Previous Year Paper

UPPSC AE Electrical 13 Dec 2020 Official Paper II (Previous Year Paper)

Held in 2020

125 questions150 minutes
With answers
Free

Paper last updated:

Practise under exam conditions

Take this paper as a timed mock test. Review your answers after you submit.

Attempt timed test

Questions & answers

Read the paper at your pace. Open an explanation when you need it.

General Studies (25 questions)

Question 1

The rotation intensity of Maize – Mustard – Mung crop is

  1. AOption (a)

    100%

  2. BOption (b)

    200%

  3. COption (c)

    300%

  4. DOption (d)

    400%

View answer & explanation

Correct answer

Answer: (c)C.

300%

Why this answer is correct

The correct answer is 300%.

 

  • Crop intensity is referred to as the number of crops grown in the same field in one agriculture year.
  • The formula to calculate any crop intensity is:
  • ​Crop intensity= Total cropped area / Total sown Area)X100
  • ​In this case, the number of different crops is 3.
  • So, here the rotation intensity of Maize – Mustard – Mung crop is 300%.

Question 2

Which of the following is not a Kharif crop?

  1. AOption (a)

    Soyabean

  2. BOption (b)

    Lentil

  3. COption (c)

    Cotton

  4. DOption (d)

    Bajra

View answer & explanation

Correct answer

Answer: (b)B.

Lentil

Why this answer is correct

The correct answer is Lentil.

  • Lentil is not a Kharif Crop among the given options.

Key Points

  • India has many growing seasons due to the prevalence of high temperatures over a long period. The different crop seasons are:​
  • Kharif Crop​
  • Crops are sown at the beginning of the southwest monsoon and harvested at the end of the South-West monsoon.
  • Sown in June-July when rains first begin.
  • Harvested in September-October.
  • Requires a lot of water and hot weather to grow.
  • Important crops: Jowar, Bajra, Soybean, Rice, Maize, Cotton, Jute, Groundnut, Sugarcane.
  • Rabi crop
  • Crops need a relatively cool climate during the period of growth but a warm climate during the germination of their seed and maturation.
  • Sown in October-November.
  • Harvested in April-May.
  • Important Crops: Wheat, Barley, Gram, Linseed, Mustard, Masur, Lentil and Potatoes, Tobacco.

Question 3

‘Five Star Village Scheme’ started by Government of India in September 2020 relates to which one of the following?

  1. AOption (a)

    Electricity Supply

  2. BOption (b)

    Postal Service Schemes

  3. COption (c)

    Health Services

  4. DOption (d)

    Primary Education

View answer & explanation

Correct answer

Answer: (b)B.

Postal Service Schemes

Why this answer is correct

The correct answer is Postal Service Schemes.

  • The Department of Posts launched a scheme called Five Star Villages.
  • It is to ensure universal coverage of flagship postal schemes in rural areas of the country.
  • The scheme is being launched on a pilot basis in Maharashtra.
  • It bridges the gaps for generating public awareness and reach of postal products and services, mainly in interior villages.
  • Under the Five Star Village scheme, all postal products and services are going to be made available and marketed, and publicized at the village level.
  • The schemes covered under the Five Star scheme include:
  • ​Savings Bank accounts, Recurrent Deposit Accounts, NSC / KVP certificates.
  • Sukanya Samridhi Accounts/ PPF Accounts.
  • Funded Post Office Savings Account linked India Post Payments Bank Accounts.
  • Postal Life Insurance Policy/Rural Postal Life Insurance Policy.
  • Pradhan Mantri Suraksha Bima Yojana Account / Pradhan Mantri Jeevan Jyoti Bima Yojana Account.

Question 4

Who won the US Open Mens Tennis Singles Title on 14 th September, 2020?

  1. AOption (a)

    Alex Zverev

  2. BOption (b)

    Dominic Thiem

  3. COption (c)

    D. Medvedev

  4. DOption (d)

    P.C. Busta

View answer & explanation

Correct answer

Answer: (b)B.

Dominic Thiem

Why this answer is correct

The correct answer is Dominic Thiem.

Key Points

  • US Open Men's single title- Dominic Thiem (from Austria).
  • US Open Women's single- Naomi Osaka (from Japan).
  • The 2020 US Open was the 140th edition of tennis US open and the second Grand Slam event of the year.
  • It was held on outdoor hard courts at the USTA Billie Jean King National Tennis Center in Queens, New York.
  • It was held without spectators due to the COVID 19 pandemic.

Question 5

Which of the following pairs is NOT correctly matched?

Ancient name of the CitiesModern name of the Cities
a. EsipattanSaranath
b. DashapurMandsor
c. BanvasiTalkad
d. MahodayKannauj
  1. AOption (a)

    a

  2. BOption (b)

    b

  3. COption (c)

    c

  4. DOption (d)

    d

View answer & explanation

Correct answer

Answer: (a)A.

a

Why this answer is correct

The correct answer is a.

Key Points

  • The ancient name of Sarnath is Isipatana.
  • ​Sarnath has been variously known as Mrigadava.
  • Just 10 km north-east of Varanasi, near the confluence of the Ganga and Varuna Rivers in Uttar Pradesh, was Initially known as Isipatana.

Additional Information 

  • The ancient name of Kannauj is Mahoday.
  • Kannauj is one of the most ancient place in India having a rich archeological and cultural heritage.
  • The ancient name of this place is Kanyakubja or Mahodya (as per Balmiki Ramayana, Mahabharat and Puran) later name kanyakubja was changed as Kannauj the present name of the District.
  • ​The ancient name of Mandsaur is Dashpur.
  • ​Mandsaur was known as Dashpur in ancient times.
  • It is also said that the name originated from Mandodri, wife of Ravana. And the ancient name Dashpur was named after her husband Dashanand, the other name of Ravana.
  • The ancient name of Talkad is Banvasi.
  • Banavasi is an ancient town in Uttara Kannada in the state of Karnataka.

Question 6

The early farming site which is located on the bank of a lake is

  1. AOption (a)

    Mehargarh

  2. BOption (b)

    Laharadeva

  3. COption (c)

    Chirand

  4. DOption (d)

    T. Narsipur

View answer & explanation

Correct answer

Answer: (c)C.

Chirand

Why this answer is correct

The correct answer is Chirand​.

Key Points

  • Chirand is the early farming site located on the northern bank of the river Ganga together with two other rivers Sarayu and Son.
  • Chirand is an archaeological site in the Saran district of Bihar.
  • It is the first known site of the Neolithic age.
  • It has a large pre-historic mound (a rounded mass projecting above a surface) containing various artifacts.
  • The mound is known for its continuous archaeological record from the Neolithic age (about 2500–1345 BC) to the reign of the Pala Dynasty, which ruled this place during the pre-medieval period.
  • This is probably one of the youngest date of early farming known from the Gangetic basin.

Additional Information

  • T. Narsipur is a place located in the Mysore district in the Indian state of Karnataka.
  • This is the place in South India where Kumbhamela is held every three years.
  • The word 'Narasipura' is the name of the town, which is derived from the famous Gunja Narasimhaswamy temple that is located on the right bank of the Kabini river.

Question 7

Author of the ‘Dastane Mazahib’ which discusses about the Din-i-Ilahi of Akbar, was

  1. AOption (a)

    Mohammad Rabbani

  2. BOption (b)

    Mohsin Fanni

  3. COption (c)

    Badauni

  4. DOption (d)

    Afif

View answer & explanation

Correct answer

Answer: (b)B.

Mohsin Fanni

Why this answer is correct

The correct answer is Mohsin Fanni.

  • The author of the ‘Dastane Mazahib’ which discusses the Din-i-Ilahi of Akbar, was Mohsin Fanni.
  • Din-i Ilahi “the religion of God,” was a system of religious beliefs introduced by the Mughal emperor Akbar in 1582 CE.
  • Akbar's idea was to combine Islam and Hinduism into one faith, but also to add aspects of Christianity, Zoroastrianism, and Jainism.
  • Akbar took a deep personal interest in religious matters.
  • He founded an academy, the Ibadat Khana, “the House of Worship,” in 1575, where representatives of all major faiths could meet to discuss questions of theology.

​

 

Akbar

  • Akbar was born as Abu'l-Fath Jalal ud-din Muhammad Akbar on October 15, 1542.
  • Akbar succeeded his father, Humayun, in 1556 when he was 13 years old.
  • Akbar was given the nickname 'the Great' because of his many accomplishments.
  • Akbar started a new religion that was based on the teachings of major religions like Hinduism, Christianity, Zoroastrianism, etc.
  • This religious path was later referred to as the Din-i-illahi or Divine Monotheism.
  • Historian Vinset Smith called Akbar's Din-i-ilahi as a monument of his folly not of wisdom.

Question 8

Match List-I with List-II and select the correct answer using the codes given below the lists:

List – I (States)List – II (Highest Peaks)
(A) Tamil Nadu1. Dhoopgarh
(B) Rajasthan2. Saramati
(C) Nagaland3. Guru Shikhar
(D) Madhya Pradesh4. Doda Betta

Choose the correct option from those given below:

  1. AOption (a)

    (A) - (3), (B) - (4), (C) - (1), (D) - (2)

  2. BOption (b)

    (A) - (1), (B) - (2), (C) - (4), (D) - (3)

  3. COption (c)

    (A) - (4), (B) - (3), (C) - (2), (D) - (1)

  4. DOption (d)

    (A) - (2), (B) - (1), (C) - (3), (D) - (4)

View answer & explanation

Correct answer

Answer: (c)C.

(A) - (4), (B) - (3), (C) - (2), (D) - (1)

Why this answer is correct

The correct answer is (A) - (4), (B) - (3), (C) - (2), (D) - (1).

  • The highest Peak of Tamil Nadu is Doda Betta.
  • The highest peak of Tamil Nadu is Doddabetta and is a part of the Nilgiri Hills at the junction of the Western Ghats as well as the Eastern Ghats.
  • ​The highest peak of Rajasthan is Guru Shikhar.
  • ​Guru Shikhar, a peak in the Arbuda Mountains of Rajasthan, is the highest point of the Aravalli Range. The peak is named Guru Shikhar or “peak of the guru” after Dattatreya, an incarnation of Vishnu.
  • ​The highest Peak of Nagaland is Saramati.
  • ​Standing at an altitude of 3841 m, Saramati is the highest peak in the state of Nagaland and occupies a place of pride in the heart of its residents.
  • ​The highest peak of Madhya Pradesh is Dhoopgarh.
  • The Dhupgarh Peak (1,350 metres), near Pachmarhi in south-central Madhya Pradesh, is the state's highest point.

Question 9

Who was appointed the Minister of ‘Ministry of Rehabilitation’ set up on 06 September, 1947?

  1. AOption (a)

    S. P. Mukerji

  2. BOption (b)

    Sardar Vallabhabhai Patel

  3. COption (c)

    J. L. Nehru

  4. DOption (d)

    K. C. Niyogy

View answer & explanation

Correct answer

Answer: (d)D.

K. C. Niyogy

Why this answer is correct

The correct answer is KC Niyogi.

Key Points

  • KC Niyogi was appointed the Minister of 'Ministry of Rehabilitation' set up on 6 September 1947.
  • Kshitish Chandra Neogy (1888–1970), also known as KC Neogi, was an Indian politician from West Bengal.
  • He was a member of the Constituent Assembly of India, a member of the first Cabinet of independent India, and the chairman of the first Finance Commission of India.
  • Neogy was elected as a member of the Constituent Assembly of India and after independence became a member of the First Cabinet of Independent India under Jawaharlal Nehru as the Minister of Relief and Rehabilitation and later as Minister for Commerce.

Question 10

‘Leopold Matrix’ is associated with

  1. AOption (a)

    Weather Forecasting

  2. BOption (b)

    Disaster Management

  3. COption (c)

    Environmental Impact Assessment Method

  4. DOption (d)

    Environmental Law

View answer & explanation

Correct answer

Answer: (c)C.

Environmental Impact Assessment Method

Why this answer is correct

The correct answer is Environmental Impact Assessment Method.

  • 'Leopold Matrix’ is associated with Environmental Impact Assessment Method.
  • It is a procedure for the evaluation of the effect or impact of a proposed development on the environment.​

 

Important Points

  • Environmental Impact Assessment (EIA) is a process of evaluating the likely environmental impacts of a proposed project or development, taking into account inter-related socio-economic, cultural and human-health impacts, both beneficial and adverse.
  • It is statutorily backed by the Environment Protection Act, 1986 which contains various provisions on EIA methodology and process.
  • UNEP defines Environmental Impact Assessment (EIA) as a tool used to identify the environmental, social and economic impacts of a project prior to decision-making.
  • It aims to predict environmental impacts at an early stage in project planning and design, find ways and means to reduce adverse impacts, shape projects to suit the local environment and present the predictions and options to decision-makers.

Question 11

The Joint Sitting of the Indian Parliament for transacting a legislative business is presided over by

  1. AOption (a)

    The President of India

  2. BOption (b)

    The senior most Member of Parliament

  3. COption (c)

    The Chairman of the Rajya Sabha

  4. DOption (d)

    The Speaker of the Lok Sabha

View answer & explanation

Correct answer

Answer: (d)D.

The Speaker of the Lok Sabha

Why this answer is correct

The correct answer is The speaker of the Lok Sabha.

Key Points

  • The joint sitting of the Indian Parliament for transacting a legislative business is presided over by The speaker of the Lok sabha.
  • The joint sitting is called by the President.
  • In his absence of the speaker of the Lok sabha, the sitting is presided over by the Deputy Chairman of the Rajya Sabha.
  • The quorum to constitute a joint sitting: 1/10th of the total number of members of the House.
  • A joint sitting of both Houses of Parliament of the Indian Constitution given in Article 108.

 

 

Additional Information

Speaker of Lok Sabha

  • The speaker of Lok Sabha is a member who elected from amongst the members of the house. He chairs the house and no proceedings in the house take place in his absence.
  • 1st Lok Sabha Speaker – Ganesh Vasudev Mavalankar
  • 17th Lok Sabha elections (2019 General Elections), Om Birla is the speaker of Lok Sabha.

Question 12

The term ‘Office of profit’ has been defined by the

  1. AOption (a)

    Constitution

  2. BOption (b)

    Parliament

  3. COption (c)

    Supreme Court

  4. DOption (d)

    Union Council of Ministers

View answer & explanation

Correct answer

Answer: (a)A.

Constitution

Why this answer is correct

The correct answer is the Constitution.

Key Points

  • The term 'Office of profit' has not been directly defined by the Constitution.
  • But The Constitution of India, apart from enlisting certain qualifications for Members of Parliament and Legislative Assembly, also enumerates certain disqualifications. One of these disqualifications is holding an “office of profit”.
  • Under the provisions of Article 102 (1) and Article 191 (1) of the Constitution, an MP or an MLA (or an MLC) is barred from holding any office of profit under the central or state government.
  • The articles clarify that “a person shall not be deemed to hold an office of profit under the government of India or the government of any state by reason only that he is a minister”.
  • A person will be disqualified if he holds any office of profit under the central or state government, other than an office declared not to disqualify its holder by a law passed by Parliament or state legislature.

 Principles for including ‘office of profit’ as a criterion for disqualification are:

  • Makers of the Constitution wanted that legislators should not feel obligated to the Executive in any way, which could influence them while discharging legislative functions.
  • In other words, an MP or MLA should be free to carry out her duties without any kind of governmental pressure. The intent is that there should be no conflict between the duties and interests of an elected member.
  • The office of profit law simply seeks to enforce a basic feature of the Constitution- the principle of separation of power between the legislature and the executive.

Question 13

While deciding any question relating to the disqualification of a Member of Parliament, the President shall obtain the opinion of

  1. AOption (a)

    Election Commission

  2. BOption (b)

    Chief Justice of India

  3. COption (c)

    Attorney General

  4. DOption (d)

    Speaker of the Lok Sabha

View answer & explanation

Correct answer

Answer: (a)A.

Election Commission

Why this answer is correct

The correct answer is Election Commission.

  • While deciding any question relating to the disqualification of a Member of Parliament, the President shall obtain the opinion of the Election Commission.
  • Election Commission of India is a permanent Constitutional Body.
  • The Constitution provides for an independent election commission to ensure free and fair election to the Parliament, the State legislature,and the offices of President and Vice-President.
  • Consists of Chief Election Commissioner +2 Election Commissioners.
  • The Chief Election Commissioner is appointed by the President and the other Election Commissioners are appointed by the President after consultation with the Chief Election Commissioner, Article 324 also provides for the appointment of Regional Commissioners at the time of General Elections after consultation with the Election Commission.
  • Election Commissioners are appointed for a term of 6 years.
  • They are not eligible for re-appointment. Also, they cannot hold any office of profit after their retirement.
  • In article 324 of the Indian constitution, it envisages the Election Commission of India (ECI).

 

Additional Information

Chief Justice of IndiaThe Chief Justice of India (CJI) is the head of the judiciary of India and the Supreme Court of India. The CJI also heads the administrative functions of the judiciary.Current- Arvind Bobde
Attorney GeneralAttorney General of India is the chief legal advisor to the government of India and advises the union government on all legal matters. The Attorney General of India is the highest law officer in the countryCurrent- KK Venugopal
Speaker of the Lok SabhaThe Speaker of Lok Sabha is both a member of the House and its Presiding Officer. The Speaker conducts the business in the HouseCurrent- Om Birla

Question 14

Soyabean seed contains

  1. AOption (a)

    20% protein and 40% oil

  2. BOption (b)

    40% protein and 10% oil

  3. COption (c)

    40% protein and 20% oil

  4. DOption (d)

    20% protein and 20% oil

View answer & explanation

Correct answer

Answer: (c)C.

40% protein and 20% oil

Why this answer is correct

The correct answer is 40% protein and 20% oil.

Key Points

  • Soybean seeds contain 40% of crude protein and about 20% of fat.
  • The soybean is one of the most economical and valuable agricultural commodities because of its unique chemical composition.
  • Since time immemorial, Soyabean has served as meat, milk, cheese, bread as well as oil for people across the globe.
  • Soyabean is India’s one of the fastest-growing crops and a significant foreign exchange earner.

Question 15

As per the results of ‘Swachh Sarvekshan 2020’, announced by Ministry of Housing and Urban Affairs on 20th August 2020, which is the cleanest City in Uttar Pradesh?

  1. AOption (a)

    Agra

  2. BOption (b)

    Ghaziabad

  3. COption (c)

    Lucknow

  4. DOption (d)

    Prayagraj

View answer & explanation

Correct answer

Answer: (c)C.

Lucknow

Why this answer is correct

The correct answer is Lucknow​.

Key Points

  • As announced by the Ministry of Housing and Urban Affairs, Lucknow is the cleanest city in Uttar Pradesh.
  • Swachh Survekshan 2020 report was released by the Union Housing and Urban Affairs Ministry.
  • Swachh Survekshan 2020 covered 4,242 cities, 62 cantonment boards and 92 Ganga towns.
  • This survey was carried out in 28 days.

 

Additional Information

Swachh Survekshan 2020

  • Indore was ranked the cleanest city in the overall category this year followed by Surat and Navi Mumbai.
  • Chhattisgarh is the cleanest state in the category of states with more than 100 urban local bodies.
  • Ahmedabad is India’s cleanest Megacity.
  • New Delhi is the cleanest capital city.
  • Chhattisgarh’s Ambikapur is the cleanest smallest city.
  • Cleanest Cantonment: Jalandhar Cantt, Punjab.

Question 16

How many teachers from Uttar Pradesh were selected for ‘National Award’ on Teachers day 5th Sept. 2020?

  1. AOption (a)

    Six

  2. BOption (b)

    Five

  3. COption (c)

    Four

  4. DOption (d)

    Three

View answer & explanation

Correct answer

Answer: (d)D.

Three

Why this answer is correct

The correct answer is Three.

Key Points

  • Three teachers from Uttar Pradesh were selected for the 'National Award' on teacher day.
  • The three from UP are — Mohammed Ishrat Ali, head teacher in a primary school, Rajwana in Mainpuri; Snehil Pandey, head teacher in a primary school Soharamau, Nawabganj in Unnao; and Vikas Kumar, principal, SD Inter College Meerapur, in Muzaffarnagar
  • Union Education Ministry inferred the National Award to Teachers as a way of recognizing their achievements in the field of education.
  • The awards were conferred by President Ram Nath Kovind on the occasion of Teacher's Day on September 5, 2020.
  • 47 teachers have been selected by the government for 'National Awards to Teachers 2020.

 

Additional Information

  • Teacher’s Day is celebrated across India today to honour Dr. Sarvepalli Radhakrishnan.
  • It is observed annually on September 5, as Dr. Radhakrishnan was born on September 5, 1888.
  • Dr. Sarvepalli Radhakrishnan was India's first Vice President and second President.
  • Teachers' Day was first celebrated in 1962, the year he became the second President of India.
  • Since then, the day has been celebrated every year. Dr. Radhakrishnan highly believed that teachers should be the best minds in the country.

Question 17

‘Poshan Maah’ was celebrated by Government of India in the year 2020, in which of the following months?

  1. AOption (a)

    September

  2. BOption (b)

    August

  3. COption (c)

    July

  4. DOption (d)

    June

View answer & explanation

Correct answer

Answer: (a)A.

September

Why this answer is correct

The correct answer is September.

Key Points

  • Rashtriya Poshan Maah was celebrated in September 2020.
  • It was celebrated to promote nutrition among Women and Children.
  • Poshan Maah is celebrated every year to encourage Jan Bhagidaari in order to ensure health and nutrition for everyone.
  • Every year Poshan Maah is celebrated all over the country under POSHAN Abhiyaan, launched in 2018.
  • The importance of Nutrition in our lives was emphasized by Prime Minister Shri Narendra Modi in his popular programme “Mann ki Baat” on 30th August 2020.

Question 18

Match List-I with List-II and select the correct answer using the codes given below the lists:

List – I (Text)List-II (Author)
(A) Kiratarjuniyam1. Dandi
(B) Dashakumar Charitam2. Kalidas
(C) Buddha Charitam3. Bharavi
(D) Vikramorvashiyam4. Ashvagosha

Choose the correct option from those given below:

  1. AOption (a)

    (A) - (3), (B) - (4), (C) - (1), (D) - (2)

  2. BOption (b)

    (A) - (3), (B) - (1), (C) - (4), (D) - (2)

  3. COption (c)

    (A) - (2), (B) - (3), (C) - (1), (D) - (4)

  4. DOption (d)

    (A) - (1), (B) - (3), (C) - (2), (D) - (4)

View answer & explanation

Correct answer

Answer: (b)B.

(A) - (3), (B) - (1), (C) - (4), (D) - (2)

Why this answer is correct

The correct answer is (A) - (3), (B) - (1), (C) - (4), (D) - (2)​.

Key Points

  • Kiratarjuniyam- It is a Sanskrit epic written in the 6th century by Bharavi.
  • It is his only recognized work.
  • It is an epic poem with eighteen cantos in which Lord Shiva tests the power of Arjuna, one of the Pandavas in the Mahabharata.
  • Dashakumar Charitam-  It is authored by renowned Sanskrit poet Dandi.
  • It relates the adventures of ten princes in their pursuit of love and royal power.
  • Buddha Charitam-  It is an epic poem in the Sanskrit maha kavya style on the life of Gautam Budha by Ashvagosha, composed in the early second century.
  • Vikramorvashiya-  It is a five-act Sanskrit play by ancient Indian poet Kalidasa who flourished in the 4th Century CE, on the Vedic love story of king Pururavas and an Apsara, a celestial nymph named Urvashi.

Question 19

A large tank near Mahoba, temples at Ajaygarh and Mahoba and city of Rajavasini were built by a Chandella king_____.

  1. AOption (a)

    Nannuk

  2. BOption (b)

    Vakpati

  3. COption (c)

    Rahil

  4. DOption (d)

    Jayashakti

View answer & explanation

Correct answer

Answer: (c)C.

Rahil

Why this answer is correct

The correct answer is Rahil. 

 

  • A large tank near Mahoba, temples at Ajaygarh and Mahoba and the city of Rajavsini were built by Chandella King Rahil.
  • The town Rahilya which is three km southwest of Mohaba was named after Rahil.
  • The Chandela or Chandel is a Rajput clan in Central India.
  • An area of the Chandelas which was otherwise called Chandela Dynasty led a great part of the Bundelkhand district of central India for a long period of time between the 10th and the thirteenth century AD.
  • Chandel Dynasty is known in Indian history for Maharaja Rao Vidyadhara, who spurned the assaults of Mahmud of Ghazni.

Question 20

Which of the following Rights a cultivator enjoyed on his own land during the Mughal period?

  1. AOption (a)

    Right to mortgage only

  2. BOption (b)

    Right to sell and gift

  3. COption (c)

    Right to mortgage and gift

  4. DOption (d)

    All the above rights

View answer & explanation

Correct answer

Answer: (c)C.

Right to mortgage and gift

Why this answer is correct

The correct answer is Right to mortgage and gift.

 

  • Cultivators during the Mughal period enjoyed the Right to mortgage and gift their land.
  • The Mughal dynasty was founded by Babur.
  • He was a Chagatai Turkic prince and was descended from the Turkic conqueror Timur (Tamerlane) on his father’s side and Genghis Khan, on his mother’s side.
  • The Mughal period was between 1526-1857.
  • Mughal Empire controlled almost the entire Indian subcontinent.
  • It stretched from the edges of the Indus river basin, northern Afghanistan and Kashmir in the north west to the now-Assam and Bangladesh highlands in the east, and down to the uplands of Deccan plateau in the south.

Question 21

Match List-I with List-II and select the correct answer using the codes given below the lists:

List – I (Tribes)List – II (States)
(A) Tharus1. Madhya Pradesh
(B) Todas2. Jharkhand
(C) Santhal3. Uttarakhand
(D) Gond4. Tamil Nadu

 

Choose the correct option from those given below:

  1. AOption (a)

    (A) - (1), (B) - (3), (C) - (4), (D) - (2)

  2. BOption (b)

    (A) - (4), (B) - (2), (C) - (1), (D) - (3)

  3. COption (c)

    (A) - (2), (B) - (1), (C) - (3), (D) - (4)

  4. DOption (d)

    (A) - (3), (B) - (4), (C) - (2), (D) - (1)

View answer & explanation

Correct answer

Answer: (d)D.

(A) - (3), (B) - (4), (C) - (2), (D) - (1)

Why this answer is correct

The correct answer is option 4.

Key Points

  • Gond is a tribe of Madhya Pradesh.
  • Gond tribe is one of the largest Adivasi communities.
  • The Gond called themselves Koi or Koiture.
  • They inhabited the dense forests of the Vindhyas, Satpura and Mandla in the Narmada region of the Amarkantak range for centuries.
  • Tharus is a tribe of Uttarakhand.
  • They are live in Khatima and Sitarganj tehsil of UdhamSingh Nagar district (Uttarakhand).
  • Todas is a tribe of Tamil Nadu.
  • Todas is a tribal group in the higher altitudes of the Nilgiris.
  • Santhal is a tribe of Jharkhand.
  • They are also called Manjhi.
  • The third-largest tribes of India are the Santhal Tribe.
  • This tribe habitation is mainly in the states of West Bengal, Bihar, Odisha, Jharkhand and Assam.

Additional Information

Important tribes of :

StateTribes
Madhya PradeshKharia, Bhils, Murias, Birhors, Bharia, Khond, Gonds
UttarakhandBhotia, Buksa, Jaunsari, Kol, Raji,  Khas, Raji, Tharu
Tamil Nadu.Kadar, Kanikar, Kotas, Todas
JharkhandSavar, Mundas, Santhals, Khaira

Question 22

Match List-I with List-II and select the correct answer using the codes given below the lists:

List – IList – II
(A) Nokrek1. Uttarakhand
(B) Agasthyamalai2. Arunachal Pradesh
(C) Nandadevi3. Kerala
(D) Dehang Debang4. Meghalaya

 

Choose the correct option from those given below:

  1. AOption (a)

    (A) - (4), (B) - (3), (C) - (1), (D) - (2)

  2. BOption (b)

    (A) - (4), (B) - (3), (C) - (2), (D) - (1)

  3. COption (c)

    (A) - (3), (B) - (4), (C) - (1), (D) - (2)

  4. DOption (d)

    (A) - (2), (B) - (3), (C) - (4), (D) - (1)

View answer & explanation

Correct answer

Answer: (a)A.

(A) - (4), (B) - (3), (C) - (1), (D) - (2)

Why this answer is correct

The correct answer is (A) - (4), (B) - (3), (C) - (1), (D) - (2).

Key Points

 In the given table, Biosphere reserves are given.  These are biosphere reserve of states:

  • Nokrek is a biosphere reserve in Meghalaya.

  • The Nokrek Biosphere Reserve is located in the northeast of India on the Tura Range, which forms part of the Meghalaya Plateau.

  • ​Agasthyamalai is a biosphere reserve in Kerala.

  • ​The Agasthyamala Biosphere Reserve (ABR) has got its name into UNESCO’s World Network of Biosphere Reserves (BR).

  • It was established in 2001 and straddles the border of Kollam and Thiruvananthapuram Districts in Kerala and Tirunelveli and Kanyakumari Districts in Tamil Nadu, South India at the southern end of the Western Ghats.

  • Nandadevi is a biosphere reserve in Uttarakhand.

  • Nanda Devi Biosphere Reserve, located in the Himalayan Mountains in the northern part of the country.

  • It includes core areas of the Nanda Devi and Valley of Flowers National Parks, which are one World Heritage site.

  • ​​​Dehang Debang is a biosphere reserve in Arunachal Pradesh.

  • Dihang-Dibang or Dehang-Debang is a biosphere reserve constituted in 1998.

  • It is in the Indian state of Arunachal Pradesh.

  • Biosphere reserves are areas of terrestrial and coastal ecosystems promoting solutions to reconcile the conservation of biodiversity with its sustainable use.

  • They are internationally recognized, nominated by national governments, and remain under the sovereign jurisdiction of the states where they are located.

  • They often include one or more National Parks and/or preserves, along with buffer zones that are open to some economic uses. Protection is granted not only to the flora and fauna of the protected region, but also to the human communities who inhabit these regions, and their ways of life.

Question 23

States get share of the revenue from

  1. AOption (a)

    Income Tax

  2. BOption (b)

    Customs Revenue

  3. COption (c)

    Excise Tax

  4. DOption (d)

    Surcharge on Income Tax

View answer & explanation

Correct answer

Answer: (c)C.

Excise Tax

Why this answer is correct

The correct answer is Excise tax.

Key Points

  • The state gets a share of the revenue from the Excise tax.
  • Excise tax is a form of indirect tax that is levied by the Central Government of India for the production, sale, or license of certain goods.
  • It is also collected by state governments for alcohol and narcotics.
  • GST has now subsumed a number of indirect taxes including excise tax.
  • This means excise tax, does not exist in India except on a few items such as **liquor and petroleum. **​

Additional Information

Income taxIncome tax is a type of tax that governments impose on income generated by businesses and individuals within their jurisdiction. Income taxes are a source of revenue for governments.
Custom revenueCustoms revenue is a tax imposed on imports and exports of goods
Surcharge on Income TaxSurcharge on income tax is levied on the tax payable, and not on the income generated.

Question 24

Which Article of the Indian Constitution empowers Parliament to make law for implementing international agreements?

  1. AOption (a)

    Article 249

  2. BOption (b)

    Article 250

  3. COption (c)

    Article 252

  4. DOption (d)

    Article 253

View answer & explanation

Correct answer

Answer: (d)D.

Article 253

Why this answer is correct

The correct answer is Article 253.

  • Article 253 of the Indian Constitution empowers Parliament to make laws for implementing international agreements.
  • Article 253- empowers Parliament to make any law for the whole or any part of the territory of India for implementing treaties, international agreements, and conventions.
  • It enables the Government of India to implement all international obligations and commitments.

Additional Information

  • Article 249- empowers the parliament to legislate with respect to a matter in the State List in the national interest.
  • Article 250- According to this parliament is empowered to make laws on any item that is included in the State List for the whole or part of India, while a Proclamation of emergency is in operation.
  • Article 252- It is about the Power of Parliament to legislate for two or more States by consent and adoption of such legislation by any other State.

Question 25

Who appoints the acting Chief Justice of India?

  1. AOption (a)

    Chief Justice of India

  2. BOption (b)

    Chief Justice of India with previous consent of the President

  3. COption (c)

    President of India

  4. DOption (d)

    President in consultation with the Chief Justice of India

View answer & explanation

Correct answer

Answer: (c)C.

President of India

Why this answer is correct

The correct answer is the President of India.

Key Points

  • The appointment of acting Chief Justice is to be made by the President under Article 126 of the Constitution.
  • Vacancy in the office of the Chief Justice must be filled whatever the period of vacancy.
  • Article 126 – Appointment of acting Chief justice.
  • Justice D Y Chandrachud is the current and 50th CJI.

Additional Information

Role of Chief Justice of India

 

  • The Chief Justice is responsible for the allocation of work to other judges.
  • The Chief Justice administers the oath of office to the President In the absence of the President and the Vice-President, the Chief Justice sits as the Acting President of India
  • The Chief Justice is the ex-officio Chancellor to most autonomous law schools in India.

Eligiblity

  • The individual must be a citizen of India.
  • The person must not exceed 65 years of age.
  • In order to be eligible to be Chief Justice of India, the person must serve as a judge at High Court for at least five years or the person should be an advocate in the High court or the Supreme court for at least 10 years or a distinguished jurist.

Technical (100 questions)

Question 26

A combination circuit has inputs A, B and C, its K-map is given below. The output of circuit is given by

  1. AOption (a)

    (AˉB+ABˉ)C;\rm(\bar AB + A \bar B)C;

  2. BOption (b)

    (AˉB+ABˉ)Cˉ\rm(\bar AB + A \bar B) \bar C

  3. COption (c)

    AˉBˉCˉ\rm\bar A \bar B \bar C

  4. DOption (d)

    A ⊕ B ⊕ C

View answer & explanation

Correct answer

Answer: (d)D.

A ⊕ B ⊕ C

Why this answer is correct

Karnaugh map (K-map):

  • The Karnaugh map (K-map) is a method of simplifying Boolean algebra expressions.
  • The Karnaugh map reduces the need for extensive calculations.
  • Karnaugh map can be explained as An array that contains 2k number of cells, where k is the number of variables in the Boolean expression that is to be reduced or optimized.

Number of cells in 2 variable k-map = 22 = 4

Number of cells in 3 variable k-map = 23 = 8

Number of cells in 4 variable k-map = 24 = 16

2 variable K-maps:

There are 4 cells in the 2-variable k-map as shown,

3 variable K-maps:

  • For a 3-variable Boolean function, there is a possibility of 8 output minterms.
  • The general representation of all the minterms using 3-variables is shown below.

Explanation:

From the given K-map, the simplified Boolean expression is

F = C A̅ B̅ + C̅ A̅ B + CAB + C̅ A B̅ 

= C̅ (A̅ B + A B̅) + C (A̅ B̅ + AB)

= A ⊕ B ⊕ C

Question 27

Find out the integrating type analog to digital converter from the following.

  1. AOption (a)

    flash type converter

  2. BOption (b)

    tracking converter

  3. COption (c)

    successive approximation type converter

  4. DOption (d)

    dual-slope analog to digital converter

View answer & explanation

Correct answer

Answer: (d)D.

dual-slope analog to digital converter

Why this answer is correct

Dual slope ADC:

  • These reduce design complexity and improves measurement quality.

  • Dual-Slope integration type ADC is the most accurate type of ADC because of non-dependency on variation in components values caused by noise.

  • It is quite slow in nature and used in application as digital voltmeter, multimeters etc.

  • In dual slope and single slope ADCs instead of using a DAC with a ramped output, we use an op-amp circuit called integrator to generate a sawtooth wave.

  • These are used in the precision application.

  • Counter type ADC and successive approximate ADC uses DAC

  • Counter type ADC uses linear search and successive approximation type ADC uses binary search

  • A ring counter is used in successive approximation type ADC

  • Flash type ADC is fastest ADC

  • Flash type ADC requires no counter

  • For an n-bit ADC, flash type ADC requires (2n – 1) comparators

  • Dual slope ADC is most accurate

Question 28

The minimum number of 2-input NAND gates required to realize the logic function Y=ABˉ;+AˉBY = A\bar B; + \bar AB is

  1. AOption (a)

    5

  2. BOption (b)

    3

  3. COption (c)

    6

  4. DOption (d)

    4

View answer & explanation

Correct answer

Answer: (d)D.

4

Why this answer is correct

Concept:

  • The EX-OR gate is used extensively in digital data processing circuits and is known as Exclusive-OR-gate.
  • The E XOR gate has a high output only when an odd number of inputs are high.
  • For the two input E XOR gates, the output will be high when the set of input is either 01 or 10.
  • The E XOR gate is used in the adder, subtractor, and controlled inverter circuit. It is also used in computers for implementing binary addition.
  • Therefore, the gate can be used as a Comparator where it gives high output if both the inputs are not equal.

NAND Gate:

The NAND or “Not AND” function is a combination of the two separate logical functions, the AND function and the NOT function in series. The logic NAND function can be expressed by the Boolean expression of, A.B.

Explanation:

The XOR Gate can be constructed with NAND gates in the following manner:

Y = A̅.B + A.B̅ 

Hence a minimum of 4 NAND gates is required to construct an EX-OR gate.

Important Points

Logic GatesMin. number of NOR GateMin. number of NAND Gate
NOT11
AND32
OR23
EX-OR54
EXNOR45
NAND41
NOR14
Half-Adder55
Half-Subtractor55
Full-Adder99
Full-Subtractor99

Question 29

Find the cut-off frequency for an RC low pass filter of R = 8.2 Ω and C = 0.0033 μF.

  1. AOption (a)

    6 kHz

  2. BOption (b)

    5.88 MHz

  3. COption (c)

    4.26 kHz

  4. DOption (d)

    170 MHz

View answer & explanation

Correct answer

Answer: (b)B.

5.88 MHz

Why this answer is correct

Concept:

Low-Pass RC filter:

  • One simple low-pass filter circuit consists of a resistor in series with a load and a capacitor in parallel with the load.
  • The capacitor exhibits reactance, and blocks low-frequency signals, forcing them through the load instead.
  • At higher frequencies, the reactance drops, and the capacitor effectively functions as a short circuit.

 

The cut-off frequency is also known as the break frequency, turnover frequency, corner frequency and it is given by

fc=12πRC{f_c} = \dfrac{1}{{2\pi RC}}

Calculation:

Given that, R = 8.2 Ω and C = 0.0033 μF

fc=12π×8.2×0.0033×10−6{f_c} = \dfrac{1}{{2\pi \times 8.2 \times 0.0033 \times {{10}^{ - 6}}}}

= 5.88 MHz

Question 30

Why synchronous transmission is preferred more?

  1. AOption (a)

    it has no start and stop bit

  2. BOption (b)

    it is cheaper than asynchronous

  3. COption (c)

    it is easier to implement

  4. DOption (d)

    less complex

View answer & explanation

Correct answer

Answer: (a)A.

it has no start and stop bit

Why this answer is correct

The main difference between synchronous and asynchronous transmission is that the clocking is derived from the data in synchronous transmission and it is absent in asynchronous transmission.

Synchronous transmission is more preferred because it has no start and stop bit

Some basic differences between synchronous & asynchronous transmission are given below

Basis for ComparisonSynchronous TransmissionAsynchronous Transmission
MeaningTransmission starts with the block header which holds a sequence of bitsIt uses start bit and stop bit preceding and following a character respectively
Transmission mannerSends data in the form of blocks of framesSends 1 byte or character at a time
SynchronizationPresent with the same clock pulse.Absent
Implemented byHardware and softwareHardware only
Transmission speedFastSlow
CostExpensiveEconomical
Gap between the dataDoes not existExist
Time intervalConstantRandom
ExamplesChat Rooms, Video Conferencing, telephonic Conversations, etcLetters, emails, forums, etc

Question 31

A 400 W carrier is amplitude modulated with m = 0.75. The total power in AM is

  1. AOption (a)

    400 W

  2. BOption (b)

    512 W

  3. COption (c)

    588 W

  4. DOption (d)

    650 W

View answer & explanation

Correct answer

Answer: (b)B.

512 W

Why this answer is correct

Concept:

The total transmitted power for an AM system is given by:

Pt=Pc(1+μ22){P_t} = {P_c}\left( {1 + \frac{{{μ^2}}}{2}} \right)

Pc = Carrier Power

μ = Modulation Index

Calculation:

Given:

Pc = 400 W, μ = 0.75

Pt=400(1+0.7522){P_t} = 400\left( {1 + \frac{{{{0.75}^2}}}{2}} \right)

= 512.5 W

Question 32

An air filled rectangular waveguide has inner dimensions of 3 cm × 2 cm. The wave impedance of the TE20 mode of propagation in the waveguide at a frequency of 30 GHz is ________. (free space impedance η0 = 377 Ω)

  1. AOption (a)

    308 Ω

  2. BOption (b)

    355 Ω

  3. COption (c)

    400 Ω

  4. DOption (d)

    461 Ω

View answer & explanation

Correct answer

Answer: (c)C.

400 Ω

Why this answer is correct

Concept:

The wave impedance of the waveguide is given by:

\({η } = \frac{{{η 0}}}{{\sqrt {1 - \frac{{f_c^2}}{{f;^2}}} }}\)  ---(1)

Where,

fc = cutoff frequency

f = operating frequency

The cutoff frequency can be calculated by:

fc=c2(ma)2 + (nb)2f_c=\frac{c}{2}\sqrt{{(\frac{m}{a}})^2 \ + \ (\frac{n}{b})^2}  ----(2)

Where,

c = 3 × 1010 cm/s

a and b are dimensions of rectangular waveguide

m and n determines the mode number

For a > b, TE10 is the dominant mode for the waveguide.

Calculation:

Given:

a = 3 cm

b = 2 cm

The cutoff frequency for TE20 can be calculated using equation (2):

fc=3×10102(23)2 + (02)2f_c=\frac{3\times10^{10}}{2}\sqrt{{(\frac{2}{3}})^2 \ + \ (\frac{0}{2})^2}

fc = 10 GHz

Now the wave impedance can be calculated using equation (1)

η=3771−(10 GHz)2(30 GHz)2{η } = \frac{{{377}}}{{\sqrt {1 - \frac{{{(10 \ GHz})^2}}{{(30 \ GHz)}^2}} }}

η = 400 Ω 

**Hence option (3) is the correct answer.**​

Question 33

Noise temperature of Sun is more than __________ K.

  1. AOption (a)

    1000

  2. BOption (b)

    5000

  3. COption (c)

    100000

  4. DOption (d)

    500

View answer & explanation

Correct answer

Answer: (c)C.

100000

Why this answer is correct

Explanation:

Noise temperature

1. It is one way of expressing the level of available noise power introduced by a component or source. The power spectral density of the noise is expressed in terms of the temperature (in kelvins) that would produce that level of Johnson–Nyquist noise.

2. It is useful in dealing with UHF.

The Sun is a strong variable noise source with a noise temperature of about 106 K at 50 to 200 MHz and at least 104 K at 10 GHz under quiet Sun conditions.

Large increases occur when the Sun is disturbed. Hence option (3) is the correct answer.

Important Points

Thermal noise:

  • It is also called Johnson-Nyquist noise
  • It arises due to thermal agitation of electrons in a conductor material when the temperature is increased above absolute zero and it is also called thermal agitation noise
  • It is distributed across the entire frequency spectrum range so it is also called white noise
  • Thermal noise is generally observed in the passive component like R, L & C due to the random movement of charge carriers electrons.
  • Random noise power is

Pn = KTB

Where,

K = Boltz man's constant

T = temperature

B = Bandwidth over which noise is measured

Question 34

A cavity magnetron uses strapping to

  1. AOption (a)

    prevent mode jumping

  2. BOption (b)

    prevent cathode back heating

  3. COption (c)

    ensure bunching

  4. DOption (d)

    improve the phase focussing effect

View answer & explanation

Correct answer

Answer: (a)A.

prevent mode jumping

Why this answer is correct

The cavity magnetron is acts like a microwave oscillator and generates microwaves and it uses strapping to prevent mode jumping.

Cavity Magnetron:

  • The cavity magnetron is a high-power vacuum tube that generates microwaves using the interaction of a stream of electrons with a magnetic field while moving past a series of cavity resonators which are small, open cavities in a metal block.

  • Electrons pass by the cavities and cause microwaves to oscillate within, similar to the functioning of a whistle producing a tone when excited by an air stream blown past its opening.

  • The resonant frequency of the arrangement is determined by the cavities' physical dimensions.

  • Advance magnetron is the resonant cavity magnetron or electron-resonance magnetron

  • The cavity magnetron consists of a large, solid cylinder of metal with a hole drilled through the center of the circular face.

  • A wire acting as the cathode is run down the center of this hole, and the metal block itself forms the anode.

  • Around this hole, known as the "interaction space", are a number of similar holes ("resonators") drilled parallel to the interaction space, connected to the interaction space by a short channel.

  • An AC circuit the electrons travel along the surface, not the core, of the conductor, the parallel sides of the slot acts as a capacitor while the round holes form an inductor: an LC circuit made of solid copper, with the resonant frequency defined entirely by its dimensions.

  • The oscillating currents flowing around the cavities, and their effect on the electron flow within the tube, causes large amounts of microwave radiofrequency energy to be generated in the cavities.

  • The cavities are open on one end, so the entire mechanism forms a single, larger, microwave oscillator.

  • A "tap", normally a wire formed into a loop, extracts microwave energy from one of the cavities.

  • In some systems the tap wire is replaced by an open hole, which allows the microwaves to flow into a waveguide.

Question 35

A microwave tube amplifier uses an axial magnetic field and a radial electric field. This is a

  1. AOption (a)

    Reflex klystron

  2. BOption (b)

    Co-axial magnetron

  3. COption (c)

    Travelling wave magnetron

  4. DOption (d)

    CFA

View answer & explanation

Correct answer

Answer: (d)D.

CFA

Why this answer is correct

  • The Crossed Field Amplifier (CFA) is a broadband microwave amplifier that can also be used as an oscillator.
  • It is a microwave tube amplifier that uses an axial magnetic field and radial electric field
  • Its operation is similar in operation to the magnetron and can provide relatively large amounts of power with high efficiency.

 

Travelling Wave Tube:

  • A specialized vacuum tube that is used in electronics to amplify radio frequency (RF) signals in the microwave range.
  • The TWT belongs to a category of "linear beam" tubes, such as the klystron, in which the radio wave is amplified by absorbing power from a beam of electrons as it passes down the tube.
  • A major advantage of the TWT over some other microwave tubes is its ability to amplify a wide range of frequencies i.e. a large bandwidth.
  • The bandwidth of the helix TWT can be as high as two octaves, while the cavity versions have bandwidths of 10% - 20%.
  • Operating frequencies range from 300 MHz to 50 GHz.
  • The power gain of the tube is on the order of 40 to 70 decibels, and output power ranges from a few watts to megawatts.

Question 36

In a circular waveguide, the dominated mode is

  1. AOption (a)

    TE01

  2. BOption (b)

    TE11

  3. COption (c)

    TE20

  4. DOption (d)

    TE21

View answer & explanation

Correct answer

Answer: (b)B.

TE11

Why this answer is correct

Explanation:

  • A circular waveguide is a tubular, circular conductor. A plane wave propagating through circular waveguide results in transverse electric (TE) or transverse magnetic (TM) mode.
  • Transverse electric (TE) and transverse magnetic (TM) waves are propagated in circular waveguides in almost the same manner as in rectangular waveguides.
  • A plane wave propagating through circular waveguide results in TE and TM modes and one of these modes will be present depending upon the wave launcher.
  • The field configuration in the circular waveguide closely follows a sine wave pattern.
  • In a circular waveguide, TE11 mode has the lowest cut-off frequency and is, therefore, the dominant mode. Hence option (2) is the correct answer.
  • If D is the diameter of the waveguide, then λc = 1.706 D for TE11 mode

1. The dominant mode in a rectangular waveguide is TE10, and in a circular waveguide is TE11

2. Cut-off frequency equation for circular waveguide given below is defined as:

fc=1.8412.c2πa{f_c} = \frac{{1.8412.c}}{{2\pi a}}

a = Radius of the inner circular cross-section

c = Speed of light

3. The cutoff frequency for the dominant mode in the rectangular waveguide is given as:

fc=c2af_c=\frac{c}{2a}

Where a = length of rectangular waveguide.

Question 37

A hollow rectangular waveguide can NOT propagate TEM wave because

  1. AOption (a)

    Of the existence of only one conductor

  2. BOption (b)

    Of the losses caused

  3. COption (c)

    It is dependent on the type of the material used

  4. DOption (d)

    None of the above

View answer & explanation

Correct answer

Answer: (a)A.

Of the existence of only one conductor

Why this answer is correct

Explanation:

1. A waveguide is a special form of transmission line consisting of a hollow, metal tube. The tube wall provides distributed inductance, while the empty space between the tube walls provides distributed capacitance.

2. Waveguides are practical only for signals of extremely high frequency, where the wavelength approaches the cross-sectional dimensions of the waveguide. 

A hollow rectangular waveguide cannot propagate TEM wave because of the following reasons:

1. If a transmission line is made by perfect conductors then propagation of pure TEM wave will be not possible as in TEM wave propagation electron and magnetic field components are perpendicular to the guide axis and its cut-off frequency is zero and TEM wave propagate only along guide axis.

2. A transmission line such that rectangular waveguide and cylindrical waveguide are hollow waveguides in which center conductor (i.e. guide axis) does not exist. Therefore in this TEM wave can not propagate.

Hence option (1) is the correct answer.

Important Points

  • A rectangular waveguide is a hollow metal tube with a rectangular cross-section.
  • The conducting walls of the waveguide confine the electromagnetic fields and thereby guide the electromagnetic wave.
  • Microwave energies propagate the length of the waveguide by the reflection of its sidewalls.

Question 38

The most commonly used method for the protection of three phase feeder is

  1. AOption (a)

    Time graded protection

  2. BOption (b)

    Differential protection

  3. COption (c)

    Reverse power protection

  4. DOption (d)

    None of these

View answer & explanation

Correct answer

Answer: (b)B.

Differential protection

Why this answer is correct

Differential relay:

  • Differential relay operation depends on the phase difference of two or more electrical quantities.
  • It works on the principle of comparison between the phase angle and the magnitude of the same electrical quantities.
  • The differential relay is used for the protection of the feeder, large busbars, etc.

 

Differential protection for feeders consist of

  1. Voltage balance differential relay

  2. Current balance differential relay

Note:

Generally Translay relay is used for feeder protection

  • The translay relay is a differential relay

  • The arrangement is similar to overcurrent relay, but the secondary winding is not closed on itself

  • These types of relays are used in the feeder protection and the scheme is called Translay scheme

  • In this scheme, two such relays are employed at the two ends of feeder as shown in the Fig

  • The secondaries of the two relays are connected to each other using pilot wires

  • The connection is such that the voltages induced in the two secondaries oppose each other

  • The copper coils are used to compensate the effect of pilot wire capacitance currents and unbalance between two currents transformers

  • Under normal operating conditions, the current at the two ends of the feeder is same

  • The primaries of the two relays carry the same currents inducing the same voltage in the secondaries

  • As these two voltages are in opposition, no current flows through the two secondaries circuits and no torque is exerted on the discs of both the relays

  • When the fault occurs, the currents at the two ends of the feeder are different, hence unequal voltages are induced in the secondaries

  • Hence the circulating current flows in the secondary circuit causing torque to be exerted on the disc of each relay

  • But as the secondaries are in opposition, hence torque in one relay operates to close the trip circuit while in other relay the torque just holds the movement in unoperated position

  • The care is taken that at least one relay operates under the fault condition

Question 39

Discrimination between main and backup protection is provided by the use of relays which are

  1. AOption (a)

    Fact

  2. BOption (b)

    Sensitive

  3. COption (c)

    Slow

  4. DOption (d)

    None of these

View answer & explanation

Correct answer

Answer: (c)C.

Slow

Why this answer is correct

Types of Protection:

  • The fault occurs on any part of the electric power system, it must be cleared as soon as possible to avoid damage or interference with the rest of the system.
  • The protection scheme divided into two-part that is primary protection and back-up protection.

Primary Protection:

  • It is the protection scheme that is designed to protect the component parts of the power system.
  • The fault occurs on any line, it will be cleared first by its relay and circuit breaker.
  • This forms the primary or main protection and serves as the first line of defense.
  • The service record of primary relaying is very high with well over ninety percent of all operations being correct.
  • Sometimes faults are not cleared by the primary relay system because of trouble within the relay, wiring system, or breaker. Under such conditions, back-up protection used.

Back-up protection:

  • It is the second line of defense in case of failure of the primary protection.
  • It is designed to operate with sufficient time delay so that primary relaying will be given enough time hence it is slower than primary protection.
  • Definite time delay is used in backup protection.

Question 40

Which of the following statements is correct?

  1. AOption (a)

    Station batteries are used to operate relay only

  2. BOption (b)

    The lightning arrestors have surge diverters

  3. COption (c)

    An impedance relay has maximum fault current near the relay

  4. DOption (d)

    A high speed relay has an operation of 1 – 2 cycles

View answer & explanation

Correct answer

Answer: (b)B.

The lightning arrestors have surge diverters

Why this answer is correct

Substation Battery:

  • In a Substation, DC power is supplied to the various equipment such as trip and Closing circuit of the circuit breaker, Protection Relay, isolator control circuit, indication lamp, alarm, PLC circuit, emergency lamps in the control room, indicating instrument, etc.
  • Suppose the Transformer is failed due to any reason, in that case, supply should be available for the panels of line and Power Transformer protection or other equipment protection to monitor the type of failure.

Lightning arresters or Surge diverters:

  • A lightning arrester or a surge diverter is a protective device that diverts the high voltage surges on the power system to the ground.
  • It consists of a spark gap in series with a non-linear resistor.
  • The property of the non-linear resistance is that its resistance decreases as the voltage (or current) increases and vice-versa.
  • One end of the diverter is connected to the terminal of the equipment to be protected and the other end is effectively grounded.

**Impedance Relay:**​

  • Its working depends on the distance between the impedance of the faulty section and the position of the relay.
  • It measures the impedance of the faulty part, if the impedance is less than the impedance of the relay setting, it gives the tripping command to the circuit breaker for closing their contacts.
  • In the normal operating condition, the value of voltage is more than the current and hence impedance is large.
  • On the occurrence of a fault on the line, the magnitude of the fault current rises and the voltage becomes less and hence impedance is less.
  • The fault occurs nearer to the location of the relay, the fault current will be minimum, and if the fault is farther, then the fault current will be maximum at constant fault impedance.

Speed of Protective Relay:

  • A protective relay must operate at the required speed.
  • It should neither be too slow which may result in damage to the equipment nor should it be too fast which may result in undesired operation during transient faults.
  • A high-speed relay should be performed an operation from 2 cycles to 8 cycles.

Question 41

With the use of high speed circuit breakers, which among the following stability is increased?

  1. AOption (a)

    Steady-state stability

  2. BOption (b)

    Transient stability

  3. COption (c)

    Frequency stability

  4. DOption (d)

    All of the above

View answer & explanation

Correct answer

Answer: (b)B.

Transient stability

Why this answer is correct

Transient stability: Transient stability is the ability of the power system to maintain synchronism when subjected to a severe transient disturbance.

Transient stability of the system can be improved by

  • Increasing the system voltage
  • Increase in the X/R ratio
  • ​Using high-speed governors on machines
  • Series capacitance
  • Excitation control
  • High-speed circuit breakers help to clear the fault as quickly as possible
  • By turbine fast valving
  • High-speed excitation
  • Use of auto re-closing breakers
  • Some of the other ways to improve the transient stability are by employing lightning arresters, high neutral grounding impedance, single pole switching, quick Automatic Voltage Regulators (AVRs).

 

Important Points

Steady-state stability limit = V1;V2X\frac{{{V_1};{V_2}}}{X}

More steady-state stability represents more transient stability of the system.

Steady-state stability limit of the system can be increased by the following methods:

  • Upgrading voltage on the existing transmission system or opting for higher voltages on the new transmission system.
  • The use of an additional parallel transmission line reduces transfer reactance X, thereby increases it.
  • The use of a transformer with lower leakage reactance improves a steady-state stability limit.
  • Series capacitive compensation of transmission line reduces transfer reactance X and hence steady-state stability limit increases.
  • The use of bundled phase conductors reduces the reactance thereby increasing the stability limit.

Question 42

The arcing contacts in a circuit breaker is made of 

  1. AOption (a)

    Copper tungsten alloy

  2. BOption (b)

    Porcelain

  3. COption (c)

    Electrolytic copper

  4. DOption (d)

    Aluminium alloy

View answer & explanation

Correct answer

Answer: (a)A.

Copper tungsten alloy

Why this answer is correct

Explanation:

In a circuit breaker, the main contacts are usually made up of copper and conduct current in closed positions. Circuit breakers have low contact resistance and they are silver plated. The arcing contacts are solid, resistant to heat and are made up of copper tungsten alloy.

Important Points

Contact resistance is the resistance to current flow, due to surface conditions and other causes, when contacts are touching one another (in the closed condition of the device). This can occur between contacts of breakers.

The contact resistance is in the order of μΩ and it is approximately 20 μΩ.

Additional Information

**There are three types of circuit breaker contacts:**Tulip type contacts:

  • It consists, of moving contact which moves inside the fixed contacts.
  • During the separation of contact, the arc is established between the tips of the fixed contacts and the tip of the moving contact.
  • The advantage of this type of contact is that arcing is confined to the regions which are not in contact in the fully engaged position.

Finger and wedge contacts: 

This type of contact is mainly used for low-voltage oil circuit breakers because of general unsuitability use with arc control devices.

Butt contacts:

  • It made up of springs and the moving contact.
  • Spring pressure is available to assist contact separation.
  • It mainly used single-break oil circuit breakers and air-blast circuit breakers.

Question 43

A shunt reactor of 100 MVAR is operated at 98% of its rated voltage and at 96% of its rated frequency. The reactive power absorbed by the reactor is∷

  1. AOption (a)

    98 MVAR

  2. BOption (b)

    10.402 MVAR

  3. COption (c)

    96.04 MVAR

  4. DOption (d)

    100.04 MVAR

View answer & explanation

Correct answer

Answer: (d)D.

100.04 MVAR

Why this answer is correct

Concept:

We know that

Q=V2XL=V22πfLQ = \frac{{{V^2}}}{{{X_L}}} = \frac{{{V^2}}}{{2\pi fL}}

Q2Q1=(V2V1)2×(f1f2)\frac{{{Q_2}}}{{{Q_1}}} = {\left( {\frac{{{V_2}}}{{{V_1}}}} \right)^2} \times \left( {\frac{{{f_1}}}{{{f_2}}}} \right)

Calculation:

Q2=100;MVAR[0.98V1V1]2[f10.96f1]{Q_2} = 100;MVAR{\left[ {\frac{{0.98{V_1}}}{{{V_1}}}} \right]^2}\left[ {\frac{{{f_1}}}{{0.96{f_1}}}} \right]

= 100.042 MVAR

Question 44

Protective relays can be designed to respond to

  1. AOption (a)

    Light intensity, impedance

  2. BOption (b)

    Temperature, resistance, reactance

  3. COption (c)

    Voltage and current

  4. DOption (d)

    All of these

View answer & explanation

Correct answer

Answer: (d)D.

All of these

Why this answer is correct

Protective Relays:

  • It is a sensing device.
  • It senses the fault or given situation when the current attains a certain predetermined value.
  • It knows its position and finally, it gives the tripping command to the circuit breaker.
  • The protective relay gives the command to the circuit breaker to disconnect the faulted element.
  • Relays can be designed to respond to changes in resistance, reactance, impedance, voltage, current, light intensity and temperature.

 

Additional InformationOverload relay:

An overload relay is an electrical device used to protect an electric motor from overheating. It is mainly three types.

Thermal relay: 

Thermal overload relay is a protective device, and that is mainly designed to cut the power whenever the motor uses too much current for an extended time period.

Once extreme current supplies throughout the motor circuit, then the relay gets open because of the improved temperature of the motor.

Magnetic relay: 

Magnetic overload relay can be operated by detecting the magnetic field strength which is generated by the flow of current towards the motor. This relay can be built with a variable magnetic core within a coil that holds the motor current.

Solid-state relay: 

Solid-state relays are semiconductor equivalents of the electromechanical relay and can be used to control the electrical loads without the use of moving parts.

Question 45

Which one of the following methods used for solution of ordinary differential equations is conditionally stable?

  1. AOption (a)

    Euler’s method

  2. BOption (b)

    Milne’s method

  3. COption (c)

    Taylor’s series method

  4. DOption (d)

    Adams-Bashforth method

View answer & explanation

Correct answer

Answer: (a)A.

Euler’s method

Why this answer is correct

Considering the Euler’s method,

Yn+1 = yn + h f(tn, yn)

Euler’s method is only conditionally stable, i.e., the step size has to be chosen sufficiently small to ensure stability.

Question 46

Which one of the following methods used for solving non-linear algebraic equation has rate of convergence 2.0?

  1. AOption (a)

    Bisection method

  2. BOption (b)

    Secant method

  3. COption (c)

    Newton-Raphson method

  4. DOption (d)

    Muller’s method

View answer & explanation

Correct answer

Answer: (c)C.

Newton-Raphson method

Why this answer is correct

Explanation:

Newton Raphson method has a second order of quadratic convergence.

According to Newton Raphson method:

\({{\rm{x}}{{\rm{n}} + 1}} = {{\rm{x}}{\rm{n}}} - \frac{{{\rm{f}}\left( {{{\rm{x}}{\rm{n}}}} \right)}}{{{\rm{f'}}\left( {{{\rm{x}}{\rm{n}}}} \right)}}\)

Suppose xn differs from the root α by a small quantity ϵn so that x0 = α + ϵn and xn+1 = α + ϵn+1  

Now the above equation will become

\(\begin{array}{l} \alpha + {{\rm{\varepsilon }}_{n + 1}} = ;\alpha + {{\rm{\varepsilon }}_n} - \frac{{f\left( {\alpha + {{\rm{\varepsilon }}_n}} \right)}}{{f'\left( {\alpha + {{\rm{\varepsilon }}n}} \right)}};\ {{\rm{\varepsilon }}{n + 1}} = {{\rm{\varepsilon }}_n} - \frac{{f\left( {\alpha + {{\rm{\varepsilon }}_n}} \right)}}{{f'\left( {\alpha + {{\rm{\varepsilon }}_n}} \right)}} \end{array}\)

By Taylor’s expansion

=n−f(α)+εnf′(α)+12!εn2;f′′α+…f′(α)+;εnf′(α)+…; f(α)=0, =εn−εnf′(α)+12!εn2;f′′α+…f′(α)+;εnf′(α)+…\begin{array}{l} = {_n} - \frac{{f\left( \alpha \right) + {{\rm{\varepsilon }}_n}f'\left( \alpha \right) + \frac{1}{{2!}}{\rm{\varepsilon }}_n^2;f''\alpha + \ldots }}{{f'\left( \alpha \right) + ;{{\rm{\varepsilon }}_n}f'\left( \alpha \right) + \ldots }};\ f\left( \alpha \right) = 0,\ = {{\rm{\varepsilon }}_n} - \frac{{{{\rm{\varepsilon }}_n}f'\left( \alpha \right) + \frac{1}{{2!}}{\rm{\varepsilon }}_n^2;f''\alpha + \ldots }}{{f'\left( \alpha \right) + ;{{\rm{\varepsilon }}_n}f'\left( \alpha \right) + \ldots }} \end{array}

 Neglecting third and higher powers of ϵn

=εn2f′(α)2;[f′(α)+;εnf′(α)];≈εn22.;f′′(α)f′(α) = \frac{{{\rm{\varepsilon }}_n^2f'\left( \alpha \right)}}{{2;[f'\left( \alpha \right) + ;{{\rm{\varepsilon }}_n}f'\left( \alpha \right)]}}; \approx \frac{{{\rm{\varepsilon }}_n^2}}{2}.;\frac{{f''\left( \alpha \right)}}{{f'\left( \alpha \right)}}

This shows that the subsequent error at each step is proportional to the square of the previous error and as such the convergence is quadratic.

Important Points

Iterative MethodConvergence
Bisection methodVery slow
Regula-Falsi methodOrder – 1
Newton-Raphson methodOrder – 2
Secant methodOrder – 1.62
Successive approximation methodOrder – 1

Question 47

Which one of the following methods is NOT used for solution of non-linear algebraic equations?

  1. AOption (a)

    Regula-Falsi Method

  2. BOption (b)

    Milne’s-Predictor-Corrector Method

  3. COption (c)

    Secant Method

  4. DOption (d)

    Bisection Method

View answer & explanation

Correct answer

Answer: (b)B.

Milne’s-Predictor-Corrector Method

Why this answer is correct

Methods used for the solution of non-linear algebraic equations:

  • Bisection method
  • Regula falsi method
  • Newton-Raphson method
  • Secant method

 

Additional Information

Methods used for the solution of differential equations:

Single step methods:

  • Euler’s method
  • Heun’s method
  • Runge’s method
  • Runge-Kutta method
  • Taylor’s series method

Multi step methods:

  • Milne’s-predicator Simpson-corrector method
  • Adam’s Bash forth Moulton method

Question 48

In a Triclinic crystal, a lattice plane makes intercepts at a length a, 2b and −3c2 - \frac{{3c}}{2}. The Miller indices of the plane are

  1. AOption (a)

    3 : 6 : 4

  2. BOption (b)

    6 : 3 : 4

  3. COption (c)

    6 : 3 : - 4

  4. DOption (d)

    6 : 3 : -2

View answer & explanation

Correct answer

Answer: (c)C.

6 : 3 : - 4

Why this answer is correct

Concept:

Miller Indices:

  • Miler indices is a symbolic representation of vector for the orientation of an atomic plane in the crystal lattice.
  • It is defined as the reciprocal of fractional intercept which the plane makes with the crystallographic axes.

Procedure to find Miller Indices:

  1. Determine the intercept of the plane along each of three crystallographic directions.
  2. Taking reciprocal of intercept.
  3. Taking LCM of the fraction and multiply it by reciprocal of intercept.

Calculation:

Given,

Intercepts of plane = (a, 2b, −3c2 - \frac{{3c}}{2})

Intercept = (1, 2, −32 - \frac{{3}}{2})

Reciprocal of intercept = 1, 12 \frac{{1}}{2}, −23 - \frac{{2}}{3})

LCM = 6

Miller indicates of the plane = LCM × Reciprocal of intercept

∴ Miller indicates of the plane = (6, 3, - 4)

Question 49

The critical field needed to destroy super conductivity is

  1. AOption (a)

    H0 (Tc/T)

  2. BOption (b)

    H0 (Tc/T)2

  3. COption (c)

    H0[1−(T0Tc)2]{H_0}\left[ {1 - {{\left( {\frac{{{T_0}}}{{{T_c}}}} \right)}^2}} \right]

  4. DOption (d)

    H0[1−(TcTo)2]{H_0}\left[ {1 - {{\left( {\frac{{{T_c}}}{{{T_o}}}} \right)}^2}} \right]

View answer & explanation

Correct answer

Answer: (c)C.

H0[1−(T0Tc)2]{H_0}\left[ {1 - {{\left( {\frac{{{T_0}}}{{{T_c}}}} \right)}^2}} \right]

Why this answer is correct

Explanation:

The critical magnetic field of a superconductor is given by

Hc=H0[1−(TTc)2]{H_c} = {H_0}\left[ {1 - {{\left( {\frac{T}{{{T_c}}}} \right)}^2}} \right]

Where,

Hc is a critical magnetic field at T°K

H0 is a critical magnetic field at 0°K

Tc is a critical temperature

The superconductivity can be destroyed with the applications of the magnetic field and it depends upon the temperature as 

From the above-given graph we may conclude that

  • At absolute zero critical magnetic field Hc is maximum
  • At temperature equal to critical temperature the critical magnetic field Hc is zero.
  • Superconductors remain in the state of super conduction for T < Tc

Question 50

The instruction for starting the computer are housed in

  1. AOption (a)

    Random Access Memory

  2. BOption (b)

    CD-ROM

  3. COption (c)

    Read Only Memory Chip

  4. DOption (d)

    All of the above

View answer & explanation

Correct answer

Answer: (c)C.

Read Only Memory Chip

Why this answer is correct

Explanation:

The instruction for starting the computer are housed in ​Read Only Memory (ROM) Chip.

The difference between RAM and ROM is given below.

RAMROM
The full form is Random Access MemoryThe full form is Read-Only Memory
It is a form of temporary memory where the memory content is lost if power is switched offIt is a form of permanent or non-volatile memory in which the contents are stored permanently.
It is used to form the working memory of the computer.It is used to form the BIOS chip of the computer.
One can both read and write data to a RAMOne can only read the data from a ROM

Question 51

When memory write or I/O read are active, data remains ______ of the processor.

  1. AOption (a)

    Input

  2. BOption (b)

    Output

  3. COption (c)

    Processor

  4. DOption (d)

    None of these

View answer & explanation

Correct answer

Answer: (b)B.

Output

Why this answer is correct

Control and Status Signals:

This group contains:

  • Two control signals (RD‾;and;WR‾)\overline {RD} ;and;\overline {WR} )
  • Three status signals (IO/M̅, S1 and S0) to identify the nature of the operation
  • One special signal (ALE) to indicate the beginning of the operation.

ALE: (Address Latch Enable)

It indicates that the bits on AD7 - AD0 are address bits.

This signal is used to latch the lower order address from multiplexed bus and generate a separate set of eight address lines A7 – A0.

RD‾−Read:\overline {{\bf{RD}}} - {\bf{Read}}:

This is a Read control signal (active low).

This signal indicates that the selected I/O or memory device is to be read and data are available on the data bus.

WR‾−Write:\overline {{\bf{WR}}} - {\bf{Write}}:

This is a Write control signal (active low). This signal indicates that the data on the data bus are to be written into a selected memory or I/O location.

IO/Mˉ:{\bf{IO}}/{\bf{\bar M}}:

This is a status signal used to differentiate between I/O and memory operations.

When it is high, it indicates an I/O operation; when it is low, it indicates a memory operation.

This signal is combined with RD‾(Read);and;WR‾;(Write)\overline {{\rm{RD}}} \left( {{\rm{Read}}} \right);{\rm{and;}}\overline {{\rm{WR}}} {\rm{;}}\left( {{\rm{Write}}} \right) to generate I/O and memory control signals.

S1 and S0:

These status signals, similar to IO/Mˉ{\rm{IO}}/{\rm{\bar M}}, can identify various operations, but they are rarely used in small systems.

(All the operations and their associated status signals are listed in Table)

Machine CycleStatusControl signals
IO/M̅S1S0
Opcode Fetch011RD‾=0\overline {{\rm{RD}}} = 0
Memory Read010RD‾=0\overline {{\rm{RD}}} = 0
Memory Write001WR‾=0\overline {{\rm{WR}}} = 0
I/O Read110RD‾=0\overline {{\rm{RD}}} = 0
I/O Write101WR‾=0\overline {{\rm{WR}}} = 0
Interrupt Acknowledge111INTA‾=0\overline {{\rm{INTA}}} = 0

 

From the above table, when memory write or I/O read are active, data remains output of the processor.

Question 52

While performing read operation, one must taken care that much current should NOT be

  1. AOption (a)

    Sourced from data lines

  2. BOption (b)

    Sinked from data lines

  3. COption (c)

    Sourced or sinked from data lines

  4. DOption (d)

    Sinked from address lines

View answer & explanation

Correct answer

Answer: (c)C.

Sourced or sinked from data lines

Why this answer is correct

The correct answer is option 3

Key Points

  • A memory unit stores binary information in groups of bits called words.
  • Data input lines provide the information to be stored in the memory, Data output lines carry the information out from the memory.
  • While performing read operation, one must take care that much current should NOT be sourced or sinked from data lines while reading to avoid loading

​

Additional Information

  • Data Acknowledge signal asserts that the data has been placed onto the memory bus, and is available to the processor for reading.

Question 53

A three phase induction motor has shaft output of 16 kW. The constant losses are 1 kW. If the slip be 4%, the rotor copper losses would be

  1. AOption (a)

    600 W

  2. BOption (b)

    708 W

  3. COption (c)

    667 W

  4. DOption (d)

    720 W

View answer & explanation

Correct answer

Answer: (b)B.

708 W

Why this answer is correct

Concept:

Power flow in the Induction motor is as shown below.

Rotor input or air gap power \({{P}{in}}=\frac{3I{2}^{2}{{R}_{2}}}{s}\)

Rotor copper losses \({{P}{cu}}=s\times {{P}{in}}=3I_{2}^{2}{{R}_{2}}\)

Gross mechanical power output \({{P}{g}}={{P}{in}}-{{P}{cu}}=\frac{3I{2}^{2}{{R}{2}}}{s}-3I{2}^{2}{{R}{2}}=3I{2}^{2}{{R}_{2}}\left( \frac{1-s}{s} \right)\)

The relation between the rotor air gap power, rotor copper losses, and gross mechanical power output is,

\({{P}{in}}:{{P}{cu}}:{{P}{g}}=\frac{3I{2}^{2}{{R}{2}}}{s}:3I{2}^{2}{{R}{2}}:3I{2}^{2}{{R}_{2}}\left( \frac{1-s}{s} \right)\)

\(\Rightarrow {{P}{in}}:{{P}{cu}}:{{P}_{g}}=\frac{1}{s}:1:\left( \frac{1-s}{s} \right)=1:s:\left( 1-s \right)\)

Therefore, the electrical rotor losses are proportional to the slip.

Calculation:

Given that,

Shaft output = 16 kW

Constant losses = Mechanical losses = 1 kW

Rotor output = 16 + 1 = 17 kW

Slip (s) = 4%

Rotor copper losses Pcu=s(1−s)×Pg{P_{cu}} = \frac{s}{{\left( {1 - s} \right)}} \times {P_g}

=0.041−0.04×17×103=708.33;W = \frac{{0.04}}{{1 - 0.04}} \times 17 \times {10^3} = 708.33;W

Question 54

In a three stack 12/8 pole variable reluctance motor, rotor pole pitch is

  1. AOption (a)

    15°

  2. BOption (b)

    30°

  3. COption (c)

    45°

  4. DOption (d)

    60°

View answer & explanation

Correct answer

Answer: (c)C.

45°

Why this answer is correct

Concept:

Let N be the number of rotor poles (or teeth) and m is the number of stacks or phases. Then

Pole pitch = 360° / N

Step angle = 360° / (m × N)

Calculation:

In a three-stack 12/8 pole variable reluctance motor,

Number of rotor poles = 8

Pole pitch = 360/8 = 45°

 Mistake Points

Students usually get confused in pole pitch and step angle. Both are different terms with different meanings which are mentioned below.

Pole pitch: The distance measured in terms of armature slots or armature conductors between two adjacent pole centers.

Pole pitch = 360° / N

Step angle: The step angle of a stepper motor is defined as the angle by which the rotor of a stepper motor moves when one input pulse is applied to the stator of the motor.

The step angle for a stepper motor is given by:

β=360°m×Nrβ = \frac{360°}{m × N_r}

where, β = Step angle

m = No. of stator phases

Nr = No. of rotor teeth

Here in our question rotor pole pitch is to be calculated, so the calculations should be done accordingly.

Question 55

The condition of a three phase induction motor at no-load resembles those of a transformer whose secondary

  1. AOption (a)

    Short circuited

  2. BOption (b)

    Open circuited

  3. COption (c)

    Supplying a variable resistive load

  4. DOption (d)

    Supplying an inductive load

View answer & explanation

Correct answer

Answer: (a)A.

Short circuited

Why this answer is correct

Explanation:

The principle of operation of a 3-phase induction motor is most similar to that of the transformer with a shorted secondary. A transformer has primary and secondary windings, primary winding induces a voltage in secondary. In 3 phase induction motor, primary winding induces a voltage in secondary but secondary is shorted.

Important Points

Induction motor is also known as a generalized transformer. Both the machines are almost similar, but they have following differences.

  • Transformer is a device in which two windings are magnetically coupled and when one winding is excited by AC supply of certain frequency, the emf gets induced in the second winding having same frequency as that of supply given to the first winding
  • The winding to which supply is given is called primary winding while winding in which emf gets induced is called secondary winding, the induction motor can be regarded as the transformer
  • The difference is that the normal transformer is an alternating flux transformer while induction motor is rotating flux transformer
  • The normal transformer has no air gap as against this an induction motor has distinct air gap between its stator and rotor
  • In an alternating flux transformer, the frequency of induced emf and current in primary and secondary is always same, however, in the induction motor frequency of emf and current on the stator side remains same but frequency of rotor emf and current depends on the slip
  • In case of the alternating flux transformer the entire energy present in the secondary circuit, is in the electrical form
  • In an induction motor part of its energy in the rotor circuit is in electrical form and the remaining part is converted into mechanical form

Question 56

Torque angle ‘δ’ is the angle between

  1. AOption (a)

    Rotor field axis and resultant field axis

  2. BOption (b)

    Stator field axis and rotor field axis

  3. COption (c)

    Stator field axis and mutual field axis

  4. DOption (d)

    Stator field axis and resultant field axis

View answer & explanation

Correct answer

Answer: (b)B.

Stator field axis and rotor field axis

Why this answer is correct

  • The angle between the rotor poles and stator poles in a synchronous motor is known as the Torque angle.
  • The term torque angle is used in the context of the asynchronous motor. It is the angle by which rotor trails behind the revolving field produced by armature currents.
  • The term load angle (or power angle) is used in the context of a synchronous generator. It is the angle by which the rotor magnetic axis is ahead of the resultant air-gap flux. The resultant flux is the vectorial sum of the armature flux and rotor flux and rotates synchronously.

Question 57

In case of the air gap in an induction motor is increased

  1. AOption (a)

    The magnetizing current of the rotor will decrease

  2. BOption (b)

    The power factor will decrease

  3. COption (c)

    The speed of motor will increase

  4. DOption (d)

    The windage losses will increase

View answer & explanation

Correct answer

Answer: (b)B.

The power factor will decrease

Why this answer is correct

Explanation:

The presence of air-gap between the stator and rotor of an induction motor increases the reluctance of the magnetic circuit. Consequently, an induction motor draws a large magnetizing current (Im) to produce the required flux in the air-gap. That is why the small air-gap is preferred for the induction motor which helps to reduce the magnetizing current.

If the air gap of an induction motor is increased,

  • The permeability of the magnetic circuit will decrease
  • The magnetizing inductance of the motor will decrease
  • Leakage reactance will increase
  • Leakage flux will increase
  • The magnetizing current will increase
  • This will cause a poorer power factor at all loads

Question 58

A stepper motor having a resolution of 300 steps/revolution and running at 2400 rpm has a pulse rate of ______ pps.

  1. AOption (a)

    4000

  2. BOption (b)

    8000

  3. COption (c)

    6000

  4. DOption (d)

    10000

View answer & explanation

Correct answer

Answer: (c)C.

6000

Why this answer is correct

Concept:

Pulse per second is mathematically given as

PPS = (rpm/120) × (number of steps per minute)

Calculation:

The speed of motor = 2400 rpm

By converting into rps,

= 2400/60 = 40 revolutions per second

Resolution of motor = 300 steps/revolution

Steps per second = revolutions per second × number of steps/revolution

= 40 × 300 = 12000

Pulses per second = 6000

Question 59

A 3-phase. 6-pole, 50 Hz, squirrel cage induction motor is running at a slip of 5%. The speed of stator magnetic field to rotor magnetic field and speed of rotor with respect to stator magnetic field are

  1. AOption (a)

    Zero, -50 rpm

  2. BOption (b)

    Zero, 955 rpm

  3. COption (c)

    1000 rpm, -50 rpm

  4. DOption (d)

    1000 rpm, 955 rpm

View answer & explanation

Correct answer

Answer: (a)A.

Zero, -50 rpm

Why this answer is correct

Concept:

In an induction motor,

  • The stator is stationary and the stator field rotates with synchronous speed.
  • The rotor field rotates with synchronous speed and the rotor rotates at a speed less than the synchronous speed.

 

Synchronous speed in rpm of a three-phase induction motor is given by,

Ns=120fP{N_s} = \frac{{120f}}{P}

Where f is the frequency in Hz

P is the number of poles

A rotor of a three-phase induction motor rotates at a speed close to the synchronous speed but not equal to the synchronous speed.

The difference between the synchronous speed and the rotor speed is known as slip speed. It is given by

Slip speed = Ns - Nr

Slip is defined as the ratio of slip speed to the rotor speed.

s=Ns−NrNss = \frac{{{N_s} - {N_r}}}{{{N_s}}}

⇒ Nr = Ns (1 – s)

Calculation:

Given that,

Number of poles (P) = 6

Frequency (f) = 50 Hz

Synchronous speed, Ns=120×506=1000;rpm{N_s} = \frac{{120 \times 50}}{6} = 1000;rpm

Slip at no load, s = 5 %

Rotor speed N = Ns (1 – s) = 1000(1 – 0.05) = 950 rpm

The speed of stator magnetic field = speed of rotor magnetic field = 1000 rpm

The speed of the stator magnetic field with respect to the rotor magnetic field = 1000 – 1000 = 0

The speed of the rotor with respect to the stator magnetic field = 950 – 1000 = -50 rpm

Question 60

In a commutation circuit employed to turn off an SCR, satisfactory turn off is obtained when

  1. AOption (a)

    circuit turn off time > device turn off time

  2. BOption (b)

    circuit time constant  > device turn off time 

  3. COption (c)

    circuit time constant  < device turn off time

  4. DOption (d)

    circuit turn off time < device turn off time

View answer & explanation

Correct answer

Answer: (a)A.

circuit turn off time > device turn off time

Why this answer is correct

Concept:

Thyristor commutation:

  • Commutation is defined as the process of turning off a thyristor.
  • Thyristor commutation is a necessary mechanism for obtaining the controlled output in many of the thyristor circuits
  • A thyristor is a semi-controlled device, It cannot be turned off directly by the gate signal.
  • So by the use of external commutation circuits, we can turn off the SCR.

 

Thyristor turnoff time (tq):

  • It is the time between the instant anode current becomes zero and the instant SCR regains forward blocking capability.
  • During this time (tq) all the excess carriers from four layers of SCR are removed.
  • The turn off time is divided into two intervals of reverse recovery time (trr) and gate recovery time (tgr)

tq = trr  + tgr

Circuit turnoff time (tc):

It is defined as the time between the instant anode current becomes zero and the instant reverse voltage due to practical circuit reaches zero.

Note:

The circuit turn off time should be more than the device turnoff time for reliable turn off, otherwise, the device may turn on at an undesired instant, a process called Commutation failure.

Question 61

A triac is a:

  1. AOption (a)

    2 terminal bidirectional switch

  2. BOption (b)

    2 terminal unilateral switch

  3. COption (c)

    3 terminal unilateral switch

  4. DOption (d)

    3 terminal bidirectional switch

View answer & explanation

Correct answer

Answer: (d)D.

3 terminal bidirectional switch

Why this answer is correct

TRIAC:

  • A TRIAC is equivalent to two SCRs joined together in parallel; It has two main terminal and one gate
  • In the TRIACs, there will be single gate control conduction in both the directions
  • It is a bidirectional device and in both the directions it will conduct
  • It is available in high voltage ratings
  • TRIAC is a five-layer device

Question 62

Two thyristors of same rating and same specifications

  1. AOption (a)

    Will have equal turn-on and turn-off periods

  2. BOption (b)

    Will have equal turn-on, but unequal turn-off periods

  3. COption (c)

    May have equal or unequal turn-on and turn-off periods

  4. DOption (d)

    Will have unequal turn-on and turn-off periods

View answer & explanation

Correct answer

Answer: (c)C.

May have equal or unequal turn-on and turn-off periods

Why this answer is correct

Turn on time: thyristor takes some transition time to go from forward blocking mode to forward conduction mode. This transition time is called turn on time of SCR

Turn off time: time during which a reverse voltage is applied across the thyristor during its commutation process.

Turn off time of a thyristor is greater than turn-on time.

Two thyristors of the same rating and same specifications may have equal or unequal turn-on and turn-off periods.

Question 63

Assertion (A): Inverter and choppers use fast switching thyristors.

Reason (R): Fast switching SCR has low turn-off time.

  1. AOption (a)

    Both (A) and (R) are correct and (R) is the correct explanation of (A)

  2. BOption (b)

    Both (A) and (R) are correct but (R) is not the correct explanation of (A)

  3. COption (c)

    (A) is correct but (R) is wrong

  4. DOption (d)

    (A) is wrong but (R) is correct

View answer & explanation

Correct answer

Answer: (a)A.

Both (A) and (R) are correct and (R) is the correct explanation of (A)

Why this answer is correct

Fast Switching Thyristor: Fast Switching Thyristor is a fast turn-off semiconductor device, also called “Inverter Thyristor”.

Application of Fast Switching Thyristor: Inverters, Chopper, Inductive heating, Various types of forced converters, Electric welding, AC motor speed control.

The turn-off time of Thyristor:

  • Once the thyristor is switched ON (the anode current is above the latching current), the gate loses control over it. That means the gate circuit cannot turn off the device.
  • For turning off the SCR anode current must fall below the holding current. After the anode current falls to zero, we cannot apply a forward voltage across the device due to the presence of the carrier. So, we must sweep out or recombine these charges to properly turn off SCR.
  • So, the turn-off time of SCR can be defined as the interval between anode current falls to zero and the device regains its forward blocking mode.
  • Fast switching SCR has a low turn-off time.
  • Low turn-off time enables fast switching.

Explanation:

  • SCR is also known as thyristor and the turn-off time SCR is low.
  • For switching operations in Inverter and Chopper, we used fast switching thyristor.

Hence, Both (A) and (R) are correct and (R) is the correct explanation of (A)

Question 64

In a single phase fully controlled bridge rectifier, the output load current I is ripple free. The r.m.s. value of source current would be

  1. AOption (a)

    2√2I/π

  2. BOption (b)

    I

  3. COption (c)

    I/2

  4. DOption (d)

    I/4

View answer & explanation

Correct answer

Answer: (b)B.

I

Why this answer is correct

Explanation:

The expression for the source current is,

{I_{st}} = \mathop \sum \limits_{n = 1,3,5}^\infty \frac{{4;Io}}{{n\pi }}\sin \left( {n\omega t - n \alpha } \right)

R.M.S value of nth harmonic input current

isn=4Io2;nπ=22I0nπisn = \frac{{4Io}}{{\sqrt 2 ;n\pi }} = \frac{{2\sqrt 2 {I_0}}}{{n\pi }}

R.M.S value of fundamental current

Is1=22;I0π{I_{s1}} = \frac{{2\sqrt {2;} {I_0}}}{\pi }

R.M.S value of input current = I0

Additional Information

In a three-phase full converter,

Peak current flows through the thyristor = load current = I0

RMS value of thyristor current =I013= {I_0}\sqrt {\frac{1}{3}}

RMS value of source current =I023= {I_0}\sqrt {\frac{2}{3}}

Question 65

Consider the following statements related to dc drives:

  1. Wide speed control range
  2. High starting torque
  3. High power to weight ratio
  4. Fast transient response
  5. No limit on highest operating voltage

Out of these statements

  1. AOption (a)

    1, 2 and 3 are correct

  2. BOption (b)

    2, 3 and 4 are correct

  3. COption (c)

    1, 2 and 4 are correct

  4. DOption (d)

    3, 4 and 5 are correct

View answer & explanation

Correct answer

Answer: (c)C.

1, 2 and 4 are correct

Why this answer is correct

Electrical Drive:

The system employed for motion control (rotational or translational) by means of an electrical input parameter such as voltage, frequency, etc is called an electric drive.

Advantages of Electrical Drive:

  • It is simple in construction and has less maintenance cost.
  • Its speed control is easy and smooth.
  • It is neat, clean, and free from any smoke or flue gases.
  • It can be installed at any desired convenient place thus affording more flexibility in the layout, being compact, it requires less space.
  • It can be started immediately without any loss of time.
  • It has a comparatively longer life.

Disadvantages of Electrical Drive:

  • It comes to stop as soon as there is a failure of the electric supply.
  • It cannot be used at far-off places that are not served by electric supply.

Classification of Electrical Drive:

 

AC Drive:

  • AC drives are used to step-less speed control of motors mostly used in process industries due to their ruggedness and maintenance-free long life.
  • Speed control of AC drive mainly achieved by voltage-frequency speed control by means of a power semiconductor-based device.
  • Squirrel cage induction motor is widely used in AC drive due to its simple and rugged construction.
  • AC drive is available at various voltage levels and there is no limit on the operating voltage.
  • For the same power rating, the weight of the AC motor drive is less than that of the DC motor drive.

DC Drive:

  • The main reason for using a DC drive is that it has a wide range of speed control.
  • It has high starting torque (DC Series motor) hence can be used in traction, steel rolling mills, etc.
  • It gives a fast response with the input parameter and can provide smooth speed control.
  • It has the ability to quick starting and stopping.
  • The cost of a DC motor drive is more than that of an AC motor drive because of additional equipment required for DC supply such as converter, battery, etc.

Additional Information

Individual Drive:

  • In the case of an individual drive, each machine is driven by its own separate motor with the help of gears, pulley, etc.
  • It is most economical, with less maintenance.
  • Application: Ceiling fan, drilling machine, etc

Group Drive:

  • In group drive, a single motor drives a number of machines through belts from a common shaft.
  • It is also called line shaft drive
  • It is more economical as compared to Individual drive.
  • Application: Several machine tools perform their option by using a single motor in a belt or rope drive.

Multi motor Drive:

  • In multi-motor drives, separate motors are provided for actuating different parts of the driven mechanism.
  • Application: Cranes

Important Points

Wide Speed control range Drive:

  • The drive used for speed control over a wide range that is above or below the base speed then we have required various speed control method such as frequency changer method, Ward Leonard System, Armature control method, Flux control method, etc.
  • The frequency changer method is used for AC motor drive speed control. But this method cause saturation of the core in the motor.
  • Ward Leonard System, Armature control method, Flux control method is used for speed control of DC motor over a wide range and it operated motor satisfactory. Hence DC motor has a wide range of speed control.

High Starting Torque Drive:

  • High starting torque drive is used in traction, Rolling mills, crane, etc.
  • DC series motor has very high starting torque among all AC motor. Therefore, we preferred DC motor drive for high starting torque application.

Transient Stability of Electric Drive:

  • The stability of a drive is caused by the inertia of the rotating masses and inductances of the motor, in the same manner as the transient behavior.
  • In cases of sudden changes in input or output response causing the drive to change its equilibrium state, the effects of these components cannot be ignored.
  • The stability behavior of the electric drive is due to the effects of change in param­eters is called Transient stability.
  • Transient response in the case of DC drive is faster than the AC drive.

Question 66

A 20 kW electric motor has heating time constant 60 min. Iron loss is equal to full load copper loss. The short time rating of the motor for 15 minute is

  1. AOption (a)

    43.5 kW

  2. BOption (b)

    56.7 kW

  3. COption (c)

    60.0 kW

  4. DOption (d)

    None of the above

View answer & explanation

Correct answer

Answer: (b)B.

56.7 kW

Why this answer is correct

Concept:

The heating time constant is defined as the time taken by the machine to attain 0.623 of its final steady temperature rise.

The heating curve of an electric motor is given as below

The equation of the curve is given as

ΔT=PαA(1−e−tτ)Δ T=\frac{{P}}{{α A}}(1-e^{\frac{{-t}}{{τ}}})

At time t = τ,

ΔT = Tmax(1 - e-1) = 0.623 Tmax

Where,

Tmax = P/αA

ΔT = Temperature raise

P = Power rating of the motor in Watts

τ = Time constant of the motor

t = Time for which motor is loaded.

A = Heating surface area in m2

α = Specific heat dissipation or emissivity in J/sec/m2

Calculation:

Given, P1 = 20 kW for t1 = τ = 60 min, t2 = 15 min

Temperature raise for an electric motor must be constant, so

From equation (1)

P∝1(1−e−tτ)P \propto \frac{{1}}{{(1-e^{\frac{{-t}}{{τ}}})}}

P1P2=(1−e−t2τ)(1−e−t1τ)\frac{{P_1}}{{P_2}}=\frac{{(1-e^{\frac{{-t_2}}{{τ}}})}}{{(1-e^{\frac{{-t_1}}{{τ}}})}}

20P2=(1−e−1560)(1−e−6060)\frac{{20}}{{P_2}}=\frac{{(1-e^{\frac{{-15}}{{60}}})}}{{(1-e^{\frac{{-60}}{{60}}})}}

P2 = 57 kW

Additional Information

Cooling curve:

The cooling time constant is defined as the time required to cool the machine down to 0.368 times the initial temperature rise above ambient temperature.

The cooling curve of an electric motor is given as below

The equation of the curve is given as

ΔT=Tmax;e−tτΔ T=T_{max};e^{\frac{{-t}}{{τ}}}

At t = τ, ΔT = 0.368 Tmax

Question 67

A 220 V, 20 A, 1000 rpm, separately excited d.c. motor has armature resistance of 1 ohm. The motor is supplied from 250 V dc supply via a step down chopper, for operation of motor at 500 rpm at the rated torque, the duty ratio of the chopper should be

  1. AOption (a)

    0.40

  2. BOption (b)

    0.44

  3. COption (c)

    0.48

  4. DOption (d)

    0.50

View answer & explanation

Correct answer

Answer: (c)C.

0.48

Why this answer is correct

Concept:

For a step-down chopper,

VoVs=δ=;TonT=fTon\frac{{{V_o}}}{{{V_s}}} = \delta = ;\frac{{{T_{on}}}}{T} = f{T_{on}}

Ton is the ON time

T is time period

f is the chopping frequency

Vs is the input supply

V0 is the average output voltage

Calculation:

Case 1:

Voltage (V1) = 220 V

Line current (I) = 20 A

Speed (N1) = 1000 rpm

Armature resistance (Ra) = 1 Ω

Back emf (Eb1) = V1 – IRa = 220 – 20 (1) = 200 V

Case 2:

As the rated torque is the same, the current remains the same.

Line current (I) = 20 A

Speed (N2) = 500 rpm

Eb2=Eb1×N2N1{E_{b2}} = {E_{b1}} \times \frac{{{N_2}}}{{{N_1}}}

=200×5001000=100;V = 200 \times \frac{{500}}{{1000}} = 100;V

Armature resistance (Ra) = 1 Ω

Terminal voltage (V2) = Eb2 + IRa = 100 + 20(1) = 120 V

The output of the chopper (V0) = 120 V

Input of the chopper (Vi) = 250 V

V0 = δ Vi

⇒ 120 = δ × 250

⇒ δ = 0.48

Question 68

The consideration involved in the selection of the type of electric drive for a specific application depends upon

  1. AOption (a)

    Speed control range and its nature

  2. BOption (b)

    Starting nature

  3. COption (c)

    Environmental condition

  4. DOption (d)

    All the above

View answer & explanation

Correct answer

Answer: (d)D.

All the above

Why this answer is correct

Electrical Drive:

  • The system employed for motion control (rotational or translational) by means of an electrical input parameter such as voltage, frequency, etc is called an electric drive.
  • Parts of Electric Drive are, Power Modulator, Motor, Controlling Unit, Sensing Units.

Following are the consideration involved in the selection of the type of electric drive for a specific application:

  • The limits of the speed range and its nature
  • Motor efficiency
  • Starting requirements
  • Reliability of operation
  • Environmental effects
  • Availability of supply
  • Effects of supply variations
  • Economical aspects
  • Power factor
  • Load factor
  • Braking

 

Additional Information

Classification of Electrical Drive:

 

AC Drive:

  • AC drives are used to step-less speed control of motors mostly used in process industries due to their ruggedness and maintenance-free long life.
  • Speed control of AC drive mainly achieved by voltage-frequency speed control by means of a power semiconductor-based device.
  • Squirrel cage induction motor is widely used in AC drive due to its simple and rugged construction.
  • AC drive is available at various voltage levels and there is no limit on the operating voltage.
  • For the same power rating, the weight of the AC motor drive is less than that of the DC motor drive.

DC Drive:

  • The main reason for using a DC drive is that it has a wide range of speed control.
  • It has high starting torque (DC Series motor) hence can be used in traction, steel rolling mills, etc.
  • It gives a fast response with the input parameter and can provide smooth speed control.
  • It has the ability to quick starting and stopping.
  • The cost of a DC motor drive is more than that of an AC motor drive because of additional equipment required for DC supply such as converter, battery, etc.

 

Individual Drive:

  • In the case of an individual drive, each machine is driven by its own separate motor with the help of gears, pulley, etc.
  • It is most economical, with less maintenance.
  • Application: Ceiling fan, drilling machine, etc

Group Drive:

  • In group drive, a single motor drives a number of machines through belts from a common shaft.
  • It is also called line shaft drive
  • It is more economical as compared to Individual drive.
  • Application: Several machine tools perform their option by using a single motor in a belt or rope drive.

Multi motor Drive:

  • In multi-motor drives, separate motors are provided for actuating different parts of the driven mechanism.
  • Application: Cranes

 

Advantages of Electrical Drive:

  • It is simple in construction and has less maintenance cost.
  • Its speed control is easy and smooth.
  • It is neat, clean, and free from any smoke or flue gases.
  • It can be installed at any desired convenient place thus affording more flexibility in the layout, being compact, it requires less space.
  • It can be started immediately without any loss of time.
  • It has a comparatively longer life.

Disadvantages of Electrical Drive:

  • It comes to stop as soon as there is a failure of the electric supply.
  • It cannot be used at far-off places that are not served by electric supply.

Question 69

A single phase half-wave rectifier circuit has free-wheeling diode, the free-wheeling diode will conduct only if

  1. AOption (a)

    load is purely resistive

  2. BOption (b)

    load is purely inductive

  3. COption (c)

    load is combination of R and L

  4. DOption (d)

    load is purely inductive or combination of R and L

View answer & explanation

Correct answer

Answer: (d)D.

load is purely inductive or combination of R and L

Why this answer is correct

Concept:

Freewheeling  Diode: 

A freewheeling diode is basically a diode connected across the inductive load terminals to prevent the development of high voltage across the switch. When the inductive circuit is switched off, this diode gives a short circuit path for the flow of inductor decay current and hence dissipation of stored energy in the inductor. Freewheeling diodes are also known as Flyback diode, kickback diode, clamp diodes, commutating diodes, suppression diodes, or snubber diode, etc.

Characteristics of an Ideal Freewheeling Diode:

  • The diode must have very large forward current carrying capacity so that the freewheeling diode carry current without burning
  • It should have a low forward voltage drop nearly 0.2 V
  • It must undergo a quick reverse bias operation.

 

Purpose of using Freewheeling Diode:

  • The Freewheeling Diode improves the waveform of the load current of Rectifier circuits, inverter circuits, and chopper circuits by making it continuous.
  • The Freewheeling protect the SCRs from damage in the circuits with Inductive Load from the excessive reverse voltage creating by the Inductive Load.
  • In the converter, freewheeling diode is used to conduct current during the off period of the thyristor
  • The Freewheeling Diode improves the Input Power Factor of Phase controlled Rectifiers.
  • It decreases the possibility of discontinuous conduction in the load.
  • The Freewheeling diode sustains the average output voltage of the circuit with an Inductive Load.
  • It also helps to reduce Ripple components in the output signal of the circuit with Inductive Load.

 

 

Explanation:

Freewheeling diode conducts when load consists of any inductive load. Therefore, the free-wheeling diode will conduct only if load is purely inductive or combination of R and L.

Question 70

Find the expression for peak capacitor voltage in case of current commuted chopper circuit.

  1. AOption (a)

    I0LC{I_0}\sqrt {\frac{L}{C}}

  2. BOption (b)

    Vs+LC{V_s} + \sqrt {\frac{L}{C}}

  3. COption (c)

    Vs+I0LC{V_s} + {I_0}\sqrt {\frac{L}{C}}

  4. DOption (d)

    0 (Zero)

View answer & explanation

Correct answer

Answer: (c)C.

Vs+I0LC{V_s} + {I_0}\sqrt {\frac{L}{C}}

Why this answer is correct

Current commutated chopper:

The power circuit diagram for current commutated chopper is shown in figure. In this diagram, T1 is the main thyristor, TA is the auxiliary thyristor, C is the capacitor, L is the inductor diodes D1 and D2 constitute commutation circuitry. FD is the freewheeling diode and Rc is the charging resistor.

The peak capacitor voltage is given by

Vcp=Vs+I0LC{V_{cp}} = {V_s} + {I_0}\sqrt {\frac{L}{C}}

The peak capacitor current is given by

Icp=VsCL{I_{cp}} = {V_s}\sqrt {\frac{C}{L}}

The values of Icp and Vcp are the peak ratings of the thyristors T1 and TA.

Question 71

Which one of the following is NOT inherently constant torque motor?

  1. AOption (a)

    DC series motor

  2. BOption (b)

    DC shunt motor

  3. COption (c)

    Three phase induction motor

  4. DOption (d)

    Single phase induction motor

View answer & explanation

Correct answer

Answer: (a)A.

DC series motor

Why this answer is correct

Explanation:

DC series motor is not the constant torque motor. 

For a DC series motor, the torque is inversely proportional to the speed. The torque sped curve is, therefore, a rectangular parabola. The speed-torque relation in a DC shunt and the series motor is as shown:

D.C.Series Motor:

  • DC series motor has high starting torque; This is one of the most required characteristics of DC series motor.
  • Speed control of DC series motor is easy and various methods are available for this.
  • The size of the DC series motor is small. (i.e. small size and high-power rating).
  • This motor can handle overload easily.
  • Regenerative braking can be applied to DC series motor, But with some modifications.
  • The maintenance cost required is less.

Question 72

A 4-bit R-2R digital to analog converter (DAC) has a reference of 5 Volts. What is the analog output for input code 1010?

  1. AOption (a)

    0.3125 V

  2. BOption (b)

    3.125 V

  3. COption (c)

    0.78125 V

  4. DOption (d)
    • 3.125 V
View answer & explanation

Correct answer

Answer: (d)D.
  • 3.125 V

Why this answer is correct

Concept:

R – 2R ladder DAC:

3 bit R – 2R DAC  by using Inverting op-amp is shown below:

Output voltage is defined as:

V0 = - I1(RF) ⋯ (i)

Current is calculated as:

I1=[a22+a14+a08]II_1 = \left[ {\frac{{{a_2}}}{2} + \frac{{{a_1}}}{4} + \frac{{{a_0}}}{8}} \right]I     ⋯ (ii)

Current drawn from the source is

I = V / R ⋯ (iii)

Current is calculated as:

I1=[a22+a14+a08]VRI_1 = \left[ {\frac{{{a_2}}}{2} + \frac{{{a_1}}}{4} + \frac{{{a_0}}}{8}} \right]\frac{V}{R}

The final output voltage is

V0=−VR[a22+a14+a08]RF{V_0} = - \frac{V}{R}\left[ {\frac{{{a_2}}}{2} + \frac{{{a_1}}}{4} + \frac{{{a_0}}}{8}} \right]{R_F}

For n bit DAC output voltage is

V0=−VR[an−121+an−222+⋯+a02n]RF{V_0} = - \frac{V}{R}\left[ {\frac{{{a_{n - 1}}}}{{{2^1}}} + \frac{{{a_{n - 2}}}}{{{2^2}}} + \cdots + \frac{{{a_0}}}{{{2^n}}}} \right]{R_F}

Calculation:

Given digital input is 1010 and the reference voltage is 5 V

a3 = 1, a2 = 0, a1 = 1, a0 = 0

considering the value of the feedback resistor for Op amp is R Ω

Output voltage is

V0=−5RR[12+04+18+016];{V_0} = - \frac{{5R}}{R}\left[ {\frac{1}{2} + \frac{0}{4} + \frac{1}{8} + \frac{0}{{16}}} \right];

V0=−5×58;{V_0} = -5\times\frac{5}{8};

V0 = -3.125 V

Question 73

Which of the following equation satisfy the J-K flip-flop?

  1. AOption (a)

    Qn+1 = Jn Q̅n + K̅nQn

  2. BOption (b)

    Qn+1 = J̅n Q̅n + KnQn

  3. COption (c)

    Qn+1 = Jn Qn + KnQn

  4. DOption (d)

    Qn+1 = J̅n Q̅n + K̅nQ̅n

View answer & explanation

Correct answer

Answer: (a)A.

Qn+1 = Jn Q̅n + K̅nQn

Why this answer is correct

JK flip flop:

Characteristic Table of JK flip flop

JKQnQn+1
0000
0011
0100
0110
1001
1011
1101
1110

 

Qn+1 = JQ̅n + K̅Qn

Flip – flopCharacteristic equation
SRQn+1 =  S + R̅ Qn
J-KQn+1 = JQ̅n + K̅Qn
DQn+1 = D
TQn+1 = TQ̅n + T̅Qn

Question 74

The output f of and 4 ∶ 1 MUX shown in figure is 

(x = S1, y = S0)

  1. AOption (a)

    xy‾+x\rm \overline {xy} +x

  2. BOption (b)

    x + y

  3. COption (c)

    x‾+y‾\rm \overline x + \overline y

  4. DOption (d)

    xy+x‾\rm xy + \overline x

View answer & explanation

Correct answer

Answer: (b)B.

x + y

Why this answer is correct

Concept:

In a 4 × 1 MUX

Truth-Table

S1S0V
00I0
01I1
10I2
11I3

 

Y = Output = S̅1 S̅0 I0 + S̅1 S0 I1 + S1 S̅0 I2 + S1 S0 I3

MUX contains AND gate followed by OR gate

Calculation:

By re-drawing circuit diagram

∴ I0 = 0, I1 = 1, I2 = 1, I3 = 1 & (x = S1, y = S0)

Now output of 4 × 1 MUX is

Y = F = S̅1 S̅0 I0 + S̅1 S0 I1 + S1 S̅0 I2 + S1 S0 I3

F = x̅ y̅ 0 + x̅ y 1 + x y̅ 1 + x y 1

∴ F = x + y

Question 75

POS form of Boolean expression is suitable for circuit implementation, using

  1. AOption (a)

    XOR

  2. BOption (b)

    NAND

  3. COption (c)

    AND

  4. DOption (d)

    NOR

View answer & explanation

Correct answer

Answer: (d)D.

NOR

Why this answer is correct

Concept:

A Boolean expression consisting purely of Minterms (product terms) is said to be in the canonical sum of products form.

A Boolean expression consisting purely of Maxterms (sum terms) is said to be in the canonical product of sums form.

a) (A + B)(C + D) – POS form

b) (A)B(C + D) – POS form

c) AB + CD – SOP form

Explanation:

POS form of a Boolean expression is suitable for circuit implementation, using NOR gate.

SOP form of a Boolean expression is suitable for circuit implementation, using NAND gate.

Question 76

The Boolean function A + BC is a reduced form of

  1. AOption (a)

    AB + BC

  2. BOption (b)

    (A + B) (A + C)

  3. COption (c)

    A’B + AB’C

  4. DOption (d)

    (A + C)B

View answer & explanation

Correct answer

Answer: (b)B.

(A + B) (A + C)

Why this answer is correct

Distributive Law:

A + (BC) = (A + B) (A +C)

Proof:

(A+B) (A+C) = A.A + A.C + B.A + B.C

Since A.A = A, the above expression becomes:

= A + A.C + A.B + B.C

= A(1 + C + B) + B.C

Since 1 + any variable = 1, the above expression becomes:

= A + B.C

(A+B) (A+C) = A + B.C

NameAND FormOR Form
Identity law1.A=A0+A=A
Null Law0.A=01+A=1
Idempotent LawA.A=AA+A=A
Inverse LawAA’=0A+A’=1
Commutative LawAB=BAA+B=B+A
Associative Law(AB)C(A+B)+C = A+(B+C)
Distributive LawA+BC=(A+B)(A+C)A(B+C)=AB+AC
Absorption LawA(A+B)=AA+AB=A
De Morgan’s Law(AB)’=A’+B’(A+B)’=A’B’

Question 77

A 10-bit D/A converter gives a maximum output of 10.23 V. The resolution is

  1. AOption (a)

    10 mV

  2. BOption (b)

    20 mV

  3. COption (c)

    15 mV

  4. DOption (d)

    25 mV

View answer & explanation

Correct answer

Answer: (a)A.

10 mV

Why this answer is correct

Concept:

  • Analog-to-Digital Converters (ADCs) transform an analog voltage to a binary number (a series of 1’s and 0’s).
  • Then eventually to a digital number (base 10) for reading on a meter, monitor, or chart.
  • The ADC resolution depends upon the number of bits used to represent the digit number.
  • As the number of bits increases the resolution of an Analog to Digital Converter improves and the quantization error decreases.

 

The resolution of DAC is a change in analog voltage corresponding to the LSB bit increment at the input.

The resolution (R) is calculated as:

R=VFS2N−1 R= \frac{{{V_{FS}}}}{{{2^N} - 1}}

No. of levels = 2N – 1

Vr is reference voltage 'or' Full-scale voltage

Resolution for n – bit A/D converter in percentage will be:

=VFS2n−1×100= \frac{V_{FS}}{{{2^n} - 1}} \times 100

Calculation:

Given: n = 10, VFS = 10.23 V

=10.23210−1 = \frac{10.23}{{{2^{10}} - 1}}

= 10 mV

Question 78

Which of the following expressions does NOT represent exclusive NOR of x and y?

  1. AOption (a)

    xy + x̅ y̅

  2. BOption (b)

    x ⨁ y̅

  3. COption (c)

    x̅ ⨁ y

  4. DOption (d)

    x̅ ⨁ y̅

View answer & explanation

Correct answer

Answer: (d)D.

x̅ ⨁ y̅

Why this answer is correct

Concept:

XNOR Gate:

Symbol:

Truth Table:

Input AInput BOutput Y=A⊕B‾Y={\overline{A\oplus B}}
001
010
100
111

 

Output Equation: Y=A⊕B‾Y={\overline{A\oplus B}}

Key Points: 

1) If B is always Low, the output is the inverted value of the other input A, i.e. A̅.

2) The output is low when both the inputs are different.

3) The output is high when both the inputs are the same.

4) XNOR gate produces an output only when the two inputs are same.

 

XOR Gate: output goes HIGH to a logic level 1 only when both of its

inputs are different. If inputs are the same, the output will be LOW '0'.

Y=A.B‾+A‾.BY=A.\overline{B}+\overline{A}.B

ABY
000
011
101
110

 

Explanation:

  1. xy + x̅ y̅

It represents the EX-NOR gate.

  1. x ⨁ y̅ = x̅ y̅ + xy

It represents the EX-NOR gate.

  1. x ⨁ y̅ = xy + x̅ y̅

It represents the EX-NOR gate.

  1. x̅ ⨁ y̅ = x̅y + xy̅

It represents the EX-OR gate.

Question 79

A ripple counter’s speed is limited by the propagation delay of 

  1. AOption (a)

    Each flip-flop

  2. BOption (b)

    All flip-flops and gates

  3. COption (c)

    The flip-flops only with gates

  4. DOption (d)

    Only circuit gates

View answer & explanation

Correct answer

Answer: (a)A.

Each flip-flop

Why this answer is correct

A ripple counter’s speed is limited by the propagation delay of each flip-flop.

Ripple Counter:

  • Ripple counter is a special type of Asynchronous counter in which the clock pulse ripples through the circuit.
  • The n-MOD ripple counter can count 2n states, and then the counter resets to its initial value.
  • Features of the Ripple Counter: Different types of flip flops with different clock pulse are used.

 Important Points

The effective propagation delay in a ripple counter is equal to the sum of propagation delays due to different flip-flops.

An increased propagation delay puts a limit on the maximum frequency used as clock input to the counter.

In synchronous counter, all flip flops are triggered with same clock simultaneously.

In asynchronous counter, different flip flops are triggered with different clock, not simultaneously.

Synchronous Counter is also called Parallel Counter. Asynchronous Counter is also called Serial Counter.

Asynchronous counters are slower than synchronous counters because of the delay in the transmission of the pulses from flip-flop to flip-flop.

Asynchronous counters are also called ripple-counters because of the way the clock pulse ripples it way through the flip-flops.

Applications of counters

  • Frequency counters.
  • Digital clocks.
  • Analog to digital convertors.
  • With some changes in their design, counters can be used as frequency divider circuits.
  • In time measurement.
  • We can design digital triangular wave generator by using counters.

Question 80

When aliasing takes place

  1. AOption (a)

    Sampling signals less than Nyquist rate

  2. BOption (b)

    Sampling signals more than Nyquist rate

  3. COption (c)

    Sampling signals equal to Nyquist rate

  4. DOption (d)

    Sampling signals at a rate which is twice of Nyquist rate

View answer & explanation

Correct answer

Answer: (a)A.

Sampling signals less than Nyquist rate

Why this answer is correct

  • The sampling theorem states that “a signal can be exactly reproduced if it is sampled at the rate fs which is greater than twice the maximum frequency W in the modulating signal."
  • The minimum rate at which a signal can be sampled and still be reconstructed from its samples is known as Nyquist rate.
  • If the sampled frequency is less than the Nyquist frequency, overlapping of lower and upper sidebands known as aliasing takes place.
  • The main reason for aliasing is undersampling i.e.;fs<2fmi.e.;{f_s} < 2{f_m}

           fs = Sampling frequency and fm = Modulating frequency

Aliasing is explained with the help of the spectrum as shown:

Question 81

Consider sinusoidal modulation in an AM system. Assuming no over-modulation, the modulation index (𝜇) when the maximum and minimum values of the envelope, respectively, are 3 V and 1 V is ________.

  1. AOption (a)

    0.8

  2. BOption (b)

    0.5

  3. COption (c)

    0.2

  4. DOption (d)

    0.1

View answer & explanation

Correct answer

Answer: (b)B.

0.5

Why this answer is correct

Concept:

A single tone modulated signal is given as:

Maximum envelope Amax : Ac (1+μ)

Minimum envelope Amin : Ac (1-μ)

AmaxAmin=1+μ1−μ\frac{{{A_{max}}}}{{{A_{min}}}} = \frac{{1 + μ}}{{1 - μ}}

The above can be written as:

μ=Amax−AminAmax+Aminμ = \frac{{{A_{max}} - {A_{min}}}}{{{A_{max}} + {A_{min}}}}

Calculation:

Given:  Amax = 3 V and Amin = 1 V

The modulation index will be:

μ=3−13+1μ = \frac{{{3} - 1}}{{3 + 1}}

μ = 0.5

Question 82

The Q-factor of a waveguide resonator is given by (ω0 is resonant frequency, U is energy storage and ωL is power loss)

  1. AOption (a)

    Q=ω0UωLQ = \frac{{{\omega _0}U}}{{{\omega _L}}}

  2. BOption (b)

    Q=ω0ωLUQ = \frac{{{\omega _0}{\omega _L}}}{U}

  3. COption (c)

    Q = ω0UωL

  4. DOption (d)

    Q=UωLω0Q = \frac{{U{\omega _L}}}{{{\omega _0}}}

View answer & explanation

Correct answer

Answer: (a)A.

Q=ω0UωLQ = \frac{{{\omega _0}U}}{{{\omega _L}}}

Why this answer is correct

Concept:

The quality factor is in general a measure of the ability of a resonator to store energy in relation to time-average power dissipation.

Specifically, the Q of a resonator is defined as:

Q=2πMaximum energy storedEnergy dissipated per cycleQ=2\pi\frac{Maximum \ energy \ stored}{Energy \ dissipated \ per \ cycle}

In the case of resonators, the Quality factor is given by:

Q=ω0WPlQ=\frac{ω_0W}{P_l}  ---(1)

Where,

ω0 = Resonant frequency

W = Total Energy

Pl = Power loss in the cavity.

Calculation:

Given:

Pl = ωL

ω0 = resonant frequency

W = U

Putting the above values in equation (1) we get the Quality factor as:

Q=ω0UωLQ = \frac{{{\omega _0}U}}{{{\omega _L}}}

Hence option (1) is the correct answer.

Important Points

  • Microwave resonators are tunable circuits used in microwave oscillators, filters, and frequency meters.
  • The operation of microwave resonators is very similar to that of the lumped-element resonators (such as parallel and series RLC resonant circuits) of circuit theory.
  • A cavity resonator is not a waveguide. It is a metallic enclosure that confines the electromagnetic energy within itself.
  • If excited properly, oscillations take place inside of it.
  • It is used as a tuned circuit at high frequencies.

Question 83

A speech signal is sampled at 8 kHz and encoded in PCM format using 8-bit/sample PCM data is transmitted through a baseband channel via 4-level PAM. Minimum Bandwidth required for transmission is

  1. AOption (a)

    16 kHz

  2. BOption (b)

    8 kHz

  3. COption (c)

    24 kHz

  4. DOption (d)

    10 kHz

View answer & explanation

Correct answer

Answer: (a)A.

16 kHz

Why this answer is correct

Concept:

Baseband communication is given.

Minimum Bandwidth will be required if transmission of data takes place using sinc pulses and the bandwidth is given by:

BWmin=Rb2log⁡2MB{W_{{\rm{min}}}} = \frac{{{R_b}}}{{2{{\log }_2}M}} 

Where Rb = n  fs

n = number of bits used to represent samples

fs = sampling rate.

Calculation:

In the Question, it is asked about minimum Bandwidth. ∴ we will consider that the transmission of data is taking place through sinc pulses.

Given fs = 8 kHz

n = 8 bits/sample

M = 4

Rb = nfs

(BW)min=Rb2log⁡2M{\left( {BW} \right)_{min}} = \frac{{{R_b}}}{{2{{\log }_2}M}} 

=n;fs2log⁡2M=8×82log⁡24= \frac{{n;{f_s}}}{{2{{\log }_2}M}} = \frac{{8 \times 8}}{{2{{\log }_2}4}} 

=642×2=16;kHz= \frac{{64}}{{2 \times 2}} = 16;kHz

Question 84

For best low level noise performance in the X-band, an amplifier should use

  1. AOption (a)

    A bipolar transistor

  2. BOption (b)

    A gunn diode

  3. COption (c)

    A step-recovery diode

  4. DOption (d)

    An IMPATT diode

View answer & explanation

Correct answer

Answer: (c)C.

A step-recovery diode

Why this answer is correct

Explanation:

For the best low-level noise performance in the X-band, an amplifier should use a step-recovery diode.

Step Recovery Diode:

It is a semiconductor device with unusual doping. 

  • The doping density is very small near the junction area due to which the density of charge carriers is also small near the junction area.
  • As the charge storage is negligible near the junction, it helps in the fast switching of the diode from on to off state.
  • It works as a normal diode under forward and reverse bias condition but it changes its state instantly when it is switched from forward to reverse bias.
  • Step Recovery Diode works as a Multiplier as it can multiply the frequency of signal up to 20 times.
  • The fast switching time of this diode imparts the ability to generate sharp pulses.
  • During forward biasing they store charge and when reversed biased they use this charge to generate harmonics. Hence option (3) is the correct answer.

​

Important Points

Bipolar Junction Transistor:

  • B = Bipolar (because conduction is due to two opposite type of carriers Holes and electrons)
  • J = Junction refers to the two PN junctions between emitter and base, and collector and base.
  • BJT's are current-driven devices.
  • The current through the two terminals is controlled by a current at the third terminal (base).
  • It is a bipolar device (current conduction by both types of carriers, i.e. majority and minority electrons and holes)
  • It has a low input impedance.

Gunn diode:

  • A Gunn diode is considered as a type of diode even though it does not contain any typical PN diode junction like the other diodes, but it consists of two electrodes.
  • It is also called as a Transferred Electronic Device.
  • It is a negative differential resistance device, which is frequently used as a low-power oscillator to generate microwaves.
  • It consists of only an N-type semiconductor in which electrons are the majority charge carriers.
  • To generate short radio waves such as microwaves, it utilizes the Gunn Effect.
  • In some semiconductor materials like GaAs, the conduction band is further divided into light mass high mobility valley and high mass low mobility valley, when the voltage has applied the electrons at sufficient electric field jump from high mobility light mass valley to high mass low mobility zones, thereby dropping drift current (effectively the diode has negative resistance) along with an increase in electric potential applied across diode.

 

 

IMPATT diode:

  • IMPATT diode consists of 4 layers according to the construction.

  • An IMPATT diode has an n+ - p - i - p + structure and is used with reverse bias.

  • It exhibits negative resistance and operates on the principle of avalanche breakdown. I

  • MPATT diode circuits are classified as broadly tunable circuits, low Q circuits, and high Q circuits. The impedance of the IMPATT diode is a few ohms. The word IMPATT stands for Impact Avalanche Transit Time diode.

  • The features of the IMPATT diode oscillator are:

  1. Frequency 1 to 300 GHz, Power output (0.5 W to 5 W for single diode circuit and up to 40 W for the combination of several diodes),
  2. It has an efficiency of about 20%.
  3. Its applications include police radar systems, low-power microwave transmitters, etc.

Question 85

A lossless line of characteristic impedance z0 is terminated in pure reactance of -jz0, Voltage Standing Wave Ratio (VSWR) is

  1. AOption (a)

    10

  2. BOption (b)

    2

  3. COption (c)

    1

  4. DOption (d)

    infinity

View answer & explanation

Correct answer

Answer: (d)D.

infinity

Why this answer is correct

Concept:

The voltage standing wave ratio is defined as the ratio of the maximum voltage (or current) to the minimum voltage (or current).

\(VSWR = \frac{{{{\rm{V}}{{\rm{max}}}}}}{{{{\rm{V}}{{\rm{min}}}}}} = \frac{{{{\rm{I}}{{\rm{max}}.}}}}{{{{\rm{I}}{{\rm{min}}.}}}};\)

This can also be written as:

VSWR=1+∣Γ∣1−∣Γ∣;VSWR = \frac{{1 + {\rm{|Γ| }}}}{{1 - {\rm{|Γ|}}}};

Γ = Reflection coefficient, defined as:

Γ=ZL−Z0ZL+Z0;{\rm{Γ }} = \frac{{{Z_L} - {Z_0}}}{{{Z_L} + {Z_0}}};

ZL = Load impedance

Z0 = Characteristic Impedance

Calculation:

Given:

Z0 = Z0 Ω

ZL = -jZ0 Ω

Γ=ZL−Z0ZL+Z0;{\rm{Γ }} = \frac{{{Z_L} - {Z_0}}}{{{Z_L} + {Z_0}}};

Γ=−jZ0−Z0−jZ0+Z0=−1−j1−j=2∠−135∘2∠−45∘=1∠−90∘{\rm{Γ }} = \frac{{-jZ_0 - Z_0}}{{-jZ_0 + Z_0}} = \frac{-1-j}{1-j}=\frac{\sqrt2\angle -135^{\circ}}{\sqrt 2\angle-45^{\circ}}=1\angle -90^\circ

Γ = -j

Now:

VSWR=1+∣−j∣1−∣−j∣=1+11−1=20=∞VSWR = \frac{{1 + |-j|}}{{1 - |-j|}} =\frac{1+1}{1-1}=\frac{2}{0}= \infty

Question 86

In colour TV receiver, varactor diode is used for

  1. AOption (a)

    Deflection

  2. BOption (b)

    Rectification

  3. COption (c)

    Tuning

  4. DOption (d)

    Both (a) and (b)

View answer & explanation

Correct answer

Answer: (c)C.

Tuning

Why this answer is correct

Varactor diode is commonly used for Electronic tuning.

Varactor diode:

  • It is represented by a symbol of diode terminated in the variable capacitor as shown below:

  • Varactor diode refers to the variable Capacitor diode, which means the capacitance of the diode varies linearly with the applied voltage when it is reversed biased.

  • The junction capacitance across a reverse bias PN junction is given by

​           C=AϵWC=\frac{A\epsilon}{W}

  • As the reverse bias voltage increases, the depletion region width increases resulting in a decrease in the junction capacitance.
  • Varactor diodes are used in electronic tuning systems to eliminate the need for moving parts
  • Varactor [also called varicap, variable reactance diode, or tuning diode] diodes are the semiconductor, voltage-dependent, variable capacitors
  • Varactors are used as voltage-controlled capacitors and it operated in a reverse-biased state. Hence option (3) is the correct answer.
DiodesApplication
Schottky diodeVoltage reference
Varactor diodeTuned circuits
PIN diodeHigh-frequency switch
Zener diodeCurrent controlled attenuator

Question 87

FDM and analog multiplexing technique used to combine

  1. AOption (a)

    Analog signals

  2. BOption (b)

    Digital signals

  3. COption (c)

    Both analog and digital signals

  4. DOption (d)

    Alternatively passes analog and digital signal

View answer & explanation

Correct answer

Answer: (a)A.

Analog signals

Why this answer is correct

Explanation:

Multiplexing is the process of combining multiple signals into one signal, over a shared medium. 

Types of Multiplexing include:

Analog Multiplexing: The signals used in analog multiplexing techniques are analog in nature. The analog signals are multiplexed according to their frequency (FDM) or wavelength (WDM). Hence option (1) is the correct answer.

Frequency Division Multiplexing:

  • In analog multiplexing, the most used technique is Frequency Division Multiplexing (FDM).
  • This technique uses various frequencies to combine streams of data, for sending them on a communication medium, as a single signal.
  • Example: A traditional television transmitter, which sends a number of channels through a single cable uses FDM.

Digital Multiplexing: The term digital represents discrete bits of information. Hence, the available data is in the form of frames or packets, which are discrete.

Time Division Multiplexing:

  • In Time Division Multiplexing (TDM), the time frame is divided into slots.
  • This technique is used to transmit a signal over a single communication channel, by allotting one slot for each message.
  • Time Division Multiplexing (TDM) can be classified into Synchronous TDM and Asynchronous TDM.

Question 88

Large internal faults in transformer are protected by

  1. AOption (a)

    Merz-price percentage differential protection

  2. BOption (b)

    Mho and ohm relays

  3. COption (c)

    Horn gaps and temperature relays

  4. DOption (d)

    Earth fault and positive sequence relays

View answer & explanation

Correct answer

Answer: (a)A.

Merz-price percentage differential protection

Why this answer is correct

  • When an unloaded transformer is switched on, it draws a large initial magnetizing current. It is called as magnetizing inrush current.
  • As the inrush current flows only in the primary winding, the differential protection will see this inrush current as an internal fault.
  • The harmonic contents in the inrush currents are different than those in the usual fault current.
  • The dc component varies from 40 to 60%, the second harmonic 30 to 70% and the third harmonic 10 to 30%.
  • The third harmonic and its multiples do not appear in CT leads connected as these harmonics circulate in the delta winding of the transformer.
  • As the second harmonic is more in the inrush current than in the fault current, this feature can be utilized to distinguish between a fault and magnetizing inrush current.

 

The figure shows a high-speed biased differential scheme incorporating a harmonic restraint feature.

Operating principle:

  • The operating principle is to filter out the harmonics from the differential current, rectify them and add them to percentage restraint.
  • The tuned circuit XCXL allows only the current of the fundamental frequency to flow through the operating coil.
  • The dc and harmonics, mostly second harmonics in case of magnetic inrush current, are diverted into the restraining coil.
  • The relay is adjusted so as not to operate when the second harmonic (restraint) exceeds 15% of fundamental current (operating).

Question 89

If the fault current is 2000 amps, the relay setting is 50% and the CT ratio is 400/5, then the plug setting multiplier will be _____

  1. AOption (a)

    25

  2. BOption (b)

    15

  3. COption (c)

    50

  4. DOption (d)

    10

View answer & explanation

Correct answer

Answer: (d)D.

10

Why this answer is correct

Concept:

Plug Setting Multiplier (PSM): It is the ratio between the actual fault current in the relay operating coil to pick up current or the relay current setting.

\(PSM=\frac{FaultCurrent}{CurrentSetting× CT~Ratio}\)

  • Plug setting multiplier (PSM) Indicates the severity of the fault.
  • The plug setting multiplier is used only in Electromagnetic relays not in numerical relays.
  • The operating Times of the Relay operation are depending upon the PSM. The high value of PSM indicates low operating time.

 

Calculation:

Given that, fault current = 2000 A

current setting = 0.5 × 5 = 2.5

PSM = 20002.5×4005\frac{2000}{2.5\times\frac{400}{5}}

= 10

Question 90

An ideal circuit breaker should offer

  1. AOption (a)

    Zero & infinite impedance before & after interruption respectively

  2. BOption (b)

    Infinity & zero impedance before & after interruption respectively

  3. COption (c)

    Equal impedance before & after interruption

  4. DOption (d)

    None of these

View answer & explanation

Correct answer

Answer: (a)A.

Zero & infinite impedance before & after interruption respectively

Why this answer is correct

  • A circuit breaker is a switching device that interrupts the abnormal or fault current
  • It is a mechanical device that disturbs the flow of high magnitude (fault) current and in additions performs the function of a switch
  • The circuit breaker is mainly designed for closing or opening of an electrical circuit, thus protects the electrical system from damage
  • When the circuit breaker is closed, it acts as short switch; Thus, before interruption ideal circuit breaker should offer zero impedance
  • When the circuit breaker is open, it acts as open switch; Thus, after interruption ideal circuit breaker should offer infinite impedance

Question 91

A three-phase, 33 kV oil circuit breaker is rated 1200 A, 2000 MVA, 3 s. The symmetrical breaking current is

  1. AOption (a)

    1200 A

  2. BOption (b)

    3600 A

  3. COption (c)

    35 kA

  4. DOption (d)

    104.8 kA

View answer & explanation

Correct answer

Answer: (c)C.

35 kA

Why this answer is correct

Concept:

Breaking current: It expresses the highest number of short-circuit currents that the breakers are capable of breaking under specified conditions of transient recovery voltage and power frequency voltage. It is expressed in kA (RMS) at contact separation. The breaking capacities are divided into two types.

  • Symmetrical breaking capacity of a circuit breaker
  • Asymmetrical breaking capacity of a circuit breaker

 

Rated symmetrical breaking current IB=S3VL{I_B} = \frac{S}{{\sqrt 3 {V_L}}}

Making current of a circuit breaker is the peak value of the maximum current loop during sub transient condition including the DC component when the breaker closes.

Symmetrical making current = 2.55 × symmetrical breaking current

Calculation:

Rated current = 1200 A

MVA rating = 2000 MVA

Rated symmetrical breaking current =2000×1063×33×103=35;kA= \frac{{2000 \times {{10}^6}}}{{\sqrt 3 \times 33 \times {{10}^3}}} = 35;kA

Question 92

With the help of reactive compensator, it is possible to have

  1. AOption (a)

    Constant voltage operation only

  2. BOption (b)

    Unity p.f. operation only

  3. COption (c)

    Both constant voltage and unit p.f.

  4. DOption (d)

    Either constant voltage operation or unity p.f. operation

View answer & explanation

Correct answer

Answer: (d)D.

Either constant voltage operation or unity p.f. operation

Why this answer is correct

Reactive compensation can be done by either series compensation or shunt compensation.

Series compensation:

  • It is the method of improving the system voltage by connecting a capacitor or reactor in series with the transmission line.
  • In series compensation, reactive power is inserted in series with the transmission line for improving the impedance of the system.
  • The following are the advantages of series capacitive compensation.
  • Increase in power transfer capability
  • Improvement in system stability
  • Load division among parallel line
  • Control of voltage

​

Shunt compensation:

  • Whenever an inductive load is connected to the transmission line, power factor lags because of lagging load current.
  • To compensate this, a shunt capacitor is connected which draws current leading the source voltage, thereby the power factor can be improved.
  • Whenever an capacitive load is connected to the transmission line, power factor leads because of leading load current.
  • To compensate this, a shunt reactor is connected which draws current lagging the source voltage, thereby the power factor can be improved.

​

Conclusion:

  • When reactive compensation is used in series it improves the voltage of the systems.
  • When reactive compensation is used in shunt it improves the power factor of the system.
  • So, based on the type of the compensation, it  maintain either constant voltage or unity power factor but not both at a time.,

Question 93

The most efficient torque-producing actuating structure for induction-type relays is

  1. AOption (a)

    Shaded-pole structure

  2. BOption (b)

    Watt-hour-meter structure

  3. COption (c)

    Induction-cup structure

  4. DOption (d)

    Single-induction-loop structure

View answer & explanation

Correct answer

Answer: (c)C.

Induction-cup structure

Why this answer is correct

Induction-cup structure is most efficient torque-producing actuating structure for Induction-type relays.

Induction Relays:

  • The induction type relays are also called magnitude relays.
  • These relays work on the principle of the induction motor or an energy meter.
  • In these relays, a metallic disc is allowed to rotate between the two electromagnets.
  • The coils of the electromagnets are energized with the help of alternating currents.
  • The torque is produced in Induction relays due to the interaction of one alternating flux with eddy currents induced in the rotor by another alternating flux.
  • The two fluxes have the same frequency but are displaced in time and space.
  • As the interaction of alternating fluxes is the base of operation of Induction relays.
  • Based on the construction, the various types of induction relays are:                 

1)Shaded pole Relays                                            

2)Watt-hour meter Relays                                                

3)Induction cup Relays

 

Induction Cup Relay:

  • The basis construction of this relay is just like four poles or eight pole induction motor.

  • The number of poles in the protective relay depends upon the number of winding to be accommodated.

  • The figure shows a four pole induction cup relay.

  • In four poles design both pair of poles are supplied from same current transformer’s secondary, but phase difference between the currents of two pole pairs is 90 degree.

  • This is done by inserting an inductor in series with coil of one pole pair, and by inserting a resistor in series with coil of another pole pair.

  • The rotating magnetic field induces current in the aluminum brum or cup.

  • As per working principle of induction motor, the cup starts rotating in the direction of rotating magnetic field, with a speed slightly less than the speed of rotating magnetic field.

  • The aluminum cup is attached with a hair sprin.

  • In normal condition the restoring torque of the spring is higher than deflecting torque of the cup.

  • So there is no movement of the cup.

  • But during faulty condition of system, the current through the coil is quite high, hence, deflecting torque produced in the cup is much higher than restoring torque of spring.

  • Hence the cup start rotating as rotor of induction motor.

  • The contacts attached to the moving of the cup to specific angle of rotation.

Question 94

Why are the ternary lead cables used near the railway track?

  1. AOption (a)

    Because they have high tensile strength

  2. BOption (b)

    Have a low coefficient of thermal expansion

  3. COption (c)

    Have low specific gravity

  4. DOption (d)

    Can withstand shocks and vibrations

View answer & explanation

Correct answer

Answer: (c)C.

Have low specific gravity

Why this answer is correct

  • In electrical signaling and power cables, lead has been used as a sheathing material, the choice of selecting lead is made because of its cheapness, corrosion resistance, and ease of fabrication.
  • However the low strength of the lead resulted in a number of failures, mostly due to fatigue, and consequently lead alloys began to be used, those containing up to 3% of tin being the popular choice, but subsequently, other binary and ternary lead alloys were allowed.
  • Lead and tin are both soft materials. A small addition of tin is used to strengthen lead. larger additions of 15% - 25% are used to make a protective coating on the steel by dipping in the molten alloy.

 

Ternary alloys:

  • When the lead is mixed with the other two alloys resulting in the mixture of three different materials forming a single material called ternary lead alloys.
  • Ternary alloys consist of lead, tin, and antimony, with generally 10% - 20% antimony, and 2% - 10% tin.
  • This alloy is suitable for making sheaths and cables near the railway track due to having low specific gravity.

​

​

Additional Information

The relative density or specific gravity of a substance is defined as the ratio of the density(ρs), mass(ms), or weight(Ws) of the substance to the density(ρw), mass(mw), or weight(Ww) of water at 4° C

Specific gravity =ρsρw≈msmw≈WsWw= \frac{{\rho_s}}{{\rho_w}} \approx \frac{{m_s}}{{m_w}} \approx \frac{{Ws}}{{W_w}}

Here specific gravity is unitless and the density of water at 4° C is 1.0×103 kg/m3

Whereas density, ρ=MassVolumeρ = \frac{{Mass}}{{Volume}}

Question 95

Given that dydx=x2+y,\frac{{dy}}{{dx}} = {x^2} + y, with y(0) = 1, when x = 0, taking h = 0.2 the value of y after 1 iteration using Euler’s modified method is

  1. AOption (a)

    1.2

  2. BOption (b)

    1.224

  3. COption (c)

    1.228

  4. DOption (d)

    1.232

View answer & explanation

Correct answer

Answer: (b)B.

1.224

Why this answer is correct

Concept:

Heun’s Method:

Consider dydx=f(x,;y)\frac{{dy}}{{dx}} = f\left( {x,;y} \right) with the initial condition y(x0) = y0

Initially y1 is computed by Euler’s formula.

y1p=y0+h;f(x0,;y0)y_1^p = {y_0} + h;f\left( {{x_0},;{y_0}} \right)

Then the modified value of y1 is given by

y1c=y0+h2[f(x0,;y0)+f(x1,;y1p)]y_1^c = {y_0} + \frac{h}{2}\left[ {f\left( {{x_0},;{y_0}} \right) + f\left( {{x_1},;y_1^p} \right)} \right]

Similarly, we can find y2, y3, …. yn

Where p indicates predicator and c indicates character.

This method is also called modified Euler’s method (or) second order Range-kutta method.

Calculation:

Given differential equation is,

f(x,;y)=dydx=x2+yf\left( {x,;y} \right) = \frac{{dy}}{{dx}} = x^2 + {y}

Initial condition y0 = 1, x0 = 0

Step size, h = 0.2

y1p=1+0.2;[f(0,;1)]=1+0.2(0+1)=1.2y_1^p = 1 + 0.2;\left[ {f\left( {0,;1} \right)} \right] = 1+ 0.2(0+1)= 1.2

y1c=1+0.22;[f(0,;1)+f(0.2,;1.2)]y_1^c = 1 + \frac{{0.2}}{2};\left[ {f\left( {0,;1} \right) + f\left( {0.2,;1.2} \right)} \right]

f(0,;1)=0+1=1f\left( {0,;1} \right) = 0 + 1 = 1

f(0.2,;1.2)=0.22+1.2=1.24f\left( {0.2,;1.2} \right) = 0.2^2+1.2=1.24

y1c=1+0.1[1+1.24]=1.224y_1^c = 1 + 0.1\left[ {1 + 1.24} \right] = 1.224

Question 96

The point where Newton-Raphson method fails are called

  1. AOption (a)

    Floating

  2. BOption (b)

    Continuous

  3. COption (c)

    Non-stationary

  4. DOption (d)

    Stationary

View answer & explanation

Correct answer

Answer: (d)D.

Stationary

Why this answer is correct

Concept:

Newton-Raphson Method:

The iteration formula is given by

xn+1=xn−f(xn)f′(xn){x_{n + 1}} = {x_n} - \frac{{f\left( {{x_n}} \right)}}{{f'\left( {{x_n}} \right)}}

Where x0 is the approximate root of the equation f(x) = 0

Important Points:

  • Newton’s method is useful in cases of large values of f’(x) i.e. when the graph of f(x) while crossing the x-axis is nearly vertical.
  • It is not preferred when the graph of f(x) is nearly horizontal where it crosses the x-axis as the values of f’(x) have negative values in this case.
  • It is sensitive to starting value. Convergence fails if the starting point is nor near the root.
  • The formula converges provided the initial approximation x0 is chosen sufficiently close to the root.
  • It is generally used to improve the result obtained by the other methods.
  • It has quadratic convergence i.e. order of convergence is 2. The subsequent error at each step is proportional to the square of the error at the previous step.

 

Explanation:

The points where the function f(x) approaches infinity are called as Stationary points. At stationary points, Newton Raphson fails and hence it remains undefined for Stationary points.

Question 97

Newton-Raphson method is used to compute a root of the equation x2 – 13 = 0 with 3.5 as initial value. The approximation after one iteration is

  1. AOption (a)

    3.575

  2. BOption (b)

    3.676

  3. COption (c)

    3.667

  4. DOption (d)

    3.607

View answer & explanation

Correct answer

Answer: (d)D.

3.607

Why this answer is correct

Concept:

According to Newton-Raphson Method

Xn+1=Xn−f(Xn)f′(Xn){X_{n + 1}} = {X_n} - \frac{{f\left( {{X_n}} \right)}}{{f'\left( {{X_n}} \right)}}

Calculation:

f(x) = x2 – 13

f’(x) = 2x

Initial guess (x0) = 3.5

Iteration 1:

f(x0) = -0.75

f’(x0) = 7

x1=x0−f(x0)f′(x0)=3.5−(−0.757)=3.607{x_1} = {x_0} - \frac{{f\left( {{x_0}} \right)}}{{f'\left( {{x_0}} \right)}} = 3.5 - \left( {\frac{{ - 0.75}}{7}} \right) = 3.607

Question 98

Which one of the following materials is a diamagnetic material?

  1. AOption (a)

    Copper 

  2. BOption (b)

    Nickel

  3. COption (c)

    Iron

  4. DOption (d)

    Aluminium

View answer & explanation

Correct answer

Answer: (a)A.

Copper 

Why this answer is correct

Diamagnetic Substance:

  • Diamagnetic substances are those which develop feeble magnetization in the opposite direction of the magnetizing field.
  • Such substances are feebly repelled by magnets and tend to move from stronger to weaker parts of a magnetic field.
  • Magnetic susceptibility is small and negative i.e. -1 ≤  χ ≤ 0.
  • Examples: Bismuth, copper, lead, zinc, etc.

 

Additional Information

Magnetic susceptibility

  • Magnetic susceptibility (χm): It is the property of the substance which shows how easily a substance can be magnetized.
  • It is defined as the ratio of the intensity of magnetization (I) in a substance to the magnetic intensity (H) applied to the substance,  i.e.
  • It is a scalar quantity with no units and dimensions.
  • The susceptibility of free space or air is exactly zero.

 

Paramagnetic substances:

  • Paramagnetic substances are those which develop feeble magnetization in the direction of the magnetizing field.
  • Such substances are feebly attracted by magnets and tend to move from weaker to stronger parts of a magnetic field.
  • Magnetic susceptibility is small and positive i.e. 0 <  χ.
  • Example: Manganese, aluminum, chromium, platinum, etc.

Ferromagnetic substances:

  • Ferromagnetic substances are those which develop strong magnetization in the direction of the magnetizing field.
  • They are strongly attracted by a magnet and tend to move from weaker to the stronger part of a magnetic field.
  • Magnetic susceptibility is very large and positive i.e. χ > 1000
  • Example: Iron, cobalt, nickel, gadolinium, and alloys like alnico.

 

MaterialMagnetic Susceptibility (Xm­)Relative Permeability (Km = 1 + Xm)Magnetic Permeability (μm = Kmμ0)
Diamagnetic-10-5 to -10-9< 1μm < μ0
Paramagnetic10-5 to 10-3> 1μm > μ0
Ferromagnetic≫ 1≫ 1μm ≫ μ0

Question 99

The structure sensitive property of a super conductor is

  1. AOption (a)

    Critical magnetic field

  2. BOption (b)

    Transition temperature

  3. COption (c)

    Critical current density

  4. DOption (d)

    None of the above

View answer & explanation

Correct answer

Answer: (c)C.

Critical current density

Why this answer is correct

Explanation:

Critical current density is the structure sensitive property of a super conductor.

The Silsbee effect states that, if the current exceeds a critical level, the superconducting state will be destroyed.

Critical current is mathematically defined as:

IC = 2πr Hc

r = radius of superconductor wire

Hc = critical magnetic field strength

Critical current density will be the ratio of the critical current to the area, i.e.

Jc=IcA{J_c} = \frac{{{I_c}}}{A}

Jc=2πr;HcA{J_c} = \frac{{2\pi r;{H_c}}}{A}

Jc=2πr;;H0[1−(TTc)2]A{J_c} = \frac{{2\pi r;;{H_0}\left[ {1 - {{\left( {\frac{T}{{{T_c}}}} \right)}^2}} \right]}}{A}

Question 100

The 2’s complement representation of – 17 is 

  1. AOption (a)

    100001

  2. BOption (b)

    101111

  3. COption (c)

    110011

  4. DOption (d)

    101110

View answer & explanation

Correct answer

Answer: (b)B.

101111

Why this answer is correct

Concept:

The procedure for representing a negative decimal in 2's complement representation is as shown:

Application:

The binary representation of 17

217
281
240
220
210
01

 

1710 = (10001)2

Taking the 1's complement of the above, we get 01110

Adding 1 to the 1's complement, we get the 2's complement representation of the number, i.e.

11101110 + 1 = 01111

(-17)10 in 2's complement is written as:

101111

Question 101

The smallest integer that can be represented by an 8- bit number in 2’s complement form is

  1. AOption (a)

    -256

  2. BOption (b)

    -128

  3. COption (c)

    127

  4. DOption (d)

    -255

View answer & explanation

Correct answer

Answer: (b)B.

-128

Why this answer is correct

The Correct Answer is -128.

  • The smallest integer that can be represented by an 8- bit number in 2’s complement form is -128.
  • The sign bit is the most important bit.
  • 00000001 is +1, a number which is positive.
  • So, the range of 8-bit complement numbers of two is -128 to 127, since 128 is not representable (it would be 10000000, but the sign bit rule says that would be a negative number).
  • 10000000 is the most negative figure.
  • The leading 1 tells you it is negative, and you flip all the bits (011111111) to get the magnitude of the number, then add one (10000000 = 128).
  • So -128 is the resulting number.

Additional Information

  • The range of numbers that can be represented by n-bits in 2's complement form is
  • (-2)n-1 to (2n-1) -1
  • Hence, here the smallest number is (-2)7 = -128.

Question 102

In a single phase induction motor, the reason for having high resistance rotor is to achieve

  1. AOption (a)

    Reduced size

  2. BOption (b)

    Low starting torque

  3. COption (c)

    High efficiency

  4. DOption (d)

    High acceleration

View answer & explanation

Correct answer

Answer: (d)D.

High acceleration

Why this answer is correct

In a single phase induction motor, if the rotor resistance is high then the motor achieves quick acceleration and starting torque increases and this can be achieved by double squirrel cage induction motor.

Double squirrel-cage induction motor:

  • A double squirrel-cage induction motor has two parallel windings in the rotor

  • The rotor of a double squirrel cage motor has two independent cages on the same rotor

  • The figure below shows the cross-sectional diagram of a double squirrel cage rotor

  • Bars of high resistance and low reactance are placed in the outer cage, and bars of low resistance and high reactance are placed in the inner cage

  • The outer cage has a high ‘resistance to reactance ratio' whereas, the inner cage has a low 'resistance to reactance ratio'

  • The outer cage has a smaller cross-sectional area than the lower cage.

 

Important Points for double cage induction motor:

  • Higher starting torque
  • Outer cage increases cu loss due to high resistance
  • Inner cage reduces full load power factor
  • Efficiency reduces
  • Cost is higher

 

Application:

  • Rolling Mills
  • Cranes
  • Compressors
  • Conveyors
  • Reciprocating pumps

Question 103

BLDC motor is analogous to

  1. AOption (a)

    Permanent magnet synchronous motor

  2. BOption (b)

    DC motor

  3. COption (c)

    Rotating transformer

  4. DOption (d)

    Single phase induction motor

View answer & explanation

Correct answer

Answer: (a)A.

Permanent magnet synchronous motor

Why this answer is correct

Brushless DC motor:

  • A brushless DC motor is a permanent magnet synchronous electric motor which is driven by direct current (DC) electricity and it accomplishes electronically controlled commutation system instead of a mechanical commutation system
  • It has a permanent magnet rotor
  • Unlike conventional brushed type DC motor, wherein the brushes make the mechanical contact with a commutator on the rotor so as to form an electric path between a DC electric source and rotor armature windings, BLDC motor employs electrical commutation with permanent magnet rotor and a stator with a sequence of coils
  • In this motor, permanent magnet (or field poles) rotates and current-carrying conductors are fixed

 

Important Points

  • The torque-speed characteristics of BLDC motor are similar to the DC motor.
  • Three-phase induction motor is analogous to a rotating transformer.

Question 104

In a Squirrel cage rotor, the bars are NOT placed parallel to the shaft, but are skewed to have

  1. AOption (a)

    Greater mechanical strength

  2. BOption (b)

    Less rotor losses

  3. COption (c)

    Uniform torque

  4. DOption (d)

    None of the above

View answer & explanation

Correct answer

Answer: (c)C.

Uniform torque

Why this answer is correct

Skewing:

  • ​In the squirrel cage induction motor, the rotor slots in lamination or rotor core are not made parallel to the rotor shaft.
  • A slight angle is maintained between the rotor slots and the rotor shaft due to some operational advantages. This is called rotor skewing.
  • As the rotor slot of the induction motor skewed through some angle so that the bars lie under alternate harmonic poles of the same polarity.​

 

​The functions of skewed rotor slots in induction motor:

  • The skewed rotor slot increases the length of the copper bar thereby increases the resistance of the rotor bars hence starting torque of the machine can be improved and also the starting current is drawn by the machine can be reduced.
  • It makes the air gap flux distribution uniform thereby reduces harmonic torque produced by the machine.
  • As harmonic torque is reduced, the cogging or magnetic locking phenomenon due to harmonic torque can also be reduced. Here the magnetic locking tendency occurs when rotor teeth remain directly under stator teeth thus they might be magnetically locked.
  • And we can also eliminate a particular harmonic by selecting a proper skew angle.
  • The humming noise can be reduced.
  • To eliminate the nth harmonic the skew angle required is α = 3600/n electrical degrees = 720 / (n × P) mechanical degrees. Where P is the number of poles.

Question 105

The presence of a dominant 7th harmonics in the winding distribution of 3-phase, 6-pole, 50 Hz, induction motor may cause the motor to crawl at a speed of about

  1. AOption (a)

    750 rpm

  2. BOption (b)

    143 rpm

  3. COption (c)

    243 rpm

  4. DOption (d)

    500 rpm

View answer & explanation

Correct answer

Answer: (b)B.

143 rpm

Why this answer is correct

Concept:

Crawling:

  • The crawling in the induction motor is caused by harmonics developed in the motor.
  • Crawling is the tendency of particularly squirrel-cage rotor to run at speeds as low as one-seventh of their synchronous speed.
  • This phenomenon is known as the crawling of an induction motor.
  • When the no. of rotor slots is equal to the number of stator slots, the speed of all the harmonics by the stator slotting coincide with the speed of corresponding rotor harmonics.
  • Thus harmonics of every order would try to exert synchronous torques at their synchronous speeds and the machine would refuse to start. This is known as cogging or magnetic locking.
  • Therefore the no. of stator slots should never equal to the rotor slots.
  • Cogging can be easily overcome by making no. of rotor slots prime to no. of stator slots.

 

Calculation:

Given that, number of poles (P) = 6

Frequency (f) = 50 Hz

Synchronous speed Ns=120×506=1000;rpm{N_s} = \frac{{120 \times 50}}{6} = 1000;rpm

The dominant harmonics are 7th harmonics

Speed at crawl =17×Ns=10007=143;rpm = \frac{1}{7} \times {N_s} = \frac{{1000}}{7} = 143;rpm

Question 106

A synchronous motor installed at the receiving end substation operates with such an excitation that it takes power at lagging power factor. Now if the applied voltage of the synchronous motor goes down, the power factor of synchronous motor will

  1. AOption (a)

    Remain constant 

  2. BOption (b)

    Go down

  3. COption (c)

    Be improved 

  4. DOption (d)

    None of the above

View answer & explanation

Correct answer

Answer: (c)C.

Be improved 

Why this answer is correct

Concept:

Over Excited Synchronous Motor:

  • If DC field excitation of a synchronous motor is such that back EMF Eb is greater than applied voltage V, then the motor is said to be over-excited.
  • An over-excited synchronous motor draws leading current. Therefore, if the field of the synchronous motor is overexcited then its power factor will be leading.
  • An over-excited synchronous motor running at no load is known as the synchronous capacitor or synchronous condenser. Synchronous capacitors are always totally enclosed. The shaft does not extend beyond the case of the motor. They are used for correcting the power factor of a lagging load such as transformers and induction motors in an installation.
  • Power factor correction means raising the power factor of the load from its low value to a higher value. Some industrial loads run at very low power factors. It is advantageous to raise this power factor to unity or near about.
  • Synchronous motor is used as capacitor where load is so large that construction of a static capacitor is impractical
  • Any increase in power factor, increases supply capacity, efficiency and improves the operating characteristics of the system.
  • Synchronous capacitors cancel the lagging kVARs of the installation with their leading kVARs. They are usually connected in parallel with the incoming power lines to the plant.

 

Explanation:

If the synchronous motor takes power at lagging power factor that means it is delivering power at leading power factor and acts as synchronous condenser.

The synchronous condenser works at over-excited condition, so the back EMF will be greater than the terminal voltage.

Now if the applied voltage of the synchronous motor is decreased further, then the difference between the back EMF and the terminal voltage will be much more and the motor will deliver more leading power and therefore the power factor of the synchronous motor will improve.

Question 107

Slip of an induction motor increases with

  1. AOption (a)

    Increase in current and decrease in torque

  2. BOption (b)

    Increase in current and torque

  3. COption (c)

    decrease in current and torque

  4. DOption (d)

    decrease in current and increase in torque

View answer & explanation

Correct answer

Answer: (b)B.

Increase in current and torque

Why this answer is correct

The torque equation of the three-phase induction motor is given as

T=32πNssE22R22+(sX2)2T = \frac{3}{{2\pi {N_s}}}\frac{{sE_2^2}}{{R_2^2 + {{(s{X_2})}^2}}}

Rotor current I2=sE2Z2{I_2} = \frac{{s{E_2}}}{{{Z_2}}}

Ns = speed of the motor

s = slip of the motor

R2 = rotor resistance

X2 = rotor reactance

E2 = rotor induced emf

From the torque equation, we can say that the slip is directly proportional to the torque and the synchronous speed of the motor.

From the current expression, slip is also directly proportional to the rotor current.

So, the Slip of an induction motor increases with an increase in current and torque

Question 108

The slip of an induction motor normally does not depend on: 

  1. AOption (a)

    Rotor speed 

  2. BOption (b)

    Synchronous speed

  3. COption (c)

    Shaft torque

  4. DOption (d)

    Core-loss component

View answer & explanation

Correct answer

Answer: (d)D.

Core-loss component

Why this answer is correct

The slip of an induction motor is given by,

s=Ns−NrNs×100s = \frac{{{N_s} - {N_r}}}{{{N_s}}} \times 100

It directly depends on rotor speed and synchronous speed. It is indirectly depends on shaft torque but it is independent of core loss component.

Question 109

A precise phase control for an A.C. load can be controlled by a (an)

  1. AOption (a)

    Triac

  2. BOption (b)

    SCR

  3. COption (c)

    Transformer

  4. DOption (d)

    Trigger pulse

View answer & explanation

Correct answer

Answer: (a)A.

Triac

Why this answer is correct

Explanation:

  • TRIAC (Triode for AC) is the semiconductor device widely used in power control and switching applications.
  • It finds applications in switching, phase control, chopper designs, brilliance control in lamps, speed control of motors, etc.

 

Important Points

  • TRIAC is used in the domestic fan speed control circuits.
  • In the TRIAC based electronic fan regulator circuit, the main components used are a resistor, capacitor, DIAC, and TRIAC.
  • TRIAC is directly used to control the speed by holding and releasing the current flow.

 

Additional Information

TRIAC:

  • A TRIAC is equivalent to two SCRs joined together in parallel; It has two main terminal and one gate
  • In the TRIACs, there will be single gate control conduction in both the directions
  • It is a bidirectional device and in both the directions it will conduct
  • It is available in high voltage ratings
  • TRIAC is a four-layer device

Question 110

UJT is known as

  1. AOption (a)

    Voltage-controlled device

  2. BOption (b)

    Current-controlled device

  3. COption (c)

    Relaxation oscillator

  4. DOption (d)

    A transistor

View answer & explanation

Correct answer

Answer: (c)C.

Relaxation oscillator

Why this answer is correct

Uni Junction Transistor (UJT):

  • The uni-junction transistor is a solid-state three-terminal device that can be used in gate pulse, timing circuits, and trigger generator applications to switch and control both thyristors and triacs for AC power control type applications.

  • When a UJT is used for triggering an SCR, the wave shape of the voltage obtained from the UJT circuit is a saw-tooth wave.

  • The UJT is a three-terminal, semiconductor device which exhibits negative resistance and switching characteristics for use as a relaxation oscillator in phase control applications.

 

Applications of UJT:

  • Uses negative oscillator resistance property for the generation of the sawtooth waveform
  • Used as a Relaxation oscillator.
  • Used as a Voltage regulator.
  • Used as a switching circuit.
  • Widely used as a triggering device for silicon control rectifiers (SCR).
  • Used as a phase control circuit.
  • Used as a timing circuit.
  • Used in a sawtooth generator.
  • Used to generate magnetic flux.

Question 111

In a step-up chopper, if Vs is the source voltage and α is duty cycle, then the output voltage is

  1. AOption (a)

    Vs/(1 + α)

  2. BOption (b)

    Vs(1 + α)

  3. COption (c)

    Vs(1 - α)

  4. DOption (d)

    Vs/(1 - α)

View answer & explanation

Correct answer

Answer: (d)D.

Vs/(1 - α)

Why this answer is correct

Explanation:

The circuit diagram of a boost converter is shown below.

Step Up or Boost converter is used to obtain the output voltage greater than the input voltage.

The relation between the output voltage and the input voltage is given by

Vo=Vs1−αVo=\frac{{{V}_{s}}}{1-α}

Where α is the duty cycle of the chopper. 

Additional Information

ConverterCircuit diagramOutput voltage
Buck converterVo = δ Vin
Boost converterVo=Vin1−δ{V_o} = \frac{{{V_{in}}}}{{1 - \delta }}
Buck-Boost converterVo=−δ1−δVin{V_o} = - \frac{\delta }{{1 - \delta }}{V_{in}}
Cuk converterVo=−δ1−δVin{V_o} = - \frac{\delta }{{1 - \delta }}{V_{in}}

Question 112

A modern power semi-conductor device that combines the characteristics of both BJT and MOSFET

  1. AOption (a)

    GTO

  2. BOption (b)

    FCT

  3. COption (c)

    IGBT

  4. DOption (d)

    MCT

View answer & explanation

Correct answer

Answer: (c)C.

IGBT

Why this answer is correct

Insulated Gate Bipolar Transistor (IGBT):  It is a three-terminal power semiconductor device primarily used as an electronic switch. It is a 4 layer PNPN device that combines an insulated gate N-channel MOSFET input with a PNP BJT output in a type of Darlington configuration.

​Insulated gate Bipolar Transistor is also known as Conductivity-Modulated Field Effect Transistor.

The IGBT is developed by combining the characteristics of a BJT and a MOSFET.

Advantages:

  • The insulated gate bipolar transistor (IGBT) is easy to turn ON and OFF.
  • The switching frequency is higher than that of power BJT.
  • It has a low on state power dissipation.
  • It has simpler driver circuit.

 

Disadvantages:

  • The switching frequency of insulated gate bipolar transistor (IGBT) is not as high as that of a power MOSFET.
  • High turn-off time
  • It cannot block high reverse voltages.

 

Important Points

BJTMOSFETIGBT
Bipolar deviceUnipolar deviceThe bipolar device, Three terminal device (emitter-collector and gate)
Low input impedanceHigh input impedanceHigh input impedance
Current controlled deviceVoltage-controlled deviceVoltage-controlled device
Low on-state voltage drop and low conduction lossHigh on-state voltage drop and higher conduction lossLow forward voltage drop, low ON state power loss than MOSFET, low conduction loss than MOSFET
Secondary breakdown occursFree from the secondary breakdownThe secondary breakdown does not occur
Negative temperature coefficientPositive temperature coefficientPositive temperature coefficient
Not advisable for parallel operationadvisable for parallel operationUsed for parallel operation
Lower operating frequency(10kHz)higher operating frequency(100kHz)
On state in the saturation regionOn state in the ohmic region
Controlled turn on and turn off the deviceControl turn on and turn off the deviceControlled turn on and turn off the device
Turn on and turn off time depend on junction capacitanceSmaller turn off time
Controlled signal requirement continuouslyControlled signal requirement continuouslyControlled signal requirement continuously

Question 113

In a single phase full wave converter (M-2 connection) feeding a highly inductive load, the firing angle for each thyristor is ‘a’ in the respective half cycle. This period of conduction of each thyristor is

  1. AOption (a)

    π – a

  2. BOption (b)

    π

  3. COption (c)

    π + a

  4. DOption (d)

    π – 2a

View answer & explanation

Correct answer

Answer: (b)B.

π

Why this answer is correct

Single-phase full-wave Controlled Bridge Rectifier:

Circuit diagram:

For the first half cycle of supply voltage, T1 will start conduction at firing angle 'a' and will conduct up to (π + a).

The load is highly inductive, therefore the current is continuous and the second thyristor T2 is triggered at (π + a) which conducts up to (2π + a).

The conduction period of each thyristor = [(2π + a) - (π + a)] = π

Waveforms:

Additional Information

The average value of the output voltage is given by

V0=2Vmπcos⁡α{V_0} = \frac{{2{V_m}}}{π }\cos α

Where,

V0 is the average output voltage

Vm is the maximum input voltage

α is the firing angle or conduction angle

When a = 180° (conduction angle is 180°)

V0=2Vmπcos⁡180°{V_0} = \frac{{2{V_m}}}{π }\cos180°

V0=−2Vmπ{V_0} = \frac{{-2{V_m}}}{π }

Therefore, at 180° firing angle we get, minimum output voltage in the single-phase full converter circuit

When a = 0° (conduction angle is 0°)

V0=2Vmπcos⁡0°{V_0} = \frac{{2{V_m}}}{π }\cos0°

V0=2Vmπ{V_0} = \frac{{2{V_m}}}{π }

Therefore, at 0° firing angle, we get maximum output voltage in the single-phase full converter circuit.

Question 114

In a 3-phase voltage source inverter used for speed control of induction motor anti parallel diodes are used across each switching device as shown in figure. The main purpose of diodes is to

  1. AOption (a)

    Protect the switching device against over voltage

  2. BOption (b)

    Provide the path for free wheeling current

  3. COption (c)

    Allow the motor to return energy during regeneration

  4. DOption (d)

    Help in switching off the devices

View answer & explanation

Correct answer

Answer: (c)C.

Allow the motor to return energy during regeneration

Why this answer is correct

Concept:

  • In a 3-phase voltage source inverter used for speed control of induction motor, anti-parallel diodes are used across each switching device.
  • The main purpose of diodes is to allow the motor to return energy during regeneration.
  • In regenerative braking, the motor, instead of being disconnected from the supply, remains connected to the supply and returns the braking energy to the supply line.
  • VSI fed IM drive has a voltage source inverter at the machine end and a six-pulse converter at the source end.
  • When the induction machine is motoring, the source end converter operates as a rectifier, and the machine end converter operates as an inverter.
  • With a single 6 pulse converter at the input side, regeneration is not possible since the electrolytic capacitor does not allow reversal of the voltage Polarity and the SCRs do not allow the reversal of currents.

 

Explanation:

  • Regeneration is possible by having an antiparallel 6 pulse converter at the input side.
  • When regeneration takes place, firing pulses to the converter 1 are stopped and firing pulses are given to machine end converter such that it operates as an inverter.
  • The motor operates as an induction generator since it converts the mechanical power into electrical power.
  • The diode rectifier part of VSI converts AC to DC.
  • Converter II converts DC power into AC power and is fed to the AC mains.
  • The disadvantage being that an additional six-pulse converter is required for regeneration.

Question 115

Consider the following statements related to induction motor drives:

  1. Power to weight ratio is high.
  2. Suitable for operation at high voltage.
  3. Suitable for high speed operation.
  4. Power converter is simple and economical.
  5. Speed control is easy and of low cost.
  6. Reliability is good.

Out of these statements

  1. AOption (a)

    1, 2, 4 and 6 are correct

  2. BOption (b)

    2, 3, 5 and 6 are correct

  3. COption (c)

    1, 2, 3 and 5 are correct

  4. DOption (d)

    1, 2, 3 and 6 are correct

View answer & explanation

Correct answer

Answer: (d)D.

1, 2, 3 and 6 are correct

Why this answer is correct

Advantages of Induction Motor:

  • Construction is quite simple in nature.
  • Induction motor is Robust and mechanically strong, so working of the motor is independent of the environmental condition.
  • A Squirrel cage induction motor does not contain Brushes, Slip rings, and Commutators. Due to this reason, the cost of the motor is quite low and also the power to weight ratio is high.
  • However, Slip Rings are used in Wound type induction motor to add external resistance to the rotor winding.
  • Due to the absence of Brushes, there are no sparks in the motor. It can also be operated in hazardous conditions.
  • Unlike synchronous motors, a 3-phase induction motor has a high starting torque, good speed regulation, and reasonable overload capacity.
  • An induction motor is a highly efficient machine with full load efficiency varying from 85 to 97 percent, reliability is good and suitable to operate at high voltages.

​

Disadvantages of Induction Motor:

  • A single-phase induction motor, unlike a 3 phase induction motor, does not have a self-starting torque. Auxiliaries are required to start a single-phase motor.
  • During light load conditions, the power factor of the motor drops to a very low value. This is because, during the start, the motor draws a large magnetizing current to overcome the reluctance offered by the air gap between the Stator and the Rotor.
  • Due to the high magnetizing current, the copper losses of the motor increase. This in turn leads to a decrease in the efficiency of the motor.
  • Speed control of an induction motor is very difficult to attain. This is because a 3 phase induction motor is a constant speed motor and for the entire loading range, the change in the speed of the motor is very low. The power converter is complex and expensive.
  • Induction motors have high input surge currents, which are referred to as Magnetizing Inrush currents. This causes a reduction in voltage at the time of starting the motor.
  • Due to poor starting torque, the motor cannot be used for applications that require high starting torque.

Question 116

In constant V/F speed control of a 3-phase induction motor, if frequency is increased from low value to the rated value, the maximum torque (Tmax) and slip corresponding to the maximum torque (Sm) varies as

  1. AOption (a)

    Tmax increases, Sm decreases

  2. BOption (b)

    Tmax increases, Sm increases

  3. COption (c)

    Tmax constant, Sm decreases

  4. DOption (d)

    Tmax constant, Sm increases

View answer & explanation

Correct answer

Answer: (c)C.

Tmax constant, Sm decreases

Why this answer is correct

Concept:

(V / f) control or frequency control method: 

It is basically frequency control but to maintain Bmax constant

The frequency variations should be done by keeping the (V / f) ratio constant.

The synchronous speed of the induction motor in rpm is

NS=120fP{N_S} = \frac{{120f}}{P} rpm 

NS ∝ f

NS = Synchronous speed

f = Frequency

P = No. of poles

Torque produced in the motor is

T=3×602πNS×sE22R2R22+(sX2)2T = \frac{{3 \times 60}}{{2\pi {N_S}}} \times \frac{{sE_2^2{R_2}}}{{R_2^2 + {{\left( {s{X_2}} \right)}^2}}}

E2 = Rotor induced emf

R2 = Rotor resistance

X2 = Rotor reactance

s = slip      

Eph=4.44ϕnf;;{E_{ph}} = 4.44\phi nf;;

E∝V ϕ∝Bmax∝Vf\begin{array}{l} E ∝ V\ \phi ∝ {B_{max}} ∝ \frac{V}{f} \end{array}

The Torque - Speed characteristics:

Explanation:

From the above characteristics, Let motor runs at speed of Ns0 at a frequency of fo with a slip of Sm0.

Let at frequency f1 < f0, the speed of the motor reduced with Ns1 and slip increased from sm0 to sm1.

Now at frequency f2 > f0, the speed of the motor increases with the synchronous speed of Ns2, and slip decreases from sm0 to sm2.

∴ The slip is inversely proportional to the frequency applied to the motor.

The slip corresponding to the maximum torque decreases with an increase in frequency and the maximum torque remains constant for different values of slip.

Question 117

The drive has following equations of motor and load torque in terms of speed

T=2ω+2,;TL=4/ω;T = \frac{2}{\omega } + 2,;{T_L} = 4/{\rm{\omega }};

The equilibrium point is

  1. AOption (a)

    Unstable

  2. BOption (b)

    Stable

  3. COption (c)

    Marginally stable

  4. DOption (d)

    Nothing can be said

View answer & explanation

Correct answer

Answer: (a)A.

Unstable

Why this answer is correct

Concept:

When the motor is operating at the equilibrium point, consider the following two cases to state the stability of that equilibrium point

When speed is increased:

  • If the TL is more than Te then the TL dominated Te and rotor comes back to its initial speed, the motor operates in stable mode.
  • If the Te is more than TL, in this case, Te dominates TL, and speed further increases and the motor becomes unstable.​

​

When speed is decreased:

  • If the TL is more than Te then the TL dominated Te and rotor speed further decreases and the motor becomes unstable.
  • If the Te is more than TL, in this case, Te dominates TL, and comes back to its initial speed, the motor operates in stable mode.

​

Application:

Given,

Electromagnetic torque of the motor Te=2ω+2T_e = \frac{2}{ω } + 2

Load torque TL=4ω{T_L} = \frac{{4}}{{ω}}

At the equilibrium point load torque is equal to the electromagnetic torque.

TL = Te

4ω=2ω+2\frac{{4}}{{ω}}= \frac{2}{ω } + 2

ω = 1 rad/sec

Consider ω = 2, then TL = 2, Te = 3

In this case, Te is more than TL so motor speed increases further and the motor becomes unstable.

Consider ω = 0.5, then TL = 8, Te = 6

In this case, TL is more than Te so motor speed further reduces and the motor becomes unstable.

At the equilibrium point of the two torque curves, either increase in speed or a decrease in speed leads to the unstable operation of the motor.

So the equilibrium point of the two curves is unstable.

Question 118

In a non-circulating current mode dual converters, the circulating current is avoided by

  1. AOption (a)

    Connecting a series reactor

  2. BOption (b)

    Maintaining α1 + α2 = 180°

  3. COption (c)

    Operating only one converter

  4. DOption (d)

    Adding an extra SCR

View answer & explanation

Correct answer

Answer: (c)C.

Operating only one converter

Why this answer is correct

Explanation:

  • Dual converter, the name itself says two converters. It is really an electronic converter or circuit which comprises of two converters. One will perform as a rectifier and the other will perform as an inverter. Therefore, we can say that double processes will occur at a moment.
  • In this, the circulating current allows smooth reversal of load current with improved speed of response. The circulating current helps in maintaining continuous conduction of both the converters irrespective of load and the time response to change the operation from one quadrant to other is faster.

Modes of Operation of Dual Converter:

There are two functional modes: Non-circulating current mode and circulating mode.

Circulating Current Mode:

  • Two converters will be in the ON condition at the same time. So, the circulating current is present.
  • The firing angles are adjusted such that the firing angle of converter 1 (α1) + firing angle of converter 2 (α2) = 180o.
  • Converter 1 performs as a controlled rectifier when firing angle be 0 < α1 < 90o and Converter 2 performs as an inverter when the firing angle be 90o < α2 < 180o. In this condition, Vdc and Idc are positive.
  • Converter 1 performs as an inverter when firing angle be 90o < α1 < 180o and Converter 2 performs as a controlled rectifier when the firing angle be 0 < α2 < 90o in this condition, Vdc and Idc are negative.

Non-Circulating Current Mode:

  • The circulating current does exist in both the converter circuits, but it is avoided by using a reactor in non-circulating type and by operating only one circuit in case of circulating type.
  • During the converter 1 operation, firing angle (α1) will be 0 < α1 < 90o; Vdc and Idc are positive.
  • During the converter 2 operation, firing angle (α2) will be 0 < α2 < 90o; Vdc and Idc are negative.

Conclusion:

  • In a non-circulating dual converter - One converter is operated at a time.
  • In circulating current dual converter - reactor + maintaining α1 + α2 = 180°

Question 119

An SCR is made up of silicon because

  1. AOption (a)

    Silicon has large leakage current than germanium

  2. BOption (b)

    Silicon has small leakage current than germanium

  3. COption (c)

    Silicon has small leakage voltage than germanium

  4. DOption (d)

    Silicon has large leakage voltage than germanium

View answer & explanation

Correct answer

Answer: (b)B.

Silicon has small leakage current than germanium

Why this answer is correct

An SCR is made up of silicon because Silicon has a small leakage current than Germanium.

A Silicon Controlled Rectifier (SCR) is a 3 terminal and 4 layer semiconductor current controlling device. It is mainly used in devices for the control of high power.

SCR has three operating modes.

Forward blocking mode:

  • Anode voltage is made positive with respect to the cathode, with the gate circuit open
  • Both outer junctions are forward biased
  • The inner junction is reversed biased
  • SCR remains in the off state

Forward conduction mode:

  • Anode voltage is greater than the forward break over voltage
  • All three junction is forward biased
  • The device is in conduction mode

 

Reverse blocking mode:

  • The cathode is at a higher potential than the anode
  • Both outer junctions are reverse biased (high resistance)
  • The inner (middle) junction is forward biased.
  • It is reversed biased and non-conducting

 

The forward and reverse characteristic of an SCR is as shown:

Question 120

For an application which requires smooth and precise control over the wide range at low cost, the motor preferred is

  1. AOption (a)

    Squirrel cage induction motor

  2. BOption (b)

    Synchronous motor

  3. COption (c)

    D.C. motor

  4. DOption (d)

    Wound rotor induction motor

View answer & explanation

Correct answer

Answer: (c)C.

D.C. motor

Why this answer is correct

For an application that requires smooth and precise speed control over the wide range, the DC motor is preferred.

  • A DC motor is any of a class of rotary electrical machines that converts direct current electrical energy into mechanical energy.
  • Controlling the speed of DC motors is a crucial matter since different machines and equipment have different aspects and output speed or torque requirements in which prospect.
  • Speed Control may require to be very precise and over wide ranges as well.

 

Generally, the rotational speed of a DC motor is proportional to the voltage applied to it, and the torque is proportional to the current. Speed control can be achieved by variable battery tapings, variable supply voltage, resistors, or electronic controls. The direction of a wound field DC motor can be changed by reversing either the field or armature connections but not both. This is commonly done with a special set of contactors (direction contactors). The effective voltage can be varied by inserting a series resistor or by an electronically controlled switching device made of thyristors, transistors or, formerly, mercury arc rectifiers.

Speed control over a wide range both above and below the rated speed:

The attractive feature of the dc motor is that it offers a wide range of speed control both above and below the rated speeds. This can be achieved in dc shunt motors by methods such as armature control method and field control method. This is one of the main applications in which dc motors are widely used in fine speed applications such as in rolling mills and in paper mills.

High starting torque:

DC series motors are termed as best suited drives for electrical traction applications used for driving heavy loads in starting conditions. DC series motors will have a starting torque as high as 500% compared to normal operating torque. Therefore dc series motors are used in the applications such as in electric trains and cranes.

Accurate steep less speed with constant torque:

Constant torque drives are one such drive that will have motor shaft torque constant over a given speed range. In such drives, shaft power varies with speed.

  • Quick starting, stopping, reversing and acceleration
  • Free from harmonics, reactive power consumption and many factors which makes dc motors more advantageous compared to ac induction motors.
  • Smooth and precise speed control over the wide range

Question 121

In adjustable frequency 3-phase induction motor drives, for constant power application the slip speed is kept

  1. AOption (a)

    Constant

  2. BOption (b)

    Proportional to synchronous speed

  3. COption (c)

    Inversely proportional to synchronous speed

  4. DOption (d)

    Proportional to square of synchronous speed

View answer & explanation

Correct answer

Answer: (a)A.

Constant

Why this answer is correct

Concept:

In a 3-phase induction motor, the synchronous speed can be calculated as

Ns=;120fP{N_s} = ;\frac{{120f}}{P}

s=;Ns−NrNss = ;\frac{{{N_s} - {N_r}}}{{{N_s}}}

Where, Ns = Synchronous speed in rpm,

Nr = Rotor speed in rpm,

s = Slip of the machine,

f = Supply frequency in Hz,

P = Number of poles.

Slip speed: The difference between the synchronous speed and the actual speed of the rotor is known as the slip speed.

Slip speed sNs = Ns - Nr

Explanation:

In adjustable frequency 3-phase induction motor drives, the induction motor is supplied by a dedicated generator so that frequency can be easily varied by changing the speed of prime mover and for constant power application, the slip speed is kept constant.

At a frequency f1 we got a field speed of Ns1 then by performing the experiment we find out the rotor speed Nr1 of the motor then we will calculate the slip s1.

Slip speed = s1Ns1

Now when the frequency is changed to f2 then the field speed changes to Ns2 then by keeping the slip speed constant we can calculate theoretically the rotor speed Nr2 at which the motor can rotate for that particular frequency f2 as shown

s1Ns1 = Ns2 - Nr2

Nr2 = Ns2 - s1Ns1

Also, s1Ns1 = s2Ns2 = constant

Question 122

The output of a logic gate is "1" when all its input are at logic "0". The gate is either

  1. AOption (a)

    a NAND gate or an EX-OR gate

  2. BOption (b)

    a NOR gate or an EX-OR gate

  3. COption (c)

    an AND gate or an EX-NOR gate

  4. DOption (d)

    a NOR gate or an EX-NOR gate

View answer & explanation

Correct answer

Answer: (d)D.

a NOR gate or an EX-NOR gate

Why this answer is correct

NOT GATE

 

Symbol:

Truth Table:

Input (A)Output (A̅)
0 (Low)1 (High)
1 (High)0 (low)

 

Output Equation: Y = A̅

Key Points: The output of NOT gate is an invert of the input

AND GATE

Symbol:

Truth Table:

Input AInput BOutput Y = A.B
000
010
100
111

 

Output Equation: Y = A.B

Key Points: The output is high only when both the inputs are high

OR GATE

Symbol:

Truth Table:

Input AInput BOutput Y = A + B
000
011
101
111

 

Output Equation: Y = A + B

Key Points: The output is low only when both the inputs are low

NAND GATE

Symbol:

Truth Table:

Input AInput BOutput Y=AB‾Y = \overline {AB}
001
011
101
110

 

Output Equation: Y=A.B‾=Aˉ+BˉY = \overline {A.B} = \bar A + \bar B

Key Points:

1) The output is low only when both the inputs are high

2) It is a universal gate

NOR GATE

Symbol:

Truth Table:

Input AInput BOutput Y=(A+B)‾Y = \overline {\left( {A + B} \right)}
001
010
100
110

 

Output Equation: Y=A+B‾=Aˉ.BˉY = \overline {A + B} = \bar A.\bar B

Key Points:

1) The output is high only when both the inputs are low

2) It is a universal gate

XOR GATE

Symbol:

Truth Table:

Input AInput BOutput Y = A ⊕ B
000
011
101
110

 

Output Equation: Y=A⊕B=AˉB+ABˉY = {\bf{A}} \oplus {\bf{B}} = \bar AB + A\bar B

Key Points:

1) The output is low when both the inputs are the same

2) The output is high when both the inputs are different

XNOR GATE

Symbol:

Truth Table:

Input AInput BOutput Y = AB
001
010
100
111

 

Output Equation: Y=A⊕B‾=A⊙B=AB+AˉBˉY = \overline {{\bf{A}} \oplus {\bf{B}}} = A \odot B = AB + \bar A\bar B

Key Points:

1) The output is high when both the inputs are the same

2) The output is low when both the inputs are different

∴ The correct combination is the NOR gate and EX-NOR gate. 

Note: 

For NAND and NOT gate also the output is logic 1, when all inputs are 0.

Question 123

Hamming code is capable of

  1. AOption (a)

    Only detects single bit error

  2. BOption (b)

    Only corrects single bit error

  3. COption (c)

    Detects and corrects single bit error

  4. DOption (d)

    None of the above

View answer & explanation

Correct answer

Answer: (c)C.

Detects and corrects single bit error

Why this answer is correct

​​Hamming code:

Hamming codes are linear block codes. The family of (n, k) hamming codes for q ≥ 3 is defined by the following expressions:

  1. Number of Block diagrams (n) = 2q – 1
  2. Number of message bits (k) = 2q – q – 1
  3. Number of Parity bits (q) = (n – k)

Hamming code is a set of error-correction codes that can be used to detect and correct '1' bit errors that can occur when bit stream are sent through channel. It can be employed in both burst and signal error correction

Error detecting code:

  • An error occurs when, it is altered between transmission and reception (1 is transmitted and 0 is received, and vice versa)
  • For reliable communication, errors must be detected and corrected.
  • Error detection means deciding whether the received data is correct or not without having a copy of the original message.
  • Error detection and correction uses the concept of redundancy, which means adding extra bits for detecting errors at the destination.
  • These redundant bits are added by the sender and removed by the receiver.
  • The error detection methods include:

1). VRC (Vertical Redundancy Check): It is an error-detecting code commonly used in digital networks and storage devices to detect an error in data sent by the sender.

2). LRC (Longitudinal Redundancy Check): It is an error-checking method used on an eight-bit ASCII character

3). CRC (Cyclic Redundancy Check)

4). Checksum

Question 124

D flip flop can be made from a J-K flip flop by making

  1. AOption (a)

    J = K

  2. BOption (b)

    J = K = 1

  3. COption (c)

    J = 0, K = 1

  4. DOption (d)

    J = K̅

View answer & explanation

Correct answer

Answer: (d)D.

J = K̅

Why this answer is correct

D flip flop:

D flip flop has only one input terminal. The output of the D flip flop will be the same as the input. Hence, it is used in delay circuits.

The circuit is as shown below.

Logic symbol:

Truth table:

DQn (Present state)Qn+1 (Next state)
000
010
101
111

 

Characteristic equation: Qn+1 = D

The D flip flop may be obtained from an S-R flip flop by just putting one inverter between the S and R as shown in the figure below.

S = R̅

The D flip flop may be obtained from a J-K flip flop by just putting one inverter between the J and K as shown in the figure below.

K = J̅

T flip flop:

T flip flop has only one input terminal. The output of the T flip flop will be toggled when the input is high on every new clock pulse. The output will be the same as the previous state when the input is low.

The circuit is as shown below.

Logic symbol:

Truth table:

TQn (Present state)Qn+1 (Next state)
000
011
101
110

 

Characteristic equation: Qn+1 = TQ̅­n + T̅Qn

The T flip flop may be obtained from a J-K flip flop by making both the inputs are the same i.e. J = K.

Question 125

The complement of [(A⋅B‾+C‾)⋅D+E‾]⋅F[(A \cdot \overline B + \overline C)\cdot D + \overline E]\cdot F is

  1. AOption (a)

    (A⋅B‾)⋅C‾+D⋅E‾]+F(A \cdot \overline B) \cdot \overline C + D \cdot \overline E]+F

  2. BOption (b)

    (A‾+B)⋅C‾+D⋅E‾]⋅F(\overline A + B) \cdot \overline C + D \cdot \overline E]\cdot F

  3. COption (c)

    (A‾+B)⋅C+D‾]⋅E+F‾(\overline A + B) \cdot C + \overline D] \cdot E + \overline F

  4. DOption (d)

    (A+B‾)⋅C+D‾]⋅E‾+F( A + \overline B) \cdot C + \overline D] \cdot \overline E +F

View answer & explanation

Correct answer

Answer: (c)C.

(A‾+B)⋅C+D‾]⋅E+F‾(\overline A + B) \cdot C + \overline D] \cdot E + \overline F

Why this answer is correct

Concept:

The complement of a Boolean expression is formed by:

  • Complementing each literal
  • Replace “.” By “ + ” and vice versa
  • Replace 0’s by 1’s and 1’s by 0’s

 

Application:

The given Boolean expression is [(A.Bˉ;+Cˉ).;D+Eˉ].;F;\left[ {\left( {A.\bar B; + \bar C} \right).;D + \bar E} \right].;F;

The complement is [(Aˉ+B).C+Dˉ].E+Fˉ;\left[ {\left( {\bar A + B} \right).C + \bar D} \right].E + \bar F;

125 questions in the full paper