Shortcut Trick
In a right-angled triangle ΔPQR (at Q), angles P and R are complementary.
By trigonometric property: sin R = cos P.
Given sec P = 13/5, we know that cos P = 1/sec P.
⇒ cos P = 5/13.
⇒ sin R = 5/13.
∴ The correct answer is 5/13.
Alternate Method
Given: ΔPQR is right-angled at Q, and sec P = 13/5.
Formula Used: sec θ = Hypotenuse / Base and sin θ = Perpendicular / Hypotenuse.
⇒ For angle P: Hypotenuse (PR) = 13 and Base (PQ) = 5.
⇒ Using Pythagoras Theorem: QR = √(PR2 − PQ2)
⇒ QR = √(132 − 52) = √(169 − 25) = √144 = 12.
⇒ For angle R: The opposite side (Perpendicular) is PQ and the Hypotenuse is PR.
⇒ sin R = Opposite / Hypotenuse = PQ / PR.
⇒ sin R = 5/13.
∴ The correct answer is 5/13.
Additional Information
Complementary Angle Relations
In a right-angled triangle, if A + B = 90°, then sin A = cos B, tan A = cot B, and sec A = cosec B.
Pythagorean Triplets
Common integer sets that satisfy a2 + b2 = c2 include (3, 4, 5), (5, 12, 13), (8, 15, 17), and (7, 24, 25).
Reciprocal Identities
sec θ = 1/cos θ, cosec θ = 1/sin θ, and cot θ = 1/tan θ.