E. Boulding summed up the finite nature of our planet as viewed in the context of the vast expanse of space in his metaphor "Spaceship Earth".
  • ​Thus the metaphor "Spaceship Earth" is used to describe the Earth as a tiny part of vast space.

​Therefore, the correct answer is the tiny sphere in the vast universe.

Question 83

Inference of the passage is that the Earth is an ecosystem of

  1. AOption (a)

    Infinite carrying capacity

  2. BOption (b)

    Infinite resources for exploitation

  3. COption (c)

    Finite carrying capacity

  4. DOption (d)

    Unlimited power of self-sustenance

View answer & explanation

Correct answer

Answer: (c)C.

Finite carrying capacity

Why this answer is correct

The correct answer is Finite carrying capacity.

Key Points

  • Take a look at the last sentence of the passage:
  • ​What had been perceived throughout human history as a limitless frontier had suddenly become a tiny sphere: limited in its resources, crowded by an ever-expanding human population, and threatened by our use of the atmosphere and the oceans as repositories for our consumptive wastes.
  • ​By analyzing this sentence and the passage as a whole, we can infer that the Earth is a tiny part of the vast universe that supports life on it. Before 1968 it was presumed that the Earth had infinite resources but after 1968, it was concluded that there are finite resources on the Earth which means that there is a finite carrying capacity of the Earth to support the life on it.

​Therefore, the correct answer is finite carrying capacity.

Question 84

Volatile Organic Compounds (VOCs) are of great concern because :

  1. AOption (a)

    Once such compounds are in the vapour state, they are difficult to control in the environment.

  2. BOption (b)

    Most of them are ozone depleting substances

  3. COption (c)

    They contribute to a general increase in reactive hydrocarbons in the atmosphere.

  4. DOption (d)

    They are less soluble in water.

View answer & explanation

Correct answer

Answer: (c)C.

They contribute to a general increase in reactive hydrocarbons in the atmosphere.

Why this answer is correct

The correct answer is They contribute to a general increase in reactive hydrocarbons in the atmosphere.

Key Points

Volatile organic compounds (VOC):

  • Volatile organic compounds (VOC) means any compound of carbon, excluding carbon monoxide, carbon dioxide, carbonic acid, metallic carbides or carbonates and ammonium carbonate, which participates in atmospheric photochemical reactions
  • Their composition makes it possible for them to evaporate under normal indoor atmospheric conditions of temperature and pressure.
  • A VOC is any organic compound having an initial boiling point less than or equal to 250° C measured at a standard atmospheric pressure of 101.3 kPa.
  • When VOCs react with the OH radical, they in turn are converted into reactive free radicals and hydrocarbons that react with nitric oxide. This reaction eventually leads to the production of tropospheric ozone.
  • Some VOCs are more reactive than others so even relatively small emissions of more reactive VOCs may contribute significantly to the rates of ozone production.
  • VOCs in the atmosphere include saturated, unsaturated, aromatic, and a variety of other substituted hydrocarbons. They are emitted from anthropogenic and natural sources mainly as gaseous, often nonpolar, compounds of high vapour pressure.

Therefore, volatile organic compounds (VOCs) are of great concern because they contribute to a general increase in reactive hydrocarbons in the atmosphere.

Question 85

Hyperthermophilic microorganisms prefer temperatures in excess of.

  1. AOption (a)

    45° C

  2. BOption (b)

    80° C

  3. COption (c)

    65° C

  4. DOption (d)

    70° C

View answer & explanation

Correct answer

Answer: (b)B.

80° C

Why this answer is correct

The correct answer is 80° C.

Key PointsClassification of microorganisms on the basis of temperature required for their growth:

MicroorganismsTemperature range (in °C)
Psychrophiles- 20 to 10
Mesophiles20 to 45
Thermophiles45 to 70
Hyperthermophiles80 to 110

 

 

 

 

Therefore, hyperthermophilic microorganisms prefer temperatures in excess of 80°C.

Additional Information

  • Psychrophilic microorganisms are called cold-loving microbes. They live in permanently cold environments such as polar regions and the deep sea.
  • ​​Examples: Pseudoalteromonas, Moraxella, Psychrobacter, Flavobacterium, etc.
  • ​Mesophilic microorganisms are called moderate temperature-loving microbes. Mesophiles in the bacteria domain can be either gram-positive or gram-negative. Their oxygen requirements can be aerobic or anaerobic. 
  • Examples: Escherichia, Klebsiella, Aeromonas and Alcaligenes, Enterococcus etc.
  • Thermophilic microorganisms are called heat-loving microbes. They can be found in various geothermally heated areas of the Earth, including hot springs found in Yellowstone National Park and deep-sea hydrothermal vents, as well as decaying plant matter like peat bogs and compost.
  • Examples: Lactobacilli, Streptococcus thermophilus, bifidobacteria, etc.
  • Hyperthermophilic microorganisms are called superheat-loving microbes. Although some bacteria can tolerate extreme temperatures, hyperthermophiles are typically found in the Archaea domain.
  • ​Examples: Pyrolobus fumarii, Aeropyrum pernix, Pyrococcus furious etc.

Question 86

What is the correct sequence in decreasing order of hardness among the following?

A. Gypsum

B. Fluorite

C. Feldspar

D. Topaz

Choose the correct answer from the options given below :

  1. AOption (a)

    C > D > B > A

  2. BOption (b)

    D > B > C > A

  3. COption (c)

    D > C > B > A

  4. DOption (d)

    C > D > A > B

View answer & explanation

Correct answer

Answer: (c)C.

D > C > B > A

Why this answer is correct

The correct answer is D > C > B > A.

Key Points

  • On the basis of relative hardness, minerals are ranked from 1 to 10.
  • Moh's scale is based on the ten index minerals while other minerals are ranked relative to these minerals.
Mineral nameScale number
Talc1
Gypsum2
Calcite3
Fluorite4
Apatite5
Feldspar6
Quartz7
Topaz8
Corundum9
Diamond10

 

 

 

 

 

 

 

 

As the scale number increases, the hardness of the mineral increases.

Therefore, the decreasing order of hardness of minerals is Topaz > Feldspar > Fluorite > Gypsum.

Question 87

At 1 atm pressure and 25° C temperature, NO2 concentration of 80 ppb is equivalent to

  1. AOption (a)

    40 μg/m3

  2. BOption (b)

    160 μg/m3

  3. COption (c)

    240 μg/m3

  4. DOption (d)

    150.4 μg/m3

View answer & explanation

Correct answer

Answer: (d)D.

150.4 μg/m3

Why this answer is correct

Concept-

One mole of any gas occupies 22.4 liters at 0° C temperatures and at 1 atm. pressure.

The ideal gas equation is PV = nRT 

where P = Pressure, V = Volume, n = number of moles, T = Temperature in Kelvin

Calculation:

Temperature = 25° C = 298 K

P1V1T1=P2V2T2\frac{{{P_1}{V_1}}}{{{T_1}}} = \frac{{{P_2}{V_2}}}{{{T_2}}}

1×22.4273=1×V2298\frac{{1 \times 22.4}}{{273}} = \frac{{1 \times {V_2}}}{{298}}

V2 = 24.45 liters

1 mole of NO2 contains 24.45 liters at 25° C at 1 atm pressure.

Molecular weight of NO2 = 14 + 32 = 46 gm

Concentration of NO2 = 80 ppb

109 cum air has 80 cum of NO2.

109 cum air has 80,000 liters of NO2.

Number of moles = 8000024.45\frac{80000}{24.45} = 3271.983

109 cum air has 150511.2474 gm of NO2.

So 150511.2474109\frac{{150511.2474}}{{{{10}^9}}} = 150. 4 μg/m3

Question 88

Given below are two statements.

Statement I : Leslie's matrix population model is a discrete and age-independent model

Statement II : The first row in Leslie's projection matrix represents fertility

In light of the above statements, choose the most appropriate answer from the options given below

  1. AOption (a)

    Both Statement I and Statement II are correct

  2. BOption (b)

    Both Statement I and Statement II are incorrect

  3. COption (c)

    Statement I is correct but Statement II is incorrect

  4. DOption (d)

    Statement I is incorrect but Statement II is correct

View answer & explanation

Correct answer

Answer: (b)B.

Both Statement I and Statement II are incorrect

Why this answer is correct

The correct answer is Both Statement I and Statement II are incorrect.

Key Points

Statement I: Leslie's matrix population model is a discrete and age-independent model – is incorrect because:

  • Leslie’s matrix model is indeed a discrete-time model, meaning it models population changes at fixed time intervals (e.g., yearly).
  • However, it is not age-independent; rather, it is fundamentally age-structured.
  • The entire structure of the Leslie matrix depends on age classes — each element in the population vector represents a specific age group.
  • Survival and fecundity rates vary with age, and the future state of the population is directly determined by the current age distribution.
  • Hence, describing it as "age-independent" is inaccurate, making this statement incorrect.

Statement II: The first row in Leslie’s projection matrix represents fertility – is also incorrect because:

[ f1f2f3Lfns100L00s20L0MMOOM00Lsn−1sn]\rm \begin{bmatrix}\ f_1&f_2&f_3&L&f_n\\ s_1&0&0&L&0\\ 0&s_2&0&L&0\\ M&M&O&O&M\\ 0&0&L&s_{n-1}&s_n\end{bmatrix}

  • In the Leslie matrix, the first row contains the average number of female offspring produced per female in each age class, which are technically offspring production rates or fecundities.
  • While often colloquially referred to as fertility rates, this is a simplification. Fertility generally refers to a broader demographic concept (e.g., births per 1000 women), whereas these matrix entries are more precise representations of per capita female births.
  • Therefore, saying that the first row “represents fertility” is technically imprecise and oversimplified. It leads to misunderstanding unless clarified in the context of matrix modeling.
  • Moreover, these values (fi) only account for female offspring, not total fertility, and are specific to mathematical modeling — not to demographic fertility in a general sense.
  • Thus, the statement is inaccurate and hence incorrect.

Additional Information

  • Leslie Matrix is a widely used mathematical model for projecting population growth in age-structured populations, introduced by Patrick H. Leslie in 1945.
  • It assumes:
  • A closed population (no immigration/emigration)
  • Single-sex (usually females)
  • Discrete time steps
  • Fixed age-specific survival and reproduction rates
  • Matrix Structure:
  • First row: fi = average number of female offspring from age class i
  • Sub-diagonal: si = proportion of individuals surviving from age class i to i+1
  • Population projection: N(t+1) = L × N(t), where L is the Leslie matrix and N is the population vector.
  • The model helps determine long-term growth rate (dominant eigenvalue) and stable age distribution (eigenvector).
  • This model is useful in both ecological research and demographic planning, but must be interpreted correctly in terms of terminology and assumptions.

Question 89

Arrange the environmental movements in chronological order

A. Silent Valley struggle

B.Chipko movement

C. Appiko movement

D. Narmada Bachao movement

Choose the correct answer from the options given below

  1. AOption (a)

    A, B, C, D

  2. BOption (b)

    B, A, C, D

  3. COption (c)

    A, D, B, C

  4. DOption (d)

    A, B, D, C

View answer & explanation

Correct answer

Answer: (b)B.

B, A, C, D

Why this answer is correct

Concept-

Silent Valley struggle-

  • Silent Valley Movement was a movement against the state to protect Silent valley, an evergreen tropical forest in the Palakkad district of Kerala, India.
  • It was started in 1978 to save the Silent Valley Reserve Forest from being flooded by a hydroelectric project.
  • The movement was first initiated by the local people and was subsequently taken over by the Kerala Sastra Sahitya Parishad (KSSP).
  • The KSSP effectively aroused public opinion by publishing a techno-economic and socio-political assessment report on the Silent Valley hydroelectric project.
  • The KSSP generated public opinion against the project.

Chipko movement-

  • Chipko Movement started on April 24, 1973, at Mandal of Chamoli district of Gharwal division of Uttarakhand.
  • The Chipko is one of the world-known environmental movements in India.
  • The movement was raised out of ecological destabilization in the hills.
  • The fall in the productivity of the forest produces forced the hill dwellers to depend on the market, which became a central concern for the inhabitants.
  • Forest resource exploitation was considered the reason behind natural calamities like floods, and landslides.
  • On March 27 the decision was taken to ‘Chipko” that is ‘to hug’ the trees that were threatened by the axe and thus the chipko Andolan (movement) was born.
  • This form of protest was instrumental in driving away the private companies from felling the ash trees.

Appiko movement-

  • It is a movement inspired by the Chipko movement by the villagers of the western ghats.
  • In the Uttar Kannada region of Karnataka, the villagers of Western Ghats started the Appiko Chalewali movement during the month of September – November 1983.
  • Here, the destruction of forest was caused due to commercial felling of trees for timber extraction.
  • Natural forests of the region were felled by the contractors, which resulted in soil erosion and the drying up of perennial water resources.
  • In the Saklani village in Sirsi, the forest dwellers were prevented from collecting usufructs like twigs and dried branches, and non-timber forest products for the purposes of fuelwood, fodder, honey, etc. They were denied their customary rights to these products.

Narmada Bachao movement-

  • Narmada is one of the major rivers of the Indian Peninsula.
  • The scope of the Sardar Sarovar project, a terminal reservoir on Narmada in Gujurat in fact is the main issue in the Narmada Water dispute.
  • It started in the year 1985.
  • The aim of the movement is to question the rationale behind the developmental projects, especially dam construction across the river.

So the correct chronological order is Chipko movement > Silent Valley struggle > Appiko movement >  Narmada Bachao movement.

Option B is the correct answer.

Question 90

Good absorbers are good emitters. This statement refers to which of the following laws?

  1. AOption (a)

    Stefan's Law

  2. BOption (b)

    Wien's Displacement Law

  3. COption (c)

    Planck's Law

  4. DOption (d)

    Kirchhoff's Law

View answer & explanation

Correct answer

Answer: (d)D.

Kirchhoff's Law

Why this answer is correct

The correct answer is Kirchhoff's Law.

Key PointsKirchhoff's Law:

  • ​It states that "At thermal equilibrium, the power radiated by an object must be equal to the power absorbed".
  • It means that if an object absorbs 100% of the radiation incident upon it, it must reradiate 100%.
  • This proves the statement that good absorbers are good emitters.

Stefan-Boltzmann law:

  • ​It states that "the total radiant heat power emitted from a surface is proportional to the fourth power of its absolute temperature".
  • If E is the radiant heat energy emitted from a unit area in one second (that is, the power from a unit area) and T is the absolute temperature (in kelvins), then E = σT4, sigma (σ) is called the Stefan-Boltzmann constant. This constant has the value 5.670374419 × 10−8 watts per metre2 per K4.
  • The law applies only to blackbodies, theoretical surfaces that absorb all incident heat radiation.

Wien's Displacement Law:

  • ​It states that "the black body’s temperature has an inverse relationship with the wavelength with the highest emissive power".
  • With a rise in the black body’s absolute temperature (T), the wavelength at which it emits the most monochromatic emissive power drops.
  • λmax = b / T

Where,

λmax = Wavelength at which the blackbody dominantly radiates,

b = Wien’s constant and its value is 2.897 × 10-3 m K,

T = Temperature (Kelvin).

Planck's Law:

  • It describes the spectral density of electromagnetic radiation emitted by a black body in thermal equilibrium at a given temperature T when there is no net flow of matter or energy between the body and its environment.
  • Every physical body spontaneously and continuously emits electromagnetic radiation and the spectral radiance of a body, B, describes the spectral emissive power per unit area, per unit solid angle, and per unit frequency for particular radiation frequencies.
  • With increasing temperature, the total radiated energy of a body increases, and the peak of the emitted spectrum shifts to shorter wavelengths.

Question 91

A rock compound entirely of crystals is said to be

  1. AOption (a)

    Hypocrystalline

  2. BOption (b)

    Microcrystalline

  3. COption (c)

    Holocrystalline

  4. DOption (d)

    Holohyaline

View answer & explanation

Correct answer

Answer: (c)C.

Holocrystalline

Why this answer is correct

Concept:

Hypocrystalline:

  • Hypocrystalline is a textural term describing an igneous rock consisting of a mixture of glass and crystals where the ratio of crystals to glass is greater than 3:5.
  • Rocks containing a higher ratio of glass are described as hypohaline or holohyaline. Usually, devitrified glass is treated as glass in the classification of hypohyaline rocks.

Microcrystalline:

  • A microcrystalline material is a crystallized substance or rock that contains small crystals visible only through microscopic examination.
  • There is little agreement on the range of crystal sizes that should be regarded as microcrystalline, but the extreme range of values suggested is 1 to 200 microns.

Holocrystalline:

  • The texture of an igneous rock composed entirely of crystals, i.e., having no glassy part is known as Holocrystalline rock.
  • Those holocrystalline rocks in which mineral grains can be recognized with the unaided eye are called phanerites, and their texture is called phaneritic.
  • Those with mineral grains so small that their outlines cannot be resolved without the aid of a hand lens or microscope are termed aphanites, and their texture is termed aphanitic.

Question 92

The fast neutrons produced in the process of nuclear fission of 235U, have an average energy of about

  1. AOption (a)

    100 keV

  2. BOption (b)

    1.0 Mev

  3. COption (c)

    2.0 Mev

  4. DOption (d)

    2.6 Mev

View answer & explanation

Correct answer

Answer: (c)C.

2.0 Mev

Why this answer is correct

Concept-

Thermal NeutronFast Neutron
- A thermal neutron remains in thermal equilibrium with the ambient molecules at Normal Temperature and Pressure (NTP). - A free thermal neutron has energy in the order of 0.025 eV (minor deviation possible). - All such nuclear reactors that work primarily based on thermal neutrons are called Thermal Reactors.- Fast neutron does not exist in thermal equilibrium with the ambient molecules at Normal Temperature and Pressure (NTP). - Fast neutron has significantly higher energy, in a range of 1 – 20 MeV. - All such nuclear reactors that work primarily based on fast neutrons are called Fast Reactors.
  • For uranium-235 (total mean fission energy 202.79 MeV typically ~169 MeV appears as the kinetic energy of the daughter nuclei, which fly apart at about 3% of the speed of light, due to Coulomb repulsion.
  • Also, an average of 2.5 neutrons are emitted, with a mean kinetic energy per neutron of ~2 MeV (total of 4.8 MeV).

Question 93

The maximum cross-section for the fusion reaction 12H{}_1^2H + 13H{}_1^3H is reached at energies of nuclei at

  1. AOption (a)

    ∼ 10 keV

  2. BOption (b)

    ∼ 100 keV

  3. COption (c)

    ∼ 1.0 keV

  4. DOption (d)

    ∼ 17.6 keV

View answer & explanation

Correct answer

Answer: (b)B.

∼ 100 keV

Why this answer is correct

The correct answer is ∼ 100 keV.

Key Points

  • Nuclear cross-section is used to describe the probability that a nuclear reaction will occur.
  • The Deuterium (D) – Tritium (T) reaction has the largest cross section and also the largest Q-value (i.e. the released energy of a reaction) of varieties of fusion reactions.
  • It produces an alpha particle (or Helium-4), a neutron and releases 17.6 MeV of energy in the form of kinetic energy of the products (3.5 MeV to alpha particle and 14.1 MeV to neutron).
  • At a plasm a ion temperature of 5 keV, the largest fraction of the D- T reaction rate occurs at deuteron energies of ~ 20-15 0 keV.
  • At energies above ~ 100 keV, the uncertainties in the D-T cross section introduces errors into the calculated reaction rate of ~ 10.
  • At energie s below ~ 100 keV, the fit to the cross section used in calculating the reaction rate is based on a single experiment , so the sensitivity of the reaction rate to the D-T cross section may be quite uncertain.

Therefore, the maximum cross-section for the fusion reaction 12H{}_1^2H + 13H{}_1^3H is reached at energies of nuclei at ∼ 100 keV.

Question 94

What is the sound pressure level (in dB) associated with a root mean square pressure of 100 Pa?

  1. AOption (a)

    148 dB

  2. BOption (b)

    134 dB

  3. COption (c)

    120 dB

  4. DOption (d)

    110 dB

View answer & explanation

Correct answer

Answer: (b)B.

134 dB

Why this answer is correct

Concept:

Sound pressure:

  • Sound pressure is the difference between the instantaneous pressure at a point in the presence of a sound wave and the ambient atmospheric pressure.
  • The SI unit of sound pressure is the pascal (Pa).
  • Other common units for measuring the sound pressure are a newton per square meter (N/m²), a bar, and a dyne per square centimeter (dyn/cm²)

Sound Pressure level:

  • Sound pressure level (SPL) is a logarithmic (decibel) measure of the sound pressure relative to the reference value of 20 μPa threshold of hearing.
  • The threshold of hearing is the quietest sound that most young healthy people can hear.
  • Sound pressure level Lp is measured in decibels (dB) and is calculated as follows:
  • Lp=20log⁡pp0{L_p} = 20\log \frac{p}{{{p_0}}}
  • Where p is the root mean square sound pressure and P0 is the reference sound pressure (usually 20 μPa or 0.00002 Pa).
  • The sound pressure level is an absolute value because it is referenced to another absolute value — the threshold of hearing.
  • Therefore, the sound pressure in linear values like pascals can be converted into the sound pressure level in decibels and vice versa if the reference sound pressure is known.

Calculation:

Root mean square pressure is given as 100 Pa.

.​Lp=20log⁡10020×10−6{L_p} = 20\log \frac{{100}}{{20 \times {{10}^{ - 6}}}} 

LP = 133.98 dB = 134 dB​

Question 95

Heteromorphic rocks have

  1. AOption (a)

    Same mineral composition arising from similar magmas under different conditions of crystallization.

  2. BOption (b)

    Different mineral composition arising from similar magmas under different conditions of crystallization.

  3. COption (c)

    Different mineral composition arising from different magmas under different conditions of crystallization.

  4. DOption (d)

    Same mineral composition arising from different magmas under different conditions of crystallization.

View answer & explanation

Correct answer

Answer: (b)B.

Different mineral composition arising from similar magmas under different conditions of crystallization.

Why this answer is correct

The correct answer is Different mineral composition arising from similar magmas under different conditions of crystallization.

Key Points

  • The crystallization of two magmas of a nearly identical chemical composition into two different mineral aggregates resulting from different cooling histories is defined as heteromorphism in geology.
  • It may be caused by microheterogeneity, increasing viscosity and other energy efficiencies of specific mineral formations.
  • The rocks formed as a result of heteromorphism are called heteromorphic rocks.
  • These rocks are characterised by a different mineral composition which arises from similar magmas.
  • The difference in mineral composition is explained due to different conditions of crystallization.

Therefore, heteromorphic rocks have different mineral composition arising from similar magmas under different conditions of crystallization.

Question 96

The transitional zone (ecotone) between freshwater and terrestrial ecosystems is known as

  1. AOption (a)

    Riparian Zone

  2. BOption (b)

    Hyporheic zone

  3. COption (c)

    Benthic zone

  4. DOption (d)

    Epilimnetic zone

View answer & explanation

Correct answer

Answer: (a)A.

Riparian Zone

Why this answer is correct

The correct answer is Riparian Zone.

Key Points

  • Riparian zones are lands found along the banks of rivers, streams, lakes, and other bodies of water. Streambanks, riverbanks, and flood plains are some examples. They differ from the surrounding uplands because the presence of water shapes the soils and vegetation.
  • Hyporheic zone is defined as a subsurface volume of sediment and porous space adjacent to a stream that allows for easy exchange of stream water. It has a strong influence on stream ecology, stream biogeochemical cycling, and stream-water temperatures.
  • Benthic zone is the lowest ecological zone in a body of water, and it typically consists of seafloor sediments. These sediments are vital in supplying nutrients to the organisms that live in the benthic zone.
  • Epilimnetic zone occupies the well-lighted, well-oxygenated surface waters away from the shore and above the thermocline. Its fish fauna is perhaps the most variable from the reservoir to reservoir.

Therefore, the transitional zone (ecotone) between freshwater and terrestrial ecosystems is known as the riparian zone.

Additional Information

  • Ecotones are areas of steep transition between ecological communities, ecosystems, and/or ecological regions along an environmental or other gradient.
  • Ecotones occur at multiple spatial scales and range from natural ecotones between ecosystems and biomes to human-generated boundaries.
  • They have a wider range of organisms.
  • Because of the greater genetic diversity present, they act as a conduit for gene flow from one population to another.
  • Examples: Mangrove forests represent an ecotone between marine and terrestrial ecosystems, grassland (between forest and desert), estuary (between fresh water and saltwater) and riverbank or marshland (between dry and wet).
  • The edge effect refers to the changes in population or community structures that occur at the boundary of two habitats (ecotone).

Question 97

Which one of the following silicate clay minerals exhibits highest interlayer expansion?

  1. AOption (a)

    Montmorillonite

  2. BOption (b)

    Vermiculite

  3. COption (c)

    Chlorite

  4. DOption (d)

    Kaolinite

View answer & explanation

Correct answer

Answer: (a)A.

Montmorillonite

Why this answer is correct

The correct answer is Montmorillonite.

Key Points

  • The smectite group of minerals is noted for their interlayer expansion and swelling when wetted. The water enters the interlayer space and forces the layers apart.
  • Montmorillonite is the most prominent member of this group. It has a high specific surface, high cation exchange capacity and the highest affinity to water. It can be expanded several times to its original volume when it comes in contact with water.
  • It's CEC = 100 to 120.

​

Additional Information

  • Kaolinite: Purest of clays with the lowest cation exchange capacity. Due to the presence of intricate silica bonding, it does not absorb water. Therefore, its expansion capacity is the least.
  • Chlorite: It is a clay mineral where the central cation in octahedral sheets is either iron or magnesium. It shows minimum swelling and is practically non-expandable.
  • Vermiculite: It is a hydrous phyllosilicate mineral. When heated to 1000°C, it can expand 6-20 times its original size. It has the highest expansion capacity after montmorillonite.

Question 98

A small hydropower station based on the conversion of the kinetic energy of a river water generates power. If the flow of water is 10 m3s-1 and the speed of water is 3 ms-1, what is the maximum power the station can generate? (Assume efficiency of the power station to be 0.6)

  1. AOption (a)

    18 kW

  2. BOption (b)

    27 kW

  3. COption (c)

    36 kW

  4. DOption (d)

    45 kW

View answer & explanation

Correct answer

Answer: (b)B.

27 kW

Why this answer is correct

Calculation:

Given:

The flow of water, Q = 10 m3s-1

Speed of water, v = 3 ms-1

Efficiency (ɳ) = 0.6

Since, Power,

P = 12 {1{} \over 2} Q × ɳ ×1000 × v2

P = 0.5 × 10 × 0.6 ×1000 × (3)2

P = 27000 W = 27×103 = 27 kW

Therefore, Power, P = 27 kW

Question 99

According to National Ambient Air Quality Standards (NAAQS), the annual limits for PM10 and PM2.5 in ecologically sensitive areas (in μg/m3) are

  1. AOption (a)

    100 and 60, respectively

  2. BOption (b)

    60 and 40, respectively

  3. COption (c)

    40 and 20, respectively

  4. DOption (d)

    40 and 15, respectively

View answer & explanation

Correct answer

Answer: (b)B.

60 and 40, respectively

Why this answer is correct

Concept-

  • The national ambient air quality standards in India were first notified in 1994, under the Environment (protection) rules, 1986.
  • These standards have, however, been recently revised by notifying much tougher air quality standards on 16:11: 2009, under which, unlike the old norms, the residential and industrial areas will have the same standards.
  • Additionally as compared to the regulation of only five pollutants under the old standards, now 12 pollutants are required to be monitored.
  • The highly dangerous pollutants, like PM 2.5, ozone gas (ground level Ozone), lead, Benzene, Benzo (a) pyrene, arsenic, and nickel have been included for regulation under the new norms.
PollutantIndustrial, Residential, Rural and other areasEcologically sensitive area
Sulphur dioxide5020
Nitrogen dioxide4030
PM 106060
PM 2.54040
Ozone100100
Lead0.50.5
Carbon Monoxide0202
Ammonia100100
Benzene0505
Banzo (a) Pyrene0101
Arsenic0606
Nickel2020
  • According to National Ambient Air Quality Standards (NAAQS), the annual limits for PM10 and PM2.5 in ecologically sensitive areas (in μg/m3) are 60 and 40, respectively.

Question 100

A N-fixing actinomycete associated with higher plants is :

  1. AOption (a)

    Azospirillum

  2. BOption (b)

    Clostridium

  3. COption (c)

    Frankia

  4. DOption (d)

    Anabaena

View answer & explanation

Correct answer

Answer: (c)C.

Frankia

Why this answer is correct

The correct answer is Frankia.

Key Points

  • Frankia is a gram-positive species of filamentous actinomycete capable of nitrogen fixation. It establishes root-nodule symbiosis with actinorhizal plants such as Alnus or Casuarina trees, where bacterial nitrogen fixation takes place.
  • It can fix nitrogen in inhospitable environmental conditions such as mine locations and degraded and reclaimed lands, and the range of N2 fixation is 2–300 kg N ha−1 year−1.
  • Frankia is a genus of soil actinomycetes in the family Frankiaceae that fix nitrogen both under symbiotic and free-living aerobic conditions.

Therefore, Frankia is the N-fixing actinomycete that is associated with higher plants.

Additional Information

  • Clostridium is a genus of gram-positive, spore forming bacteria belonging to the family Clostridiceae. The majority of the species are obligate anaerobs, however, some species can grow under aerobic conditions or are aerotolerant.
  • Among nitrogen-fixing organism, the genus Clostridium occupies a very special place.
  • The species Clostridium pasteurianum is the first known free-living nitrogen-fixing bacteria.
  • Anabaena is a plankton-forming genus of flilamentous cynobacteria. They are noted for their nitrogen-fixing ability and their symbiotic relationship with plants like mosquito fern.
  • Azospirillum is a gram-negative, microaerophilic, non-fermentative and nitrogen-fixing bacterial genus from the family of Rhodospirillaceae.
  • Azospirillum bacteria can promote plant growth.

100 questions in the full paper