What is the solution of the following equations ?
2x + 3y = 12 and 3x − 2y = 5
- ((a))
x = 3, y = 2
- ((b))
x = 2, y = 3
- ((c))
x = −2, y = 3
- ((d))
x = 3, y = −2
Show Answer
x = 3, y = 2

Shortcut Trick
The fastest way to solve systems of linear equations is to verify the given options.
Check Option (1): x = 3, y = 2
In 2x + 3y = 12: 2(3) + 3(2) = 6 + 6 = 12 (Satisfied)
In 3x − 2y = 5: 3(3) − 2(2) = 9 − 4 = 5 (Satisfied)
Since both equations are satisfied, Option (1) is the correct solution.
∴ The correct answer is x = 3, y = 2.

Alternate Method
Given Equations:
2x + 3y = 12 ... (i)
3x − 2y = 5 ... (ii)
Method Used: Elimination Method
⇒ To eliminate y, multiply equation (i) by 2 and equation (ii) by 3:
⇒ 2 × (2x + 3y = 12) → 4x + 6y = 24 ... (iii)
⇒ 3 × (3x − 2y = 5) → 9x − 6y = 15 ... (iv)
⇒ Add equations (iii) and (iv):
⇒ (4x + 9x) + (6y − 6y) = 24 + 15
⇒ 13x = 39
⇒ x = 39 ÷ 13 = 3
⇒ Substitute x = 3 into equation (i):
⇒ 2(3) + 3y = 12
⇒ 6 + 3y = 12
⇒ 3y = 12 − 6 = 6
⇒ y = 6 ÷ 3 = 2
∴ The correct answer is x = 3, y = 2.

Additional Information
Nature of Solutions for a1x + b1y = c1 and a2x + b2y = c2
A unique solution exists if a1/a2 ≠ b1/b2. No solution exists if a1/a2 = b1/b2 ≠ c1/c2 (parallel lines). Infinite solutions exist if a1/a2 = b1/b2 = c1/c2 (coincident lines).
Cramer's Rule
For a system of equations, x = Dx/D and y = Dy/D, where D is the determinant of coefficients and Dx, Dy are determinants replaced by constants.
Substitution Method
Solve one equation for one variable (e.g., x = (12 − 3y)/2) and substitute it into the other equation to find the value of the second variable.


















































































