Shortcut Trick
Average speed for 3 equal distances at speeds a, b, c = 3abc ÷ (ab + bc + ca)
Average speed = (3 × 5 × 8 × 10) ÷ (40 + 80 + 50) = 1200 ÷ 170 = 120/17 km/h.
Total Time = 61 min 12 sec = 306/5 mins = 51/50 hours.
Total Distance = Average Speed × Total Time = (120/17) × (51/50) = 7.2 km.
∴ The correct answer is 7.2 km.
Alternate Method
Given:
Speeds = 5 km/h, 8 km/h, 10 km/h
Total time = 61 min 12 sec
Formula Used:
Time = Distance ÷ Speed
Total Time = 61 min 12 sec
d km
d km
d km
5 km/h
8 km/h
10 km/h
Total Distance = 3d
Calculations:
⇒ Let the total distance be 3d, so each equal part is d km.
⇒ Total Time = 61 min + 12 sec = 61 + 12/60 = 61 + 1/5 = 306/5 mins.
⇒ Total Time in hours = (306/5) × (1/60) = 306/300 = 51/50 hours.
⇒ Time taken for each part = d/5, d/8, and d/10.
⇒ Total Time = d/5 + d/8 + d/10 = 51/50
⇒ Taking LCM of 5, 8, 10 which is 40:
⇒ (8d + 5d + 4d) / 40 = 51/50
⇒ 17d / 40 = 51/50
⇒ d = (51/50) × (40/17)
⇒ d = 3 × (4/5) = 12/5 = 2.4 km
⇒ Total Distance = 3d = 3 × 2.4 = 7.2 km
∴ The correct answer is 7.2 km.
Additional Information
Average Speed for Equal Distances
When a body travels n equal distances at speeds v1, v2, ... vn, Average Speed = n ÷ (1/v1 + 1/v2 + ... + 1/vn).
Average Speed for Equal Time
When a body travels at speeds v1, v2, ... vn for equal time intervals, Average Speed = (v1 + v2 + ... + vn) ÷ n.
Relative Speed
For two bodies moving in the same direction, relative speed = |v1 − v2|. In opposite directions, relative speed = v1 + v2.