Given:
I. The value of 1002 - 992 + 982 - 972 + 962 - 952 + 942 - 932 + ...... + 222 - 212 is 4840.
II. The value of
(k2+k21)(k−k1)(k4+k41)(k+k1)(k4−k41) is k16 - k161.
Concept used:
A, (A + D), (A + 2D), ....., L is an arithmetic progression with the first term A and common difference D. (L being the Nth term)
Number of terms, N = (L - A)/D + 1
Sum of all terms = (A + L)/2 × N
Calculation:
II. According to the concept,
1002 - 992 + 982 - 972 + 962 - 952 + 942 - 932 + ...... + 222 - 212
(100 + 99)(100 - 99) + (98 + 97)(98 - 97)+...........(22 + 21)(22 - 21)
So, the series will be
100 + 99 + 98 + 97 .............................................22 + 21.
The first term is 100 and the last is 21, the difference is 1.
Sum = (100 + 21) × 80/2 = 121 × 40 = 4840
II. (k2+k21)(k−k1)(k4+k41)(k+k1)(k4−k41)
⇒ (k+k1)(k−k1)(k2+k21)(k4+k41)(k4−k41)
⇒ (k2−k21)(k2+k21)(k4+k41)(k4−k41)
⇒ (k4−k41)(k4+k41)(k4−k41)
⇒ (k8−k81)(k4−k41) ≠ (k16−k161)
∴ Only I is true.