If the polynomial 6x4 + 8x3 + 17x2 + 21x + 7 is divided by another polynomial 3x2 + 4x +1, the remainder comes out to be ax + b, find a and b.
- AOption (a)
a = 3; b = 1
- BOption (b)
a = 1; b = 2
- COption (c)
a = 1; b =3
- DOption (d)
a = 1; b = 1
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Correct answer
a = 1; b = 2
Why this answer is correct
Given:
Polynomial 6x4 + 8x3 + 17x2 + 21x + 7 is divided by another polynomial 3x2 + 4x +1
Concept used:
In such questions, we fix non-zero value of x and then calculate and compare values of remainder and quotient and solve using options.
Calculation:
Let x = 1,
then dividend 6x4 + 8x3 + 17x2 + 21x + 7 (x = 1) = 6 + 8 + 17 + 21 + 7 = 59
and divisor 3x2 + 4x +1 (x = 1) = 3 + 4 + 1 = 8
When 6x4 + 8x3 + 17x2 + 21x + 7 is divided by polynomial 3x2 + 4x +1, that is, when 59 is divided by 8 then remainder comes out to be 3
∴ ax + b (x = 1) = 3
⇒ a + b = 3
Only option that satisfies a + b = 3 is option 2)
NOTE: if more than one option satisfies then we check the satisfying options with another variable value of x.










