Shortcut Trick
If the angle of elevation (or depression) of a tower of height h changes from θ1 to θ2 as an object moves directly towards it, the distance travelled is:
Distance = h × (cot θ1 − cot θ2)
Here, h = 42 m, θ1 = 30°, θ2 = 45°
Distance = 42 × (cot 30° − cot 45°)
Distance = 42 × (√3 − 1)
∴ The correct answer is 42(√3 − 1) m.
Alternate Method
Given:
Height of the lighthouse (AB) = 42 m
Angle of depression at initial position C = 30° ⇒ Angle of elevation ∠ACB = 30°
Angle of depression at final position D = 45° ⇒ Angle of elevation ∠ADB = 45°
Formula Used:
In a right-angled triangle, tan θ = Perpendicular ÷ Base
Calculations:
In right-angled triangle ΔABD,
⇒ tan 45° = AB ÷ BD
⇒ 1 = 42 ÷ BD
⇒ BD = 42 m
In right-angled triangle ΔABC,
⇒ tan 30° = AB ÷ BC
⇒ 1 ÷ √3 = 42 ÷ BC
⇒ BC = 42√3 m
The distance travelled by the ship is CD, which is the difference between BC and BD.
⇒ Distance CD = BC − BD
⇒ Distance CD = 42√3 − 42
⇒ Distance CD = 42(√3 − 1) m
∴ The correct answer is 42(√3 − 1) m.
Additional Information
Heights and Distances (Trigonometry)
The angle of elevation is the angle formed between the horizontal reference line and the line of sight when looking up at an object. The angle of depression is the angle formed when looking down from a height.
Two Objects on the Same Side
If two objects are observed on the ground from a tower of height h at angles θ1 and θ2, the distance separating them is easily calculated as h(cot θ1 − cot θ2).
Two Objects on Opposite Sides
When two objects are situated on opposite sides of a central tower of height h, having respective angles of elevation θ1 and θ2, the total distance between them is h(cot θ1 + cot θ2).