Shortcut Trick
In ΔPQR, the sum of all angles is always 180°.
∠QPR = 180° − (60° + 80°) = 40°
The angle subtended by an arc at the centre is twice the angle subtended by it at any point on the remaining part of the circle.
Angle at centre subtended by arc QR = 2 × 40° = 80°.
∴ The correct answer is 80°.
Alternate Method
O
P
Q
R
40°
60°
80°
80°
Given:
Points P, Q, and R lie on the circle with centre O.
∠PQR = 60° and ∠QRP = 80°
Formula Used:
Sum of all interior angles of a triangle is always 180°.
The angle subtended by an arc at the centre is double the angle subtended by it at any remaining part of the circle.
Calculations:
In ΔPQR, the sum of all interior angles is 180°.
⇒ ∠PQR + ∠QRP + ∠QPR = 180°
⇒ 60° + 80° + ∠QPR = 180°
⇒ 140° + ∠QPR = 180°
⇒ ∠QPR = 180° − 140°
⇒ ∠QPR = 40°
Now, arc QR subtends ∠QPR at the circumference and ∠QOR at the centre.
Using the circle property, the central angle is twice the inscribed angle.
⇒ ∠QOR = 2 × ∠QPR
⇒ ∠QOR = 2 × 40°
⇒ ∠QOR = 80°
∴ The correct answer is 80°.
Additional Information
Angle Subtended by an Arc
The angle subtended by an arc at the centre is strictly double the angle subtended by it at any point on the remaining part of the circle.
Angles in the Same Segment
Angles subtended by the same arc at any point on the alternate segment of the circle are always equal to each other.
Angle in a Semicircle
The angle subtended by a diameter at any point on the circumference of the circle is always a right angle (90°).
Cyclic Quadrilateral Property
If a quadrilateral is inscribed inside a circle, the sum of its opposite angles is always exactly 180°.