Given:
The capsule is shaped like a cylinder with two hemispheres attached to each end.
Length of the entire capsule = 15 mm
Diameter of the capsule = 6 mm
Radius of the capsule (r) = Diameter / 2 = 6 / 2 = 3 mm
π = 22/7
Formula used:
The total surface area (SA) of the capsule consists of three parts:
The surface area of the cylindrical part (excluding the hemispherical ends): 2πr × h
The surface area of the two hemispheres (together): 4πr²
Where h is the height of the cylindrical part.
The height of the cylindrical part (h) is the total length minus the two radii (one for each hemisphere):
h = 15 - 2r = 15 - 2 × 3 = 9 mm
Calculation:

The surface area of the cylindrical part:
SAcylinder = 2πr × h = 2 × (22/7) × 3 × 9 = 2 × (22/7) × 27 = 2 × (594/7) = 1188 / 7 ≈ 169.71 mm²
The surface area of the two hemispheres:
SAhemispheres = 4πr² = 4 × (22/7) × 3² = 4 × (22/7) × 9 = 4 × (198/7) = 792 / 7 ≈ 113.14 mm²
The total surface area of the capsule is the sum of the areas of the cylindrical part and the two hemispheres:
Total SA = 169.71 + 113.14 ≈ 282.85 mm² ≈ 282mm2.
∴ The correct answer is option 2.