Shortcut Trick
In a parallelogram ABDC, a diagonal divides it into two congruent triangles. Thus, ΔABC ≅ ΔDCB and ΔABD ≅ ΔDCA.
However, ΔADC and ΔABD are not congruent unless the parallelogram is a rhombus (where all sides are equal).
Check symmetry: ΔAEB and ΔDFC are congruent by RHS as AE = DF (distance between parallels) and AB = DC (opposite sides).
Check small triangles: ΔAOE and ΔDOF are congruent by AAS as ∠AEO = ∠DFO = 90°, ∠AOE = ∠DOF (vertically opposite), and AO = DO (diagonals bisect).
∴ The correct answer is ΔADC ≅ ΔABD.
Alternate Method
Given: Parallelogram ABDC, diagonals AD and BC intersect at O. AE ⊥ BC and DF ⊥ BC.
Formula used: Congruence criteria (SSS, SAS, ASA, RHS).
⇒ In ΔABC and ΔDCB: AB = DC, AC = DB (Opp. sides), BC = BC (Common). ∴ ΔABC ≅ ΔDCB (Option 3 is True).
⇒ In ΔAEB and ΔDFC: ∠AEB = ∠DFC = 90°, AB = DC (Opp. sides), AE = DF (Height). ∴ ΔAEB ≅ ΔDFC by RHS (Option 4 is True).
⇒ In ΔAOE and ΔDOF: ∠AOE = ∠DOF (V.O.A), ∠AEO = ∠DFO = 90°, AO = DO (Diagonals bisect). ∴ ΔAOE ≅ ΔDOF by AAS (Option 2 is True).
⇒ In ΔADC and ΔABD: AD is common, AC = BD, but CD is not necessarily equal to AB in terms of relative position for this specific pair. Since ΔADC and ΔABD share the same base AD but have different heights relative to that base unless the parallelogram is a rectangle, they are not congruent.
∴ The correct answer is ΔADC ≅ ΔABD.
Additional Information
Parallelogram Properties
Opposite sides are equal and parallel; opposite angles are equal; diagonals bisect each other.
Area and Congruence
A diagonal divides a parallelogram into two congruent triangles. Triangles on the same base and between the same parallels are equal in area but not necessarily congruent.
RHS Congruence Rule
Two right-angled triangles are congruent if the hypotenuse and one side of one triangle are equal to the hypotenuse and the corresponding side of the other.