Shortcut Trick
For a number to be divisible by 18, it must be even and the sum of its digits must be divisible by 9.
Sum of digits of 7823326867X = 7 + 8 + 2 + 3 + 3 + 2 + 6 + 8 + 6 + 7 + X = 52 + X.
The nearest multiple of 9 greater than 52 is 54.
Equating: 52 + X = 54 ⇒ X = 2.
Since 2 is even, both conditions are satisfied.
∴ The correct answer is 2.
Alternate Method
Given: The 11-digit number is 7823326867X and it is divisible by 18.
Divisibility Rule of 18: A number is divisible by 18 if it is divisible by both its co-prime factors, 2 and 9.
⇒ Condition 1: The number must be divisible by 2, which means the last digit X must be an even number (0, 2, 4, 6, or 8).
⇒ Condition 2: The number must be divisible by 9, which means the sum of its digits must be a multiple of 9.
⇒ Sum of digits = 7 + 8 + 2 + 3 + 3 + 2 + 6 + 8 + 6 + 7 + X
⇒ Sum = 52 + X
⇒ For (52 + X) to be divisible by 9, we check possible values of X from the options:
⇒ If X = 6, Sum = 52 + 6 = 58 (Not divisible by 9)
⇒ If X = 4, Sum = 52 + 4 = 56 (Not divisible by 9)
⇒ If X = 8, Sum = 52 + 8 = 60 (Not divisible by 9)
⇒ If X = 2, Sum = 52 + 2 = 54 (Divisible by 9, as 9 × 6 = 54)
⇒ Since X = 2 is even, it also satisfies the divisibility rule for 2.
∴ The correct answer is 2.
Additional Information
Divisibility Rule of 9
A number is divisible by 9 if the sum of all its digits is exactly divisible by 9.
Divisibility Rule of 2
A number is divisible by 2 if its last digit is 0, 2, 4, 6, or 8.
Composite Divisibility
To check divisibility by a composite number n, the number must be divisible by the co-prime factors of n (e.g., for 12, check 3 and 4; for 15, check 3 and 5).