6 years ago, a mother’s age was 6 times her daughter’s age. Three years hence, the daughter will be one-third her mother’s age. The current age (in years) of the mother is:
- AOption (a)
45
- BOption (b)
39
- COption (c)
36
- DOption (d)
42
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Correct answer
42
Why this answer is correct
Shortcut Trick
Ratio of Mother : Daughter 6 years ago = 6 : 1 (Difference = 5 units)
Ratio 3 years hence = 3 : 1 (Difference = 2 units). Make difference same: 12 : 2 and 15 : 5.
Difference in units = 15 − 12 = 3 units. Total time gap = 6 + 3 = 9 years.
3 units = 9 years ⇒ 1 unit = 3 years. Mother 6 years ago = 12 × 3 = 36 years.
Present age of Mother = 36 + 6 = 42 years.
∴ The correct answer is 42 years.
Alternate Method
Given: 6 years ago, Mother (M − 6) = 6(D − 6). 3 years hence, (D + 3) = 1/3 × (M + 3).
Calculations:
⇒ M − 6 = 6D − 36 ⇒ M − 6D = −30 --- (i)
⇒ 3D + 9 = M + 3 ⇒ M − 3D = 6 --- (ii)
⇒ Subtracting (i) from (ii): (M − 3D) − (M − 6D) = 6 − (−30)
⇒ 3D = 36 ⇒ Daughter's current age = 12 years.
⇒ Putting D = 12 in (ii): M − 3(12) = 6
⇒ M − 36 = 6 ⇒ M = 42
∴ The correct answer is 42 years.
Additional Information
Age Ratio Constant Difference
The age difference between two people remains constant throughout their lives. Always equate the difference in ratio parts to simplify calculations.
Linear Equations in Ages
When solving via variables, let current ages be x and y. Then 'n' years ago is (x−n) and 'n' years hence is (x+n).













