The diagonals of a rhombus are 19 cm and 29 cm. Find its area.
- AOption (a)
275.5 cm2
- BOption (b)
265.5 cm2
- COption (c)
255.5 cm2
- DOption (d)
285.5 cm2
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Correct answer
275.5 cm2
Why this answer is correct
Shortcut Trick
For a Rhombus, the area is always half the product of its diagonals.
Area = 1/2 × (d1 × d2)
Area = 1/2 × 19 × 29 = 551 ÷ 2 = 275.5
∴ The correct answer is 275.5 cm2.
Alternate Method
Given:
Length of first diagonal (d1) = 19 cm
Length of second diagonal (d2) = 29 cm
Formula Used:
Area of Rhombus = (d1 × d2) ÷ 2
Calculations:
⇒ Area = (19 × 29) ÷ 2
⇒ Area = 551 ÷ 2
⇒ Area = 275.5 cm2
∴ The correct answer is 275.5 cm2.
Additional Information
Perpendicular Bisectors
The diagonals of a rhombus always bisect each other at a 90° angle (perpendicularly).
Relation between Side and Diagonals
The side length s is related to the diagonals by: 4s2 = d12 + d22 or s = 1/2 × √(d12 + d22).
Perimeter of Rhombus
Since all four sides of a rhombus are equal, the Perimeter = 4 × side.
Area with Base and Height
The area can also be calculated as Base × Height, similar to a parallelogram.
