The corresponding altitudes of two similar triangles are 8 cm and 11 cm. Find the ratio of their areas:
- AOption (a)
8 : 11
- BOption (b)
121 : 64
- COption (c)
64 : 121
- DOption (d)
11 : 8
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Correct answer
64 : 121
Why this answer is correct
Given:
The corresponding altitudes of two similar triangles are 8 cm and 11 cm.
Concept used:
In similar triangles, the Ratio of areas is equal to the ratio of squares of the corresponding sides and altitudes.
Calculations:
According to the concept,
area of first ∆ : area of second ∆ = (altitude of first∆)² : (altitude of second ∆)²
⇒area of first ∆ : area of second ∆ = (8)² : (11)²
⇒area of first ∆ : area of second ∆ = 64 : 121
Hence, The Required ratio is 64 : 121.



















