A train travels at a constant speed and crosses two persons moving in the same direction in 10.8 seconds and 11.4 seconds respectively. The first one was running at the speed of 4.8 km/h while the second one was running at the speed of 6.6 km/h. What is the speed of the train in km/h?
- AOption (a)
39.6
- BOption (b)
40.2
- COption (c)
38.4
- DOption (d)
39.0
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Correct answer
39.0
Why this answer is correct
Shortcut Trick
In same direction, Distance (Length of train) = Relative Speed × Time.
L = (V − 4.8) × 10.8 = (V − 6.6) × 11.4
⇒ 10.8V − 51.84 = 11.4V − 75.24
⇒ 0.6V = 23.4
⇒ V = 23.4 ÷ 0.6 = 39
∴ The correct answer is 39.0 km/h.
Alternate Method
Given: Speed of first person (S1) = 4.8 km/h, Time (T1) = 10.8 s. Speed of second person (S2) = 6.6 km/h, Time (T2) = 11.4 s.
Formula: Distance = Relative Speed × Time
⇒ Let Speed of Train be V km/h.
⇒ (V − 4.8) × (5/18) × 10.8 = (V − 6.6) × (5/18) × 11.4
⇒ (V − 4.8) × 10.8 = (V − 6.6) × 11.4
⇒ 10.8V − 51.84 = 11.4V − 75.24
⇒ 11.4V − 10.8V = 75.24 − 51.84
⇒ 0.6V = 23.4
⇒ V = 234 ÷ 6 = 39
∴ The correct answer is 39.0 km/h.
Additional Information
Relative Speed Concept
When two objects move in the same direction, relative speed = S1 − S2. When they move in opposite directions, relative speed = S1 + S2.
Unit Conversion
To convert km/h to m/s, multiply by 5/18. To convert m/s to km/h, multiply by 18/5.
Train Crossing Person
When a train crosses a stationary or moving person, the distance covered is equal to the length of the train.





















