Find the mode of the given frequency distribution.
| x | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
|---|---|---|---|---|---|
| f | 5 | 8 | 10 | 2 | 5 |
- AOption (a)
20
- BOption (b)
26
- COption (c)
22
- DOption (d)
24
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Correct answer
22
Why this answer is correct
Shortcut Trick
Identify the modal class (highest frequency): Class 20−30 with frequency 10.
Difference with preceding frequency (d1) = 10 − 8 = 2.
Difference with succeeding frequency (d2) = 10 − 2 = 8.
Mode = Lower limit + [ d1 / (d1 + d2) ] × Class Width
Mode = 20 + [ 2 / (2 + 8) ] × 10 = 20 + 2 = 22.
∴ The correct answer is 22.
Alternate Method
Given:
Modal Class = 20−30 (as it has the maximum frequency of 10)
Lower limit of modal class (l) = 20
Frequency of modal class (f1) = 10
Frequency of preceding class (f0) = 8
Frequency of succeeding class (f2) = 2
Class width (h) = 10
Formula Used:
Mode = l + [ (f1 − f0) / (2f1 − f0 − f2) ] × h
Calculations:
⇒ Mode = 20 + [ (10 − 8) / (2 × 10 − 8 − 2) ] × 10
⇒ Mode = 20 + [ 2 / (20 − 10) ] × 10
⇒ Mode = 20 + [ 2 / 10 ] × 10
⇒ Mode = 20 + 2
⇒ Mode = 22
∴ The correct answer is 22.
Additional Information
Empirical Relationship
For a moderately skewed distribution: 3 × Median = Mode + 2 × Mean or Mean − Mode = 3(Mean − Median).
Modal Class
In a grouped frequency distribution, the modal class is the class interval which contains the maximum frequency.
Measures of Central Tendency
Mean is the average, Median is the middle-most value, and Mode is the most frequently occurring value in a data set.







