Concept:
A simply supported beam subjected to couple M at the ends with its BMD and SFD is represented by:
By double integration method we get,
dx2d2y=−EIM
dxdy=−EIM∫;dx;
y=−;2EIMx2+C1x+C2
At x = 0, y =0 we get C1=;2EIML
At x = L, y =0 we get C2 = 0
So, deflection at any point at distance x from the left end is given by,
y(x)=−2EIMx2+2EIMLx=2EIMx(L−x)
The maximum deflection will be at the midpoint of the beam. So,
∴;ymax=y(2L)=;8EIML2
Important point:
Deflection and slope of various beams is given by:
| yB=3EIPL3 | θB=2EIPL2 |
|---|
| yB=8EIwL4 | θB=6EIwL3 |
| yB=2EIML2 | θB=EIML |
| yB=30EIwL4 | θB=24EIwL3 |
| yc=48EIPL3 | θB=16EI;wL2 |
| yc=3845EIwL4 | θB=24EIwL3 |
| yc=0 | θB=24EIML |
| yc=8EIML2 | θB=2EIML |
| yc=192EIPL3 | θA=θB=θC=0 |
| yc=384EIwL4 | θA=θB=θC=0 |
Where, y = Deflection of beam, θ = Slope of beam