
Shortcut Trick
CP per banana = 135 ÷ 12 = ₹11.25
Required average SP for 22% overall profit = 11.25 × 1.22 = ₹13.725
Since 50% are sold at ₹14, let the SP of the remaining 50% be x.
For equal quantities, the overall average SP is the arithmetic mean:
⇒ (14 + x) ÷ 2 = 13.725 ⇒ 14 + x = 27.45 ⇒ x = 13.45
∴ The correct answer is ₹13.45.

Alternate Method
Given:
Cost price (CP) of 1 dozen (12 bananas) = ₹135
Overall desired profit = 22%
Selling price (SP) of 50% bananas = ₹14 each
Formula Used:
SP = CP × (100 + Profit%) ÷ 100

Calculations:
⇒ CP per banana = 135 ÷ 12 = ₹11.25
⇒ Let the total number of bananas be 2x.
⇒ Total CP for 2x bananas = 11.25 × 2x = ₹22.5x
⇒ Required overall Total SP = 22.5x × (100 + 22) ÷ 100 = 22.5x × 1.22 = ₹27.45x
⇒ SP of the first half (x bananas) = 14 × x = ₹14x
⇒ SP of the remaining half = Total SP − SP of first half
⇒ SP of remaining half = 27.45x − 14x = ₹13.45x
⇒ Required price per banana for the remaining half = 13.45x ÷ x = ₹13.45
∴ The correct answer is ₹13.45.

Additional Information
Overall Profit in Equal Parts
When an overall inventory is split into equal portions, the net effective average profit or selling price will be the exact arithmetic mean of the prices of individual portions.
Successive Percentage Changes
When consecutive markups, discounts, or profits are applied, the final outcome is derived using: Final = Initial × (1 ± R1/100) × (1 ± R2/100).
Mixture Rule for Profit & Loss
The rule of alligation cross-multiplication can be effectively used to determine the exact quantity ratio of items that must be sold at distinct profit percentages to achieve a targeted cumulative overall percentage.