We need to find the day for 1st January 1755.
First, we calculate the odd days up to 31st December 1754.
Total years = 1754 years = 1600 years + 100 years + 54 years
- Odd days in 1600 years = 0
- Odd days in 100 years = 5
- Odd days in 54 years:
Number of leap years = 54 ÷ 4 = 13 leap years
Number of ordinary years = 54 − 13 = 41 ordinary years
Odd days = (13 × 2) + (41 × 1) = 26 + 41 = 67 odd days
67 odd days = 67 ÷ 7 = 4 odd days (Remainder)
Total odd days until 31st December 1754 = 0 + 5 + 4 = 9 odd days
9 odd days = 9 ÷ 7 = 2 odd days
Now, we add the day for 1st January 1755:
Total odd days = 2 (from previous years) + 1 (for 1st Jan) = 3 odd days
According to the day code:
0 = Sunday, 1 = Monday, 2 = Tuesday, 3 = Wednesday, 4 = Thursday, 5 = Friday, 6 = Saturday.
Therefore, the first day of the year 1755 was Wednesday.
Hence, the correct answer is “Option 3”.
Important Points To find the day of the week for any date, we calculate the number of odd days.
Number of odd days in 400 years = 0
Number of odd days in 100 years = 5
An ordinary year (365 days) has (365 ÷ 7) = 1 odd day.
A leap year (366 days) has (366 ÷ 7) = 2 odd days.