In a class of 66 students, the number of boys is twice that of girls. Pavithra is ranked eighteenth from the top. If there are 11 boys ahead of Pavithra, then how many girls are there after her in rank?
- ((a))
17
- ((b))
15
- ((c))
19
- ((d))
13
Show Answer
15
The logic followed here is:
Let the number of girls be G and the number of boys be B.
According to the given information:
B = 2G
B + G = 66
Substituting B = 2G into the second equation:
2G + G = 66
3G = 66
G = 66 / 3
G = 22
Therefore, the number of girls is 22 and the number of boys is 44.
Pavithra is ranked 18th from the top, and there are 11 boys ahead of her.
So, the number of girls ahead of Pavithra = 18 - 11 - 1 = 6 (since Pavithra is also a girl).
Total number of girls = 22
Number of girls after Pavithra = 22 - 7 = 15
Hence, the correct answer is "Option 2".




























































































