Brazen can paint a wall red in 12 days, while Ballary can paint the entire wall in 21 days. If Brazen and Ballari work alternately for one day each from painting the wall to coloring it red, then how many days will it take to paint the entire wall red?
- AOption (a)
16 days
- BOption (b)
15 days
- COption (c)
14 days
- DOption (d)
12 days
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Correct answer
15 days
Why this answer is correct
Shortcut Trick
Total Work (LCM of 12, 21) = 84 units.
Brazen efficiency = 84 ÷ 12 = 7 units/day; Ballary efficiency = 84 ÷ 21 = 4 units/day.
In 2 days (1 cycle), work done = 7 + 4 = 11 units.
In 14 days (7 cycles), work done = 11 × 7 = 77 units. Remaining = 84 − 77 = 7 units.
On 15th day, Brazen completes the remaining 7 units (7 ÷ 7 = 1 day).
∴ The correct answer is 15 days.
Alternate Method
Given: Time taken by Brazen = 12 days, Time taken by Ballary = 21 days.
Formula: Total Work = LCM of individual days; Efficiency = Total Work ÷ Time.
| Person | Days | Total Work | Efficiency |
|---|---|---|---|
| Brazen | 12 | 84 | 7 |
| Ballary | 21 | 4 |
⇒ Work done in the 1st 2nd-day cycle (Brazen + Ballary) = 7 + 4 = 11 units.
⇒ Number of complete cycles to reach near 84 = 84 ÷ 11 ≈ 7 cycles.
⇒ Work done in 14 days (7 cycles × 2) = 11 × 7 = 77 units.
⇒ Remaining work = 84 − 77 = 7 units.
⇒ 15th day is Brazen's turn. Brazen completes 7 units in (7 ÷ 7) = 1 day.
⇒ Total time = 14 + 1 = 15 days.
∴ The correct answer is 15 days.
Additional Information
Alternate Day Work
In alternate work, tasks are calculated in cycles. If A and B work alternately, 1 cycle = 2 days, and work per cycle = Efficiency of A + Efficiency of B.
Fractional Days
If remaining work is less than a person's daily efficiency, the time taken is calculated as (Remaining Work ÷ Efficiency).














