
Shortcut Trick
Ratio of efficiency of faster pipe to slower pipe = 3 : 1.
Combined efficiency of both pipes = 3 + 1 = 4 units/min.
Total capacity of the tank = Combined efficiency × Time = 4 × 30 = 120 units.
Time taken by slower pipe = Total capacity ÷ Efficiency of slower pipe = 120 ÷ 1 = 120 minutes.
Convert minutes to hours: 120 ÷ 60 = 2 hours.
∴ The correct answer is 2 hours.

Alternate Method
| Pipe | Efficiency (units/min) | Total Time (min) | Total Work (units) |
|---|
| Faster Pipe | 3 | 30 (together) | 120 |
| Slower Pipe | 1 | | |
Given: Filling rate of faster pipe is 3 times the slower pipe. Together they take 30 minutes.
Formula Used: Total Work = Efficiency × Time; Time = Total Work ÷ Efficiency.
⇒ Let efficiency of slower pipe = 1 unit/min.
⇒ Efficiency of faster pipe = 3 units/min.
⇒ Total efficiency = 1 + 3 = 4 units/min.
⇒ Total capacity of tank = 4 × 30 = 120 units.
⇒ Time for slower pipe = 120 ÷ 1 = 120 minutes.
⇒ Time in hours = 120 ÷ 60 = 2 hours.
∴ The correct answer is 2 hours.

Additional Information
Pipes and Cisterns Efficiency
Efficiency is inversely proportional to the time taken to complete the work. If Pipe A is n times faster than Pipe B, it takes 1/n of the time taken by B.
Work and Time Relation
Total Work = (Efficiency1 + Efficiency2) × Combined Time. This is the fundamental principle used for simultaneous pipe problems.
Unit Conversion
Always ensure the final answer matches the units in the options. 60 minutes = 1 hour.