Shortcut Trick
The first 8 even natural numbers not divisible by 3 are: 2, 4, 8, 10, 14, 16, 20, 22.
The consecutive gaps between them are 2, 4, 2, 4, 2, 4, 2, which forms a perfectly symmetric sequence.
For any symmetrically distributed series, Average = (First Term + Last Term) ÷ 2
⇒ Average = (2 + 22) ÷ 2 = 12
∴ The correct answer is 12.
Alternate Method
Given:
We need to find the average of the first eight even natural numbers which are not divisible by 3.
Formula Used:
Average = (Sum of all observations) ÷ (Total number of observations)
Avg = 12
+2
+4
+2
+4
+2
+4
+2
2
4
8
10
14
16
20
22
Symmetric sequence → Average is exactly at the midpoint
Calculations:
⇒ The series of even natural numbers is: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24...
⇒ By removing the numbers divisible by 3 (i.e., 6, 12, 18...), we get the required series.
⇒ The first 8 numbers are: 2, 4, 8, 10, 14, 16, 20, 22
⇒ Sum = 2 + 4 + 8 + 10 + 14 + 16 + 20 + 22
⇒ Sum = 96
⇒ Average = 96 ÷ 8 = 12
∴ The correct answer is 12.
Additional Information
Average of an Arithmetic Progression
For any sequence in an Arithmetic Progression, the average is simply the middle term or calculated as (First Term + Last Term) ÷ 2.
Average of Symmetric Sequences
If a sequence has symmetrically distributed gaps reading exactly the same from left-to-right as right-to-left, its average is also the mean of any two equidistant terms from the ends.
Sum of First 'n' Even Numbers
The sum of the first 'n' consecutive even numbers is given by n(n + 1), making their direct average equal to (n + 1).