A military camp has provisions for 360 soldiers for 50 days. After 10 days, 120 more soldiers arrive at the camp. Assuming the daily consumption per soldier remains constant, for how many more days will the remaining provisions last?
- AOption (a)
32 days
- BOption (b)
28 days
- COption (c)
25 days
- DOption (d)
30 days
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Correct answer
30 days
Why this answer is correct
Shortcut Trick
Remaining food is sufficient for 360 soldiers for 40 days (50 − 10).
Total soldiers after arrival = 360 + 120 = 480 soldiers.
Using M1D1 = M2D2 logic on remaining stock: 360 × 40 = 480 × Days.
Days = 14400 ÷ 480 = 30 days.
∴ The correct answer is 30 days.
Alternate Method
Given:
Initial soldiers (M1) = 360
Initial provision time (D1) = 50 days
Elapsed time = 10 days
Newly joined soldiers = 120
Calculations:
⇒ Total provision units = 360 × 50 = 18,000 units
⇒ Provision consumed in 10 days = 360 × 10 = 3,600 units
⇒ Remaining provision = 18,000 − 3,600 = 14,400 units
⇒ Total soldiers now = 360 + 120 = 480
⇒ Number of days for remaining provisions = Remaining stock ÷ Total soldiers
⇒ Number of days = 14,400 ÷ 480
⇒ Number of days = 30 days
∴ The correct answer is 30 days.
Additional Information
Chain Rule (Work and Time)
The amount of work or provisions is directly proportional to the number of people and the number of days: M1×D1×H1 = M2×D2×H2.
Inverse Variation
For a constant amount of food, the number of days the food lasts is inversely proportional to the number of soldiers. If men increase, days decrease.
Effective Man-Days
The total quantity of provisions is often measured in man-days, which is the product of the number of men and the number of days they can be fed.