Official Paper

SBI PO Mains Memory Based Paper (Held on:02 January 2022) (Previous Year Paper)

155 questions · 180 minutes · with answers · free

Reasoning & Computer Aptitude (45 questions)

Direction : Study the following information to answer the given questions below:

Twelve persons in a family are sitting around two concentric circular tables. There are 5 married couples in the family and only married couples have children Those sitting in outer circle are facing towards the center while those sitting in inner circle are facing outside the center. A, B, C, D, E, F six persons are sitting around the inner circular table. P, Q, R, S, T, U six persons are sitting around the outer circular table.

Note- Any couple is neither sitting in the same circle nor facing each other. The persons of outer circular table are sitting exactly inline with the persons sitting around the inner circular table.

E's son is sitting immediate right of R's husband. F is a youngest male member of the family but not the son of Q. Only one person sits between C and F (either from the left or from the right). C is not an immediate neighbour of E.R's father is sitting in the inner circle and faces the immediate neighbour of R. R's son sits second to the right of R. Only two persons sit between R and T (either from the left or from the right). U is an immediate neighbour of P. U does not sits opposite to the immediate neighbours of the one who faces R. F does not face Q. B is not R's father. R's husband is sitting third to the right of R's father. Q is son of D. R's mother and R are sitting opposite to each other in the same circle. E is not an immediate neighbour of R's father. Q's daughter is sitting second to the right of Q.D's daughter in law is sitting second to the left of F. P is B's spouse. D is sitting immediate left of B. B is sitting second to the right of R's brother who is sitting in inner circle. R is an immediate neighbour of the one who faces B.

Who face D?

((a))
P
((b))
Q
((c))
R
((d))
S
((e))
T

Show Answer

Answer: ((b))

Given:

Twelve persons in a family are sitting around two concentric circular tables. There are 5 married couples in the family. Those sitting in outer circle are facing towards the center while those sitting in inner circle are facing outside the center. A, B, C, D, E, F six persons are sitting around the inner circular table. P, Q, R, S, T, U six persons are sitting around the outer circular table.

1. B is sitting second to the right of R's brother who is sitting in inner circle.

2. R is an immediate neighbour of the one who faces B.

3. R's son sits second to the right of R.

4. R's father is sitting in the inner circle and faces the immediate neighbour of R. B is not R's father.

Here case 1 gets eliminated.

5. Only two persons sit between R and T (either from the left or from the right).

6. D is sitting immediate left of B. R's husband is sitting third to the right of R's father.Here we get that D is R's husband.

7. Q is son of D. Q's daughter is sitting second to the right of Q.

This means Q is R's son also, because D and R are husband and wife.

8. U is an immediate neighbour of P. U does not sits opposite to the immediate neighbours of the one who faces R.

9. R's mother and R are sitting opposite to each other in the same circle.

This means T is R's mother. Also we will put S in the outer circle at the only position left.

10. E is not an immediate neighbour of R's father.

We get that E is R's brother.

11. Only one person sits between C and F (either from the left or from the right). C is not an immediate neighbour of E.

Now we put A at the only remaining place in inner circle, thus A is R's father.

12. D's daughter in law is sitting second to the left of F.

This means C is D's daughter in law i.e. C is wife of Q.

13. E's son is sitting immediate right of R's husband. P is B's spouse.

This means B is E's son and P is his wife.

14. F is a youngest male member of the family but not the son of Q.

Now the only remaining member is S. Given that there are 5 married couples in the family it can be concluded that S is E's wife. Thus we have final arrangement as below:

Hence, Q faces D.

Who is sitting exactly between R's son and R's mother when counted from right of R's son?

((a))
P
((b))
R
((c))
No one
((d))
S
((e))
T

Show Answer

Answer: ((c))

No one

Given:

1. B is sitting second to the right of R's brother who is sitting in inner circle.

2. R is an immediate neighbour of the one who faces B.

3. R's son sits second to the right of R.

4. R's father is sitting in the inner circle and faces the immediate neighbour of R. B is not R's father.

Here case 1 gets eliminated.

5. Only two persons sit between R and T (either from the left or from the right).

6. D is sitting immediate left of B. R's husband is sitting third to the right of R's father.

Here we get that D is R's husband.

7. Q is son of D. Q's daughter is sitting second to the right of Q.

This means Q is R's son also, because D and R are husband and wife.

8. U is an immediate neighbour of P. U does not sits opposite to the immediate neighbours of the one who faces R.

9. R's mother and R are sitting opposite to each other in the same circle.

This means T is R's mother. Also we will put S in the outer circle at the only position left.

10. E is not an immediate neighbour of R's father.

We get that E is R's brother.

11. Only one person sits between C and F (either from the left or from the right). C is not an immediate neighbour of E.

Now we put A at the only remaining place in inner circle, thus A is R's father.

12. D's daughter in law is sitting second to the left of F.

This means C is D's daughter in law i.e. C is wife of Q.

13. E's son is sitting immediate right of R's husband. P is B's spouse.

This means B is E's son and P is his wife.

14. F is a youngest male member of the family but not the son of Q.

Now the only remaining member is S. Given that there are 5 married couples in the family it can be concluded that S is E's wife. Thus we have final arrangement as below:

Hence, No one is sitting between R's son and R's mother (T) when counted from right of R's son (Q)

What is the relation of D with respect to B?

((a))
Son
((b))
Father
((c))
Grandfather
((d))
Uncle
((e))
None of these

Show Answer

Answer: ((d))

Uncle

Given:

1. B is sitting second to the right of R's brother who is sitting in inner circle.

2. R is an immediate neighbour of the one who faces B.

3. R's son sits second to the right of R.

4. R's father is sitting in the inner circle and faces the immediate neighbour of R. B is not R's father.

Here case 1 gets eliminated.

5. Only two persons sit between R and T (either from the left or from the right).

6. D is sitting immediate left of B. R's husband is sitting third to the right of R's father.

Here we get that D is R's husband.

7. Q is son of D. Q's daughter is sitting second to the right of Q.

This means Q is R's son also, because D and R are husband and wife.

8. U is an immediate neighbour of P. U does not sits opposite to the immediate neighbours of the one who faces R.

9. R's mother and R are sitting opposite to each other in the same circle.

This means T is R's mother. Also we will put S in the outer circle at the only position left.

10. E is not an immediate neighbour of R's father.

We get that E is R's brother.

11. Only one person sits between C and F (either from the left or from the right). C is not an immediate neighbour of E.

Now we put A at the only remaining place in inner circle, thus A is R's father.

12. D's daughter in law is sitting second to the left of F.

This means C is D's daughter in law i.e. C is wife of Q.

13. E's son is sitting immediate right of R's husband. P is B's spouse.

This means B is E's son and P is his wife.

14. F is a youngest male member of the family but not the son of Q.

Now the only remaining member is S. Given that there are 5 married couples in the family it can be concluded that S is E's wife. Thus we have final arrangement as below:

Hence, D is uncle of B.

If T and R interchange their positions then who faces E?

((a))
T
((b))
R
((c))
U
((d))
P
((e))
None of these

Show Answer

Answer: ((b))

Given:

1. B is sitting second to the right of R's brother who is sitting in inner circle.

2. R is an immediate neighbour of the one who faces B.

3. R's son sits second to the right of R.

4. R's father is sitting in the inner circle and faces the immediate neighbour of R. B is not R's father.

Here case 1 gets eliminated.

5. Only two persons sit between R and T (either from the left or from the right).

6. D is sitting immediate left of B. R's husband is sitting third to the right of R's father.

Here we get that D is R's husband.

7. Q is son of D. Q's daughter is sitting second to the right of Q.

This means Q is R's son also, because D and R are husband and wife.

8. U is an immediate neighbour of P. U does not sits opposite to the immediate neighbours of the one who faces R.

9. R's mother and R are sitting opposite to each other in the same circle.

This means T is R's mother. Also we will put S in the outer circle at the only position left.

10. E is not an immediate neighbour of R's father.

We get that E is R's brother.

11. Only one person sits between C and F (either from the left or from the right). C is not an immediate neighbour of E.

Now we put A at the only remaining place in inner circle, thus A is R's father.

12. D's daughter in law is sitting second to the left of F.

This means C is D's daughter in law i.e. C is wife of Q.

13. E's son is sitting immediate right of R's husband. P is B's spouse.

This means B is E's son and P is his wife.

14. F is a youngest male member of the family but not the son of Q.

Now the only remaining member is S. Given that there are 5 married couples in the family it can be concluded that S is E's wife. Thus we have final arrangement as below:

Hence, if T and R interchange their positions then R faces E.

Who is the oldest member of the family?

((a))
A
((b))
T
((c))
A and T
((d))
A or T
((e))
R

Show Answer

Answer: ((d))

A or T

Given:

1. B is sitting second to the right of R's brother who is sitting in inner circle.

2. R is an immediate neighbour of the one who faces B.

3. R's son sits second to the right of R.

4. R's father is sitting in the inner circle and faces the immediate neighbour of R. B is not R's father.

Here case 1 gets eliminated.

5. Only two persons sit between R and T (either from the left or from the right). T is not sitting behind E.

6. D is sitting immediate left of B. R's husband is sitting third to the right of R's father.

Here we get that D is R's husband.

7. Q is son of D. Q's daughter is sitting second to the right of Q.

This means Q is R's son also, because D and R are husband and wife.

8. U is an immediate neighbour of P. U does not sits opposite to the immediate neighbours of the one who faces R.

9. R's mother and R are sitting opposite to each other in the same circle.

This means T is R's mother. Also we will put S in the outer circle at the only position left.

10. E is not an immediate neighbour of R's father.

We get that E is R's brother.

11. Only one person sits between C and F (either from the left or from the right). C is not an immediate neighbour of E.

Now we put A at the only remaining place in inner circle, thus A is R's father.

12. D's daughter in law is sitting second to the left of F.

This means C is D's daughter in law i.e. C is wife of Q.

13. E's son is sitting immediate right of R's husband. P is B's spouse.

This means B is E's son and P is his wife.

14. F is a youngest male member of the family but not the son of Q.

Now the only remaining member is S. Given that there are 5 married couples in the family it can be concluded that S is E's wife. Thus we have final arrangement as below:

Hence, either A or T is the oldest member of the family.

Directions: Study the following information carefully and answer the questions that follow.

The following words are coded in this manner:

‘festival for women only’ is coded as ‘(p) 12D% 21H@ 4E@’

‘cindrella (q) to rescue’ is coded as ‘7B% 24I% 8G@ 9F%’

‘bugs ate all carrots’ is coded as ‘25D% (r) 24G% 26c@’

‘fight game play card’ is coded as ‘20D% (s) (t) 11D%’

Which of the folowing will replace the the blank '(p)'?

((a))
12D%
((b))
6C@
((c))
21C@
((d))
21C%
((e))
None of these

Show Answer

Answer: ((c))

21C@

The codes are as follows

Number	Place value of reverse order of first alphabet Example: festival → f → u (reverse of f) → 21
Alphabet	Place value of number of alphabets in a word Example: festival → 8 letters → H (place value of H is 8)
Symbol	If the place value of last letter in a word is even → @ Example: all → l (last letter) → 12 → even→ @
If the place value of the last letter in a word is odd → % Example : carrots → s (last letter) → 19 → odd → %

for	Number	for → f → u (reverse of f) → 21
Alphabet	for → 3 letters → C (place value of C is 3)
Symbol	for → r (last letter) → 18 → even → @
Code: 21C@

Hence, 21C@ will come in the place of '(p)'.

Which of the following word will replace the blank '(q)'?

((a))
doing
((b))
shoutes
((c))
shouted
((d))
fight
((e))
women

Show Answer

Answer: ((c))

shouted

The codes are as follows

Number	Place value of reverse order of first alphabet Example: festival → f → u (reverse of f) → 21
Alphabet	Place value of number of alphabets in a word Example: festival → 8 letters → H (place value of H is 8)
Symbol	If the place value of last letter in a word is even → @ Example: all → l (last letter) → 12 → even→ @
If the place value of the last letter in a word is odd → % Example : carrots → s (last letter) → 19 → odd → %

8G@	Number	8 → h → s (reverse of h)
Alphabet	G → 7 letters
Symbol	@ → even
Word: shouted

From the given options 'shouted' will have the code '8G@'.

Hence, 'shouted' will replace the blank '(q)'.

Direction: Study the following information carefully and answer the given questions.

A word, number and symbol arrangement device when given an input line of words, number and symbols rearrange them following a particular pattern on each step. The following of input and rearrangement.

INPUT: OTHER BUILD HOME WITH STRONG MUSIC

STEP I: QVJGT DWKNF JQOG YKVJ UVTQPI OWUKE

STEP II: DWKNF JQOG OWUKE QVJGT UVTQPI YKVJ

STEP III: GZNQI MTRJ RZXNH TYMJW XYWTSL BNYM

STEP IV: GZIQN MTRJ RZHNX TYMJW XYWLST BNYM

STEP V: ATCKH GNLD LTBHR NSGDQ RSQFMN VHSG

And step V is the last step of the above input, as the desired arrangement is obtained.

As per the logic followed on the above steps. Find out in each of the following questions the appropriate step for the given input.

INPUT: NONE LINK USED SENT MORE TABLE

What word is to the 4^th right of the word which is 6^th from right in step IV?

((a))
RTWJ
((b))
QPSN
((c))
YFJQG
((d))
XJSY
((e))
SJST

Show Answer

Answer: ((c))

YFJQG

In the given illustration:

Step I: Every letter is changed to the 2nd next letter according to alphabetic order.

Step II: All words are arranged in ascending order according to the English alphabet from left to right considering the first letter of the word.

If two words consist of the same first letter the second letter would be considered for arrangement and so on.

Step III: Every letter is changed to the 3rd next letter according to alphabetic order.

Step IV: In every alternate word positions of last and 3rd last letters are interchange.

Step V: Every letter is changed to the 6th previous letter according to alphabetic order.

Similarly steps for the given input.

INPUT: NONE LINK USED SENT MORE TABLE

STEP I: PQPG NKPM WUGF UGPV OQTG VCDNG

STEP II: NKPM OQTG PQPG UGPV VCDNG WUGF

STEP III: QNSP RTWJ STSJ XJSY YFGQJ ZXJI

STEP IV: QPSN RTWJ SJST XJSY YFJQG ZXJI

STEP V: KJMH LNQD MDMN RDMS SZDKA TRDC

Hence, YFJQG is to the 4^th right of the word which is 6^th from right in step IV.

What word is to the immediate left of the word which is 5^th from the left end of step III?

((a))
STSJ
((b))
XJSY
((c))
ZXJI
((d))
RTWJ
((e))
QNSP

Show Answer

Answer: ((b))

XJSY

In the given illustration:

Step I: Every letter is changed to the 2^nd next letter according to alphabetic order.

Step II: All words are arranged in ascending order according to the English alphabet from left to right considering the first letter of the word.

If two words consist of the same first letter the second letter would be considered for arrangement and so on.

Step III: Every letter is changed to the 3^rd next letter according to alphabetic order.

Step IV: In every alternate word positions of last and 3^rd last letters are interchange.

Step V: Every letter is changed to the 6^th previous letter according to alphabetic order.

Similarly steps for the given input.

INPUT: NONE LINK USED SENT MORE TABLE

STEP I: PQPG NKPM WUGF UGPV OQTG VCDNG

STEP II: NKPM OQTG PQPG UGPV VCDNG WUGF

STEP III: QNSP RTWJ STSJ XJSY YFGQJ ZXJI

STEP IV: QPSN RTWJ SJST XJSY YFJQG ZXJI

STEP V: KJMH LNQD MDMN RDMS SZDKA TRDC

Hence, “XJSY” is to the immediate left of the word which is 5^th from the left end of step III.

In which step RDMS is 4^th form left end for the given input?

((a))
Step V
((b))
Step VI
((c))
Step VII
((d))
Step IV
((e))
Step VIII

Show Answer

Answer: ((a))

Step V

In the given illustration:

Step I: Every letter is changed to the 2nd next letter according to alphabetic order.

Step II: All words are arranged in ascending order according to the English alphabet from left to right considering the first letter of the word.

If two words consist of the same first letter the second letter would be considered for arrangement and so on.

Step III: Every letter is changed to the 3rd next letter according to alphabetic order.

Step IV: In every alternate word positions of last and 3rd last letters are interchange.

Step V: Every letter is changed to the 6th previous letter according to alphabetic order.

Similarly steps for the given input.

INPUT: NONE LINK USED SENT MORE TABLE

STEP I: PQPG NKPM WUGF UGPV OQTG VCDNG

STEP II: NKPM OQTG PQPG UGPV VCDNG WUGF

STEP III: QNSP RTWJ STSJ XJSY YFGQJ ZXJI

STEP IV: QPSN RTWJ SJST XJSY YFJQG ZXJI

STEP V: KJMH LNQD MDMN RDMS SZDKA TRDC

Hence, in Step V RDMS is 4^th form left end for the given input.

What will be the next step for the below input, if the below input is the step IV for certain input?

GCIOD YILIR GSNIG RUEMN HESIN

((a))
BXDJ TDGDM BNIBV MPZHI CZNDI
((b))
AWXIC SCFCL AMUAH LOHGY BYHCM
((c))
GCDOI YILIR GSGIN RUEMN HENIS
((d))
AWCIX SCFCL AMHCA LOYGH BYMCH
((e))
None of the above

Show Answer

Answer: ((d))

AWCIX SCFCL AMHCA LOYGH BYMCH

In the given illustration:

Step I: Every letter is changed to the 2nd next letter according to alphabetic order.

Step II: All words are arranged in ascending order according to the English alphabet from left to right considering the first letter of the word.

If two words consist of the same first letter the second letter would be considered for arrangement and so on.

Step III: Every letter is changed to the 3rd next letter according to alphabetic order.

Step IV: In every alternate word positions of last and 3rd last letters are interchange.

Step V: Every letter is changed to the 6th previous letter according to alphabetic order.

Here,

Step IV: GCIOD YILIR GSNIG RUEMN HESIN

Step V: AWCIX SCFCL AMHCA LOYGH BYMCH

Hence, AWCIX SCFCL AMHCA LOYGH BYMCH will be the next step for a given input.

Direction: In the following questions, the symbols @, ?, ×, β and Ω are used with the following meaning as illustrated below:

‘X ? Y’ means ‘X is neither greater than nor equal to Y’.

‘X × Y’ means ‘X is neither smaller than nor greater than Y’.

‘X β Y’ means ‘X is not greater than Y’.

‘X Ω Y’ means ‘X is greater than Y’.

‘X @ Y’ means ‘X is either greater than or equal to Y’.

Now in each of the following questions assuming the given statements to be true, find which of the conclusion/s given below them is/are definitely true?

Statement:

D ? M β P × K Ω F ? T; M × G

Conclusions:

I. K @ G

II. T ? P

III. F β M

((a))
Only conclusion I is true
((b))
Both conclusion I and II are true
((c))
Either II or III is true
((d))
All I, II and III are true
((e))
Both II and III are true

Show Answer

Answer: ((a))

Only conclusion I is true

According to the given information,

X is
Symbol	?	×	β	Ω	@
Meaning	<	=	≤	>	≥
to Y

Given Statement: D ? M β P × K Ω F ? T; M × G

On converting:- D < M ≤ P = K > F < T; M = G

On combining:- D < M = G ≤ P = K > F < T

Conclusion:

I. K @ G → K ≥ G → True

II. T ? P → T < P → False

III. F β M → F ≤ M → False (as relation between F and M can’t be determined)

Hence, Only conclusion I are true.

Statement:

T @ I × H Ω U ? P β V ? L; H @ L

Conclusions:

I. T Ω L

II. V β T

III. I @ L

((a))
Only II conclusion is true
((b))
Both conclusion I and II are true
((c))
Either conclusion II or conclusion III is true
((d))
Only III conclusion is true
((e))
Both conclusion I and III are true

Show Answer

Answer: ((d))

Only III conclusion is true

According to the given information,

X is
Symbol	?	×	Β	Ω	@
Meaning	<	=	≤	>	≥
to Y

Given Statement: T @ I × H Ω U ? P β V ? L; H @ L

On converting:- T ≥ I = H > U < P ≤ V < L; H ≥ L

On combining:- T ≥ I = H ≥ L > V ≥ P > U

Conclusions:

I. T Ω L → T > L → False (as it is a possibility, but not specific)

II. V β T → V ≤ T → False (as V < T holds true, but V = T is not possible)

III. I @ L → I ≥ L → True

Hence, only conclusion III is true.

Directions: Question below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question.

Six people – Megha, Suhas, Rakesh, Akshay, Safia and Nidhi are standing in a line according to their height. But not necessarily in the same order. Who is the second tallest person?

Statement I: Megha is taller than just two person. Rakesh is taller than Nidhi and Safia but he is not the tallest. Suhas is the shorter than just two person.

Statement II: Nidhi is the second shortest person. Megha is shorter than three persons. Suhas is shorter than Akshay and Rakesh. Safia is the shortest.

((a))
The data in statement I alone is sufficient to answer the question, while the data in statement II alone is not sufficient to answer the question
((b))
The data in statement II alone is sufficient to answer the question, while the data in statement I alone is not sufficient to answer the question
((c))
The data either in statement I alone or in statement II alone is sufficient to answer the question
((d))
The data in both statements I and II together is not sufficient to answer the question
((e))
The data in both statements I and II together is necessary to answer the question

Show Answer

Answer: ((a))

The data in statement I alone is sufficient to answer the question, while the data in statement II alone is not sufficient to answer the question

According to the given information,

Names of person: Megha, Suhas, Rakesh, Akshay, Safia and Nidhi

Total members: Six

Statement I: Megha is taller than just two person. Rakesh is taller than Nidhi and Safia but he is not the tallest. Suhas is the shorter than just two person.

1. Megha is taller than just two person.

_______ > ______ > _____ > Megha > _____ > _____

2. Suhas is the shorter than just two person.

_____ > _____ > Suhas > Megha > _____ > _____

3. Rakesh is taller than Nidhi and Safia but he is not the tallest.

(According to this, Akshay will be the tallest, but we can't determine who is the shortest between Nidhi and Safia.)

Akshay > Rakesh > Suhas > Megha > Nidhi/Safia > Nidhi/Safia

Hence, Rakesh is the second tallest person. The data in statement I alone is sufficient to answer the question.

Statement II: Nidhi is the second shortest person. Megha is shorter than three persons. Suhas is shorter than Akshay and Rakesh. Safia is the shortest.

1. Nidhi is the second shortest person.

_____ > _____ > _____ > _____ > Nidhi > _____

2. Megha is shorter than three persons.

_____ > _____ > _____ > Megha > Nidhi > _____

3. Safia is the shortest.

_____ > _____ > _____ > Megha > Nidhi > Safia

4. Suhas is shorter than Akshay and Rakesh.

Akshay/Rakesh > Akshay/Rakesh > Suhas > Megha > Nidhi > Safia

Therefore, we can't determine who is the second tallest person.

The data in statement I alone is sufficient to answer the question, while the data in statement II alone is not sufficient to answer the question.

Direction: In each of the following questions, a question followed by three statements. You have to decide whether the data provided in the statements are sufficient to answer the question. Read all the three statements and given answer.

There are six letters W, I, M, D, Y and A. ‘MIDWAY’ is the word formed after performing the following operations using these six letters only?

I. A is placed fourth to the right of M. D is not placed immediately next to either M or A.

II. Y is placed immediately next (either left or right) to A. W is placed immediately next (either left or right) to D.

III. Both I and W are placed immediately next to D. The word does not begin with Y. M is not placed immediately next to W.

((a))
Statement I and II are sufficient to answer the question, while the statement III are not required to answer the question.
((b))
Statement I and III are sufficient to answer the question, while statement II are not required to answer the question.
((c))
Statement II and III are sufficient to answer the question, while statement I are not required to answer the question.
((d))
Either statement I alone or statement II alone or statement III alone is sufficient to answer the question.
((e))
All statement I, II and III together are necessary to answer the question.

Show Answer

Answer: ((b))

Statement I and III are sufficient to answer the question, while statement II are not required to answer the question.

From statement I: A is placed fourth to the right of M. D is not placed immediately next to either M or A.

From statement II: Y is placed immediately next (either left or right) to A. W is placed immediately next (either left or right) to D.

From statement III: Both I and W are placed immediately next to D. The word does not begin with Y. M is not placed immediately next to W.

Hence, statement I and III together are necessary to answer the question.

Directions: Question below consists of a question and three statements numbered I, II and III given below it. You have to decide whether the data provided in the statements are sufficient to answer the question.

Seven friends - S, T, R, F, G, J and V are living on different floors of a seven storey building having seven floors numbered one to seven (The ground floor is numbered 1, the floor above it is numbered 2 and so on and the topmost floor is numbered 7). Who is staying immediately below G’s floor?

Statement I: R lives on one of the odd numbered floors above floor 3. And only two people live between the R and S.

Statement II: Only one person lives between S and G, who is staying below T and above S. T does not stay on the top floor.

Statement III: V stays above F but below J.

((a))
The data in statement II alone are sufficient to answer the question, and the data in statement I or III is not required to answer the question.
((b))
The data in either statement I, II or III are sufficient to answer the question.
((c))
The data in statement II and III is sufficient to answer the question, and the data in statement I is not required to answer the question.
((d))
The data in all three statements together is needed to answer the question.
((e))
The data in all the statements, even together are not sufficient to answer the question.

Show Answer

Answer: ((d))

The data in all three statements together is needed to answer the question.

According to the information given,

Names of Person: S, T, R, F, G, J and V

Floors: The ground floor is numbered 1, the floor above it is numbered 2 and so on and the topmost floor is numbered 7.

Statement I: R lives on one of the odd numbered floors above floor 3. And only two people live between the R and S.

(There are two cases here. Case - 1: R lives on floor number 5 and two people live between R and S. Case - 2: R lives on floor number 7 and two people live between R and S.)

Case - 1	Case - 2
Floor Number	Person	Floor Number	Person
7		7	R
6		6
5	R	5
4		4	S
3		3
2	S	2
1		1

Hence, we can't find who lives below G using only statement I.

Statement II: Only one person lives between S and G, who is staying below T and above S. T does not stay on the top floor.

(Here Case- 2 gets eliminated as both G and T can not be placed above S, with one person between S and G.)

Case - 1
Floor Number	Person
7
6	T
5	R
4	G
3
2	S
1

Hence, from statement I and II also we can't find who lives below G.

Statement III: V stays above F but below J.

Case - 1
Floor Number	Person
7	J
6	T
5	R
4	G
3	V
2	S
1	F

Now we get our final answer. V is staying immediately below G.

The data in all three statements together is needed to answer the question.

Directions: In the following question, a given question is followed by information in three statements. You have to decide the data in which statement(s) is sufficient to answer the question and mark your answer accordingly.

There are seven persons, Kabir, Roy, Manav, Adi, Babu, Malik, and Boman are sitting in a row facing north direction. Each person owns a different brand of car which are Kia, Tata, Maruti, Toyota, Hyundai. BMW, and Mahindra but not necessarily in the same order.

The one who owns Toyota sits fourth to the left of Adi, who owns Tata and either of them sits at the extreme end of the row. Roy owns Mahindra. The one who owns Kia sits third to the left of the one who owns BMW, who neither sits adjacent to the one who owns Toyota nor adjacent to Adi. Babu neither owns Toyota nor Kia, sits third to the left of Roy.

Who sits at the immediate right of Kabir?

Statement I: Two persons sit between the one who owns Maruti and Manav. Three persons sit between Boman and the one who owns Hyundai.

Statement II: The one who owns Hyundai sits second to the left of Manav. The one who owns Maruti sits at the immediate right of Boman.

Statement III: Three persons sit between Malik and Kabir, who doesn't own Maruti. Boman and the one who owns Maruti sit together.

((a))
The data in any two statements are sufficient to answer the question.
((b))
The data in statement III is sufficient to answer the question, and the data in statement I and II is not required to answer the question.
((c))
The data in either statement I, II or III are sufficient to answer the question.
((d))
The data in statement II and III is sufficient to answer the question, and the data in statement I is not required to answer the question.
((e))
The data in all the statements, even together are not sufficient to answer the question.

Show Answer

Answer: ((b))

The data in statement III is sufficient to answer the question, and the data in statement I and II is not required to answer the question.

By the information:

The one who owns Toyota sits fourth to the left of Adi, who owns Tata and either of them sits at the extreme end of the row. (considering 2 cases)

Roy owns Mahindra.

The one who owns Kia sits third to the left of the one who owns BMW, who neither sits adjacent to the one who owns Toyota nor adjacent to Adi.

Babu neither owns Toyota nor Kia, sits third to the left of Roy.

Case 1:

Case 2:

From Statement I:

We have,

Two persons sit between the one who owns Maruti and Manav. (case 1 canceled)

Three persons sit between Boman and the one who owns Hyundai.

Case 2:

The position of Kabir is not definite.

From Statement II:

We have,

The one who owns Hyundai sits second to the left of Manav.

The one who owns Maruti sits at the immediate right of Boman.

Case 1:

Case 2:

The position of Kabir is not definite.

From Statement III:

We have,

Three persons sit between Malik and Kabir, who doesn't own Maruti.

Boman and the one who owns Maruti sit together. (case 1 eliminated)

Manav sits at the immediate right of Kabir.

The data in statement III is sufficient to answer the question, and the data in statement I and II is not required to answer the question.

Directions: Study the following information carefully and answer the questions following it.

A family has 9 members A, B, C, D, E, F, G, H & I and they are sitting in a row facing north. There are 2 couples in the family. H who has 2 sons and 1 daughter is sitting third to the right of C. A is sitting immediate left of his wife C. Members at both the extreme ends are children of B. B is sitting immediate right of his wife H. The daughters G and I are sitting with their respective fathers. D who is brother-in-law of A is sitting in the middle of the row and second to the right of A. E who is male is sitting immediate right of his maternal uncle D. I who is granddaughter of H is not sitting at any of the extreme ends. I is daughter of C.

Who is sitting second to the left of G?

((a))
A
((b))
B
((c))
H
((d))
I
((e))
None of these

Show Answer

Answer: ((c))

Nine members A, B, C, D, E, F, G, H & I and all are facing north.

First, we will draw the sitting arrangement and then the family tree.

D who is the brother-in-law of A is sitting in the middle of the row and second to the right of A.
A is sitting immediate left of his wife C.
H who has 2 sons and 1 daughter is sitting third to the right of C.
E is sitting immediate right of his maternal uncle D.
B is sitting immediate right of his wife H.

Members at both the extreme ends are children of B.
The daughters G and I are sitting with their respective fathers. I is daughter of C.
I who is the granddaughter of H is not sitting at any of the extreme ends.

As mentioned in 8), I is not sitting at any of the extreme ends, I will be sitting immediate left of A. Then G who must be the daughter of B will sit with her father B as per 7). Then F will sit at the extreme left end.

Therefore, the final arrangement is as follows.

Now we will draw the family tree.

From the given information,

H has 2 sons and 1 daughter.
B is sitting immediate right of his wife H.
Members at both the extreme ends are children of B.

Hence, H is the wife of B and from the arrangement F & G who are sitting at extreme ends are two out of three children of H & B.

A is sitting immediate left of his wife C
I who is the granddaughter of H.
The daughters G and I are sitting with their respective fathers.

Hence, A is the husband of C and from the arrangement, I is the daughter of A. Hence A, F & G are the children of H & B in which A & F are sons, G is the daughter.

D who is the brother-in-law of A is sitting in the middle of the row and second to the right of A.
E is sitting immediate right to his maternal uncle D.

Hence, C who is wife of A is sister of D and E is the son of A & C.

Hence, we can draw the family tree as below:

Hence, H is sitting second to the left of G.

How is E related to F?

((a))
Niece
((b))
Son
((c))
Daughter
((d))
Nephew
((e))
Cannot be determined

Show Answer

Answer: ((d))

Nephew

Nine members A, B, C, D, E, F, G, H & I and all are facing north.

First, we will draw the sitting arrangement and then the family tree.

D who is brother-in-law of A is sitting in the middle of the row and second to the right of A.
A is sitting immediate left of his wife C.
H who has 2 sons and 1 daughter is sitting third to the right of C.
E is sitting immediate right of his maternal uncle D.
B is sitting immediate right of his wife H.

Members at both the extreme ends are children of B.
The daughters G and I are sitting with their respective fathers. I is daughter of C.
I who is the granddaughter of H is not sitting at any of the extreme ends.

Therefore, the final arrangement is as follows.

Now we will draw the family tree.

From the given information,

H has 2 sons and 1 daughter.
B is sitting immediate right of his wife H.
Members at both the extreme ends are children of B.

Hence, H is the wife of B and from the arrangement F & G who are sitting at extreme ends are two out of three children of H & B.

A is sitting immediate left of his wife C
I who is granddaughter of H.
The daughters G and I are sitting with their respective fathers.

Hence, A is the husband of C and from the arrangement; I is the daughter of A. Hence A, F & G are the children of H & B in which A & F are sons, G is the daughter.

D who is the brother-in-law of A is sitting in the middle of the row and second to the right of A.
E is sitting immediate right of his maternal uncle D.

Hence, C who is the wife of A is sister of D and E is the son of A & C.

Hence, we can draw the family tree as below:

From the family tree, E is the nephew of F.

Who is sitting third to the right of I’s mother?

((a))
H
((b))
G
((c))
B
((d))
E
((e))
Can’t be determined

Show Answer

Answer: ((a))

Nine members A, B, C, D, E, F, G, H & I and all are facing north.

First, we will draw the sitting arrangement and then the family tree.

D who is brother-in-law of A is sitting in the middle of the row and second to the right of A.
A is sitting immediate left of his wife C.
H who has 2 sons and 1 daughter is sitting third to the right of C.
E is sitting immediate right of his maternal uncle D.
B is sitting immediate right of his wife H.

Members at the both the extreme ends are children of B.
The daughters G and I are sitting with their respective fathers. I is daughter of C.
I who is granddaughter of H is not sitting at any of the extreme end.

As mentioned in 8), I is not sitting at any of the extreme ends, I will be sitting immidiete left of A. Then G who must be daughter of B will sit with her father B as per 7). Then F will sit at extreme left end.

Therefore, the final arrangement is as follows.

Now we will draw the family tree.

From the given information,

H has 2 sons and 1 daughter.
B is sitting immediate right of his wife H.
Members at both the extreme ends are children of B.

Hence, H is the wife of B and from the arrangement; F & G who are sitting at extreme ends are two out of three children of H & B.

A is sitting immediate left of his wife C
I who is granddaughter of H.
The daughters G and I are sitting with their respective fathers.

Hence, A is the husband of C and from the arrangement; I is the daughter of A. Hence A, F & G are the children of H & B in which A & F are sons, G is the daughter.

D who is the brother-in-law of A is sitting in the middle of the row and second to the right of A.
E is sitting immediate right of his maternal uncle D.

Hence, C who is the wife of A is sister of D and E is the son of A & C.

Hence, we can draw the family tree as below:

From the family tree, I’s mother is C and from the linear arrangement, H is sitting third to the right of C.

What is the position of A’s brother with respect to E’s mother?

((a))
Fourth to the left
((b))
Second to the left
((c))
Third to the right
((d))
Third to the left
((e))
Cannot be determined

Show Answer

Answer: ((d))

Third to the left

Nine members A, B, C, D, E, F, G, H & I and all are facing north.

First, we will draw the sitting arrangement and then the family tree.

D who is the brother-in-law of A is sitting in the middle of the row and second to the right of A.
A is sitting immediate left of his wife C.
H who has 2 sons and 1 daughter is sitting third to the right of C.
E is sitting immediate right of his maternal uncle D.
B is sitting immediate right of his wife H.

Members at both the extreme ends are children of B.
The daughters G and I are sitting with their respective fathers. I is daughter of C.
I who is the granddaughter of H is not sitting at any of the extreme ends.

Therefore, the final arrangement is as follows.

Now we will draw the family tree.

From the given information,

H has 2 sons and 1 daughter.
B is sitting immediate right of his wife H.
Members at both the extreme ends are children of B.

Hence, H is the wife of B from the arrangement, F & G who are sitting at extreme ends are two out of three children of H & B.

A is sitting immediate left of his wife C
I who is granddaughter of H.
The daughters G and I are sitting with their respective fathers.

Hence, A is the husband of C and from the arrangement; I is the daughter of A. Hence A, F & G are the children of H & B in which A & F are sons, G is the daughter.

D who is the brother-in-law of A is sitting in the middle of the row and second to the right of A.
E is sitting immediate right of his maternal uncle D.

Hence, C who is the wife of A is sister of D and E is the son of A & C.

Hence, we can draw the family tree as below:

From the family tree, A’s brother is F and E’s mother is C. From the linear arrangement, F is third to the left of C.

If D is replaced with his sister then what will be the position of H with respect to her daughter-in-law?

((a))
Third to the left
((b))
Second to the right
((c))
Third to the right
((d))
Fourth to the left
((e))
Cannot be determined.

Show Answer

Answer: ((b))

Second to the right

ine members A, B, C, D, E, F, G, H & I and all are facing north.

First, we will draw the sitting arrangement and then the family tree.

D who is brother-in-law of A is sitting in the middle of the row and second to the right of A.
A is sitting immediate left of his wife C.
H who has 2 sons and 1 daughter is sitting third to the right of C.
E is sitting immediate right of his maternal uncle D.
B is sitting immediate right of his wife H.

Members at both the extreme ends are children of B.
The daughters G and I are sitting with their respective fathers. I is daughter of C,
I who is granddaughter of H is not sitting at any of the extreme ends.

As mentioned in 8), I is not sitting at any of the extreme ends, I will be sitting immediate left of A. Then G who must be daughter of B will sit with her father B as per 7). Then F will sit at the extreme left end.

Therefore, the final arrangement is as follows.

Now we will draw the family tree.

From the given information,

H has 2 sons and 1 daughter.
B is sitting immediate right of his wife H.
Members at both the extreme ends are children of B.

Hence, H is the wife of B and from the arrangement, F & G who are sitting at extreme ends are two out of three children of H & B.

A is sitting immediate left of his wife C
I who is granddaughter of H.
The daughters G and I are sitting with their respective fathers.

Hence, A is the husband of C and from the arrangement; I is the daughter of A. Hence A, F & G are the children of H & B in which A & F are sons, G is the daughter.

D who is brother-in-law of A is sitting in the middle of the row and second to the right of A.
E is sitting immediate right of his maternal uncle D.

Hence, C who is wife of A is sister of D and E is the son of A & C.

Hence, we can draw the family tree as below:

From the family tree, D’s sister is C and H’s daughter-in-law is C.

When C will come in place of D, H will be second to the right of C.

Directions: A statement is given followed by two inferences I and II. You have to consider the statement to be true even if it seems to be at variance from commonly known facts. You have to decide which of the given inferences, if any, follow from the given statement.

Statement: This benchmark is increasingly applied in choosing who will be hired and who will not, who will be let go, and who retained, who passed over, and who promoted.

Inference:

I.The benchmark is an integral part of the employee management policy of an organization.

II. Those who are not hired do not make it to the benchmark.

((a))
Only I follows.
((b))
Only II follows.
((c))
Either I or II follows.
((d))
Neither I nor II follows.
((e))
Both I and II follow.

Show Answer

Answer: ((e))

Both I and II follow.

The statement mentions that a benchmark is applied in choosing, rejecting, retaining, and promoting a candidate.

From what has been supplied we can infer that the Benchmark is a necessary part of the employee management policy of an organization. Therefore, the inference I follow.

Also from the statement, it can be deduced that those who get rejected and are not hired do not make it to the specified benchmark. So, inference II follows.

Hence**,** Both I and II follow.

Directions : Study the following information and answer the questions given below.

Distance and direction between various points is shown in a coded form as follows

A # B (58m) – A is 46m west of B.

A & B (89m) – A is 77m south of B.

A @ B (110m) – A is 98m north of B.

A % B (52m) – A is 40m east of B.

N * AB – N is the mid point of line AB.

L @ Z (28m), S # K (20m), R % H (17m), Q # Z (26m), T # M (21m), Q & H (22m), S & M (27m), T @ R (28m)

Which of the following statement is sufficient to find shortest distance between points M and J?

I. J & P (19m), P % N (22m), N @ O (25m)

II. P & Q (27m), N % P (20m), O @ N (22m), O # J (18m)

((a))
Data in Statement I alone is sufficient to answer the question, while the data in Statement II alone is not sufficient to answer the question
((b))
Data in Statement II alone is sufficient to answer the question, while the data in Statement I alone is not sufficient to answer the question
((c))
Data either in Statement I alone or in Statement II alone is sufficient to answer the question
((d))
Data given in both Statements I and II together are not sufficient to answer the question
((e))
Data in both Statements I and II together are necessary to answer the question

Show Answer

Answer: ((b))

Data in Statement II alone is sufficient to answer the question, while the data in Statement I alone is not sufficient to answer the question

Given:

A # B (58m) – A is 46m west of B, here (58-46) = 12m

A & B (89m) – A is 77m south of B, here (89-77) = 12m

A @ B (110m) – A is 98m north of B, here (110-98) = 12m

A % B (52m) – A is 40m east of B, here (52-40) = 12m

The actual distance between A and B is 12m less than the distance given in the code.

Now the given sentence,

L @ Z (28m), S # K (20m), R % H (17m), Q # Z (26m), T # M (21m), Q & H (22m), S & M (27m), T @ R (28m)

L is 16m north of Z, S is 8m west of K, R is 5m east of H, Q is 14m west of Z, T is 9m west of M, Q is 10m south of H, S is 15m south of M, T is 16m north of R

From the above sentences, we get the following diagram -

Checking Statement I. J & P (19m), P % N (22m), N @ O (25m)

J is 7m south of P, P is 10m east of N, N is 13m north of O.

From Statement I alone we can not find the distance between points M and J.

Checking Statement II. P & Q (27m), N % P (20m), O @ N (22m), O # J (18m)

P is 15m south of Q, N is 8m east of P, O is 10m north of N, O is 6m west of J.

From Statement II alone, we can find distance between points M and J.

Hence, Data in Statement II alone is sufficient to answer the question, while the data in Statement I alone is not sufficient to answer the question

Which of the following statement is sufficient to prove B * RT?

I. F # H (17m), F & E (28m), D % E (17m)

II. D @ C (20m), B % C (17m)

((a))
Data in Statement I alone is sufficient to answer the question, while the data in Statement II alone is not sufficient to answer the question
((b))
Data in Statement II alone is sufficient to answer the question, while the data in Statement I alone is not sufficient to answer the question
((c))
Data either in Statement I alone or in Statement II alone is sufficient to answer the question
((d))
Data given in both Statements I and II together are not sufficient to answer the question
((e))
Data in both Statements I and II together are necessary to answer the question

Show Answer

Answer: ((e))

Data in both Statements I and II together are necessary to answer the question

Given:

A # B (58m) – A is 46m west of B, here (58-46) = 12m

A & B (89m) – A is 77m south of B, here (89-77) = 12m

A @ B (110m) – A is 98m north of B, here (110-98) = 12m

A % B (52m) – A is 40m east of B, here (52-40) = 12m

The actual distance between A and B is 12m less than the distance given in the code.

Now the given sentence,

L @ Z (28m), S # K (20m), R % H (17m), Q # Z (26m), T # M (21m), Q & H (22m), S & M (27m), T @ R (28m)

L is 16m north of Z, S is 8m west of K, R is 5m east of H, Q is 14m west of Z, T is 9m west of M, Q is 10m south of H, S is 15m south of M, T is 16m north of R

From above sentences we get following diagram-

Checking Statement I. F # H (17m), F & E (28m), D % E (17m)

F is 5m west of H, F is 16m south of E, D is 5m east of E.

From Statement I alone we can not prove B * RT i.e., B is the mid point of line RT.

Checking Statement II. D @ C (20m), B % C (17m)

D is 8m north of C, B is 5m east of C.

From Statement II alone we can not prove B * RT i.e., B is the mid point of line RT.

Combining Statement I and II we get,

Thus from Statement I and II together, we can prove B * RT i.e., B is the mid point of line RT.

Hence, Data in both Statements I and II together are necessary to answer the question

Direction : Study the following information to answer the given questions below:

Eight persons A, B, C, D, E, F, G and H are living in different cities Chennai, Bangalore, Hyderabad, Mumbai, Ahmedabad, Ernakulam, Jaipur and Bhubaneshwar, not necessarily in the same order. Each has a different weight –89, 50, 55,71, 49, 66,92 and 56 (in Kg) not necessarily in the same order. A has a weight which is multiple of 11 and 5 and lives in Bhubaneshwar. D lives in Bangalore but his weight is not 89Kg or 71Kg. The one who lives in Hyderabad has a weight 56Kg. G has a weight of 49Kg and does not live in Mumbai or Chennai. E has weight of 71Kg and lives in Ahmedabad or Ernakulam. F lives in Chennai but his weight is not 92Kg. C lives in Mumbai. The sum of weights of H and C is 181Kg. Neither G nor H lives in Ernakulam. G does not live in Jaipur. The sum of weights of D and H is 142Kg.

Further, a code is assigned to each person depending on the city in which they live and their weight according to the following conditions:

If the name of the city starts with vowel and the weight is a prime number then the code will be 5^th succeeding letter of the person’s name as per English Alphabetical Series.
If the name of the city starts with a vowel and the weight is a composite number then the code will be 3^rd preceding letter of the person’s name as per the English Alphabetical Series.
If the name of the city starts with consonant and the weight is a prime number then the code will be sum of digits of the person’s weight.
If the name of the city starts with consonant and the weight is a composite number then the code will be difference of digits of the person’s weight.

What is the sum of codes of C and H and weight of D ?

((a))
66
((b))
74
((c))
50
((d))
64
((e))
19

Show Answer

Answer: ((b))

Persons : A, B, C, D, E, F, G, H

Cities: Chennai, Bangalore, Hyderabad, Mumbai, Ahmedabad, Ernakulam, Jaipur, Bhubaneshwar

Weights : 89, 50, 55, 71, 49, 66, 92, 56

1. A has a weight which is multiple of 11 and 5 and lives in Bhubaneshwar.

Persons	Weight	City
A	55	Bhubaneshwar.
B
C
D
E
F
G
H

2. F lives in Chennai but his weight is not 92Kg. C lives in Mumbai.

Persons	Weight	City
A	55	Bhubaneshwar.
B
C		Mumbai
D
E
F		Chennai
G
H

3. The sum of weights of H and C is 181Kg. The sum of weights of D and H is 142Kg.

⇒ Here there is one pair of weights whose sum is 181 which is 92 and 89. Thus H and C can have weights of 92Kg and 89Kg in any order. Further there is one pair whose sum is 142 which is 92 and 50. Thus D and H can have weights of 92Kg and 50Kg in any order. But taking into consideration both the statements we get H's weight is 92 Kg, D's weight is 50Kg and C's weight is 89Kg.

Persons	Weight	City
A	55	Bhubaneshwar.
B
C	89	Mumbai
D	50
E
F		Chennai
G
H	92

4. G has a weight of 49Kg and does not live in Mumbai or Chennai. E has weight of 71Kg and lives in Ahmedabad or Ernakulam.

Persons	Weight	City
A	55	Bhubaneshwar.
B
C	89	Mumbai
D	50
E	71	Ahmedabad /Ernakulam
F		Chennai
G	49
H	92

5. The one who lives in Hyderabad has a weight 56Kg. D lives in Bangalore but his weight is not 89Kg or 71Kg.

Persons	Weight	City
A	55	Bhubaneshwar.
B	56	Hyderabad
C	89	Mumbai
D	50	Bangalore
E	71	Ahmedabad /Ernakulam
F		Chennai
G	49
H	92

6. Neither G nor H lives in Ernakulam. G does not live in Jaipur.

Persons	Weight	City
A	55	Bhubaneshwar.
B	56	Hyderabad
C	89	Mumbai
D	50	Bangalore
E	71	Ernakulam
F		Chennai
G	49	Ahmedabad
H	92	Jaipur

After filling the only weight left we get final arrangement as below:

Persons	Weight	City
A	55	Bhubaneshwar.
B	56	Hyderabad
C	89	Mumbai
D	50	Bangalore
E	71	Ernakulam
F	66	Chennai
G	49	Ahmedabad
H	92	Jaipur

Now the given conditions :

If the name of the city starts with vowel and the weight is a prime number then the code will be 5th succeeding letter of the person’s name as per English Alphabetical Series.
If the name of the city starts with a vowel and the weight is a composite number then the code will be 3rd preceding letter of the person’s name as per the English Alphabetical Series.
If the name of the city starts with consonant and the weight is a prime number then the code will be sum of digits of the person’s weight.
If the name of the city starts with consonant and the weight is a composite number then the code will be difference of digits of the person’s weight.

Thus after applying all the conditions, the codes of all the persons will be as shown in the below table.

Persons	Weight	City	Code
A	55	Bhubaneshwar.	0
B	56	Hyderabad	1
C	89	Mumbai	17
D	50	Bangalore	5
E	71	Ernakulam	J
F	66	Chennai	0
G	49	Ahmedabad	D
H	92	Jaipur	7

Hence, sum of codes of C and H and age of D = 17 + 7 + 50 = 74

What is the code for the one who lives in Ernakulam?

((a))
5
((b))
D
((c))
1
((d))
17
((e))
J

Show Answer

Answer: ((e))

Persons : A, B, C, D, E, F, G, H

Cities: Chennai, Bangalore, Hyderabad, Mumbai, Ahmedabad, Ernakulam, Jaipur, Bhubaneshwar

Weights : 89, 50, 55, 71, 49, 66, 92, 56

1. A has a weight which is multiple of 11 and 5 and lives in Bhubaneshwar.

Persons	Weight	City
A	55	Bhubaneshwar.
B
C
D
E
F
G
H

2. F lives in Chennai but his weight is not 92Kg. C lives in Mumbai.

Persons	Weight	City
A	55	Bhubaneshwar.
B
C		Mumbai
D
E
F		Chennai
G
H

3. The sum of weights of H and C is 181Kg. The sum of weights of D and H is 142Kg.

Persons	Weight	City
A	55	Bhubaneshwar.
B
C	89	Mumbai
D	50
E
F		Chennai
G
H	92

4. G has a weight of 49Kg and does not live in Mumbai or Chennai. E has weight of 71Kg and lives in Ahmedabad or Ernakulam.

Persons	Weight	City
A	55	Bhubaneshwar.
B
C	89	Mumbai
D	50
E	71	Ahmedabad /Ernakulam
F		Chennai
G	49
H	92

5. The one who lives in Hyderabad has a weight 56Kg. D lives in Bangalore but his weight is not 89Kg or 71Kg.

Persons	Weight	City
A	55	Bhubaneshwar.
B	56	Hyderabad
C	89	Mumbai
D	50	Bangalore
E	71	Ahmedabad /Ernakulam
F		Chennai
G	49
H	92

6. Neither G nor H lives in Ernakulam. G does not live in Jaipur.

Persons	Weight	City
A	55	Bhubaneshwar.
B	56	Hyderabad
C	89	Mumbai
D	50	Bangalore
E	71	Ernakulam
F		Chennai
G	49	Ahmedabad
H	92	Jaipur

After filling the only weight left we get final arrangement as below:

Persons	Weight	City
A	55	Bhubaneshwar.
B	56	Hyderabad
C	89	Mumbai
D	50	Bangalore
E	71	Ernakulam
F	66	Chennai
G	49	Ahmedabad
H	92	Jaipur

Now the given conditions

If the name of the city starts with vowel and the weight is a prime number then the code will be 5th succeeding letter of the person’s name as per English Alphabetical Series.
If the name of the city starts with a vowel and the weight is a composite number then the code will be 3rd preceding letter of the person’s name as per the English Alphabetical Series.
If the name of the city starts with consonant and the weight is a prime number then the code will be sum of digits of the person’s weight.
If the name of the city starts with consonant and the weight is a composite number then the code will be difference of digits of the person’s weight.

Thus after applying all the conditions, codes of all the persons will be as shown in below table.

Persons	Weight	City	Code
A	55	Bhubaneshwar.	0
B	56	Hyderabad	1
C	89	Mumbai	17
D	50	Bangalore	5
E	71	Ernakulam	J
F	66	Chennai	0
G	49	Ahmedabad	D
H	92	Jaipur	7

Hence, code for the one who lives in Ernakulam is J.

Who lives in Ahmedabad?

((a))
G
((b))
A
((c))
F
((d))
C
((e))
D

Show Answer

Answer: ((a))

Persons : A, B, C, D, E, F, G, H

Cities: Chennai, Bangalore, Hyderabad, Mumbai, Ahmedabad, Ernakulam, Jaipur, Bhubaneshwar

Weights : 89, 50, 55, 71, 49, 66, 92, 56

1. A has a weight which is multiple of 11 and 5 and lives in Bhubaneshwar.

Persons	Weight	City
A	55	Bhubaneshwar.
B
C
D
E
F
G
H

2. F lives in Chennai but his weight is not 92Kg. C lives in Mumbai.

Persons	Weight	City
A	55	Bhubaneshwar.
B
C		Mumbai
D
E
F		Chennai
G
H

3. The sum of weights of H and C is 181Kg. The sum of weights of D and H is 142Kg.

Persons	Weight	City
A	55	Bhubaneshwar.
B
C	89	Mumbai
D	50
E
F		Chennai
G
H	92

4. G has a weight of 49Kg and does not live in Mumbai or Chennai. E has weight of 71Kg and lives in Ahmedabad or Ernakulam.

Persons	Weight	City
A	55	Bhubaneshwar.
B
C	89	Mumbai
D	50
E	71	Ahmedabad /Ernakulam
F		Chennai
G	49
H	92

5. The one who lives in Hyderabad has a weight 56Kg. D lives in Bangalore but his weight is not 89Kg or 71Kg.

Persons	Weight	City
A	55	Bhubaneshwar.
B	56	Hyderabad
C	89	Mumbai
D	50	Bangalore
E	71	Ahmedabad /Ernakulam
F		Chennai
G	49
H	92

6. Neither G nor H lives in Ernakulam. G does not live in Jaipur.

Persons	Weight	City
A	55	Bhubaneshwar.
B	56	Hyderabad
C	89	Mumbai
D	50	Bangalore
E	71	Ernakulam
F		Chennai
G	49	Ahmedabad
H	92	Jaipur

After filling the only weight left we get final arrangement as below:

Persons	Weight	City
A	55	Bhubaneshwar.
B	56	Hyderabad
C	89	Mumbai
D	50	Bangalore
E	71	Ernakulam
F	66	Chennai
G	49	Ahmedabad
H	92	Jaipur

Now the given conditions

If the name of the city starts with vowel and the weight is a prime number then the code will be 5th succeeding letter of the person’s name as per English Alphabetical Series.
If the name of the city starts with a vowel and the weight is a composite number then the code will be 3rd preceding letter of the person’s name as per the English Alphabetical Series.
If the name of the city starts with consonant and the weight is a prime number then the code will be sum of digits of the person’s weight.
If the name of the city starts with consonant and the weight is a composite number then the code will be difference of digits of the person’s weight.

Thus after applying all the conditions, codes of all the persons will be as shown in below table.

Persons	Weight	City	Code
A	55	Bhubaneshwar.	0
B	56	Hyderabad	1
C	89	Mumbai	17
D	50	Bangalore	5
E	71	Ernakulam	J
F	66	Chennai	0
G	49	Ahmedabad	D
H	92	Jaipur	7

Hence, G lives in Ahmedabad.

What is the code for H?

((a))
1
((b))
17
((c))
5
((d))
7
((e))
D

Show Answer

Answer: ((d))

Persons : A, B, C, D, E, F, G, H

Cities: Chennai, Bangalore, Hyderabad, Mumbai, Ahmedabad, Ernakulam, Jaipur, Bhubaneshwar

Weights : 89, 50, 55, 71, 49, 66, 92, 56

1. A has a weight which is multiple of 11 and 5 and lives in Bhubaneshwar.

Persons	Weight	City
A	55	Bhubaneshwar.
B
C
D
E
F
G
H

2. F lives in Chennai but his weight is not 92Kg. C lives in Mumbai.

Persons	Weight	City
A	55	Bhubaneshwar.
B
C		Mumbai
D
E
F		Chennai
G
H

3. The sum of weights of H and C is 181Kg. The sum of weights of D and H is 142Kg.

Persons	Weight	City
A	55	Bhubaneshwar.
B
C	89	Mumbai
D	50
E
F		Chennai
G
H	92

4. G has a weight of 49Kg and does not live in Mumbai or Chennai. E has weight of 71Kg and lives in Ahmedabad or Ernakulam.

Persons	Weight	City
A	55	Bhubaneshwar.
B
C	89	Mumbai
D	50
E	71	Ahmedabad /Ernakulam
F		Chennai
G	49
H	92

5. The one who lives in Hyderabad has a weight 56Kg. D lives in Bangalore but his weight is not 89Kg or 71Kg.

Persons	Weight	City
A	55	Bhubaneshwar.
B	56	Hyderabad
C	89	Mumbai
D	50	Bangalore
E	71	Ahmedabad /Ernakulam
F		Chennai
G	49
H	92

6. Neither G nor H lives in Ernakulam. G does not live in Jaipur.

Persons	Weight	City
A	55	Bhubaneshwar.
B	56	Hyderabad
C	89	Mumbai
D	50	Bangalore
E	71	Ernakulam
F		Chennai
G	49	Ahmedabad
H	92	Jaipur

After filling the only weight left we get final arrangement as below:

Persons	Weight	City
A	55	Bhubaneshwar.
B	56	Hyderabad
C	89	Mumbai
D	50	Bangalore
E	71	Ernakulam
F	66	Chennai
G	49	Ahmedabad
H	92	Jaipur

Now the given conditions

If the name of the city starts with vowel and the weight is a prime number then the code will be 5th succeeding letter of the person’s name as per English Alphabetical Series.
If the name of the city starts with a vowel and the weight is a composite number then the code will be 3rd preceding letter of the person’s name as per the English Alphabetical Series.
If the name of the city starts with consonant and the weight is a prime number then the code will be sum of digits of the person’s weight.
If the name of the city starts with consonant and the weight is a composite number then the code will be difference of digits of the person’s weight.

Persons	Weight	City	Code
A	55	Bhubaneshwar.	0
B	56	Hyderabad	1
C	89	Mumbai	17
D	50	Bangalore	5
E	71	Ernakulam	J
F	66	Chennai	0
G	49	Ahmedabad	D
H	92	Jaipur	7

Hence, code for H is 7.

How many persons have the same code?

((a))
1
((b))
2
((c))
3
((d))
4
((e))
5

Show Answer

Answer: ((b))

Persons : A, B, C, D, E, F, G, H

Cities: Chennai, Bangalore, Hyderabad, Mumbai, Ahmedabad, Ernakulam, Jaipur, Bhubaneshwar

Weights : 89, 50, 55, 71, 49, 66, 92, 56

1. A has a weight which is multiple of 11 and 5 and lives in Bhubaneshwar.

Persons	Weight	City
A	55	Bhubaneshwar.
B
C
D
E
F
G
H

2. F lives in Chennai but his weight is not 92Kg. C lives in Mumbai.

Persons	Weight	City
A	55	Bhubaneshwar.
B
C		Mumbai
D
E
F		Chennai
G
H

3. The sum of weights of H and C is 181Kg. The sum of weights of D and H is 142Kg.

Persons	Weight	City
A	55	Bhubaneshwar.
B
C	89	Mumbai
D	50
E
F		Chennai
G
H	92

4. G has a weight of 49Kg and does not live in Mumbai or Chennai. E has weight of 71Kg and lives in Ahmedabad or Ernakulam.

Persons	Weight	City
A	55	Bhubaneshwar.
B
C	89	Mumbai
D	50
E	71	Ahmedabad /Ernakulam
F		Chennai
G	49
H	92

5. The one who lives in Hyderabad has a weight 56Kg. D lives in Bangalore but his weight is not 89Kg or 71Kg.

Persons	Weight	City
A	55	Bhubaneshwar.
B	56	Hyderabad
C	89	Mumbai
D	50	Bangalore
E	71	Ahmedabad /Ernakulam
F		Chennai
G	49
H	92

6. Neither G nor H lives in Ernakulam. G does not live in Jaipur.

Persons	Weight	City
A	55	Bhubaneshwar.
B	56	Hyderabad
C	89	Mumbai
D	50	Bangalore
E	71	Ernakulam
F		Chennai
G	49	Ahmedabad
H	92	Jaipur

After filling the only weight left we get final arrangement as below:

Persons	Weight	City
A	55	Bhubaneshwar.
B	56	Hyderabad
C	89	Mumbai
D	50	Bangalore
E	71	Ernakulam
F	66	Chennai
G	49	Ahmedabad
H	92	Jaipur

Now the given conditions

If the name of the city starts with vowel and the weight is a prime number then the code will be 5th succeeding letter of the person’s name as per English Alphabetical Series.
If the name of the city starts with a vowel and the weight is a composite number then the code will be 3rd preceding letter of the person’s name as per the English Alphabetical Series.
If the name of the city starts with consonant and the weight is a prime number then the code will be sum of digits of the person’s weight.
If the name of the city starts with consonant and the weight is a composite number then the code will be difference of digits of the person’s weight.

Thus after applying all the conditions, codes of all the persons will be as shown in below table.

Persons	Weight	City	Code
A	55	Bhubaneshwar.	0
B	56	Hyderabad	1
C	89	Mumbai	17
D	50	Bangalore	5
E	71	Ernakulam	J
F	66	Chennai	0
G	49	Ahmedabad	D
H	92	Jaipur	7

Hence, two persons have the same code.

Direction: In following question two conclusions have been given followed by 5 sets of possible Statements. You have to take the given Conclusions to be true even if they seem to be at variance with the commonly known facts and then decide for the given Conclusions logically follows from the which of the given statements disregarding commonly known facts.

Conclusions:

I. All Roots can not be Grass.

II. Some Leaves being Grass is a possibility.

Statements:

I. Some Roots are Grass. All Trees are Leaves. Some Leaves are Roots.

II. Only a few Leaves are Roots. Some Roots are Grass. All Trees are Leaves.

III. Only a few Leaves are Roots. Some Roots are Grass. Some Trees are Leaves.

IV. Only a few Roots are Grass. All Trees are Leaves. Some Leaves are Roots.

V. Only a few Roots are Grass. Some Trees are Leaves. Some Leaves are Roots.

((a))
Only statement IV
((b))
Only statement V
((c))
Both statement I and II
((d))
Both statement I and III
((e))
Both statement IV and V

Show Answer

Answer: ((e))

Both statement IV and V

From statement I,

Some Roots are Grass. All Trees are Leaves. Some Leaves are Roots.

Minimum possible diagram,

I) All Roots can not be Grass → False ( it is possible but not definite)

II) Some Leaves being Grass is a possibility → True ( It is possible)

Therefore, Statement I will not be the result of the given conclusions.

From Statement II:

Only a few Leaves are Roots. Some Roots are Grass. All Trees are Leaves.

I) All Roots can not be Grass → False (It is possible but not definite)

II) Some Leaves being Grass is a possibility → True

Therefore, Statement II will not be the result of the given conclusions.

From Statement III:

Only a few Leaves are Roots. Some Roots are Grass. Some Trees are Leaves.

I) All Roots can not be Grass → False (it is possible but not definite)

II) Some Leaves being Grass is a possibility → True

Therefore, Statement III will not be the result of the given conclusions.

From Statement IV:

Only a few Roots are Grass. All Trees are Leaves. Some Leaves are Roots.

I) All Roots can not be Grass → True (because some roots are grass and some roots are not grass)

II) Some Leaves being Grass is a possibility → True (It is possible)

Therefore, Statement IV will be the result of the given conclusions.

From Statement V:

Only a few Roots are Grass. Some Trees are Leaves. Some Leaves are Roots.

I) All Roots can not be Grass → True (because some roots are grass and some roots are not grass)

II) Some Leaves being Grass is a possibility→ True (It is possible)

Therefore, Statement V will be the result of the given conclusions.

Hence, Both statement IV and V follows.

Conclusions:

I. At least some goat being bird is a possibility.

II.Some swans are goat.

Statements:

I. All goats are Swans. All swans are crows. No goat is a bird.

II. All goats are Swans. All Swans are crows. No crow is a bird.

III. Some goats are Swans. Some goats are crows. No goat is a bird.

IV. Some goats are Swans. All Swans are crows. No goat is a bird.

V. All goats are Swans. Some goats are crows. No crow is a bird

((a))
Only statement II
((b))
Only statement V
((c))
Only statement IV
((d))
Only statement III
((e))
Only statement I

Show Answer

Answer: ((b))

Only statement V

From statement I,

All goats are Swans. All swans are crows. No goat is a bird.

Minimum possible diagram,

I. At least some goat being bird is a possibility → False

II. Some swans are goat → True

Therefore, Statement I will not be the result of the given conclusions.

From Statement II:

All goats are Swans. All Swans are crows. No crow is a bird.

I. At least some goat being bird is a possibility → False (because No crow is a bird)

II.Some swans are goat → True

Therefore, Statement II will not be the result of the given conclusions.

From Statement III:

Some goats are Swans. Some goats are crows. No goat is a bird.

I.At least some goat being bird is a possibility → False

II.Some swans are goat → True

Therefore, Statement III will not be the result of the given conclusions.

From Statement IV:

Some goats are Swans. All Swans are crows. No goat is a bird.

I. At least some goat being bird is a possibility → False

II.Some swans are goat → True

Therefore, Statement IV will not be the result of the given conclusions.

From Statement V:

All goats are Swans. Some goats are crows. No crow is a bird

I.At least some goat being bird is a possibility→ True (it is possible)

II. Some swans are goat→ True

Therefore, Statement V will be the result of the given conclusions.

Hence, only statement V follows.

Directions: Read the passage given below and select the assumption(s) that hold true based on the facts in the passage.

Cotton acreage in India during the current year has fallen by 10% as cotton growers have moved on the cultivation of other cash crops. This is the result of the cotton glut in world markets post-September 11 and the consequent slowdown in the world economy. But this scenario brought with it benefits to one segment of the industry - yarn manufacturers - as they get higher prices for their produce. Some yarn manufacturers had stocked up low priced cotton last year. The combined effect of all this is evident in the rise in net profits and net margins of yarn manufacturers.

Assumption: The farmers will again grow cotton next year due to the increased price of cotton yarn.

((a))
If the assumption is definitely true
((b))
If the assumption is probably true
((c))
If the assumption is probably false
((d))
If the assumption is definitely false
((e))
If the data are inadequate

Show Answer

Answer: ((c))

If the assumption is probably false

Correct option – 3

As we see the passage, it talks about yarn manufacturing. As cotton prices fall, The yarn manufactures get higher prices for their production. The assumption is not implicit here because this will benefit the yarn manufacturers, not the farmers unless the latter act as the former also. The yarn higher price not so much beneficial for farmers.

Hence, the assumption is probably false.

Directions: In the question below are given a statement followed by two courses of action numbered I and II. A course of action is a step or administrative decision to be taken for improvement, follow-up or further action regarding the problem, policy, etc. Based on the information given in the statement to be true, then decide which of the suggested courses of action logically follow(s) for pursuing.

Statement:

Caitlin Bosche is the Human Resource Management Head at Company X. She has received the monthly reports from all the departments in the compartment. While going through the reports, it comes to her notice that the production in Department G and Department K has fallen by 100,000 units and 150,000 units respectively. On further investigation, she concludes that the machineries in department G are breaking down more often because of being overused. While the machinery in Department K is being underutilized.

Course of Actions:

I. Caitlin sends an email to the Operations Manager directing him to buy new machinery for Department G with enough capacity to bear the workload.

II. Caitlin sends an email to the Operation Manager informing him to transfer 10,000 workers from Department G to Department K.

((a))
Only I follows.
((b))
Only Il follows.
((c))
Either I or II follows.
((d))
Neither I nor II follows.
((e))
Both I and II follow.

Show Answer

Answer: ((b))

Only Il follows.

Answer: Option 2. Only II follows.

Buying new machines will solve the problem faced by Department G as the stronger machines won’t break down because of being overworked. But Department K is not provided with the solution by this approach. But if the workers are transferred from Department G to Department K, it will solve both their problems. As the workers are moved to another department, the machines in the Department G won’t break down because of being overworked and perform satisfactorily. While machines in Department K which were previously being underutilized will be put to use with the influx of new workers. Hence, the second course of action fixes both the problems.

Directions: One statement is given followed by two conclusions, I and II. You have to consider the statement to be true, even if it seems to be at variance from commonly known facts. You are to decide which of the given conclusions can definitely be drawn from the given statement.

Statement:

80% of the employees of Edulab Ltd. earn more than Rs. 5000 per month. 70% of employees of Edulab Ltd. work as supervisors.

Conclusions:

I. All supervisors earn more than Rs.5000 per month.

II. Less than 100% of supervisors earn more than Rs.5000 per month.

((a))
Only Conclusion I follows.
((b))
Only Conclusion II follows
((c))
Both the Conclusions I and II follow.
((d))
Neither Conclusion I nor II follows.
((e))
Either Conclusion I or II follows.

Show Answer

Answer: ((e))

Either Conclusion I or II follows.

Option 5 is the correct answer. The given statement tells us that 80% of the employees of Edulab Ltd earn above Rs.5000 per month. It also tells us that 70% of the employees work as supervisors. From this we know that 20% of the employees earn Rs.5000 or less. If this 20% are all supervisors then we can say that at least 50% of the supervisors earn more than Rs.5000 per month. If none of these 20% employees are supervisors, it means that all the supervisors earn more than Rs.5000 per month. Thus we can say that either 100% of the supervisors earn more than Rs.5000, or conversely less than 100% of the supervisors earn more than Rs.5000. This is exactly what conclusions I and II state, but we know that only one of them is definitely true. Hence, either I or II follows, but not both.

Directions: The critical reasoning question is based on a short argument, a set of statements, or a plan of action. For each question, select the best answer of the choices given and explain why the chosen answer is the right fit. You have to consider the statements to be true even if they seem to be at variance from commonly known facts.

Statement:

All engineering students, except for Mechanical, work on software rather than hardware.

Which of the following can be most properly inferred from the statement above?

((a))
Mechanical engineering students work only on hardware.
((b))
Only mechanical engineering students work on software.
((c))
If an engineering student works on software, he is not a mechanical engineer.
((d))
Not all engineering students work on software.
((e))
An engineering student works on hardware, as long as he is not a mechanical engineer.

Show Answer

Answer: ((d))

Not all engineering students work on software.

Not all engineering students work on software.

"Not all engineering students work on software." is correct because the statement specifies on the fact that all engineering students work on software except mechanical engineers which directly implies that not all the engineering students use the software. The statement does not say anything about what mechanical engineers work on; hence other statements cannot be inferred from the statement. Since the statement suggests that most engineering students work on software, the statement "An engineering student works on hardware, as long as he is not a mechanical engineer." is eliminated.

Directions: In making decisions about important questions, it is desirable to be able to distinguish between strong and weak arguments. Strong arguments are those, which are both important and directly related to the question. Weak arguments are those, which are of minor importance and also may not be directly related to the question or may be related to a trivial aspect of the question. The question below is followed by two arguments numbered I and II. You have to decide which of the arguments a Strong argument is and which a weak argument is.

Statement:

Should animals be killed in the name of the laboratory experiments?

Arguments:

I. Yes, they are available in abundance.

II. No, we have to support non-violence on every step of our lives.

((a))
If only argument I is strong
((b))
If only argument II is strong.
((c))
If either I or II is strong.
((d))
If neither I nor II is strong.
((e))
If both I and II are strong.

Show Answer

Answer: ((d))

If neither I nor II is strong.

Option 4 is the correct answer. As we know that for an experiment of any kind of treatment or medicine, first of all, they experiment it on animals. An abundance of animals does not mean that we should reduce their number. Hence, argument I is a weak argument. The argument II is also a weak argument because does it not depict the real picture. Are we really supporting non-violence at every step of our lives? Moreover, it does not go into the reason for practicing non-violence. It does not provide any other measure that can be taken in its place as well.

Directions: Read the following passage and select the correct answer.

Alka had lost her job during the lockdown and started a new business to support herself. She was providing tiffin service to the people who had depended on restaurants for daily food and were facing a problem due to the lockdown. Because of the apt timing and identification of need, her business had hit the ground running. It hadn't even required a lot of investment and she used her savings from the job to start it so she had no debt hanging on her. The business flourished for over an year but then as the lockdown opened, she saw a drastic reduce in demand for her tiffins. Alka surveyed her customers and found out that the local restaurants were offering a similar meal at a lower cost than her.

Which of the following actions would help Alka improve her business?

((a))
Reduce the cost of her tiffins to get more customers, even if it means a little loss at the beginning.
((b))
Advertise to increase customer reach and extend her boundaries.
((c))
Come up with subscription and discount offers to allure customers without taking a significant loss.
((d))
Keep the business alive by reducing the prices and get back to her job thereby averting loss.
((e))
Retain the cost on her tiffins and try to change the class of target customers.

Show Answer

Answer: ((c))

Come up with subscription and discount offers to allure customers without taking a significant loss.

The passage has clearly stated that the problem is the pricing on the tiffins. So Alka needs a solution that does not cause her a lot of loss and yet increase her customer base.

Options 1 and 5 are therefore eliminated.

Option 4 is not feasible and cannot be expected to work efficiently, so it is also eliminated.

Among options 2 and 3, option 3 answers Alka's problem more efficiently as compared to the advertising idea.

Hence the correct answer is option 3.

Directions: Study the following information carefully and answer the questions that follow:

There are 15 boxes numbered from 2 to 16 arranged one above another in ascending order from top to bottom. The letters of the word "MATE" are written in the same order as given in word against the boxes which are multiple of 3, starting from 3. Further arrangement of letters P, Q, R, S, U, V and symbols @, #, $, % is as given below.

V is written below R but not below box numbered 12. There is a gap of 2 boxes between the letter the U and symbol %. Symbols P and Q are written in alphabetical order against the multiples of 7 starting from 7. Symbols # and @ are written immediate to each other. Vowels are written immediate to the third letter of the word. There is a gap of 4 boxes between the symbols # and $. S is written against the bottommost box.

Which letter or symbol is written against the box which is 4 places away from the bottommost box?

((a))
%
((b))
((c))
E
((d))
R
((e))
T

Show Answer

Answer: ((c))

Given :

⇒

Box No	Letter/ Symbol
2
3	M
4
5
6	A
7
8
9	T
10
11
12	E
13
14
15
16

Symbols P and Q are written in alphabetical order against the multiples of 7 starting from 7. S is written against the bottommost box.

⇒

Box No	Letter/ Symbol
2
3	M
4
5
6	A
7	P
8
9	T
10
11
12	E
13
14	Q
15
16	S

2. Vowels are written immediate to the third letter of the word.

⇒ U is the only vowel among the letters. T is the third letter of the word. Hence we will have the following cases.

Box No	Letter/Symbol	Letter/Symbol
	Case 1	Case 2
2
3	M	M
4
5
6	A	A
7	P	P
8	U
9	T	T
10		U
11
12	E	E
13
14	Q	Q
15
16	S	S

There is a gap of 2 boxes between the letter the U and symbol %.

⇒ There will be one more case from case 1.

Box No	Letter/Symbol	Letter/Symbol	Letter/Symbol
	Case 1	Case 2	Case 1A
2
3	M	M	M
4
5	%
6	A	A	A
7	P	P	P
8	U		U
9	T	T	T
10		U
11			%
12	E	E	E
13		%
14	Q	Q	Q
15
16	S	S	S

Symbols # and @ are written immediate to each other. There is a gap of 4 boxes between the symbols # and $.

⇒ There is no suitable place for # and $ in Case2. Hence it is eliminated.

Box No	Letter/Symbol	Letter/Symbol	Letter/Symbol
	Case 1	Case 2 (Eliminated)	Case 1A
2
3	M	M	M
4			@
5	%		#
6	A	A	A
7	P	P	P
8	U		U
9	T	T	T
10	#	U	$
11	@		%
12	E	E	E
13		%
14	Q	Q	Q
15	$
16	S	S	S

5. V is written below R but not below box numbered 12.

⇒ There is no suitable place for V in Case 1A. Hence it is eliminated. Case 1 is the final arrangement.

Box No	Letter/Symbol	Letter/Symbol
	Case 1	Case 1A (Eliminated)
2	R
3	M	M
4	V	@
5	%	#
6	A	A
7	P	P
8	U	U
9	T	T
10	#	$
11	@	%
12	E	E
13
14	Q	Q
15	$
16	S	S

Hence, Box no 12 is placed 4 places away from bottommost box. Letter E is written against it.

If a and b are box numbers of the letters M and P respectively, then find the value of (a + b)²

((a))
99
((b))
101
((c))
10
((d))
100
((e))
52

Show Answer

Answer: ((d))

100

Given :

⇒

Box No	Letter/ Symbol
2
3	M
4
5
6	A
7
8
9	T
10
11
12	E
13
14
15
16

Symbols P and Q are written in alphabetical order against the multiples of 7 starting from 7. S is written against the bottommost box.

⇒

Box No	Letter/ Symbol
2
3	M
4
5
6	A
7	P
8
9	T
10
11
12	E
13
14	Q
15
16	S

2. Vowels are written immediate to the third letter of the word.

⇒ U is the only vowel among the letters. T is the third letter of the word. Hence we will have the following cases.

Box No	Letter/Symbol	Letter/Symbol
	Case 1	Case 2
2
3	M	M
4
5
6	A	A
7	P	P
8	U
9	T	T
10		U
11
12	E	E
13
14	Q	Q
15
16	S	S

There is a gap of 2 boxes between the letter the U and symbol %.

⇒ There will be one more case from case 1.

Box No	Letter/Symbol	Letter/Symbol	Letter/Symbol
	Case 1	Case 2	Case 1A
2
3	M	M	M
4
5	%
6	A	A	A
7	P	P	P
8	U		U
9	T	T	T
10		U
11			%
12	E	E	E
13		%
14	Q	Q	Q
15
16	S	S	S

Symbols # and @ are written immediate to each other. There is a gap of 4 boxes between the symbols # and $.

⇒ There is no suitable place for # and $ in Case2. Hence it is eliminated.

Box No	Letter/Symbol	Letter/Symbol	Letter/Symbol
	Case 1	Case 2 (Eliminated)	Case 1A
2
3	M	M	M
4			@
5	%		#
6	A	A	A
7	P	P	P
8	U		U
9	T	T	T
10	#	U	$
11	@		%
12	E	E	E
13		%
14	Q	Q	Q
15	$
16	S	S	S

5. V is written below R but not below box numbered 12.

⇒ There is no suitable place for V in Case 1A. Hence it is eliminated. Case 1 is the final arrangement.

Box No	Letter/Symbol	Letter/Symbol
	Case 1	Case 1A (Eliminated)
2	R
3	M	M
4	V	@
5	%	#
6	A	A
7	P	P
8	U	U
9	T	T
10	#	$
11	@	%
12	E	E
13
14	Q	Q
15	$
16	S	S

Here a = 3 and b = 7. Hence (a + b)² = (3 + 7)² = 10² = 100

Hence, the correct answer is 100.

Directions: Study the given information carefully and answer the following questions below.

8 persons A, B, C, D, E, F, G and H are born in four different months viz. March, May, August and October in 8 different cities viz. P, Q, R, S, T, U, V and W but not necessarily in that order. They have their birthdays either on 14^th or 26^th of the given months. The one born in P has birthday just before the one born in Q. Number of people born before the one born in R is same as number of persons born after the one born in V. E and H are born in same month. One person is born in between the one born in V and other born in S. There is no person born between the one born in V and the person F. Neither E nor D is born in R and V. Three persons are born between the one born in T and the person C such that C is born before the one born in T. B is born in May and there are two people born between B and the one born in R. The one born in R does not have birthday in the month of October. There are three persons born between F and G. A is born immediately before the one born in Q. More than two people are born before F. D is not the one born in W.

What is the name of city where A is born?

((a))
U
((b))
Q
((c))
P
((d))
W
((e))
None of these

Show Answer

Answer: ((c))

8 persons: A, B, C, D, E, F, G and H.

4 Months: March, May, August and October.

8 Cities: P, Q, R, S, T, U, V and W.

They have their birthdays either on 14^th or 26^th of the given months.

B is born in May (B is either born in 14^th or 26^th of May).

Therefore, two cases arise.

Case -1

Month	14th	26^th
March
May	B
August
October

Case – 2

Month	14th	26^th
March
May		B
August
October

Two people are born between B and the one born in R.
Number of people born before the one born in R is same as number of persons born after the one born in V.
The one born in R does not have birthday in the month of October.

On combining the above statements, we get:

Case – 1

Month	14th	26^th
March
May	B(V)
August		(R)
October

Case – 2

Month	14th	26th
March	(R)
May		B
August
October		(V)

One person is born in between the one born in V and other born in S (In case – 1, two possibilities arise).

Therefore, further case – 1(a) and Case – 1(b) arise.

Case – 1(a)

Month	14th	26th
March	(S)
May	B(V)
August		(R)
October

Case – 1(b)

Month	14th	26th
March
May	B(V)
August	(S)	(R)
October

Case – 2

Month	14th	26th
March	(R)
May		B
August		(S)
October		(V)

There is no person born between the one born in V and the person F.
More than two people are born before F.
There are three persons born between F and G.

Case – 1(a)

Month	14th	26th
March	(S)
May	B(V)	F
August		(R)
October		G

Case – 1(b)

Month	14th	26th
March
May	B(V)	F
August	(S)	(R)
October		G

Case - 2

Month	14th	26th
March	(R)
May	G	B
August		(S)
October	F	(V)

Three persons are born between the one born in T and the person C such that C is born before the one born in T.

Therefore, case – 1(b) will be eliminated.

Case – 1(a)

Month	14th	26th
March	C(S)
May	B(V)	F
August	(T)	(R)
October		G

Case – 2

Month	14th	26th
March	C(R)
May	G	B
August	(T)	(S)
October	F	(V)

E is not born in R and V.
E and H are born in same month (Only month of August can accommodate two persons).

Therefore, further case – 2(a) and case – 2(b) arise.

Case – 1

Month	14th	26th
March	C(S)
May	B(V)	F
August	E(T)	H(R)
October		G

Case – 2(a)

Month	14th	26th
March	C(R)
May	G	B
August	E(T)	H(S)
October	F	(V)

Case – 2(b)

Month	14th	26th
March	C(R)
May	G	B
August	H(T)	E(S)
October	F	(V)

The one born in P has birthday just before the one born in Q.
A is born immediately before the one born in Q.

On combining the above two statements, it is implied that A is born in P.

Case – 1

Month	14th	26th
March	C(S)
May	B(V)	F
August	E(T)	H(R)
October	A(P)	G(Q)

Case – 2(a)

Month	14th	26th
March	C(R)	A(P)
May	G(Q)	B
August	E(T)	H(S)
October	F	(V)

Case – 2(b)

Month	14th	26th
March	C(R)	A(P)
May	G(Q)	B
August	H(T)	E(S)
October	F	(V)

Neither E nor D is born in R and V.
D is not the one born in W (So, only option left for D is of U. Therefore, D is born in U).

Therefore, case – 2(a) and case – 2(b) are neglected.

Month	14th	26th
March	C(S)	D(U)
May	B(V)	F
August	E(T)	H(R)
October	A(P)	G(Q)

After filling the remaining data, we get the final arrangement as shown below:

Month	14th	26th
March	C(S)	D(U)
May	B(V)	F(W)
August	E(T)	H(R)
October	A(P)	G(Q)

Therefore, A is born in P.

Hence, option 1) is correct.

Whose birthdays are in the month of October?

((a))
D and A
((b))
F and G
((c))
E and H
((d))
A and G
((e))
None of these

Show Answer

Answer: ((d))

A and G

8 persons: A, B, C, D, E, F, G and H.

4 Months: March, May, August and October.

8 Cities: P, Q, R, S, T, U, V and W.

They have their birthdays either on 14^th or 26^th of the given months.

B is born in May (B is either born in 14^th or 26^th of May).

Therefore, two cases arise.

Case -1

Month	14th	26^th
March
May	B
August
October

Case – 2

Month	14th	26^th
March
May		B
August
October

Two people are born between B and the one born in R.
Number of people born before the one born in R is same as number of persons born after the one born in V.
The one born in R does not have birthday in the month of October.

On combining the above statements, we get:

Case – 1

Month	14th	26^th
March
May	B(V)
August		(R)
October

Case – 2

Month	14th	26th
March	(R)
May		B
August
October		(V)

One person is born in between the one born in V and other born in S (In case – 1, two possibilities arise).

Therefore, further case – 1(a) and Case – 1(b) arise.

Case – 1(a)

Month	14th	26th
March	(S)
May	B(V)
August		(R)
October

Case – 1(b)

Month	14th	26th
March
May	B(V)
August	(S)	(R)
October

Case – 2

Month	14th	26th
March	(R)
May		B
August		(S)
October		(V)

There is no person born between the one born in V and the person F.
More than two people are born before F.
There are three persons born between F and G.

Case – 1(a)

Month	14th	26th
March	(S)
May	B(V)	F
August		(R)
October		G

Case – 1(b)

Month	14th	26th
March
May	B(V)	F
August	(S)	(R)
October		G

Case - 2

Month	14th	26th
March	(R)
May	G	B
August		(S)
October	F	(V)

Three persons are born between the one born in T and the person C such that C is born before the one born in T.

Therefore, case – 1(b) will be eliminated.

Case – 1(a)

Month	14th	26th
March	C(S)
May	B(V)	F
August	(T)	(R)
October		G

Case – 2

Month	14th	26th
March	C(R)
May	G	B
August	(T)	(S)
October	F	(V)

E is not born in R and V.
E and H are born in same month (Only month of August can accommodate two persons).

Therefore, further case – 2(a) and case – 2(b) arise.

Case – 1

Month	14th	26th
March	C(S)
May	B(V)	F
August	E(T)	H(R)
October		G

Case – 2(a)

Month	14th	26th
March	C(R)
May	G	B
August	E(T)	H(S)
October	F	(V)

Case – 2(b)

Month	14th	26th
March	C(R)
May	G	B
August	H(T)	E(S)
October	F	(V)

The one born in P has birthday just before the one born in Q.
A is born immediately before the one born in Q.

On combining the above two statements, it is implied that A is born in P.

Case – 1

Month	14th	26th
March	C(S)
May	B(V)	F
August	E(T)	H(R)
October	A(P)	G(Q)

Case – 2(a)

Month	14th	26th
March	C(R)	A(P)
May	G(Q)	B
August	E(T)	H(S)
October	F	(V)

Case – 2(b)

Month	14th	26th
March	C(R)	A(P)
May	G(Q)	B
August	H(T)	E(S)
October	F	(V)

Neither E nor D is born in R and V.
D is not the one born in W (So, only option left for D is of U. Therefore, D is born in U).

Therefore, case – 2(a) and case – 2(b) are neglected.

Month	14th	26th
March	C(S)	D(U)
May	B(V)	F
August	E(T)	H(R)
October	A(P)	G(Q)

After filling the remaining data, we get the final arrangement as shown below:

Month	14th	26th
March	C(S)	D(U)
May	B(V)	F(W)
August	E(T)	H(R)
October	A(P)	G(Q)

A and G have their birthday in the month of October.

Hence, option 4) is correct.

Which person has birthday immediately before the one who is born in V?

((a))
C
((b))
D
((c))
A
((d))
F
((e))
None of these

Show Answer

Answer: ((b))

8 persons: A, B, C, D, E, F, G and H.

4 Months: March, May, August and October.

8 Cities: P, Q, R, S, T, U, V and W.

They have their birthdays either on 14^th or 26^th of the given months.

B is born in May (B is either born in 14^th or 26^th of May).

Therefore, two cases arise.

Case -1

Month	14th	26^th
March
May	B
August
October

Case – 2

Month	14th	26^th
March
May		B
August
October

Two people are born between B and the one born in R.
Number of people born before the one born in R is same as number of persons born after the one born in V.
The one born in R does not have birthday in the month of October.

On combining the above statements, we get:

Case – 1

Month	14th	26^th
March
May	B(V)
August		(R)
October

Case – 2

Month	14th	26th
March	(R)
May		B
August
October		(V)

One person is born in between the one born in V and other born in S (In case – 1, two possibilities arise).

Therefore, further case – 1(a) and Case – 1(b) arise.

Case – 1(a)

Month	14th	26th
March	(S)
May	B(V)
August		(R)
October

Case – 1(b)

Month	14th	26th
March
May	B(V)
August	(S)	(R)
October

Case – 2

Month	14th	26th
March	(R)
May		B
August		(S)
October		(V)

There is no person born between the one born in V and the person F.
More than two people are born before F.
There are three persons born between F and G.

Case – 1(a)

Month	14th	26th
March	(S)
May	B(V)	F
August		(R)
October		G

Case – 1(b)

Month	14th	26th
March
May	B(V)	F
August	(S)	(R)
October		G

Case - 2

Month	14th	26th
March	(R)
May	G	B
August		(S)
October	F	(V)

Three persons are born between the one born in T and the person C such that C is born before the one born in T.

Therefore, case – 1(b) will be eliminated.

Case – 1(a)

Month	14th	26th
March	C(S)
May	B(V)	F
August	(T)	(R)
October		G

Case – 2

Month	14th	26th
March	C(R)
May	G	B
August	(T)	(S)
October	F	(V)

E is not born in R and V.
E and H are born in same month (Only month of August can accommodate two persons).

Therefore, further case – 2(a) and case – 2(b) arise.

Case – 1

Month	14th	26th
March	C(S)
May	B(V)	F
August	E(T)	H(R)
October		G

Case – 2(a)

Month	14th	26th
March	C(R)
May	G	B
August	E(T)	H(S)
October	F	(V)

Case – 2(b)

Month	14th	26th
March	C(R)
May	G	B
August	H(T)	E(S)
October	F	(V)

The one born in P has birthday just before the one born in Q.
A is born immediately before the one born in Q.

On combining the above two statements, it is implied that A is born in P.

Case – 1

Month	14th	26th
March	C(S)
May	B(V)	F
August	E(T)	H(R)
October	A(P)	G(Q)

Case – 2(a)

Month	14th	26th
March	C(R)	A(P)
May	G(Q)	B
August	E(T)	H(S)
October	F	(V)

Case – 2(b)

Month	14th	26th
March	C(R)	A(P)
May	G(Q)	B
August	H(T)	E(S)
October	F	(V)

Neither E nor D is born in R and V.
D is not the one born in W (So, only option left for D is of U. Therefore, D is born in U).

Therefore, case – 2(a) and case – 2(b) are neglected.

Month	14th	26th
March	C(S)	D(U)
May	B(V)	F
August	E(T)	H(R)
October	A(P)	G(Q)

After filling the remaining data, we get the final arrangement as shown below:

Month	14th	26th
March	C(S)	D(U)
May	B(V)	F(W)
August	E(T)	H(R)
October	A(P)	G(Q)

D is born immediately before the one born in V i.e. B.

Hence, option 2) is correct.

Which person’s birthday is between the one born in W and the person H?

((a))
E
((b))
B
((c))
A
((d))
D
((e))
None of these

Show Answer

Answer: ((a))

8 persons: A, B, C, D, E, F, G and H.

4 Months: March, May, August and October.

8 Cities: P, Q, R, S, T, U, V and W.

They have their birthdays either on 14^th or 26^th of the given months.

B is born in May (B is either born in 14^th or 26^th of May).

Therefore, two cases arise.

Case -1

Month	14th	26^th
March
May	B
August
October

Case – 2

Month	14th	26^th
March
May		B
August
October

Two people are born between B and the one born in R.
Number of people born before the one born in R is same as number of persons born after the one born in V.
The one born in R does not have birthday in the month of October.

On combining the above statements, we get:

Case – 1

Month	14th	26^th
March
May	B(V)
August		(R)
October

Case – 2

Month	14th	26th
March	(R)
May		B
August
October		(V)

One person is born in between the one born in V and other born in S (In case – 1, two possibilities arise).

Therefore, further case – 1(a) and Case – 1(b) arise.

Case – 1(a)

Month	14th	26th
March	(S)
May	B(V)
August		(R)
October

Case – 1(b)

Month	14th	26th
March
May	B(V)
August	(S)	(R)
October

Case – 2

Month	14th	26th
March	(R)
May		B
August		(S)
October		(V)

There is no person born between the one born in V and the person F.
More than two people are born before F.
There are three persons born between F and G.

Case – 1(a)

Month	14th	26th
March	(S)
May	B(V)	F
August		(R)
October		G

Case – 1(b)

Month	14th	26th
March
May	B(V)	F
August	(S)	(R)
October		G

Case - 2

Month	14th	26th
March	(R)
May	G	B
August		(S)
October	F	(V)

Three persons are born between the one born in T and the person C such that C is born before the one born in T.

Therefore, case – 1(b) will be eliminated.

Case – 1(a)

Month	14th	26th
March	C(S)
May	B(V)	F
August	(T)	(R)
October		G

Case – 2

Month	14th	26th
March	C(R)
May	G	B
August	(T)	(S)
October	F	(V)

E is not born in R and V.
E and H are born in same month (Only month of August can accommodate two persons).

Therefore, further case – 2(a) and case – 2(b) arise.

Case – 1

Month	14th	26th
March	C(S)
May	B(V)	F
August	E(T)	H(R)
October		G

Case – 2(a)

Month	14th	26th
March	C(R)
May	G	B
August	E(T)	H(S)
October	F	(V)

Case – 2(b)

Month	14th	26th
March	C(R)
May	G	B
August	H(T)	E(S)
October	F	(V)

The one born in P has birthday just before the one born in Q.
A is born immediately before the one born in Q.

On combining the above two statements, it is implied that A is born in P.

Case – 1

Month	14th	26th
March	C(S)
May	B(V)	F
August	E(T)	H(R)
October	A(P)	G(Q)

Case – 2(a)

Month	14th	26th
March	C(R)	A(P)
May	G(Q)	B
August	E(T)	H(S)
October	F	(V)

Case – 2(b)

Month	14th	26th
March	C(R)	A(P)
May	G(Q)	B
August	H(T)	E(S)
October	F	(V)

Neither E nor D is born in R and V.
D is not the one born in W (So, only option left for D is of U. Therefore, D is born in U).

Therefore, case – 2(a) and case – 2(b) are neglected.

Month	14th	26th
March	C(S)	D(U)
May	B(V)	F
August	E(T)	H(R)
October	A(P)	G(Q)

After filling the remaining data, we get the final arrangement as shown below:

Month	14th	26th
March	C(S)	D(U)
May	B(V)	F(W)
August	E(T)	H(R)
October	A(P)	G(Q)

E is born between the one born in W and H.

Hence, option 1) is correct.

Whose birthday comes on 26^th of October and where is the person born?

((a))
H, born in R
((b))
A, born in P
((c))
G, born in U
((d))
G, born in Q
((e))
None of these

Show Answer

Answer: ((d))

G, born in Q

8 persons: A, B, C, D, E, F, G and H.

4 Months: March, May, August and October.

8 Cities: P, Q, R, S, T, U, V and W.

They have their birthdays either on 14^th or 26^th of the given months.

B is born in May (B is either born in 14^th or 26^th of May).

Therefore, two cases arise.

Case -1

Month	14th	26^th
March
May	B
August
October

Case – 2

Month	14th	26^th
March
May		B
August
October

Two people are born between B and the one born in R.
Number of people born before the one born in R is same as number of persons born after the one born in V.
The one born in R does not have birthday in the month of October.

On combining the above statements, we get:

Case – 1

Month	14th	26^th
March
May	B(V)
August		(R)
October

Case – 2

Month	14th	26th
March	(R)
May		B
August
October		(V)

One person is born in between the one born in V and other born in S (In case – 1, two possibilities arise).

Therefore, further case – 1(a) and Case – 1(b) arise.

Case – 1(a)

Month	14th	26th
March	(S)
May	B(V)
August		(R)
October

Case – 1(b)

Month	14th	26th
March
May	B(V)
August	(S)	(R)
October

Case – 2

Month	14th	26th
March	(R)
May		B
August		(S)
October		(V)

There is no person born between the one born in V and the person F.
More than two people are born before F.
There are three persons born between F and G.

Case – 1(a)

Month	14th	26th
March	(S)
May	B(V)	F
August		(R)
October		G

Case – 1(b)

Month	14th	26th
March
May	B(V)	F
August	(S)	(R)
October		G

Case - 2

Month	14th	26th
March	(R)
May	G	B
August		(S)
October	F	(V)

Three persons are born between the one born in T and the person C such that C is born before the one born in T.

Therefore, case – 1(b) will be eliminated.

Case – 1(a)

Month	14th	26th
March	C(S)
May	B(V)	F
August	(T)	(R)
October		G

Case – 2

Month	14th	26th
March	C(R)
May	G	B
August	(T)	(S)
October	F	(V)

E is not born in R and V.
E and H are born in same month (Only month of August can accommodate two persons).

Therefore, further case – 2(a) and case – 2(b) arise.

Case – 1

Month	14th	26th
March	C(S)
May	B(V)	F
August	E(T)	H(R)
October		G

Case – 2(a)

Month	14th	26th
March	C(R)
May	G	B
August	E(T)	H(S)
October	F	(V)

Case – 2(b)

Month	14th	26th
March	C(R)
May	G	B
August	H(T)	E(S)
October	F	(V)

The one born in P has birthday just before the one born in Q.
A is born immediately before the one born in Q.

On combining the above two statements, it is implied that A is born in P.

Case – 1

Month	14th	26th
March	C(S)
May	B(V)	F
August	E(T)	H(R)
October	A(P)	G(Q)

Case – 2(a)

Month	14th	26th
March	C(R)	A(P)
May	G(Q)	B
August	E(T)	H(S)
October	F	(V)

Case – 2(b)

Month	14th	26th
March	C(R)	A(P)
May	G(Q)	B
August	H(T)	E(S)
October	F	(V)

Neither E nor D is born in R and V.
D is not the one born in W (So, only option left for D is of U. Therefore, D is born in U).

Therefore, case – 2(a) and case – 2(b) are neglected.

Month	14th	26th
March	C(S)	D(U)
May	B(V)	F
August	E(T)	H(R)
October	A(P)	G(Q)

After filling the remaining data, we get the final arrangement as shown below:

Month	14th	26th
March	C(S)	D(U)
May	B(V)	F(W)
August	E(T)	H(R)
October	A(P)	G(Q)

G is born on 26^th of October in Q.

Hence option 4) is correct.

Data Analysis & Interpretation (35 questions)

Given below the data about three employees of a call center named ZINTOCA. In the given table, data about calls received by them, calls selected for further lead and calls finally received is given:

	A	B	C
Initial calls(% out of total calls)	40%	30%	30%
Lead calls (% out of initial calls)	80%	x%	88%
Final received calls(% out of lead calls)	90%	80%	y%

Total number of initial calls in the company is 24000 and total number of calls not received by company C is 4464 less than the total number of calls received by company A. Find the value of y.

((a))
70
((b))
75
((c))
85
((d))
90
((e))
None of the above

Show Answer

Answer: ((b))

Calculation:

Let the total number of calls be 1000z.

Initial calls (% out of total calls) of A = (1000z × 40/100) = 400z

Initial calls (% out of total calls) of B = (1000z × 30/100) = 300z

Initial calls (% out of total calls) of C = (1000z × 30/100) = 300z

Lead calls (% out of initial calls) of A = (400z × 80/100) = 320z

Lead calls (% out of initial calls) of B = (300z × x/100) = 3zx

Lead calls (% out of initial calls) of C = (300z × 88/100) = 264z

Final received calls (% out of lead calls) of A = (320z × 90/100) = 288z

Final received calls (% out of lead calls) of B = (3zx × 80/100) = 3zx × (4/5)

Final received calls (% out of lead calls) of C = (264z × y/100)

Total number of initial calls in the company = 24000

⇒ (400z + 300z + 300z) = 24000

⇒ 1000z = 24000

⇒ z = (24000/1000)

⇒ z = 24

Total number of calls not received calls by C = (300h – 264z × y/100)

⇒ (300 × 24 – 264z × y/100)

⇒ (7200 – 264z × y/100)

According to the question

Total number of calls not received by company C is 4464 less than the total number of calls received by company A

⇒ (7200 – 264z × y/100) + 4464 = 288z

⇒ (7200 – 264 × 24 × y/100) + 4464 = 288 × 24

⇒ 7200 – 6336y/100 + 4464 = 6912

⇒ (720000 – 6336y + 446400)/100 = 6912

⇒ (720000 – 6336y + 446400) = 6912 × 100

⇒ (1166400 – 6336y) = 691200

⇒ (-6336y) = (691200 – 1166400)

⇒ (-6336y) = -475200

⇒ y = [-475200/(-6336)]

⇒ y = 75

∴ The value of y is 75

If the total number of calls not received by A and received by B is 224 and 432 respectively. Find the value of x.

((a))
80
((b))
75
((c))
90
((d))
85
((e))
None of the above