Shortcut Trick
Ratio of number of students in Class 8 and Class 9 = 20 : 15 = 4 : 3.
Let the assumed average be 152 cm.
Net deviation from assumed average = (168 − 152) × 3 = +48.
Average deviation = +48 ÷ (4 + 3) = 48 ÷ 7 ≈ +6.85 cm.
Combined average = 152 + 6.85 = 158.85 cm ≈ 159 cm.
∴ The correct answer is 159 cm.
Alternate Method
Given:
Number of students in Class 8 = 20
Average height of Class 8 = 152 cm
Number of students in Class 9 = 15
Average height of Class 9 = 168 cm
Formula Used:
Combined Average = (n1x1 + n2x2) ÷ (n1 + n2)
Class 8 (20 students)
152 cm
Class 9 (15 students)
168 cm
Combined Avg ≈ 159 cm
3 parts ratio
4 parts ratio
Calculations:
⇒ Total height of Class 8 students = 20 × 152 = 3040 cm
⇒ Total height of Class 9 students = 15 × 168 = 2520 cm
⇒ Total combined height = 3040 + 2520 = 5560 cm
⇒ Total number of students = 20 + 15 = 35
⇒ Combined Average = 5560 ÷ 35
⇒ Combined Average = 1112 ÷ 7 ≈ 158.85 cm
⇒ Rounding to the nearest cm, we get 159 cm.
∴ The correct answer is 159 cm.
Additional Information
Weighted Average Formula
When two groups of sizes n1 and n2 have averages A1 and A2, the combined average is given by: A = (n1A1 + n2A2) ÷ (n1 + n2).
Deviation Method for Averages
To simplify calculations, select an assumed average. The true average = Assumed Average + (Sum of Net Deviations ÷ Total Observations).
Alligation & Ratio Method
The distances from the combined average to the individual averages are inversely proportional to the ratio of the quantities in each group. Ratio of distances = n2 : n1.