Given:
k4+k41=194
Concept used:
(a+a1)2=a2+a21+2
If
(a+a1)=b
Then,
a3+a31=b3−3b
Calculation:
k4+k41=194
⇒ k4+k41+2=194+2
⇒ k4+k41+2=196
⇒ (k2+k21)2=142
⇒ k2+k21=14
⇒ k2+k21+2=14+2
⇒ (k+k1)2=16
⇒ (k+k1)2=42
⇒ k+k1=4
Now,
k3+k31 = 43 - 3 × 4
⇒ k3+k31 = 64 - 12
⇒ k3+k31 = 52
∴ Ther required answer is 52.
Shortcut Trick
We know,
• If k4 + 1/k4 = a then k2 + 1/k2 = √(a + 2)
• If k2 + 1/k2 = b then k + 1/k = √(b + 2)
• If k + 1/k = c then k3 + 1/k3 = c3 - 3c
So, k4 + 1/k4 = 194 then k2 + 1/k2 = √196 = 14 so, k + 1/k = √16 = 4
Then, k3 + 1/k3 = 43 - 12 = 52