
Shortcut Trick
Time taken by Train A = 8 hours and Train B = 7 hours.
Let Total Distance = LCM(8, 7) = 56 units.
Speed of A = 7 units/hr, Speed of B = 8 units/hr.
Distance covered by A in 2 hours (6 a.m. to 8 a.m.) = 7 × 2 = 14 units.
Remaining distance at 8 a.m. = 56 − 14 = 42 units.
Meeting time after 8 a.m. = 42 ÷ (7 + 8) = 42/15 hours = 2 hours 48 minutes.
∴ The correct answer is 10.48 a.m.

Alternate Method
Given:
Train A duration: 6:00 a.m. to 2:00 p.m. = 8 hours.
Train B duration: 8:00 a.m. to 3:00 p.m. = 7 hours.

Calculations:
⇒ Let distance between M and N = 56 km (LCM of 8 and 7).
⇒ Speed of Train A = 56 ÷ 8 = 7 km/hr.
⇒ Speed of Train B = 56 ÷ 7 = 8 km/hr.
⇒ Distance covered by A before B starts (from 6 a.m. to 8 a.m.) = 7 × 2 = 14 km.
⇒ Remaining distance = 56 − 14 = 42 km.
⇒ Relative speed = 7 + 8 = 15 km/hr.
⇒ Time taken to meet = 42 ÷ 15 = 2.8 hours.
⇒ 2.8 hours = 2 hours + (0.8 × 60) minutes = 2 hours 48 minutes.
⇒ Meeting time = 8:00 a.m. + 2 hours 48 minutes = 10:48 a.m.
∴ The correct answer is 10.48 a.m.

Additional Information
Relative Speed
When two objects move in opposite directions, their relative speed is the sum of their individual speeds (S1 + S2).
Time and Distance Relation
Distance = Speed × Time. If distance is constant, speed is inversely proportional to time.
Meeting Time Concept
To calculate meeting time, ensure both objects are moving. Calculate the lead distance covered by the first object before the second starts.