The sum of the digits of a two digit number is 11. If 27 is added to the number its digits are reversed. Find the ratio between the original number to the number obtained on reversing the digits.
- AOption (a)
74:47
- BOption (b)
29:23
- COption (c)
23:29
- DOption (d)
47:74
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Correct answer
47:74
Why this answer is correct
Shortcut Trick
Difference between the digits = Difference in numbers ÷ 9 = 27 ÷ 9 = 3.
Sum of digits is given as 11.
Smaller digit (Tens place) = (Sum − Difference) ÷ 2 = (11 − 3) ÷ 2 = 4.
Larger digit (Units place) = (Sum + Difference) ÷ 2 = (11 + 3) ÷ 2 = 7.
Original Number = 47 and Reversed Number = 74.
The required ratio = 47 : 74.
∴ The correct answer is 47:74.
Alternate Method
Given:
Sum of digits of a two-digit number = 11
Original Number + 27 = Reversed Number
⇒ Let the two-digit number be 10x + y, where x is the tens digit and y is the units digit.
⇒ According to the first condition: x + y = 11 → (Equation 1)
⇒ According to the second condition: (10x + y) + 27 = 10y + x
⇒ 10y − y + x − 10x = 27
⇒ 9y − 9x = 27
⇒ y − x = 3 → (Equation 2)
⇒ Adding (1) and (2): (x + y) + (y − x) = 11 + 3 ⇒ 2y = 14 ⇒ y = 7
⇒ Substituting y = 7 in (1): x + 7 = 11 ⇒ x = 4
⇒ Original number = 10(4) + 7 = 47
⇒ Number on reversing = 10(7) + 4 = 74
⇒ Ratio = 47 : 74
∴ The correct answer is 47:74.
Additional Information
Two-Digit Number Properties
Any two-digit number can be represented as 10x + y. The difference between the number and its reverse is always 9 × (x − y).
Divisibility of the Sum
The sum of a two-digit number and its reverse is always divisible by 11 and is equal to 11 × (x + y).
Finding Digits
If the sum (S) and difference (D) of two digits are known, the digits are (S + D) ÷ 2 and (S − D) ÷ 2.
