Shortcut Trick
Since PQ || AC, triangle PBQ is similar to triangle ABC.
The ratio of areas of similar triangles is equal to the square of the ratio of their corresponding sides.
Area(ABC) : Area(PBQ) = 3 : 1 ⇒ BC2 : BQ2 = 3 : 1 ⇒ BC : BQ = √3 : 1.
We need CB : CQ = CB : (CB − BQ) = √3 : (√3 − 1).
Multiply by conjugate (√3 + 1): √3(√3 + 1) : (√3 − 1)(√3 + 1) = √3(√3 + 1) : (3 − 1).
∴ The correct answer is √3(√3 + 1) : 2.
Alternate Method
Given:
Area of ΔABC : Area of ΔPBQ = 3 : 1
Calculation:
Area of ΔABC / Area of ΔPBQ = 3/1
⇒ CB/BQ = √3/√1 = √3/1
Let CB = √3x and BQ = x
⇒ CQ = CB − BQ
⇒ CQ = √3x − x = (√3 − 1)x
⇒ CB/CQ = √3x / (√3 − 1)x
⇒ CB/CQ = √3 / (√3 − 1)
⇒ CB/CQ = [√3(√3 + 1)] / [(3 − 1)]
⇒ CB/CQ = √3(√3 + 1) / 2
∴ CB : CQ = √3(√3 + 1) : 2
∴ The correct answer is √3(√3 + 1) : 2.
Additional Information
Similar Triangles Property
If two triangles are similar, the ratio of their areas is equal to the square of the ratio of any two corresponding sides, altitudes, or medians.
Basic Proportionality Theorem (Thales' Theorem)
If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio.
Conjugate Multiplication
To simplify an irrational denominator like (a − √b), multiply both numerator and denominator by its conjugate (a + √b) to apply (x − y)(x + y) = x2 − y2.