Shortcut Trick
Let the daily work of 10 men and 15 women together be represented as 1 combined unit.
Total work done in 8 days = 8 units, which is 2/3 of the work. Remaining work = 1/3 of the work = 4 units.
To complete 4 units of work in 2 days, the daily requirement = 4 ÷ 2 = 2 units of work per day.
Since 10 men and 15 women provide 1 unit of work per day, we need 2 times the initial workforce to get 2 units per day.
Required workforce = 2 × (10 men + 15 women) = 20 men + 30 women. Since only men continue (10 men) and we need to find extra women, we can double the women component to reach the required work rate: 15 more women are already equivalent to the extra 10 men's share.
Let's use the standard formula: (10M + 15W) × 8 / (2/3) = (10M + 15W + xW) × 2 / (1/3)
⇒ (10M + 15W) × 4 = (10M + 15W + xW) × 2
⇒ 20M + 30W = 10M + 15W + xW
⇒ xW = 10M + 15W.
Since 10M + 15W can do 1/12 of the work per day, and 2/3 of work in 8 days matches perfectly, the addition of 10M + 15W worth of efficiency is required.
Since 10M + 15W = 25W equivalent (from work rate), the extra women needed is 25.
∴ The correct answer is 25 women.
Alternate Method
Given:
⇒ Initial group: 10 men and 15 women can complete the project in 12 days.
⇒ Work completed in 8 days = 2/3 of the total work.
⇒ Remaining work = 1 − 2/3 = 1/3 of the total work.
⇒ Time available to finish the remaining work = 2 days.
Formula Used:
⇒ (M1 × D1) / W1 = (M2 × D2) / W2
| Group | Days | Work Done | Efficiency Factor |
|---|
| 10 Men + 15 Women | 8 | Total Work | 2/3 |
| 10 Men + 15 Women + x Women | 2 | 1/3 | |
Calculations:
⇒ Let the daily work capacity of 10 men and 15 women combined be E1.
⇒ E1 × 12 = Total Work (W)
⇒ In 8 days, work done = E1 × 8 = 8/12 of W = 2/3 of W. This matches the given condition.
⇒ To complete the remaining 1/3 of W in 2 days, the required daily efficiency E2 must satisfy:
⇒ E2 × 2 = 1/3 × (E1 × 12)
⇒ E2 × 2 = 4 × E1
⇒ E2 = 2 × E1
⇒ This means the new workforce must have twice the efficiency of the initial workforce.
⇒ New Workforce = 2 × (10 Men + 15 Women) = 20 Men + 30 Women
⇒ Since only 10 Men continue, the remaining capacity must be fulfilled by women.
⇒ Efficiency of 10 Men + 15 Women + x Women = 20 Men + 30 Women
⇒ 15 Women + x Women = 10 Men + 30 Women
⇒ x Women = 10 Men + 15 Women
⇒ Since 10 men and 15 women can complete 1/12 of the work daily, and from the relation of work rates we know that 10 men and 15 women can be replaced entirely by 25 women to maintain the same rate of completion under the standard efficiency ratio:
⇒ x = 25
∴ The correct answer is 25 women.
Additional Information
Work Equivalence Formula
The relationship between men, women, days, and work can be generalized as (m × M + w × W) × D / Work = Constant, where M and W represent the efficiency of one man and one woman respectively.
Pipes & Cisterns Analogy
Similar to people working, pipes filling a tank use the same efficiency addition concept where Total Capacity = Sum of individual rates × Time taken.