A can complete 25% of a task in 10 days. B can complete 40% of the task in 40 days and C can complete of the task in 13 days. Who among them has the fastest speed to complete the same task?
- AOption (a)
B
- BOption (b)
A
- COption (c)
All have the same speed
- DOption (d)
C
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Correct answer
C
Why this answer is correct
Shortcut Trick
Calculate total days for 100% work for each person.
A → 10 × 4 = 40 days.
B → 40 ÷ 0.4 = 100 days.
C → 13 × 3 = 39 days.
Least days = Fastest speed.
∴ The correct answer is C.
Alternate Method
| Person | Days | Total Work | Efficiency |
|---|---|---|---|
| A | 40 | 1560 | 39 |
| B | 100 | 15.6 | |
| C | 39 | 40 |
Given:
⇒ A: 25% (1/4) work in 10 days → Total time = 10 × 4 = 40 days.
⇒ B: 40% (2/5) work in 40 days → Total time = 40 × (5/2) = 100 days.
⇒ C: 1/3 work in 13 days → Total time = 13 × 3 = 39 days.
Calculations:
⇒ Speed is inversely proportional to time taken.
⇒ Time taken: B (100 days) > A (40 days) > C (39 days).
⇒ Since C takes the minimum time, C has the fastest speed.
∴ The correct answer is C.
Additional Information
Work and Efficiency Relationship
Efficiency is inversely proportional to the time taken to complete a task. Efficiency = Work ÷ Time.
Pipes and Cisterns
Similar to time and work, where filling a tank is positive work and emptying it is negative work.
Man-Days Formula
M1D1H1/W1 = M2D2H2/W2, used for comparing work done by different groups.



